Chapter 6 Frequency Response & System Concepts

Similar documents
EECE 260 Electrical Circuits Prof. Mark Fowler

Chapter 25: Current, Resistance and Electromotive Force. ~10-4 m/s Typical speeds ~ 10 6 m/s

Class Summary. be functions and f( D) , we define the composition of f with g, denoted g f by

Chapter 25: Current, Resistance and Electromotive Force. Charge carrier motion in a conductor in two parts

9.4 The response of equilibrium to temperature (continued)

Collection of Formulas

Solutions to Midterm Physics 201

School of Electrical and Computer Engineering, Cornell University. ECE 303: Electromagnetic Fields and Waves. Fall 2007

Review of Mathematical Concepts

π,π is the angle FROM a! TO b

Important design issues and engineering applications of SDOF system Frequency response Functions

Optimization. x = 22 corresponds to local maximum by second derivative test

School of Electrical and Computer Engineering, Cornell University. ECE 303: Electromagnetic Fields and Waves. Fall 2007


General Physics II. number of field lines/area. for whole surface: for continuous surface is a whole surface

This immediately suggests an inverse-square law for a "piece" of current along the line.

Ch 26 - Capacitance! What s Next! Review! Lab this week!

Radial geodesics in Schwarzschild spacetime

CHAPTER 18: ELECTRIC CHARGE AND ELECTRIC FIELD

Friedmannien equations

Michael Rotkowitz 1,2

Previously. Extensions to backstepping controller designs. Tracking using backstepping Suppose we consider the general system

ELECTRO - MAGNETIC INDUCTION

MATHEMATICS IV 2 MARKS. 5 2 = e 3, 4

1. The sphere P travels in a straight line with speed

On the Eötvös effect

DEPARTMENT OF CIVIL AND ENVIRONMENTAL ENGINEERING FLUID MECHANICS III Solutions to Problem Sheet 3

Homework 3 MAE 118C Problems 2, 5, 7, 10, 14, 15, 18, 23, 30, 31 from Chapter 5, Lamarsh & Baratta. The flux for a point source is:

Continuous Charge Distributions

Prof. Anchordoqui Problems set # 12 Physics 169 May 12, 2015

POLYPHASE CIRCUITS. Introduction:

LC transfer of energy between the driving source and the circuit will be a maximum.

Fluids & Bernoulli s Equation. Group Problems 9

(A) 6.32 (B) 9.49 (C) (D) (E) 18.97

( ) D x ( s) if r s (3) ( ) (6) ( r) = d dr D x

3.1 Magnetic Fields. Oersted and Ampere

General Physics (PHY 2140)

Efficiency of excitation of piezoceramic transducer at antiresonance frequency

Overview. Before beginning this module, you should be able to: After completing this module, you should be able to:

Chapter 7. Kleene s Theorem. 7.1 Kleene s Theorem. The following theorem is the most important and fundamental result in the theory of FA s:

Data Structures. Element Uniqueness Problem. Hash Tables. Example. Hash Tables. Dana Shapira. 19 x 1. ) h(x 4. ) h(x 2. ) h(x 3. h(x 1. x 4. x 2.

DIRECT CURRENT CIRCUITS

Physics 11b Lecture #11

Higher Checklist (Unit 3) Higher Checklist (Unit 3) Vectors

RELATIVE KINEMATICS. q 2 R 12. u 1 O 2 S 2 S 1. r 1 O 1. Figure 1

Fourier-Bessel Expansions with Arbitrary Radial Boundaries

1 Using Integration to Find Arc Lengths and Surface Areas

Chapter 28 Sources of Magnetic Field

The Formulas of Vector Calculus John Cullinan

The Wave Equation I. MA 436 Kurt Bryan

The Area of a Triangle

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

U>, and is negative. Electric Potential Energy

11.1 Balanced Three Phase Voltage Sources

Conventional Paper-I (a) Explain the concept of gradient. Determine the gradient of the given field: ( )

FSK 116 Semester 1 Mathematics and Other Essentials. Priorities

Physics 604 Problem Set 1 Due Sept 16, 2010

Section 35 SHM and Circular Motion

ELE B7 Power Systems Engineering. Power System Components Modeling

NS-IBTS indices calculation procedure

STD: XI MATHEMATICS Total Marks: 90. I Choose the correct answer: ( 20 x 1 = 20 ) a) x = 1 b) x =2 c) x = 3 d) x = 0

13.5. Torsion of a curve Tangential and Normal Components of Acceleration

Energy Dissipation Gravitational Potential Energy Power

Math 4318 : Real Analysis II Mid-Term Exam 1 14 February 2013

Designing Information Devices and Systems I Discussion 8B

Answers to test yourself questions

Introduction to Group Theory

(a) Counter-Clockwise (b) Clockwise ()N (c) No rotation (d) Not enough information

Electric Potential. and Equipotentials

z TRANSFORMS z Transform Basics z Transform Basics Transfer Functions Back to the Time Domain Transfer Function and Stability

1. Viscosities: μ = ρν. 2. Newton s viscosity law: 3. Infinitesimal surface force df. 4. Moment about the point o, dm

r a + r b a + ( r b + r c)

SPA7010U/SPA7010P: THE GALAXY. Solutions for Coursework 1. Questions distributed on: 25 January 2018.

ELE B7 Power System Engineering. Unbalanced Fault Analysis

Matrix Algebra. Matrix Addition, Scalar Multiplication and Transposition. Linear Algebra I 24

Electric Field F E. q Q R Q. ˆ 4 r r - - Electric field intensity depends on the medium! origin

u( t) + K 2 ( ) = 1 t > 0 Analyzing Damped Oscillations Problem (Meador, example 2-18, pp 44-48): Determine the equation of the following graph.

Chapter 1: Logarithmic functions and indices

332:221 Principles of Electrical Engineering I Fall Hourly Exam 2 November 6, 2006

5.4 The Quarter-Wave Transformer

Things to Memorize: A Partial List. January 27, 2017

Electricity & Magnetism Lecture 6: Electric Potential

Simple Harmonic Motion I Sem

Chapter 21: Electric Charge and Electric Field

7.5-Determinants in Two Variables

Review of Calculus, cont d

Improper Integrals, and Differential Equations

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

RELATIONSHIP BETWEEN DESIGN RESPONSE SPECTRA FOR RARE AND FREQUENT EARTHQUAKE LEVELS

Solution of Tutorial 2 Converter driven DC motor drive

ELECTROSTATICS. 4πε0. E dr. The electric field is along the direction where the potential decreases at the maximum rate. 5. Electric Potential Energy:

Mark Scheme (Results) January 2008

Polynomials and Division Theory

Lecture 11: Potential Gradient and Capacitor Review:

PROGRESSION AND SERIES

Chapter 33 Alternating Current

Analytically, vectors will be represented by lowercase bold-face Latin letters, e.g. a, r, q.

196 Circuit Analysis with PSpice: A Simplified Approach

B.A. (PROGRAMME) 1 YEAR MATHEMATICS

Lecture 10. Solution of Nonlinear Equations - II

Transcription:

hpte 6 Fequency esponse & ystem oncepts Jesung Jng stedy stte (fequency) esponse Phso nottion Filte

v v Foced esponse by inusoidl Excittion ( t) dv v v dv v cos t dt dt ince the focing fuction is sinusoid, the solution is ssumed we ( t) sin t cos t cos ( t φ ) ubstitute get v cos t inusoidl excittion ( t) into the diffeenti l eqution nd solving nd ( ) ( ) sin t ( ) ( ) NO cos t fo the to be of coefficien ts nd, n sinusoidlly excited line cicuit, ll bnch voltges nd cuents e sinusoids t the sme fequency s the excittion signl. he mplitudes of these voltges nd cuents e scled vesion of the excittion mplitude nd the voltge nd cuents my be shifted in phse with espect to the excittion signl. D the sme fom. Phso nottion to solve fo fequency, mplitude, nd phse with moe ese.

e ( cos sin ) : omplex phso nottion fo cos omplex lgeb f eithe sinusoidl voltge o cuent souce supplies line cicuit consisting of esistnce, inductnces, nd cpcitnces, ll bnch voltges nd cuents of those components will be sinusoids of the sme fequency. We need complex lgeb to pefom the ddition, subtction, division, nd multipliction of voltges nd cuents in excited cicuits. f n instntneous voltge is descibed by sinusoidl function of time such s v t cost ( t ) t { } {} v t ee e e e whee is mximum vlue, nd πf is n ngul fequency of voltges. fequency - domin (phso) fom ( t ) his simplifiction is ust mthemticl convenience. time - domin fom e e cos sin : Eule's dentity ( cos sin ) Phso concept hs no el physicl significnce. t is ust convenient mthemticl tool.

he combintion of el nd n imginy tem is clled complex numbe. omplex numbes cn be clculted s phsos. Gphiclly, the sum is the hypotenuse of the ight tingle fomed by the two phsos. e b b cos e Exmples - - - > > > e( ) m( ) (in ctesin coodinte ) ( cos sin ) (in pol coodinte ) : mgnitude, tn ( ), b sin m( ),,, π omplex lgeb (cont.) π b : gument m b e b e ( ) m( ) : conugte of w ( ± w) ± w,( w) w, if w is not eo w

5, b e b e tesin fom is esie to use fo ddition nd subtction of complex numbes. b b b b b b b b b b b b b b b b b b b b b ± ± ± ± Pol fom is esie to use fo multipliction nd division of complex numbes. ± ± e e e e e e e e You hve to be ble to convet tesin fom to pol fom nd vice ves. omplex lgeb (cont.) Multipliction: multipliction of both mgnitudes & ddition of both guments Division: division of both mgnitudes & subtction of both guments

Hee, phso is defined s e. t hs the essentil infomtion: mplitude nd phse ngle of n c signl. he impednce is mesue of the opposition to the flow of cuent. ht is, it is complex esistnce. he element equtions tht define the voltge-cuent chcteistics of the pssive elements e (the Ohm s lw of sinusoidl cicuits) whee,, nd e phsos of voltge, cuent, nd impednce of n pssive element, espectively. / Y is clled dmittnce. he pssive elements hs impednces to sinusoids Fo esistnce, Fo inductnce, mpednce ( ) 9 X 9 whee X is the inductive ectnce. Fo cpcitnce, ` ( ) 9 X 9 whee X ( ) is the cpcitive he cpcitos nd inductos e fequency-dependent esistos. ectnce. 6

mpednce (cont.) he voltge coss esistnce is in phse with the cuent though it. he voltge coss n inductive ectnce leds the cuent though it by 9 o. (/) he voltge coss cpcitive ectnce lgs the cuent though it by 9 o. 7

mpednce (cont.) he totl impednces e clculted ust s esistnces e. n seies cicuit, the totl impednce is the sum of ll the impednces. n pllel cicuit, the ecipocl of the totl impednce is the ecipocl sum of individul impednces. lthough the impednce of single cicuit elements is eithe puely el (fo esistos) o puely imginy (fo inductos nd cpcitos), the genel definition of impednce should hve both el nd imginy pts since the pcticl cicuits consist of moe o less complex combintions of diffeent cicuit elements. 8

mpednce (cont.) - X Ω X Ω X 5 φ tn X 5 tn ( φ ) ( φ ) 6( φ ) ( φ ) X ( 9 ) 8( φ 9 ) Note: he vlue of the totl voltge () is less thn the sum of individul voltges ( 6 8), which is possible becuse these voltge vlues hve diffeent phse ngles. 9

9 99.5 9.995 9.95.995.995 8 tn 5 tn 5 φ φ φ φ φ φ X X

ummy he esistive (due to D) nd ective effects (due to ) must be combined by phsos (o complex numbes). Fo seies o pllel cicuits, ll the impednces e combined to find. he totl impednces e clculted ust s esistnces e. Fo line time-invint cicuit, the Netwok theoems (mesh nlysis, nodl nlysis, hevenin s theoem etc), K, o K tht wee used in solving D cicuits cn lso be used fo detemining sinusoidl () stedy-stte esponse using the phso nottions. Fo line time-vying cicuits o nonline cicuits, the stedy-stte esponse to sinusoidl input is usully not sinusoidl. icuit with (t) o (t) ime-invint cicuit: cicuit elements e time-invint (voltge o cuents of cicuit elements to inputs do not chnge with time) o independent souce.

Nodl nlysis with impednces 5 5 5 5 5 5 K on the pinciple nodes nducto, cpcito, o esisto

Mesh nlysis with impednces Mesh cuent Mesh cuent K on the two meshes

Fequency esponse { } { } { } { } H whee Fequency esponse of cicuit povide mesue of how the cicuit esponds to sinusoidl inputs of bity fequency. Given the input signl mplitude, phse, nd fequency, knowledge of the fequency esponse of cicuit pemits the computtion of the output signl. o expess the fequency esponse of cicuit in tems of vition in output voltge s function of souce voltge, we use is phse-shifted nd mplitude-scled vesion of with the fequency unchnged.

Filtes Filttion system Filte: eliminte impuities fom dinking wte o outdoo i unglss: filte out eye-dmging ultviolet dition Electicl filte: ttenute (i.e. educe in mplitude) o eliminte signls of unwnted fequencies Filte types (in tems of mplitude esponse vs. fequency) low-pss pss low fequencies nd ttenute high fequencies. high-pss pss high fequencies nd ttenute low fequencies. bnd-pss pss only specific bnd of fequencies fom its input to its output. bnd-stop block o seveely ttenute only specific bnd of fequencies. he filtes cn be thought of s fequency-dependent voltge divide, since the mount of output voltge is function of fequency. Pssive filtes: filtes mde up of cpcito, inducto, nd esistos, tht is, pssive components, which mens they do not genete voltges o cuents. oltge o cuent souce e not pssive but ctive. 5

ow-pss Filtes low-pss filte pss lowe fequencies (-> pss bnd) nd educe the mplitude of highe fequencies. he filte psses the udio signl (lowe fequency components, pssbnd) but ttenutes dio fequencies (highe fequency components, stopbnd). utoff fequency: the fequency t which the ttenution of filte educes the output mplitude to 7.7% of its vlue in the pss bnd. H Phse of ( ) ctn( ) o o i i ( ) o ctn( ) ctn( ) i o Mgnitude of i cutoff fequency of filte oltge divide 6

7 Exmple of ow-pss Filtes [ ] [ ] [ ] d/s 6 ctn ctn Phse of : :, : Mgnitude of ctn nd he mgnitude of fequency esponse of this filte is not equl to t the pssbnd.

High-Pss Filtes high-pss filte pss highe fequencies (-> pss bnd) nd educe the mplitude of lowe fequencies (-> stop bnd). H o i ( π ) ( ) ctn( ) o o i i ( ) o π ctn( ) i ( ) Mgnitude of Phse of 8

o o, : two fequencies :constnt Mgnitude of Phse of π nd-pss Filtes, & esonnce bnd-pss filte pss fequencies within cetin fequency nge (-> pss bnd) nd educe the mplitude of the othe fequencies (-> stop bnd). H o i o i ( )( ) ( ) ( ) o π ctn i ctn( ) ctn( ) tht detemine the pssbnd of o i ( ) ( ) ( ) the filte, 9

H nd-pss Filtes, & esonnce (cont.) he esponse of second-ode filtes cn be explined by ewiting the fequency esponse function in the following foms: o i ( ζ n ) ( ) ( ζ ) the shpness of Q n : dmping tio intesecting this hoiontl line. the powe t the output of the esonnt pek ( Qn ) ( ) ( Q ) n : ntul o esonnt fequency Q : Qulity fcto (Q fcto) ζ ζ n n n Q :(hlf - powe) bndwidth he fequency nge between (mgnitude) esponse points n Hlf powe stems fom the fct tht when the mplitude esponse is equl to.77, f the filte hs decesed by fcto of /. n n π

uning nd-pss filte: uning cicuits (-> choose desied fequency you wnt to he) employed in conventionl M dio by using vible cpcito. s illustted in the figue below, the vible cpcitnce cn be dusted to tune the seies cicuit to esonnce t ny one of five diffeent fequencies. -> he desied fequency component cn be collected by chnging the cpcitnce. f n ( ) π F π 6 ( 9 )( ) 5kH Fequencies with 5kH e visible nd the othes e eliminted o ttenuted t the output. mplitude fequency esponse function Five inputs

ode Plots ode plots: Fequency esponse plots of line systems displyed in the fom of logithmic plots. he mplitude tio is expessed in units of decibel (d), whee o o i ( ) ctn( ) ( ) cutoff, o hlf - powe, fequency of filte τ -d fequency ctn i ( ) d log o i,, o i o i d d log log d d