CHAPTER II AC POWER CALCULATIONS

Similar documents
Chapter 7 AC Power and Three-Phase Circuits

ECE 2100 Circuit Analysis

ECE 2100 Circuit Analysis

Chapter 10 Sinusoidal Steady-State Power Calculations

Revision: December 13, E Main Suite D Pullman, WA (509) Voice and Fax

TUTORIAL SOLUTIONS. F.1 KCL, KVL, Power and Energy Q.1. i All units in VAΩ,,

Electrical Circuits II (ECE233b)

Chapter 5. Circuit Theorems

Circuits II EE221. Instructor: Kevin D. Donohue. Instantaneous, Average, RMS, and Apparent Power, and, Maximum Power Transfer, and Power Factors

10. A.C CIRCUITS. Theoretically current grows to maximum value after infinite time. But practically it grows to maximum after 5τ. Decay of current :

Chapter 6: AC Circuits

Energy Storage Devices

Introduction to AC Power, RMS RMS. ECE 2210 AC Power p1. Use RMS in power calculations. AC Power P =? DC Power P =. V I = R =. I 2 R. V p.

2/20/2013. EE 101 Midterm 2 Review

A capacitor consists of two conducting plates, separated by an insulator. Conduction plates: e.g., Aluminum foil Insulator: air, mica, ceramic, etc

Chapter 10 ACSS Power

ECE 320 Energy Conversion and Power Electronics Dr. Tim Hogan. Chapter 1: Introduction and Three Phase Power

Module B3 3.1 Sinusoidal steady-state analysis (single-phase), a review 3.2 Three-phase analysis. Kirtley

Graduate Macroeconomics 2 Problem set 5. - Solutions

Diode rectifier with capacitive DC link

Introduction to Digital Circuits

Response of MDOF systems

Lesson 2 Transmission Lines Fundamentals

Learning Objectives. Self Organization Map. Hamming Distance(1/5) Introduction. Hamming Distance(3/5) Hamming Distance(2/5) 15/04/2015

3. Alternating Current

Chapter 10 Objectives

Solution in semi infinite diffusion couples (error function analysis)

Energy Storage Devices

ESS 265 Spring Quarter 2005 Kinetic Simulations

Motion in Two Dimensions

THEORETICAL AUTOCORRELATIONS. ) if often denoted by γ. Note that

First-order piecewise-linear dynamic circuits

Physics 3 (PHYF144) Chap 3: The Kinetic Theory of Gases - 1

Water Hammer in Pipes

Midterm Exam. Thursday, April hour, 15 minutes

EE 247B/ME 218: Introduction to MEMS Design Lecture 27m2: Gyros, Noise & MDS CTN 5/1/14. Copyright 2014 Regents of the University of California

Chapter Lagrangian Interpolation

BEF BEF Chapter 2. Outline BASIC PRINCIPLES 09/10/2013. Introduction. Phasor Representation. Complex Power Triangle.

Example: MOSFET Amplifier Distortion

Chapters 2 Kinematics. Position, Distance, Displacement

(,,, ) (,,, ). In addition, there are three other consumers, -2, -1, and 0. Consumer -2 has the utility function

II The Z Transform. Topics to be covered. 1. Introduction. 2. The Z transform. 3. Z transforms of elementary functions

ELEC 201 Electric Circuit Analysis I Lecture 9(a) RLC Circuits: Introduction

Reading. Lecture 28: Single Stage Frequency response. Lecture Outline. Context

Chapter 9 Sinusoidal Steady State Analysis

TUTORIAL PROBLEMS. E.1 KCL, KVL, Power and Energy. Q.1 Determine the current i in the following circuit. All units in VAΩ,,

The Decibel and its Usage

Week 11: Differential Amplifiers

Critical Evaluation of FBD, PQ and Generalized Non-Active Power Theories

Active Harmonic Filtering and Reactive Power Control

Let s treat the problem of the response of a system to an applied external force. Again,

Transient Response in Electric Circuits

Lecture 28: Single Stage Frequency response. Context

Normal Random Variable and its discriminant functions

The Impact of the Earth s Movement through the Space on Measuring the Velocity of Light

Revision: June 12, E Main Suite D Pullman, WA (509) Voice and Fax

Linear Response Theory: The connection between QFT and experiments

Lecture 11 Inductance and Capacitance

1 Widrow-Hoff Algorithm

Lecture 2: Telegrapher Equations For Transmission Lines. Power Flow.

( ) () we define the interaction representation by the unitary transformation () = ()

In the complete model, these slopes are ANALYSIS OF VARIANCE FOR THE COMPLETE TWO-WAY MODEL. (! i+1 -! i ) + [(!") i+1,q - [(!

Lecture 18: The Laplace Transform (See Sections and 14.7 in Boas)

V R. Electronics and Microelectronics AE4B34EM. Electronics and Microelectronics AE4B34EM. Voltage. Basic concept. Voltage.

Chapter 3: Vectors and Two-Dimensional Motion

H = d d q 1 d d q N d d p 1 d d p N exp

CHAPTER 13. Exercises. E13.1 The emitter current is given by the Shockley equation:

Viscous Damping Summary Sheet No Damping Case: Damped behaviour depends on the relative size of ω o and b/2m 3 Cases: 1.

Notes on the stability of dynamic systems and the use of Eigen Values.

SINUSOIDAL WAVEFORMS

Lecture 2 Introduction

Lecture 12: HEMT AC Properties

CHAPTER 6: FIRST-ORDER CIRCUITS

Lecture 11 SVM cont

CHAPTER 16 KINETICS: RATES AND MECHANISMS OF CHEMICAL REACTIONS

Sklar: Sections (4.4.2 is not covered).

R th is the Thevenin equivalent at the capacitor terminals.

Linearity. If kx is applied to the element, the output must be ky. kx ky. 2. additivity property. x 1 y 1, x 2 y 2

COLLEGE OF ENGINEERING PUTRAJAYA CAMPUS FINAL EXAMINATION SPECIAL SEMESTER 2013 / 2014

2. Electric Circuit Theory

Power Electronics 7. Diode and Diode Circuits

Volatility Interpolation

NEWTON S SECOND LAW OF MOTION

Today s topic: IMPULSE AND MOMENTUM CONSERVATION

12. Introduction and Chapter Objectives

3.1.3 INTRODUCTION TO DYNAMIC OPTIMIZATION: DISCRETE TIME PROBLEMS. A. The Hamiltonian and First-Order Conditions in a Finite Time Horizon

Lecture 10: Small Signal Device Parameters

IE1206 Embedded Electronics

Mechanics Physics 151

Introduction ( Week 1-2) Course introduction A brief introduction to molecular biology A brief introduction to sequence comparison Part I: Algorithms

UNIVERSITAT AUTÒNOMA DE BARCELONA MARCH 2017 EXAMINATION

AC Circuits AC Circuit with only R AC circuit with only L AC circuit with only C AC circuit with LRC phasors Resonance Transformers

Mechanics Physics 151

Dynamic Team Decision Theory. EECS 558 Project Shrutivandana Sharma and David Shuman December 10, 2005

Control Systems. Mathematical Modeling of Control Systems.

Scattering at an Interface: Oblique Incidence

Cointegration Analysis of Government R&D Investment and Economic Growth in China

Mechanics Physics 151

matter consists, measured in coulombs (C) 1 C of charge requires electrons Law of conservation of charge: charge cannot be created or

System in Weibull Distribution

Transcription:

CHAE AC OWE CACUAON

Conens nroducon nsananeous and Aerage ower Effece or M alue Apparen ower Coplex ower Conseraon of AC ower ower Facor and ower Facor Correcon Maxu Aerage ower ransfer Applcaons

3 nroducon Eery elecrcal dece has a power rang ha ndcaes how uch power he equpen requres; exceedng he power rang can cause peranen daage. e choce of power delery n 5- or 6-Hz ac for s due o he allowed hgh-olage power ransforaon.

nsananeous ower e ndependen wce angular frequency cos cos cos cos cos cos excaon, Assung snusodal wasw as defned s power e nsananeous p p 4

Aerage ower cos cos cos cos cos cos cos oer one perod. power he nsananeous he aerage of e aerage power s d d d d d p 5

6 Aerage ower Con d cos j e * cos Case: for a purely resse crcu, f. Case : 9 for a purely reace cos 9 crcu A resse load absorbs power a all e, whle a load or C absorbs zero aerage power. reace

7 Exaple Gen ha cos377 45 cos377 fnd he nsananeous power and he aerage ol p : cos377 6 cos 55 cos754 344. 6 cos754 45cos377 35 35 W cos 344. W power.

8 Exaple Fnd he he aerage 3 across.. ol : j7 3 j7 power absorbed by when a olage 76.6 66.8 e.576 cos 66.8 s.57666.8 * e.576 66.8 37.4 W an pedance appled

9 Exaple 3 Fnd he aerage power suppledby hesource and he aerage power absorbed by heressor. ol : 53 4 j 53 4.47 6.57.856.57 5.8 cos3 56.57.5 W.8.5 W 4

Effece or M alue e effece s he dc curren ha delers power oa e power absorbed by heressor n he ac crcu s d d d Whle he power absorbed by heressor n he dc crcu s eff eff ressor as alue of eff d a he perodc curren. perodc curren, he sae eff d ac crcu dc crcu

Effece or M alue Con d For any perodc funcon x For hesnusod cos d larly, for cos, e aerage cos, power can be wren as cos cos x, he d he alue s alus s cos gen by cos d

Coplex ower sn cos where gen as he ac load s absorbed by e coplex power are gen n phasor for as olage Consderng he curren and * * j power eace : power eal : e, nce * * Q jq j j

3 Coplex ower Con d s he aerage or real power. e power delered o he load e acual power dsspaed by he load Q s he reace or quardraure power. Un: ol-apere reace A A easure of he energy exchange beween he source and he reace par of he load Q = for resse loads uny pf Q < for capace loads leadng pf Q > for nduce loads laggng pf

uary pedance sn ower eace cos e ower eal ower Apparen Coplex ower * Q Q jq 4

5 ower rangle ower rangle pedance rangle ower rangle

Apparen ower and ower Facor angle ower facor ower facor Apparen power : : cos pf : A un where pf cos cos cos s power e aerage or cos cos are olage he curren and f 6

and pf Con d load an olage curren lags eans pf load a olage curren leads eans pf nce cos pf he oad pedance of Angle ower Facor Angle nduce aggng capace eadng 7

8 CONEAON OF AC OWE Wheher he loads are conneced n seres or n parallel or n general, he oal power suppled by he source equals he oal power delered o he load. us, n general, for a source conneced o N loads,

9 EANNG EAME Deerne real and reace power losses And real and reace power suppled. j.5 e{} cos pf 4 47. 6kA pf.84 4kW pf.84laggng Q 5,839 A * 6.45 A pf cos 3. 86 6.45 3.86 A * losses lne lne losses. j.56.45 4,685 load 4 j, 73A j5.839ka Balance of power suppled losses load 4.685 j.73 4 j5.839 44.685 j37.55ka

ower Facor Correcon s he process of ncreasng he power facor whou alerng he olage or curren o he orgnal load. pf correcon C j jc Mos loads are nduce. C

pf Correcon Con d zero. s because correcon he pf no affeced by s power Noe ha hereal an an Bu an an conseraon ges Applynghe ac power an sn an sn cos cos power, he real alerng whou cos o fro cos pf o ncrease we desre f * C C C C C Q C C Q Q Q Q Q Q

Exaple When conneced o a -, 6 - Hz power lne, a load absorbs 4 - kw a laggng power facor of.8. Fnd he capacance necessary o rase he pf o.95. ol : 6 rad/s We hae 4W pf. 8 pf cos. 8 36. 87 Q cos sn 5 sn36. 87 3A 5A cos When pf s rased o.95, cos.95 8.9 Q Q C 4.5 A cos sn 4.5sn8.9 34.4 A Q Q C Q 3 34.4 685.6 A C 685.6 3.5 F

Exaple 3

4 Exaple Calculae he source coplex power and power facor, how how he power facor can be proed o.95 =* = 3.37*43<7.89+4.43 A =45 <48.3 =876 + j 979.F = cos 7.89+4.43 =.665 New p.f =.95, s = 8.948 Qc = an s an s =6456 A C Qcapacor 6456 3.37 6 878 F

5 Exaple Deerne he power facor as seen by he source. Calculae he aerage power delered by he source. ol : e oal pedance s 6 4 -j 6. 8 j. 6 7 3. 4 e power facor s pf cos 3. 4. 9734 3 7 3.4 4.863.4 5 W pf 34.86pf

Maxu ower ransfer ax * 8, he condon wh axu power, ofnd j d d d d j j j 6

7 Maxu Aerage ower ransfer H H j H j e axu aerage power can be ransferred o he load f = H and = H ax H 8 H f he load s purely resse, hen H H H

Fnd he alue of n he crcu shown for axu power ransfer. 8

oluon 9