Today s topic 2 = Setting up the Hydrogen Atom problem. Schematic of Hydrogen Atom

Similar documents
Chapter 11 Solutions ( ) 1. The wavelength of the peak is. 2. The temperature is found with. 3. The power is. 4. a) The power is

The Hydrogen Atom. Chapter 7

Magnetic effects and the peculiarity of the electron spin in Atoms

Ch. 6 Free Electron Fermi Gas

Today s topics. How did we solve the H atom problem? CMF Office Hours

The tight-binding method

8(4 m0) ( θ ) ( ) Solutions for HW 8. Chapter 25. Conceptual Questions

ENGG 1203 Tutorial. Difference Equations. Find the Pole(s) Finding Equations and Poles

Previous knowlegde required. Spherical harmonics and some of their properties. Angular momentum. References. Angular momentum operators

The Real Hydrogen Atom

( ) L = D e. e e. Example:

School of Aerospace Engineering Origins of Quantum Theory. Measurements of emission of light (EM radiation) from (H) atoms found discrete lines

Quantum Mechanics Lecture Notes 10 April 2007 Meg Noah

ELEC9721: Digital Signal Processing Theory and Applications

In the name of Allah Proton Electromagnetic Form Factors

Chapter 6 Perturbation theory

Galaxy Photometry. Recalling the relationship between flux and luminosity, Flux = brightness becomes

ECE Spring Prof. David R. Jackson ECE Dept. Notes 20

4/20/2017. The Invention of the Modern Atom Early atomic models: Dalton model: Atom as billiard ball. The First Atomic Theorist.

Worksheet: Taylor Series, Lagrange Error Bound ilearnmath.net

MATH Midterm Solutions

1985 AP Calculus BC: Section I

1. Using Einstein Summation notation, prove the identity: = A

A A A. p mu E mc K mc E p c m c. = d /dk. c = 3.00 x 10 8 m/s e = 1.60 x C 1 ev = 1.60 x J 1 Å = m M Sun = 2 x kg

Option 3. b) xe dx = and therefore the series is convergent. 12 a) Divergent b) Convergent Proof 15 For. p = 1 1so the series diverges.

Announcements: The Rydberg formula describes. A Hydrogen-like ion is an ion that

W = mgdz = mgh. We can express this potential as a function of z: V ( z) = gz. = mg k. dz dz

Chapter (8) Estimation and Confedence Intervals Examples

Derivation of a Predictor of Combination #1 and the MSE for a Predictor of a Position in Two Stage Sampling with Response Error.

Hydrogen atom. Energy levels and wave functions Orbital momentum, electron spin and nuclear spin Fine and hyperfine interaction Hydrogen orbitals

DISCRETE-TIME RANDOM PROCESSES

Homework 1: Solutions

Problem Session (3) for Chapter 4 Signal Modeling

ECEN 5005 Crystals, Nanocrystals and Device Applications Class 14 Group Theory For Crystals

Potential Energy of the Electron in a Hydrogen Atom and a Model of a Virtual Particle Pair Constituting the Vacuum

Inverse Matrix. A meaning that matrix B is an inverse of matrix A.

CHAPTER 5 : SERIES. 5.2 The Sum of a Series Sum of Power of n Positive Integers Sum of Series of Partial Fraction Difference Method

Technical Report: Bessel Filter Analysis

Lecture 7: Angular Momentum, Hydrogen Atom

Orbital Angular Momentum Eigenfunctions

APPENDIX: STATISTICAL TOOLS

Relation between wavefunctions and vectors: In the previous lecture we noted that:

Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science. Fall Problem Set 11 Solutions.

Statistics 3858 : Likelihood Ratio for Exponential Distribution

Chapter 4. Fourier Series

The angle between L and the z-axis is found from

Probability & Statistics,

Lecture 20 - Wave Propagation Response

Spin(calori)tronics = spin+heat+electronics

Mapping Radius of Regular Function and Center of Convex Region. Duan Wenxi

On composite conformal mapping of an annulus to a plane with two holes

11.6 Absolute Convrg. (Ratio & Root Tests) & 11.7 Strategy for Testing Series

PURE MATHEMATICS A-LEVEL PAPER 1

Quantum Mechanics & Spectroscopy Prof. Jason Goodpaster. Problem Set #2 ANSWER KEY (5 questions, 10 points)

2012 GCE A Level H2 Maths Solution Paper Let x,

Motivation. We talk today for a more flexible approach for modeling the conditional probabilities.

Uncertainty Principle of Mathematics

Ordinary Differential Equations

Løsningsførslag i 4M

Law of large numbers

Introduction to Machine Learning DIS10

Solution to 1223 The Evil Warden.

Math 7409 Homework 2 Fall from which we can calculate the cycle index of the action of S 5 on pairs of vertices as

and integrated over all, the result is f ( 0) ] //Fourier transform ] //inverse Fourier transform

a) The average (mean) of the two fractions is halfway between them: b) The answer is yes. Assume without loss of generality that p < r.

Cylindrical quantum well of finite depth in external magnetic field.

RADIO-FREQUENCY WALL CONDITIONING FOR STEADY-STATE STELLARATORS

EXACT MODEL MATCHING AND DISTURBANCE REJECTION FOR GENERAL LINEAR TIME DELAY SYSTEMS VIA MEASUREMENT OUTPUT FEEDBACK

CHAPTER 10 INFINITE SEQUENCES AND SERIES

MATH 10550, EXAM 3 SOLUTIONS

ln x = n e = 20 (nearest integer)

On Jackson's Theorem

Topic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or


Solutions to Final Exam Review Problems

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART II Calculators are NOT permitted Time allowed: 2 hours

Fermi Gas. separation

5. Quantum Nature of the Nano-world ( Fundamental of. Quantum mechanics)

OVERVIEW OF THE COMBINATORICS FUNCTION TECHNIQUE

A Simple Proof that e is Irrational

Acoustics and electroacoustics

(Reference: sections in Silberberg 5 th ed.)

Module II: Part A. Optical Fibers

4. PERMUTATIONS AND COMBINATIONS

Instrumentation for Characterization of Nanomaterials (v11) 11. Crystal Potential

An Asymptotic Expansion for the Non-Central Chi-square Distribution. By Jinan Hamzah Farhood Department of Mathematics College of Education

Chapter Five. More Dimensions. is simply the set of all ordered n-tuples of real numbers x = ( x 1

CIVE322 BASIC HYDROLOGY Hydrologic Science and Engineering Civil and Environmental Engineering Department Fort Collins, CO (970)

Lecture 24: Observability and Constructibility

Discrete Fourier Transform (DFT)

Control Systems. Lecture 8 Root Locus. Root Locus. Plant. Controller. Sensor

Solutions of the D-dimensional Schrödinger equation with the Hyperbolic Pöschl Teller potential plus modified ring shaped term

15/03/1439. Lectures on Signals & systems Engineering

Greatest term (numerically) in the expansion of (1 + x) Method 1 Let T

Integrals of Functions of Several Variables

PARTIAL DIFFERENTIAL EQUATIONS SEPARATION OF VARIABLES

Part I- Wave Reflection and Transmission at Normal Incident. Part II- Wave Reflection and Transmission at Oblique Incident

For use only in [the name of your school] 2014 FP2 Note. FP2 Notes (Edexcel)

International Journal of Mathematics Trends and Technology (IJMTT) Volume 47 Number 1 July 2017

Chapter At each point (x, y) on the curve, y satisfies the condition

Transcription:

Today s topic Sttig up th Hydog Ato pobl Hydog ato pobl & Agula Motu Objctiv: to solv Schödig quatio. st Stp: to dfi th pottial fuctio Schatic of Hydog Ato Coulob s aw - Z 4ε 4ε fo H ato Nuclus Z What is difft about th Quatu chaical tatt? What is th pottial fuctio of th hydog ato? Coulobic itactio is ot kow ad caot b spcifid

Sttig up th Schödig quatio s ct-of-ass coodiats: lc lc uc lc uc Wit Schödig quatio i sphical coodiats: Schödig quatio icludig Coulobic Pottial [ ] 4 ε o Hydog Ato ε o 4 si si si ϕ ϑ Wh How will w appoach solvig this pobl? Solvig th Hydog ato pobl Assu spaatio of vaiabls: aag Schödig quatio ito 3 idpdt difftial quatios Dfi bouday coditios basd o physical asoig ϕ ϑ ϕ ϑ Φ Θ

3 Bouday coditios fo H ato ϕ ϕ Φ Φ Costaits o Θ ais i solvig th quatio ad quiig that th wav fuctio b wll bhavd i.. quadatically itgabl. S vi Sc. 5.3 fo dtails. Hydog Ato: Spaatig Vaiabls [ ] si si si { { : by Schodig q'. Multiply [ ] si si si call fo fo agula otu opato: Substitut ito Schödig quatio: Hydog Ato vaiabls : of spaatio apply Now [ ] [ ] : by though ΘΦ ΘΦ ΘΦ ΘΦ ΘΦ ΘΦ Divid Ca spaat ito two difftial quatios dpdt o adius ad agls

Agula Pat of H ato pobl is th sa as igid oto call th solutio fo Φ i th igid oto { wh a th sphical haoics Φ i ± ±... Solv th difftial quatio Applid Bouday coditios Applid oalizatio coditio igid oto Th solutio fo th difftial quatio dpdt o ust b solvd usig a pow sis. Th solutio is th gd Polyoials.! Θ! call that liits o cos ± / P cos Th wav fuctios fo th igid oto a call Sphical Haoics /! P cos 4! Wh P cos a th i gd polyoial s Th solutio ivolvs placig costaits o th poptis of th wav fuctio: quadatically itgabl S vi Chpt. 5 fo dtails. 4

Sphical Haoics a igfuctios of Ĥ ad z call that K ad H K I { H I { { total agula otu igid oto Thus th sphical haoics a also igfuctios of: i i i i z z z pojctio of ag. o. is Th valus of ad l a latd sic z- pojctio ust b lss tha total agula otu sic Total Agula Motu ad th z- pojctio of agula otu ca b asud siultaously [ ] [ ] [ x y z ] z y x 5

6 Oth copots of agula otu ca NOT b asud siultaously ] [ ] [ ] [ y i x z x i z y z i y x It ca b show that adial Wavfuctio fo H ato Not: idpdt of Hydog Ato... 8 8 4 thod to giv : pow sis quatio ust b solvd with a This h a wh a h ε ε ε / 3/ / 3!] [! a a a a agu fuctios th wh a Hydog Ato that is : ad othogoal a poply oalizd Th * si d d d d d d δ δ δ si

3 Hydog Ato Th fist fw agu Fuctios a Boh adius x x! a 3 3 x 3! 3! 3 x 33 3a 3a Th fist fw Hydog Atoic Wav Fs Zatoic ub of th uc lus; σ Z / a ; a Boh adius 3/ Z σ a 3 / Z σ σ / 3 a 3 / Z σ σ / cos 3 a ± 3 / Z σ σ / si ± i 64 a 3 / Z 7 8 σ / 3 3 σ σ 8 3 a Hydog Ato Agula otu dpds tily o gy dpds oly o th picipl quatu ub Th z copot of agula otu is dtid tily by z ħ Hydog Ato Th pobability that lcto lis btw ad d is [ l ] d Th adial fuctio has -l- ods <> <> ad <K> -<> gy lvls hav l dgacy i th absc of a agtic fild 7

Hydog Ato Th sphical haoics fo a coplx ad thus caot b pstd pictoially. Howv w ca tak lia cobiatios of sphical haoics with th sa gy to giv w igfuctios which also hav th sa gy. Hydog Ato Ths th fuctios a typically usd as th agula pat of th Hydog wav fuctios bcaus thy a al ad othogoal p x 3 4 py i 3 4 / / si cos si si p z 5 d z 6 Hydog Ato / 3cos d xz 5 4 d yz i 5 4 / / d x y 5 6 d xy i 5 6 si cos cos / si cos si / si cos si si Hliu Ato Th hliu has two lctos aoud th uclus so th S is giv by: 4 ε 4 ε 4 ε 8

Hliu Ato Bcaus th uclus is so assiv w ca gad it as fixd Thus: 4 ε 4 ε This quatio caot b solvd xactly bcaus of th itlctoic pulsio t. Nothlss w ca us a appoxiat thod to obtai a solutio to ay pcisio dsid. 9