Chapter 6. Laplace Transforms

Similar documents
Chapter 6. Laplace Transforms

6.8 Laplace Transform: General Formulas

To become more mathematically correct, Circuit equations are Algebraic Differential equations. from KVL, KCL from the constitutive relationship

CHAPTER. Forced Equations and Systems { } ( ) ( ) 8.1 The Laplace Transform and Its Inverse. Transforms from the Definition.

Laplace Transform. Inverse Laplace Transform. e st f(t)dt. (2)

18.03SC Unit 3 Practice Exam and Solutions

CONTROL SYSTEMS. Chapter 3 Mathematical Modelling of Physical Systems-Laplace Transforms. Prof.Dr. Fatih Mehmet Botsalı

Sample Final Exam (finals03) Covering Chapters 1-9 of Fundamentals of Signals & Systems

13.1 Circuit Elements in the s Domain Circuit Analysis in the s Domain The Transfer Function and Natural Response 13.

EECE 301 Signals & Systems Prof. Mark Fowler

Laplace Transforms. Examples. Is this equation differential? y 2 2y + 1 = 0, y 2 2y + 1 = 0, (y ) 2 2y + 1 = cos x,

Chapter 9 - The Laplace Transform

CHAPTER 3 SIGNALS & SYSTEMS. z -transform in the z -plane will be (A) 1 (B) 1 (D) (C) . The unilateral Laplace transform of tf() (A) s (B) + + (D) (C)

( ) ( ) if t = t. It must satisfy the identity. So, bulkiness of the unit impulse (hyper)function is equal to 1. The defining characteristic is

EE Control Systems LECTURE 2

LAPLACE TRANSFORM AND TRANSFER FUNCTION

SEC. 6.3 Unit Step Function (Heaviside Function). Second Shifting Theorem (t-shifting) 217. Second Shifting Theorem (t-shifting)

6.2 Transforms of Derivatives and Integrals.

EE202 Circuit Theory II

Chapter 7: Inverse-Response Systems

ENGI 9420 Engineering Analysis Assignment 2 Solutions

More on ODEs by Laplace Transforms October 30, 2017

Instrumentation & Process Control

CONTROL SYSTEMS. Chapter 10 : State Space Response

Chapter 1 Fundamental Concepts

Chapter 8 The Complete Response of RL and RC Circuits

1 CHAPTER 14 LAPLACE TRANSFORMS

EECE 301 Signals & Systems Prof. Mark Fowler

NODIA AND COMPANY. GATE SOLVED PAPER Electrical Engineering SIGNALS & SYSTEMS. Copyright By NODIA & COMPANY

8. Basic RL and RC Circuits

CHAPTER 7: SECOND-ORDER CIRCUITS

MATH 31B: MIDTERM 2 REVIEW. x 2 e x2 2x dx = 1. ue u du 2. x 2 e x2 e x2] + C 2. dx = x ln(x) 2 2. ln x dx = x ln x x + C. 2, or dx = 2u du.

Chapter 2. First Order Scalar Equations

Exponential Sawtooth

CHAPTER 12 DIRECT CURRENT CIRCUITS

t )? How would you have tried to solve this problem in Chapter 3?

u(t) Figure 1. Open loop control system

Serial : 4LS1_A_EC_Signal & Systems_230918

The complex Fourier series has an important limiting form when the period approaches infinity, i.e., T 0. 0 since it is proportional to 1/L, but

Lectures 29 and 30 BIQUADRATICS AND STATE SPACE OP AMP REALIZATIONS. I. Introduction

EECE 301 Signals & Systems Prof. Mark Fowler

Mon Apr 2: Laplace transform and initial value problems like we studied in Chapter 5

DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2008

Laplace transfom: t-translation rule , Haynes Miller and Jeremy Orloff

Piecewise-Defined Functions and Periodic Functions

s-domain Circuit Analysis

1 1 + x 2 dx. tan 1 (2) = ] ] x 3. Solution: Recall that the given integral is improper because. x 3. 1 x 3. dx = lim dx.

10. State Space Methods

Section 3.5 Nonhomogeneous Equations; Method of Undetermined Coefficients

Solutions to Assignment 1

CHAPTER 7. Definition and Properties. of Laplace Transforms

Math 2142 Exam 1 Review Problems. x 2 + f (0) 3! for the 3rd Taylor polynomial at x = 0. To calculate the various quantities:

Delhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:

Signals and Systems Linear Time-Invariant (LTI) Systems

Challenge Problems. DIS 203 and 210. March 6, (e 2) k. k(k + 2). k=1. f(x) = k(k + 2) = 1 x k

dy dx = xey (a) y(0) = 2 (b) y(1) = 2.5 SOLUTION: See next page

MA 214 Calculus IV (Spring 2016) Section 2. Homework Assignment 1 Solutions

ln 2 1 ln y x c y C x

EEEB113 CIRCUIT ANALYSIS I

EE202 Circuit Theory II , Spring. Dr. Yılmaz KALKAN & Dr. Atilla DÖNÜK

CHAPTER 6: FIRST-ORDER CIRCUITS

where the coordinate X (t) describes the system motion. X has its origin at the system static equilibrium position (SEP).

On the Exponential Operator Functions on Time Scales

CHAPTER 2: Mathematics for Microeconomics

MATH 4330/5330, Fourier Analysis Section 6, Proof of Fourier s Theorem for Pointwise Convergence

A Theoretical Model of a Voltage Controlled Oscillator

δ (τ )dτ denotes the unit step function, and

t is a basis for the solution space to this system, then the matrix having these solutions as columns, t x 1 t, x 2 t,... x n t x 2 t...

Lecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits

Guest Lectures for Dr. MacFarlane s EE3350 Part Deux

Chapter 4 The Fourier Series and Fourier Transform

KEY. Math 334 Midterm I Fall 2008 sections 001 and 003 Instructor: Scott Glasgow

Math 334 Fall 2011 Homework 11 Solutions

EE 313 Linear Signals & Systems (Fall 2018) Solution Set for Homework #8 on Continuous-Time Signals & Systems

Direct Current Circuits. February 19, 2014 Physics for Scientists & Engineers 2, Chapter 26 1

Chapter 3 Boundary Value Problem

dt = C exp (3 ln t 4 ). t 4 W = C exp ( ln(4 t) 3) = C(4 t) 3.

, the. L and the L. x x. max. i n. It is easy to show that these two norms satisfy the following relation: x x n x = (17.3) max

R =, C = 1, and f ( t ) = 1 for 1 second from t = 0 to t = 1. The initial charge on the capacitor is q (0) = 0. We have already solved this problem.

4.6 One Dimensional Kinematics and Integration

LAPLACE TRANSFORMS. 1. Basic transforms

EECE 301 Signals & Systems Prof. Mark Fowler

DISCRETE GRONWALL LEMMA AND APPLICATIONS

6 December 2013 H. T. Hoang - www4.hcmut.edu.vn/~hthoang/ 1

Linear Time-invariant systems, Convolution, and Cross-correlation

ECE Spring Prof. David R. Jackson ECE Dept. Notes 39

ME 391 Mechanical Engineering Analysis

6.302 Feedback Systems Recitation : Phase-locked Loops Prof. Joel L. Dawson

SOLUTIONS TO ECE 3084

Math 10B: Mock Mid II. April 13, 2016

8.1. a) For step response, M input is u ( t) Taking inverse Laplace transform. as α 0. Ideal response, K c. = Kc Mτ D + For ramp response, 8-1

can be viewed as a generalized product, and one for which the product of f and g. That is, does

About the HELM Project HELM (Helping Engineers Learn Mathematics) materials were the outcome of a three-year curriculum development project

Ordinary dierential equations

Chapter One Fourier Series and Fourier Transform

2 int T. is the Fourier transform of f(t) which is the inverse Fourier transform of f. i t e

Continuous Time. Time-Domain System Analysis. Impulse Response. Impulse Response. Impulse Response. Impulse Response. ( t) + b 0.

Reading from Young & Freedman: For this topic, read sections 25.4 & 25.5, the introduction to chapter 26 and sections 26.1 to 26.2 & 26.4.

EECE 301 Signals & Systems Prof. Mark Fowler

Laplace Transform and its Relation to Fourier Transform

Transcription:

6- Chaper 6. Laplace Tranform 6.4 Shor Impule. Dirac Dela Funcion. Parial Fracion 6.5 Convoluion. Inegral Equaion 6.6 Differeniaion and Inegraion of Tranform 6.7 Syem of ODE

6.4 Shor Impule. Dirac Dela Funcion. Parial Fracion 6- Dirac dela funcion or uni impule funcion i defined a if δ a = = a a+ε a ε = oherwie ( a) d δ = The dela funcion can be obained by aking he limi of f k δ( a) = lim f k ( a) k Sifing propery of dela funcion a+ε a ε δ( ) = g a d g a The Laplace ranform of dela funcion. Sar from f k fk ( a) = u( a) u ( a k) k + { } Take he limi k and apply l Hopial rule o he quoien. k k a e a e lim e e lim k k k L δ a = e a

Example Ma-Spring yem under a quare wave Inpu i of he form of a recangular funcion 6-3 The ubidiary equaion Ue he parial fracion expanion : The invere ranform : Uing -hifing ( ) ( ) ( ) ( ) y = e + e u ( ) e e u + Example Hammer blow repone of a ma-pring yem The inpu i given by a dela funcion Solving algebraically The oluion ( ) ( ) y = e u e u

Example 3 Four-Terminal RLC-Nework 4 Find he oupu volage if R= Ω, L= H, C = F. The inpu i a dela funcion and curren and charge are zero a =. 6-4 The volage drop on R, L, C hould be equal o he inpu. Uing i = q ' The ubidiary equaion Uing -hifing and 99 99.5 The oluion More on Parial Fracion F The oluion of a ubidiary equaion i of he form Y = G Parial fracion repreenaion may be needed. () Unrepeaed facor (-a) in G() Parial fracion hould be () Repeaed facor Repeaed facor 3 a in G() Parial fracion a in G() Parial fracion α +β (3) Unrepeaed complex facor Parial fracion A + A ( a) B ( a) ( a) A B C + + 3 ( a) ( a) ( a) A + B α +β

Example 4 Unrepeaed Complex Facor. A damped ma-pring yem under a inuoidal force. r( ) = in for < <π y" + y' + y = r( ), = for >π, y y =, ' = 5 6-5 The ubidiary equaion The oluion (6) The parial fracion of he fir erm Muliplying he common denominaor Term of like power of hould be equal on he righ and lef ide A=-, B=-, M=, N=6 Therefore he fir erm become The invere ranform (8) The invere of he econd erm of (6) i obained from (8) uing -hifing { } u π () Rewrie he hird erm of (6) 3 ( + ) 4 + + + + The invere uing -hifing e co 4in (7) The final oluion For < <π y()= Eq. (8) + Eq. (7) For >π y()= Eq. (8) + Eq. (7) + Eq. ()

6.5 Convoluion. Inegral Equaion 6-6 The convoluion of wo funcion f and g i defined a ( * ) f g f τ g τ dτ : Noe he inegraion inerval Theorem Convoluion heorem If F and G are Laplace ranform of f and g, repecively, he muliplicaion FG i he Laplace ranform of he convoluion (f*g) Proof: Se p= τ, hen Calculae he muliplicaion G can be inide of F For fixed τ, inegrae from τ o. becaue and τ are independen. ( The inegraion over blue region ) The inegraion can be changed a e f g d ( * ) Some properie of convoluion

Example Convoluion Le H( ) =. Find h(). a 6-7 Rearrange : H( ) = a F() G() a Invere ranform : f( ) e g( ) =, = aτ a Uing convoluion heorem : h = f( ) * g e dτ ( e ) a Example Convoluion Le H( ) = +ω. Find h(). Rearrange : H( ) Invere of ( +ω ) : inω ω = +ω +ω ( +ω ) ( ) ( ) in ω in in * ω in in co ω Uing convoluion heorem : ω in xin y = / [ co( x + y) + co( x y)] Example 3 Unuual Properie of Convoluion f * f in general h = ωτ ω τ dτ ω + ω ω ω ω ( f * f) may no hold Applicaion o Nonhomogeneou Linear ODE Nonhomogeneou linear ODE in andard form y" + ay' + by = r : a and b, conan The oluion = ( + ) ( ) + ' + : Q( ) = Y a y y Q R Q The invere of he fir righ erm can be eaily obained. The invere of he econd erm, auming y y y = q τ rτ dτ = ' =, ranfer funcion + a + b The oupu i given by he convoluion of he impule repone q() and he driving force r(). Example 5 Ma-pring yem

Solve y" + 3 y' + y = r, for r = < < = oherwie y y = ' = 6-8 The ranfer funcion I invere Since y y = ' =, he oluion i given by he convoluion of q and r. ( ) ( ) ( τ) ( τ) ( τ) ( τ) y = q τ rτ dτ q τ uτ uτ dτ e e dτ e e For < : y() = r()= only for << For << : The upper limi i, For > : The upper limi i, Noe he change in he lower limi. hould be le han. τ= ( τ) ( τ) ( ) ( ) y = e e e e + τ= τ= y = e e e e e e τ= τ= τ= ( τ) ( τ) ( ) ( ) ( ) ( ) Inegral Equaion Convoluion can be ued o olve cerain inegral equaion Example 6 A volerra Inegral Equaion of he Second Kind Solve Convoluion of y( ) and in( ) Uing he convoluion heorem we obain he ubidiary equaion + Y( ) Y( ) = Y ( ) Y ( ) = + 4 4 + + The anwer i

6.6 Differeniaion and Inegraion of Tranform. 6-9 Differeniaion of Tranform If F() i he ranform of f(), hen i derivaive i df ( ) F ( ) = f ( ) e d F '( ) = = f ( ) e d d Conequenly L f( ) = F' ( ) and L F' ( ) = f ( ) Example Differeniaion of Tranform The able can be proved uing differeniaion of F(). The econd one d β β L [ inβ ] = d +β +β Inegraion of Tranform If f() ha a ranform and f( ) lim / exi, + f( ) = L F ( ) d and L F d = f Proof: From he definiion f( ) F ( ) d = e f ( ) d d f ( ) e d d L Revere he order of inegraion. = e /

Example Differeniaion and Inegraion of Tranform 6- Find he invere ranform of F() = I derivaive Take he invere ranform L F ' L coω = f +ω f( ) coω = Uing inegraion of ranform Le Then = ( ) ' F F F d G d Take he invere ranform of boh ide g( ) coω f( ) = f( ) = Special Linear ODE wih Variable Coefficien Ue differeniaion of ranform o olve ODE. Le L [ y] = Y [ y' ] = Y y( ) L. Uing differeniaion of ranform d dy L [ y' ] = Y y( ) Y d d Similarly, uing L [ y" ] = Y y( ) y' L d d dy d [ y" ] = Y y( ) y' Y + y( )

Example 3 Laguerre Equaion Laguerre ODE i y" + y' + ny = n=,,, 6- The ubidiary equaion Separaing variable, uing parial fracion dy n + n n + = d d Y ( ) lny = nln n+ ln ln n + n Y = ( ) n n + The invere ranform i given by Rodrigue formula l = L Y n [ ] n=,, Prove Rodrigue formula Uing -hifing Uing he n-h derivaive of f, Afer anoher -hifing

6.7 Syem of ODE 6- The Laplace ranform can be ued o olve yem of ODE. Conider a fir-order linear yem wih conan coefficien The ubidiary equaion Rearrange a Y+ a Y = y G ( ) a Y+ ( a Y ) = y( ) G( ) Solve hi yem algebraically for Y ( ) and Y ( ) and ake he invere ranform for y ( ) and y ( ) Example Elecrical Nework i and i. Find he curren v( ) = vol only for.5 and i =' i = From Kirchhoff volage law in he lower and he upper circui, Rearrange i = i = The ubidiary equaion uing Solve algebraically for I and I ( + ) 5 5 5 65 I = e e 7 7 ( / ) ( / ) + + 7 3 + + 5 5 5 5 I = e + e 7 7 ( / ) ( / ) + + 7 3 + +

The invere ranform of he quare bracke erm uing -hifing. 5 5 / 65 7 / e e 7 3 5 5 / 5 7 / e + e 7 3 6-3 Uing -hifing 5 5 / 65 7 / 5 5 (.5)/ 65 7(.5)/ i ( ) = e e e e u (.5) 7 3 7 3 5 5 / 5 7 / 5 5 (.5)/ 5 7(.5)/ i ( ) = e + e e + e u (.5) 7 3 7 3 Noe ha he oluion for i differen from ha for due o he uni ep funcion. Example 3 Two mae on Spring Ignoring he ma of he pring and he damping Newon econd law(ma X acceleraion) Hooke law (reoring force) Iniial condiion y = y = y ' = 3 k, y ' = 3k The ubidiary equaion The algebraic oluion uing Cramer rule The final oluion