Physics 8 Wednesday, October 30, 2013

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Physics 8 Wednesday, October 30, 2013 HW9 (due Friday) is 7 conceptual + 8 calculation problems. Of the 8 calculation problems, 4 or 5 are from Chapter 11, and 3 or 4 are from Chapter 12. 7pm HW sessions: Weds 2N36 (Bill), Thurs 3W2 (Zoey) Reload the online-response page in your web browser to make sure reading assignments are up-to-date. We have the next 2 3 weeks to understand & use torque. Quiz today: one easy problem from HW7.

Torque: the rotational analogue of force Just as an unbalanced force causes linear acceleration F = m a an unbalanced torque causes rotational acceleration τ = I α Torque is (lever arm) (force) τ = r F where r is the perpendicular distance from the rotation axis to the line-of-action of the force.

τ = r F = rf = rf sin θ rf = r F Four ways to get the magnitude of the torque due to a force: (perpendicular component of distance) (force) (distance) (perpendicular component of force) (distance) (force) (sin θ between r and F ) use magnitude of vector product r F (a.k.a. cross product ) To get the direction of a torque, use the right-hand rule.

Note right-hand rule for vector product τ = r F. Note that most screws have right-handed threads. Turn right (clockwise) to tighten, turn left (counterclockwise) to loosen.

If you look at the face of a clock, whose hands are moving clockwise, do the rotational velocity vectors of the clock s hands point toward you or toward the clock? (A) Toward me (B) Toward the clock (C) Neither when I curl the fingers of my right hand toward the clock, my thumb points to the left, in the 9 o clock direction

Let s go back and use torque to analyze a couple of problems that last week we were only able to analyze using energy conservation. First: an object rolling (without slipping) down an inclined plane. What 3 forces act on the object? What is the rotation axis? Draw FBD and extended FBD. What are the torque(s) about this axis? How are α and a related? Write F = m a and τ = I α.

I α = τ ( ax ) I = RF s R ( ) I F s = R 2 a x ma x = mg sin θ F s ( I ma x = mg sin θ R 2 ) a x ( m + I ) R 2 a x = mg sin θ a x = mg sin θ m + I = g sin θ 1 + ( I R 2 mr 2 ) Remember that the object with the larger shape factor I /(mr 2 ) rolls downhill more slowly.

Next: the string wrapped around either the coffee can or the big red wheel. The wheel has rotational inertia I. The string is wrapped at radius R, with an object of mass m dangling on the string. For the dangling object, write ma y = F y For the cylinder, write I α = τ

After some math, I get α = mgr I wheel + mr 2 mgr I wheel (The approximation is for the limit where the object falls at a g, so the string tension is T = (mg ma) mg.)

Why did increasing the dangling mass m increase the wheel s rotational acceleration α? Why did increasing the radius R from which the dangling mass was suspended increase the wheel s rotational acceleration? Why did sliding the big rotating masses farther out on the extended arms decrease the wheel s rotational acceleration?

Torques are important in architecture because they allow us to determine the conditions for a structure to stay put. For an object (such as a structure or a part of a structure) to stay put, it must have zero acceleration, and it must have zero rotational acceleration. So the vector sum of all forces must add to zero, and the sum of all torques (about any axis) must also be zero (to keep a = 0 and α = 0). If these conditions are met, the object is in equilibrium: no unbalanced forces or torques.

Which column supports more of the beam s weight? (A) Left column supports more than half of the beam s weight. (B) Right column supports more than half of the beam s weight. (C) Same. Each column supports half of the beam s weight.

Let s analyze this configuration, then demonstrate an upside-down version of the same problem. How do I write F y = 0? What is a good choice of rotation axis here? How do I write τ = 0? What if I picked a different axis?

Equilibrium was briefly mentioned in Mazur s Chapter 12. It was/is the main topic of today s and next Monday s reading assignments. For example: What forces act on the beam? What 3 equations can we write for the beam?

inertia m rotational inertia I = mr 2 translational velocity v translational K.E. K = 1 2 mv 2 rotational velocity ω rotational K.E. K = 1 2 I ω2 momentum p = mv angular momentum L = I ω

HW9 (due Friday): Ch11 + concepts from Ch12 7pm HW sessions: Weds 2N36 (Bill), Thurs 3W2 (Zoey) Quiz: 10 min. Work alone. Closed book, 1 page notes OK. Calculator OK but not needed. Quizzes are only 5% of grade. 80% quiz total gets full credit. Calvin is pulling Hobbes on a sled, across a level, snow-covered field, at constant velocity. The coefficient of kinetic friction between the snow and the bottom of the sled is 0.20. The combined inertia of Hobbes and the sled is 50 kg. Because Hobbes is feeling too lazy to bother with trigonometry, he cooperates wth Calvin to keep the tow rope perfectly horizontal. (a) What is the tension in the tow rope? (Use the correct units!) (b) Draw a free-body diagram for the sled (treating Hobbes as part of the sled). Try to get the relative lengths of the force vectors about right.