Heavy Element Nucleosynthesis. A summary of the nucleosynthesis of light elements is as follows

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Heavy Element Nucleosynthesis A summary of the nucleosynthesis of light elements is as follows 4 He Hydrogen burning 3 He Incomplete PP chain (H burning) 2 H, Li, Be, B Non-thermal processes (spallation) 14 N, 13 C, 15 N, 17 O CNO processing 12 C, 16 O Helium burning 18 O, 22 Ne α captures on 14 N (He burning) 20 Ne, Na, Mg, Al, 28 Si Partly from carbon burning Mg, Al, Si, P, S Ar, Ca, Ti, Cr, Fe, Ni Partly from oxygen burning Partly from silicon burning Isotopes heavier than iron (as well as some intermediate weight isotopes) are made through neutron captures. Recall that the probability for a non-resonant reaction contained two components: an exponential reflective of the quantum tunneling needed to overcome electrostatic repulsion, and an inverse energy dependence arising from the de Broglie wavelength of the particles. For neutron captures, there is no electrostatic repulsion, and, in complex nuclei, virtually all particle encounters involve resonances. As a result, neutron capture cross-sections are large, and are very nearly independent of energy. To appreciate how heavy elements can be built up, we must first consider the lifetime of an isotope against neutron capture. If the cross-section for neutron capture is independent of energy, then the lifetime of the species will be τ n = 1 N n σv 1 N n σ v T = 1 N n σ ( µn ) 1/2 2kT

For a typical neutron cross-section of σ 10 25 cm 2 and a temperature of 5 10 8 K, τ n 10 9 /N n years. Next consider the stability of a neutron rich isotope. If the ratio of of neutrons to protons in an atomic nucleus becomes too large, the nucleus becomes unstable to beta-decay, and a neutron is changed into a proton via (Z, A+1) (Z+1, A+1) + e + ν e (27.1) The timescale for this decay is typically on the order of hours, or 10 3 years (with a factor of 10 3 scatter). Now consider an environment where the neutron density is low (N n 10 5 cm 3 ), so that the lifetime of isotope A, Z against neutron capture is long 10 4 years. This happens during the helium thermal pulses of an AGB star, where, due to mixing of shell material, the reactions 13 C + 4 He 16 O + n 14 N + 4 He 18 O + 4 He 22 Ne + 4 He 25 Mg + n release free neutrons at a slow rate. In time, the isotope will capture a neutron, undergoing the reaction (Z, A) + n (Z, A+1) + γ If isotope Z, A+1 is stable, then the process will repeat, and after a while, isotope Z, A+2 will be created. However, if isotope Z, A+1 is unstable to beta-decay, the decay will occur before the next neutron capture and the result will be isotope Z+1, A+1. This is the s- process; it occurs when the timescale for neutron capture is longer than the timescale for beta-decay.

Next, consider a different environment, where the neutron density is high, N n 10 23 cm 3. (This occurs during a supernova explosion.) At these neutron densities, the timescale for neutron capture is of the order of a millisecond, and isotope Z, A+1 will become Z, A+2 via a neutron capture before it can beta-decay. Isotope Z, A+2 (or its daughter isotope if it is radioactive) would therefore be an r-process element; its formation requires the rapid capture of a neutron. Whether an isotope is an s-process or r-process element (or both) depends on both its properties and the properties of the isotopes surrounding it. In the example above, suppose the radioactive isotope Z 3, A+1 is formed during a phase of rapid neutron bombardment, and suppose that its daughters Z 2, A+1, Z 1, A+1, and Z, A+1 are all radioactive as well. Isotope Z+1, A+1 would then be the end product of the r-process, as well as the product of s-process capture and beta-decay from Z, A. On the other hand, if isotope Z 1, A+1 is stable, then the beta-decays from Z 3, A+1 will stop at Z 1, A+1, and element Z+1, A+1 would effectively be shielded from the r-process. In this case, element Z+1, A+1 would be an s-process isotope only. Isotope Z 1, A+1 would, of course, be an r-process element, and, if isotope Z 2, A were unstable, it would be shielded from the s-process. A third process for heavy element formation is the p-process. These isotopes are proton-rich and cannot be formed via neutron capture on any timescale. P-process isotopes exist to the left of the valley of beta stability and thus have no radioactive parent. These isotopes are rare, since their formation requires overcoming a coulomb barrier. Their formation probably occurs in an environment similar to that of the r-process, i.e., where the proton density is extremely high, so that proton captures can occur faster than positron decays.

A characterization of a portion of the chart of nuclides showing nuclei to the classes of s, r, and p. The s-process path of (n, γ) reactions followed by quick β-decays enters at the lower left and passes through each nucleus designated by the letter s. Neutronrich matter undergoes a chain of β-decays terminating at the most neutron-rich (but stable) isobars; these nuclei are designated by the letter r. The s-process nuclei that are shielded from the r-process are labeled s only. The rare proton-rich nuclei, which are bypassed by both neutron processes are designated by the letter p.

The valley of stability.

Isotopic Ratios The abundance of every isotope A, Z can therefore be written N(Z, A) = N s (Z, A) + N r (Z, A) + N p (Z, A) N s (Z, A) + N r (Z, A) By knowing the neutron capture cross-sections of the isotopes, and by knowing which isotopes are shielded, (i.e., which are solely s- process and which are solely r-process) the pattern of elemental abundances can be used to trace the history of all the species. Clearly, the relative abundance of a given s-process element depends on its neutron capture cross-section. If the capture cross-section is low, then nuclei from the previous species will tend to pile-up at the element, and abundance of the isotope will be high. Conversely, if the isotope has a large neutron-capture cross-section, it will quickly be destroyed and will have a small abundance. S-process abundances can therefore be derived from differential equations of the form dn A = σ A N A + σ A 1 N A 1 dt The starting point for these equations is 56 Ni (although neutron captures actually start during helium burning, since the reactions 13 C(α, n) 16 O, 17 O(α, n) 20 Ne, 21 Ne(α, n) 24 Mg and 22 Ne(α, n) 25 Mg all create free neutrons). The endpoint of the s-process is 209 Bi, since the next element in the series, 210 Bi α-decays back to 206 Pb. Thus, the entire network looks like dn 56 dt dn A dt dn 206 dt = σ 56 N 56 = σ A N A + σ A 1 N A 1 57 A 209; A 206 = σ 206 N 206 + σ 205 N 205 + σ 209 N 209 (27.2)

with the boundary conditions N A (t = 0) = { N56 (t = 0) A = 56 0 A > 56 These equations can be simplified locally by noting that the neutron capture cross-sections for adjacent non-closed-shell nuclei are large and of the same order of magnitude, so that σ A N A σ A 1 N A 1 (27.3) This is called the local approximation; it is only good for some adjacent nuclei. Over a length of A 100, abundances can drop by a factor of 10. The abundance of r-process isotopic ratios in nature can be estimated by differencing the observed cosmic abundances from that predicted from the s-process. Part of the r-process isotopic ratios may be due to processes associated with nuclear statistical equilibrium under extremely high densities (ρ > 10 10 gm-cm 3. (Under these conditions, the Fermi exclusion will force electron captures in the nucleus, and cause a build up a neutrons.) However, r-process isotopes can also be built up in more moderate densities, if the neutron density is high ( 10 23 cm 3 ). Under these conditions, a nucleus will continue to absorb neutrons until it can capture no more (i.e., until another neutron would exceed the binding energy). At this point, the nucleus must wait until a beta-decay occurs. Thus, the abundance of an isotope with charge Z will be governed by the beta-decay rates, i.e., dn Z dt = λ Z 1 N Z 1 (t) λ Z N Z (t) where λ Z is the beta-decay rate at the waiting point for charge Z. (In practice, under these circumstances, one must also take into

account proton and α-particle captures as well, since these reactions will also add charge to neutron-rich material. However, because of the electrostatic repulsion, these capture cross-sections will be much lower.) R-process nucleosynthesis stops at Z = 94 (N = 175) where nuclear fission occurs to return two additional seeds to the capture chain. Measured and estimated neutron-capture cross sections of nuclei on the s-process path. The neutron energy is near 25 kev. The cross sections show a strong odd-even effect, reflecting average level densities in the compound nucleus. Even more obvious is the strong influence of closed nuclear shells, or magic numbers, which are associated with precipitous drops in the cross section. Nucleosynthesis of the s-process is dominated by the small cross sections of the neutron-magic nuclei.

The solar system σn s curve, i.e., the product of the neutron capture cross sections for kt = 30 kev times the nuclide abundance per 10 6 silicon atoms. The solid curve is the calculated result of an exponential distribution of neutron exposures.

Calculated r-process abundances after long times. The nuclei have been driven around a fission cycle until the abundance distribution becomes characteristic of a steady state. The abundance of each nucleus grows exponentially with an efolding time of 4.9 sec. This time, calculated on the basis of β-decays rates, depends upon the neutron density and the the temperature.

The abundances of the elements in the solar system. The dots represent values obtained from the strengths of solar absorption lines, while the line is based on chemical evidence from the earth and meteorites.

Nucleocosmochronology It is possible to obtain an independent estimate of the age of the Solar System (and, indeed the universe) from the study of radioactive species (and sometimes their daughter elements). The idea is simple. Consider an radioactive species, i present in an object that was born at time τ = t in the universe. Prior to time t, this element was created in various events, and had a production rate P i p(t). The abundance of that species today (at time t = t 0 ) will be which simplifies to N = P i e λ i(t 0 t) t 0 p(τ) e λ i(t τ) dτ t N = P i e λ it 0 p(τ) e λiτ dτ (27.4) where λ is the decay rate of the species. Obviously, calculations of the production rate can be treacherous. However, if one takes the ratio of two elements which are presumed to be created together (say, in r-process events), then most of the unknowns cancel out. So N i = P t i e λit0 0 p(τ) eλiτ dτ N s P s e λ st 0 t 0 p(τ) eλ sτ dτ Moreover, if the second element is stable (with λ s = 0), then 0 N i N s = P i P s e λ it 0 t 0 p(τ) eλ iτ dτ t 0 p(τ) dτ P i P s (1 λ i (t 0 t )) (27.5)

In other words, by observing the ratio of two species, and knowing the ratio of their production ratio in a star, one can obtain t 0 t, the mean age of the elements. Long-lived Galactic Chronometers Nucleus Half-Life (yrs) Daughter Decay Mode Process 40 K 1.3 10 9 40 Ca β Si burning 40 K 1.3 10 9 40 Ar β + Si burning 87 Rb 4.9 10 10 87 Sr β r/s-process 138 La 1.1 10 11 138 Ba β cap p-process 138 La 1.1 10 11 138 Ce β p-process 147 Sm 1.1 10 11 143 Nd α s/r-process 176 Lu 3.7 10 10 176 Hf β s-process 187 Re 4.5 10 10 187 Os β r-process 232 Th 1.4 10 10 205 Pb Chain r-process 235 U 7.0 10 8 207 Pb Chain r-process 238 U 4.5 10 9 206 Pb Chain... 107 Pd 6.5 10 6 107 Ag β s/r-process 129 I 1.6 10 7 129 Xe β r-process 182 Hf 9.0 10 6 182 W β r-process 244 Pu 8.2 10 7 232 Th Chain r-process Obviously to do this experiment, one needs to work with elements that are formed in the same event. In the solar system, one can restrict the experiment to r-process only isotopes. However, it is not possible to separate out the different isotopes via stellar absorption lines. (This is not strictly true for the lightest species such as deuterium and CNO, but for heavier elements it is certainly true.) However, elements heavier than 209 Bi can only be made with the r-process (since 210 Bi α-decays back to 206 Pb).

The two most popular elements to perform this experiment with is Uranium and 232 Th (half-life 13.9 Gyr) and 238 U (half-life 4.51 Gyr). But these lines are weak!) For example, here are the results from the extreme metal-poor halo star BD+17 3248 (from Cowan et al. 2002): Chronometric Age Estimates for BD+17 3248 Element Age (Gyr) Pair Predicted Observed Solar Best Limit Th/Eu 0.507 0.309 0.4614 10.0 > 8.2 Th/Ir 0.0909 0.03113 0.0646 21.7 > 14.8 Th/Pt 0.0234 0.0141 0.0323 10.3 > 16.8 Th/U 1.805 7.413 2.32 > 13.4 > 11.0 U/Ir 0.05036 0.0045 0.0369 > 15.5 > 13.5 U/Pt 0.013 0.0019 0.01846 > 12.4 > 14.6

Fig. 8. Observed Keck/HIRES and synthetic spectra in region surrounding the Th ii 4019.12 line, in the manner of Fig. 3. In the bottom panel, the synthetic spectra were computed for abundances log ðthþ ¼ 1, 1.58, 1.18, and 0.78. Fig. 9. Spectra of BD +17 3248 in region surrounding the U ii 3859.57 line. In both panels the observed Keck/HIRES spectrum is compared to four synthetic spectra computed for abundances log ðuþ ¼ 1, 2.60, 2.10, and 1.60. (Note that some of the lines overlap.) The only difference between the two panels is the vertical scale, which is expanded in the bottom panel for easier assessment of the extremely weak U ii feature.