PHYSICS - CLUTCH CH 01: UNITS & VECTORS.

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Physics is the study of natural phenomena, including LOTS of measurements and equations. Physics = math + rules. UNITS IN PHYSICS We measure in nature. Measurements must have. - For equations to work, units have to be with one another. For example: F = m a ( Force = Mass * Acceleration ) [ ] = [ ] [ ] A group of units that work together is called a of units. - In Physics, we use the ( Système International ). - Many other conventions / standards are used in Physics. QUANTITY S.I. UNIT [ ] [ ] [ ] Non-S.I. measurements must be converted into S.I. before we plug them into equations. VIDEO: Unit Conversions - Equations must be dimensionally consistent: units are the same on both sides. VIDEO: Unit Analysis* PRECISION, SIGNIFICANT FIGURES, AND SCIENTIFIC NOTATION Measurements must be precise. Precision has to do with how many a measurement has. - When adding/multiplying/etc. measurements, we must use Sig Fig Rules*. VIDEO: Significant Figures* - To compress numbers: (a) use powers of TEN; (b) round to TWO* decimal points (digits 5 or greater, round up). - We can use to represent numbers. EXAMPLE 1: For each number below: (a) How many sig figs does it have? (b) Re-write it in scientific notation (2 decimals). (a) 010,000 (b) 010,000.0 (c) 010,010 (d) 00.010 (e) 382,400 (f) 23,560.0 Page 2

CONVERTING UNITS If given units on different systems, convert all units to the same system. Usually this means converting to S.I. units. EXAMPLE 1: Convert 44 lb into kg (1 kg = 2.2 lb): PATTERN: [ ] [ ] ( ) ( ) = [ ] [ ] EXAMPLE 2: Convert 100 m 2 into ft 2 (1 ft = 0.305 m): [ ] [ ] ( ) ( ) = [ ] [ ] EXAMPLE 3: Convert 30 m/s into miles per hour (1 mi = 1600 m, 1 hour = 3600 s): [ ] [ ] ( ) ( ) = [ ] [ ] PRACTICE 4: Convert 10 ft into km (1 ft = 0.305 m): (a) 0.00305 km (b) 327.87 km (c) 0.0305 km (d) 30.5 km PRACTICE 5: Convert 2,000 ml into m 3 (1 L = 1,000 cm 3 ): (a) 0.002 m 3 (b) 0.2 m 3 (c) 20 m 3 (d) 2,000 m 3 PRACTICE 6: Convert 80 km/h into m/s (1 km = 1000 m, 1 hour = 3600 s): (a) 288 m/s (b) 28.8 m/s (c) 4.8 m/s (d) 22.22 m/s Page 3

UNIT ANALYSIS (aka Dimensional Analysis) Equations must be dimensionally consistent: Units on both sides of the equation must be the same. - For example, from speed = we can get that distance = speed * time - Because distance is measured in meters, and time in seconds: speed = - The second equation is also dimensionally consistent: distance = speed * time = EXAMPLE 1: Suppose Wikipedia says that the distance Y (in meters) that an object free falls from rest in t seconds is given by Y = ½ g t 2, where g is the acceleration due to gravity, in m/s 2. Is this equation dimensionally consistent? EXAMPLE 2: Hooke s law states that the restoring force F on a spring is related to its displacement from equilibrium x by F = k x. If F is measured in Newtons (N) and x in meters (m), what unit(s) must the force constant k have? PRACTICE 3: If distance x is measured in [m], time t in [s], speed v in [m/s], acceleration a in [m/s 2 ], mass m in [kg], and force F in [N] = [kg * m/s 2 ], show which of the following equations is/are dimensionally consistent: (a) v 2 = 2 a x (b) v 2 = 2 a t PRACTICE 4: Newton s Law of Gravitation states that the attraction between two objects is given by F = G m1 m2 / r 2, where F is in [kg * m/s 2 ], m1 and m2 are the objects masses (in [kg]), and r is the distance between them (in [m]). What unit(s) must the Universal Constant G have? (a) kg s 2 / m 3 (b) m 3 / kg s 2 (c) m / s 2 (d) m 3 / s 2 (c) F = m (v2 v1) / t Page 4

SCALARS AND VECTORS There are two types of physical quantities: (1) SCALAR = ( ) (2) VECTOR = + ( ) POSITION, DISPLACEMENT, DISTANCE POSITION = = represented by, it is the displacement from the. Whenever you can ask IN WHAT DIRECTION? the quantity is a vector! Time Length Mass Temperature Force DISPLACEMENT =. DISTANCE =. EXAMPLE 1: Find the distance and displacement for each of the following situations: Case 1: 1D Motion Case 2: 2D Motion Case 3: Circular Motion Page 5

INTRO TO VECTOR MATH & VECTOR COMPOSITION Because Vectors have direction, doing math is not as straight forward as with scalars: Adding Scalars: 10 kg + 20 kg =. Adding Vectors: You move 3 m to the right, 4 m up, your total displacement is:. Since displacement is a vector, we ll work on some displacement problems to illustrate how to manipulate vectors. - Vectors are added either graphically or algebraically. Graphically is more visual (duh), but algebraically is faster. - We ll begin playing with vectors graphically: Vectors are represented as arrows, added using. EXAMPLE 1: For each of the following, draw your displacement vectors and calculate your total displacement: (a) You walk 3 m to the right, then 4 m to the right. (b) You walk 3 m up, then 4 m down. Vectors in the SAME axis (both X or both Y) are added just like you would any numbers. Just be careful with. - But when vectors lie on DIFFERENT axes (one X, one Y), we must use to add them: EXAMPLE 2: You walk 3 m to the right, then 4 m up. Draw your displacement and calculate its magnitude and direction. We call this Vector because the X & Y components are merged to form a 2D vector. Forces are also vectors. If multiple forces act on an object, we can use the similar process to find the force: EXAMPLE 3: A box sits on an X-Y plane. You pull on it with force 6 N towards the +X axis, while your friend pulls on it with force 8 N directed towards the +Y axis. Find the magnitude and direction of the NET force acting on the box. Page 6

VECTOR DECOMPOSITION Two vectors can only be combined if: (1) They lie on the SAME axis (both X or Y). (2) One lies on the X, one lies on the Y. A vector at an angle (not on the X or Y) must first be into its X & Y components: EXAMPLE 1: Each square on the grid below represents 1 meter. Find the X and Y components of the vectors shown (use positive/negative to indicate direction). Then calculate the magnitude and direction of each. Unfortunately, vectors typically do NOT fall on pretty grids. We use to calculate vector components: EXAMPLE 2: You walk 6 m to the right, then 5 m directed at 37 o above the positive x axis. Draw your displacement and calculate its magnitude and direction. If angle is (1) against the axis, or (2) the * angle, then AX =, AY =. Remember forces are vectors. So we can also decompose forces into their X & Y components: EXAMPLE 3: A force of 10 N is applied directed at 37 o below the positive X axis. Find the X & Y components of this force (use signs (+/ ) to indicate the direction of the components). Page 7

PRACTICE: VECTOR COMPONENTS (Part 1) VECTOR EQUATIONS PRACTICE 1: You walk 3 m down, then 4 m to the right. Draw your displacement and calculate its magnitude and direction. AX = AcosΘ AY = AsinΘ A = Θ = tan -1 (AY / AX) PRACTICE 2: You walk 7 m down, then 10 m directed at 53 o below the positive x axis. Draw your displacement and calculate its magnitude and direction. PRACTICE 3: Three forces act on an object: A = 2 N @ 0 o, B = 7 N @ 90 o, and C N = 5 @ 37 o. Calculate the magnitude and direction of the NET force acting on the object. Page 8

REVIEW: TRIG FOR PHYSICS (Part 1) There are only a few things you need from Trig in Physics. But you need to be a NINJA with them. EXAMPLE 1: For each triangle below, use Pythagorean s Theorem and/or SOH-CAH-TOA to find the missing variables: (a) A = 5, AX = 4 AY =? Θ =? (b) Θ = 30 o, AY = 8 A =? AX =? Vector Composition & Decomposition Unit Circle: 0 o, CW/CCW, Quadrants, X/Y Signs Angles in Triangle Complementary Angles Angles using N / S / W / E Eg. 30 o North of East Eg. 30 o West of South When Taking ARCTAN (composing a vector) The Arctan function ALWAYS gives you an angle in the or quadrant (relative to +X axis). - If your vector is in the or quadrant, you must add or subtract (you pick). EXAMPLE 2: For each set of vector components, find the vector s absolute angle: (a) AX = 4, AY = 3 (b) AX = 4, AY = 3 Page 9

REVIEW: TRIG FOR PHYSICS (Part 2) When Taking SINE and COSINE (decomposing a vector) Angles can be (1) ; or relative to (aka against, measured from) the (2) X axis, or (3) Y axis: EXAMPLE 1: Find the angles relative to X and Y that are equivalent to 210 o. EXAMPLE 2: A vector is directed +37 o off the negative Y axis (counter clockwise). Find the absolute angle, and the angle relative to X. If the angle is (1) or (2) against the axis, then: AX =, AY =. ( GOOD ) - If angle is (3) against the axis, then: AX =, AY =. ( BAD ) EXAMPLE 1: Decompose each vector (both have size 5) below using the GIVEN angle (don t change it!) (a) (b) 53 o 37 o If the angle is, sine & cosine will give you the correct sign ( ). Otherwise, YOU have to add the sign. EXAMPLE 2: Decompose the vector shown (size = 5) using (a) the absolute angle, and (b) the angle relative to the X axis. 37 o Page 10

PRACTICE: VECTOR COMPONENTS (Part 2) VECTOR EQUATIONS PRACTICE 1: You move 15 m due east, then 30 m north, then 25 m east. Draw displacement vectors and find the magnitude and direction (use the absolute angle) of your total displacement. AX = AcosΘ AY = AsinΘ A = Θ = tan -1 (AY / AX) PRACTICE 2: You move 4 m due east, 5 m due north, and 6 m due south. What is the magnitude and direction (use the absolute angle) displacement would you need to return to your point of origin? PRACTICE 3: You move 5 m along the positive X axis, then 10 m directed at 53 o above the negative X axis. Find the magnitude and direction (use the absolute angle) of your displacement. PRACTICE 4: You move 2 m due north, then 5 m directed at 53 o east of north. What magnitude and direction (use the absolute angle) displacement would you need to return to your point of origin? Page 11