Infinite Limits. By Tuesday J. Johnson

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Transcription:

Infinite Limits By Tuesday J. Johnson

Suggested Review Topics Algebra skills reviews suggested: Evaluating functions Graphing functions Working with inequalities Working with absolute values Trigonometric skills reviews suggested: Graphing trigonometric functions Evaluating trigonometric functions

Math 1411 Chapter 1: Limits and Their Properties 1.5 Infinite Limits

Definition: Infinite Limits Let f be a function that is defined at every real number in some open interval containing c (except possibly at c itself). The statement lim f(x) = means that for each M > 0 x c there exists a δ > 0 such that f(x) > M whenever 0 < x c < δ. Similarly, the statement lim f(x) = x c means that for each N < 0 there exists a δ > 0 such that f(x) < N whenever 0 < x c < δ.

To define the infinite limit from the left, replace 0 < x c < δ by c δ < x < c. To define the infinite limit from the right, replace 0 < x c < δ by c < x < c + δ. Note 1: Having a limit equal to infinity does NOT mean the limit exists. In fact, it means the limit is unbounded and therefore does not exist. Note 2: In WebAssign, if the limit is you should enter that for your answer and not DNE. There does not seem to be a great consistency in this however.

Vertical Asymptotes Definition If f(x) approaches infinity (positive or negative) as x approaches c from the right or the left, then the line x = c is a vertical asymptote of the graph of f(x). Theorem Let f and g be continuous on an open interval containing c. If f(c) 0, g c = 0, and there exists an open interval containing c such that g(x) 0 for all x c in the interval, then the graph of the function given by h(x) = f(x) g(x) has a vertical asymptote at x = c.

Examples: Find the vertical asymptote, 1. f x = 4x x 2 +4 if any. The numerator is zero when x = 0 The denominator is never zero for real values of x. Therefore there is no vertical asymptote.

Examples: Find the vertical asymptote, if any. 2. h s = 2s 3 s 2 25 The numerator is zero at s = 3 2. The denominator is zero at s = ±5. Therefore the vertical asymptotes are s = 5 and s = 5. Note: Vertical asymptotes are ALWAYS equations of lines, never just values.

Examples: Find the vertical asymptote, if any. 3. g x = x3 +1 = (x+1)(x2 +x+1) x+1 x+1 Both numerator and denominator are zero at x = 1. This is NOT a vertical asymptote. This situation will result in a removable discontinuity.

Examples: Find the vertical asymptote, if any. 4. h t = t2 2t t 4 16 = t(t 2) (t 2)(t+2)(t 2 +4) The numerator is zero at t = 0 and t = 2. The denominator is zero at t = 2 and t = 2. This tells us that t = 2 is NOT a vertical asymptote as it is a removable discontinuity. However, t = 2 is a vertical asymptote.

Examples: Find the vertical asymptote(s), if any. 5. f x = sec(πx) = 1 cos(πx) The numerator is never zero. The denominator is zero when πx = π 2 + πn, where n is an arbitrary integer. This means that f(x) = sec (πx) has vertical asymptotes at x = ½ + n, for all integers n.

Examples: Find the limit, if it exists. 2+x 1. lim x 1 + 1 x Tables are great if you don t have access to a graph: x 1 1.001 1.01 1.1 x gets large and negative as we read the table right to left getting closer to 1 (from the right). This means that 2+x lim =. x 1 + 1 x f(x)? -3001-301 -31

Examples: Find the limit, if it exists. 2. lim x 4 + x2 x 2 +16 We should always evaluate to find a limit if the domain allows. In this case that is the best method: x 2 lim x 4 + x 2 + 16 = 16 16 + 16 = 1 2 We could have used a table or graph, but when possible the best thing to do is evaluate.

Examples: Find the limit, if it exists. 3. lim x ( π ( 2 2 )+ cos x ) = lim x ( π ( 2 sec x) 2 )+ If we try to evaluate we get 2, but that doesn t necessarily mean our solution is negative infinity. If we try a table we realize we are in radians, what values does that suggest to get close to π from the 2 right? Let s take a look at this graph! 0

Examples: Find the limit, if it exists. 3. As x π 2+, the graph of f(x) approaches +. Therefore, 2 lim x ( π )+( ) = cos x 2 lim x ( π ( 2 2 )+ cos x ) = lim x ( π ( 2 sec x) 2 )+

Properties of Infinite Limits Let c and L be real numbers and let f and g be functions such that f x = and lim g x = L. lim x c x c 1. Sum or difference: lim x c [f x ± g x ] =. 2. Product: lim x c f x g x =, L > 0 and lim x c f x g x =, L < 0. 3. Quotient: lim x c g(x) f(x) = 0 Similar properties hold for one-sided limits and for functions for which the limit of f(x) as x approaches c is negative infinity.

The End Thank you to Desmos.com and their free online graphing utility for the graphs.