A little taste of symplectic geometry

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A little taste of symplectic geometry Timothy Goldberg Thursday, October 4, 2007 Olivetti Club Talk Cornell University 1

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What is symplectic geometry? Symplectic geometry is the study of the geometry of symplectic manifolds! 3

The game plan 0. Prologue: Schur Horn theorem (original version) 1. Symplectic vector spaces 2. Symplectic manifolds 3. Hamiltonian group actions 4. Atiyah/Guillemin Sternberg theorem 5. Epilogue: Schur Horn theorem (symplectic version) 4

0. Prologue Let H(n) = {Hermitian (n n) matrices}. (ĀT = A) Hermitian = real diagonal entries and eigenvalues. Put λ = (λ1 λ 2... λ n ), O λ = {A H(n) with eigenvalues λ} (isospectral set), f: O λ R n, f(a) = diagonal of A. Thereom: [Schur-Horn, mid-1950 s] f(o λ ) is a convex polytope in R n, the convex hull of vectors whose entries are λ 1,..., λ n (in some order). Definition: C is convex if a, b C = ab C. The convex hull of P is the smallest convex set containing P. A convex polytope is the convex hull of a finite set of points. 5

Example: n = 3, λ = (3, 2, 1). f(o λ ) lives in R 3, but is contained in the plane x+y+z = 6. 6

1. Symplectic vector spaces V = finite dimensional real vector space Definition: An inner product on V is a map g: V V R with the following properties. g is bilinear g is symmetric g is positive definite Note: positive definite = nondegenerate. Example: V = R n, g = standard dot product 7

Definition: A symplectic product on V is a map ω: V V R with the following properties. ω is bilinear ω is skew-symmetric ω is nondegenerate (Note that for all v V, ω(v, v) = 0.) A symplectic vector space is a vector space equipped with a symplectic product. Every (finite dimensional) vector space has an inner product, but not every vector space has a symplectic product! 8

Claim: If V has a symplectic product ω, then dim V is even. Proof: Let A be the matrix of ω relative to some basis for V. Then det A = det A T = det( A) = ( 1) n det A, where n = dim V. Since det A 0, 1 = ( 1) n, so n = dim V is even. Example: V = R 2n, ω = ω 0 = symplectic product) QED ( ) 0 In. (standard I n 0 If n = 2: ( ) ( ) 0 1 y1 ω( x, y) = (x 1 x 2 ) 1 0 y 2 ( ) x1 y = x 1 y 2 x 2 y 1 = det 1 x 2 y 2 = det ( x y) = oriented area of the parallelogram spanned by x, y. Thus, every even-dimensional vector space has a symplectic product, and in fact, up to a change of coordinates, every symplectic product looks like this one! 9

The gradient of f: R n R is the vector field ( f f :=,..., f ). x 1 x n Coordinate-free definition: f is the unique vector field such that p R n, v R n, (D v f)(x) = f(x) v. (D v f = directional derivative of f in the direction v.) The symplectic gradient of f is the unique vector field ω f such that p R n, v R n, (D v f)(x) = ω ( ω f(x), v). (The uniqueness follows from nondegeneracy.) 10

Example: V = R 2, ω = ω 0 = standard symplectic form. ( ω f = f y, f ) x Let f(x, y) = x 2 + y 2. Then f = (2x, 2y) and ω f = ( 2y, 2x). f is perpendicular to level curves of f, and points to increasing values of f. ω f is tangent to level curves of f, and points to constant values of f. ( D ω f(p)f ) (p) = ω ( ω f(p), ω f(p)) = 0. f energy function f points to increasing energy ω f points to stable energy Symplectic geometry is the natural setting for studying classical mechanics! 11

A game we can play: Find the Hamiltonian! Usual version Given a vector field X on R n, find a function f: R n R such that f = X. Symplectic version Given a vector field X on V, find a function f: V R such that ω f = X. Classical mechanics interpretation The vector field represents a system of moving particles (Hamiltonian system). We want to find an energy function (Hamiltonian) for this system. We are basically trying to solve Hamilton s equations. 12

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2. Symplectic manifolds Definition: A smooth manifold M consists of patches (open subsets of some R n ) smoothly knit together. (Think of smooth surfaces in R 3, like a sphere or torus.) Each point p M has a tangent space T p M attached. A Riemannian metric on M is a smoothly varying collection of inner products. g = {g p : T p M T p M R p M} A symplectic form on M is a smoothly varying collection ω = {ω p : T p M T p M R p M} of symplectic products, such that dω = 0. 14

Every manifold has a Riemannian metric (partition of unity), but not every manifold admits a symplectic form! Being even-dimensional and orientable is necessary but not sufficient! Example: M = orientable surface in R 3, ω( u, v) = oriented area of parallelogram spanned u and v. Fact: Locally, every symplectic manifold looks like (R 2n, ω 0 ). (Darboux s theorem) (No local invariants in symplectic geometry, like curvature.) Can define gradients just like before. p M, v T p M, df p ( v) = ω p ( ω f(p), v) differentiable function tangent vector field f: M R f, ω f 15

Example: M = S 2 := {(x, y, z) R 3 x 2 + y 2 + z 2 = 1}, g = dot product, ω = oriented area f: S 2 R, (x, y, z) z, (height function) f points longitudinally, ω f points latitudinally As before: f points to increasing values of f, ω f points to constant values of f. We can still play Find the Hamiltonian!. Given a tangent vector field X on M, can we find a function f: M R such that f = X? ω f = X? 16

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3. Hamiltonian group actions Definition: A Lie group is a group G with a compatible structure of a smooth manifold. A smooth action of G on a smooth manifold M is a smooth group homomorphism A: G Diff(M). Diff(M) = diffeomorphisms M M. The Lie algebra g of G is the tangent space at the identity element 1 of G. g := T 1 G g is a vector space, and more. (Lie bracket) 18

Example: Some Lie groups. (i) (V, +). Lie algebra = V. (ii) S 1 := {z C z = 1} under multiplication. Lie algebra = ir. (iii) T = S 1... S 1, a torus. Lie algebra = ir... ir. (iv) Matrix Lie groups under matrix multiplication, such as GL(n; R), SL(n; R), O(n; R), SO(n; R), U(n), etc. Their Lie algebras are certain matrix vector spaces. Example: A smooth group action. (Rotating the plane.) Let G = S 1, g = ir, M = R 2, and A: S 1 Diff(R 2 ) be defined by ( ( ) ( A(e iθ x cos θ sin θ x ) :=. y) sin θ cos θ y) 19

1 G acts as the identity map M M. infinitesimal change in G at 1 infinitesimal change at each p M. An infinitesimal change at 1 G is some ξ g. An infinitesimal change at each p M is a vector field. g Vec(M), ξ ξ M ξ M is the fundamental vector field on M induced by ξ. ξ M (p) := d dt A (exp(tξ)) p t=0 In the example of rotating the plane, if ξ = it ir = g, then ( ) ( ) x ty ξ M =. y tx 20

We can play Find the Hamiltonian! with the fundamental vector fields. If we can win this game for every ξ M, then we can form φ: g C (M) such that for every ξ g ω [φ(ξ)] = ξ M. (C (M) = {smooth functions M R}.) Take dual, and define Φ: M g by for all p M, ξ g. Φ(p)ξ = φ(ξ)(p) If Φ is also G equivariant then Φ is a moment map for A: G Diff(M). A is a Hamiltonian action of G on M if there is a moment map Φ for the action. G M Φ g. 21

Examples: (i) Rotating the plane. G = S 1, g = ir, M = R 2. Φ: M g is ( ( ) x 1 Φ (it) = y) 2 (x2 + y 2 ) t Note that ω of this function on R 2 is ( ) ty tx = (it) M ( x y (ii) M = R 6 with coordinates x, y R 3. ( x is position, y is momentum). G = R 3 acting on M by translating the position vector. Then g = R 3 = g, and Φ: M g is Φ = linear momentum. Φ( x, y) a = y a. (iii) M = cotangent bundle of R 3 with coordinates x, y R 3. ( x is still position, y is still momentum). G = SO(3) acting on M by rotation. Then g = R 3, and Φ: M g is Φ = angular momentum. Φ( x, y) a = ( x y) a. ). 22

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4. Atiyah/Guillemin Sternberg Theorem Proved independently by Sir Michael Atiyah, and Victor Guillemin and Shlomo Sternberg, in 1982. G S proof: simple and elegant A proof: even a bit more simple and elegant Thereom: (M, ω) = compact and connected symplectic manifold, T = a torus, A = Hamiltonian action of T on M with moment map Φ: M t. Then Φ(M) is a convex polytope in t, the convex hull of Φ(M T ), where M T := {p M A(t)p = p for all t T}. 24

5. Epilogue Symplectic interpretation of Schur-Horn theorem: Noticed by Bertram Kostant in the early 1970 s, then generalized by A/G S. U(n) = {A Ā T = A 1 } is a Lie group. Acts on H(n) by conjugation. (H(n) = u(n) ) T = diagonal matrices in U(n) is an n torus. Can identify t with R n. O λ = isospectral set for λ is a symplectic manifold. (coadjoint orbit, Kirillov Kostant Souriau form) Conjugation preserves eigenvalues, so T O λ. f: O λ R n, f(a) = diagonal of A, is a moment map. (O λ ) T = diagonal matrices in O λ = diagonal matrices with entries λ 1,..., λ n in some order. A/G S theorem = f(o λ ) is a convex polytope, the convex hull of f ( (O λ ) T). This is exactly the S H theorem! 25

Symplectic stuff is cool! But you don t have to take my word for it! Coming Spring 2008: Tara Holm s NEW epic MATH 758: Symplectic Geometry 26

THE END Thank you for listening. 27