Fabry-Perot Interferometers

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Fabry-Perot Interferometers Astronomy 6525 Literature: C.R. Kitchin, Astrophysical Techniques Born & Wolf, Principles of Optics

Theory: 1 Fabry-Perots are best thought of as resonant cavities formed between two flat, parallel highly reflecting mirrors. The pair of mirrors is called an etalon. θ δ Let: d = spacing between the mirrors τ = amplitude transmissivity ρ = amplitude reflectivity For a collimated beam with amplitude, A, incident at angle θ, the phase shift (difference) between successive transmitted rays is: 2π δ = 2d cosθ λ Fabry-Perot 2

Theory: 2 Here we ignored the phase shift on reflection (this just acts like a change in the cavity size) and assumed that the index of refraction between the mirrors is 1. The reflection phase shift can be included by letting: d d + d where: φ λ d = cosθ 2π and φ is the reflection phase shift (excepting the first ray). The complex amplitude for the n th transmitted ray is: ψ n = Aτ 2 ρ 2(n-1) e i(ωt-(n-1)δ) and the total amplitude is: Fabry-Perot 3 ψ = ψ n = Aτ 2 e iωt /(1 - ρ 2 e -iδ ) n = 1

Theory: 3 (Airy Function) So that the transmitted intensity is: I ψ*ψ = A 2 τ 4 /(1-2ρ 2 cosδ + ρ 4 ) Rewriting in terms of the mirror intensity coefficients: t τ 2 and r ρ 2 The transmitted intensity of the etalon is: I(δ)/I o = T max /{1 + [4r/(1 r) 2 ] sin 2 (δ/2)} where: T max t 2 /(1 r) 2 The form above is that of the Airy function. The incident intensity is given by: I o = A 2 Fabry-Perot 4

Theory: 4 (Transmission Peaks) In the limit of no absorption: t = 1 r and T max = 1 The Airy function has peak when the phase shift, δ, is an integer multiple of 2π, e.g. δ = 2πm where: for normal incidence. m = 0, 1, 2, = order of etalon m = 2d/λ (m-1) σ m σ (m+1) σ Fabry-Perot 5

Theory: 5 (Peak Width) Set: I(δ)/I o = T max /{1 + [4r/(1 r) 2 ] sin 2 (δ/2)} = T max /2! Solve for δ, resulting in δ HWHM Then, the full-width at half-maximum (FWHM) of a single peak is (phase): δ FWHM = 2 δ HWHM = 4 sin -1 ((1 r)/2 r) 2(1 r)/ r δ FWHM σ Fabry-Perot 6

Theory: 6 (Free Spectral Range) The spacing between transmission peaks (in units of wavelengths) is called the free spectral range. We have: Thus: mλ = (m 1) (λ + λ FSR ) λ FSR = λ/m λ FSR = λ/m = λ 2 /(2d) Δλ FSR σ Fabry-Perot 7

Theory: 7 (Reflectivity Finesse) The finesse, F, of an FPI is the ratio of the distance between peaks, to their FWHM. F 2π/δ FWHM π r/(1 r) This approximation is accurate to within 1% for r > 0.65. For normal incidence, we can compute the single peak width, from the definition of δ (=4πd/λ): δ = (4πd λ FWHM )/λ 2 δ FWHM hence: 2 λ 1 r λ FWHM 2d π r so that: F = λ 2 /(2d λ FWHM ) = λ/(m λ FWHM ) The finesse along with the transmission, is the primary figure of merit for an FPI. Fabry-Perot 8

Theory: 8 (Resolving Power) The resolving power: R FPI λ/ λ FWHM = m (λ/(m λ FWHM )) = m F Since the resolving power in an interferometer is determined by the largest difference between interfering rays, F can be thought of as a path length multiplier, and is roughly the number of reflections an average photon makes before being transmitted through the system. Fabry-Perot 9

Theory: 9 (Resolution Limitation) Fabry-Perot 10

Theory: 10 (Contrast) Another figure of merit for the FPI is the contrast, which is the ratio of the maximum to minimum transmission: C T max /T min = (1 + r) 2 /(1 r) 2 = 1 + (2F/π) 2 For a F > 15, C > 100, which is adequate. Graf 1986 Phd Thesis, Cornell Fabry-Perot 11 C is a strong function of F: F > 45 C > 1000

Limits to Performance: I 1. Mirror Absorption If a is the single pass intensity absorption coefficient, then the maximum transmitted intensity is: T max = {t/(1 - r)} 2 = {(1 r a)/(1 r)} 2 = {1 a / (1 - r)} 2 The reflectivity finesse is independent of the absorption coefficient. Note that for small a ( 2%), the transmission is 1 af, since F ~ the number of reflections. For af/(π r) << 1: Since F = π r/(1-r) T max ~ 1-2aF/(π r) Fabry-Perot 12

Limits to Performance: II Mirror Absorption Transmission of an FPI as a function of a = 1- t - r. Typically a ~ 1%, for which a good FPI will have F ~ 30 to 50 (r = 0.90 0.94) It is important to keep T max close to unity, since large F is not useful. Bradford 2001 Phd Thesis, Cornell Fabry-Perot 13

Limits to Performance: III θ Tip D C 2. Etalon Tip - Walk Off d Tipping the etalon causes beams to walk off the mirrors. The beam will walk a distance w before it is transmitted (after F reflections) given by: w = F d sin(θ Tip ) = R λ/2 θ sky (D p /D C ) Things get bad when the central ray has traveled a distance equal to the beam radius across the etalon, the constructive interference is significantly reduced: D C /2 F Tip d sin(θ Tip ) F Tip d θ Tip F Tip D C /(2d θ Tip ) where D C is the beam diameter. Fabry-Perot 14

Etalon Tip Limits to Performance: IV Notice that tipping the etalon shifts the central wavelength of transmission to shorter wavelength: θ Tip = 0: θ Tip small: 2d/λ o = m 2d/λ 1 (cosθ) = m 2d/λ 1 (1 - θ 2 /2) = m λ 1 - λ o λ = -λ o θ 2 Tip /2 λ = -λ o θ 2 Tip /2 (blue shift) Fabry-Perot 15

Limits to Performance: V θ par D C d 3. Mirror Parallelism If one mirror is tipped with respect to the other at an angle θ, then the problem is much more severe than a mere tipping of the entire etalon. Not only does the reflected angel grow with each reflection, but the cavity resonates at a different wavelength at different positions!! Fabry-Perot 16

Limits to Performance: VI Mirror Parallelism To make an estimate of this effect, lets assume resonance at λ o at one end of the etalon, and at λ 1 at the other. The maximum resolution of the etalon is then: R max = (λ o + λ 1 )/{2(λ o - λ 1 )} = F Par m Now, if is the gap difference, i.e. = D C sinθ par (where D C =beam diameter, θ par =deviation from parallelism), then: (λ o - λ 1 ) = 2d/m 2(d + )/m = -2 /m or, letting (λ o + λ 1 )/2 λ, then: F par m = mλ/(2 ) F Par = λ/(2 ) If the mirrors are parallel to λ/n then F Par = n/2 you need parallelism to better than λ/200 or so! Fabry-Perot 17

Limits to Performance: VII θ FP 4. Aperture Effects The resonant condition is: normal ray: off-axis ray: 2d cosθ/λ = m 2d/λ o = m 2d cosθ FP /(λ 1 ) = m d 2d/λ o 2d/λ 1 (1 - θ FP2 /2) = m λ 1 - λ o - λ = - λ o θ FP2 /2 λ/λ o 1/R = θ FP2 /2 1/(F aperture m) F aperture = R/m = 2π/{mπ(θ FP2 )} = πλ o /(d Ω FP ) R = 2π/Ω FP, or R Ω FP = 2π Fabry-Perot 18

Limits to Performance: VIII Aperture Effects Now, since etendue is conserved: A FP Ω FP = A Primary Ω Primary Ω Primary A Primary /A FP R = 2π R max = 2π{A FP /A Primary }/Ω Primary 5. Diffraction Effects Diffraction results in a minimum angle within the beam given by: θ Teldiff ~ λ/d Tel. Plugging this into our aperture effects equation: R diff = 2π{A FP /A Primary }/{π/4 (λ/d Primary ) 2 } = 8 (D FP /λ) 2 where: Ω = π/4 (λ/d) 2, D FP is the diameter of the beam through the etalon. Fabry-Perot 19

Limits to Performance: IX 6. Surface Defects Irregularities in the surfaces of the mirrors will cause irregularities in the path lengths for different regions of the cavity. Suppose we have an rms gap variation that is given by s, and is distributed in a Gaussian manner. It can be shown that: F surf = λ/{(32(ln2)) 1/2 s} λ/(4.7 s) Fabry-Perot 20

Limits to Performance: X Effective Finesse and Transmission Each effect reduces both the FPI transmission, and the finesse. The total effective finesse is given by the inverse quadratic sum of each finesse term above with the reflective finesse (Cooper, J. and Greig, J.R. 1963 J. Sci. Instrum., 40, 433.): 1/F eff2 = Σ 1/F 2 i The peak transmission is reduced, since some of the radiation is absorbed, some of it is forced out of the beam, and some of it interferes destructively. The etalon transmission is reduced by the ratio of the effective finesse to the reflective finesse: T FPI = T max {F eff /F ref } = [(1 r a)/(1 r)] 2 {F eff /F ref } Fabry-Perot 21

Limits to Performance: XI Optimizing Performance In a background limited situation, one can characterize the optimal performance of an FPI by the product of the finesse times the transmission: Fabry-Perot 22 NEP P S S/N=1 T -1/2 R -1/2 (F T) -1/2 (where P S S/N=1 is the signal power from the sky that is equivalent to the background noise) Therefore, we would wish to maximize the product: Q F T Now: T max {1 (2aF)/(π r)} Q {1 (2aF)/(π r)} F dq/df 1 (4aF)/(π r) = 0 For example: F optimal π/4a 80 for a = 1% r 96% r ~ 1

Applications of Fabry-Perot Interferometers Use a Fabry-Perot with high resolution as the spectral element that defines the resolution To filter out unwanted transmission peaks of a Fabry-Perot: Use several Fabry-Perots in series Use additional edge filters and band pass filters Some detectors are not sensitive to wavelengths outside of their range The Fabry-Perot that determines the spectral resolution is scanned over a wavelength range, by changing the plate separation to obtain a spectrum at each spatial position on the sky => resulting data is a 3D data cube: 2 spatial dimensions (from 2D detector array) 3 rd dimension is spectral dimension (scanning time) Fabry-Perot 23

Example: The UC Berkeley Tandem FPI Optical filtration train: Tunable high order FPI (HOFPI) is the resolution achieving device n ~ 20 to 600 R ~ 1000 to 36,000 (F varied from 30 to 60) HOFPI fringes evenly spaced frequency space Fixed filters (low-order FPI, LOFPI) Set in 1 st to 4 th R ~ 30 to 260 (optimize F for line of interest) One filter for each line of interest Up to 6 filters on a wheel Salt Filters Act as low frequency pass filters Block typically > 20 µm Can be put on wheel (specialized) Transmitted profile is the product of each element of the train. Fabry-Perot 24

Examples of Fabry-Perot Instruments Fabry-Perot 25

Kuiper Widefield Infrared Camera: KWIC KWIC is an Imaging Spectrometer/Photometer Tandem FPI s 1. R > 2000 (up to 10,000): Spectral Lines 2. R ~ 35, 70, 105: Dust Continuum Wide field of view with diffraction limited beams using a 128 128 pixel Si:Sb BIB Array 5.8 5.8 FOV Far-IR (18 µm < λ < 38 µm) Lines: [SIII] 18 and 33 µm [SiII] 35 µm [NeIII] 36 µm etc. Continuum: T planck ~ 85 K at 38 µm Fabry-Perot 26

Optical Layout For KWIC: I To KAO telescope LOFPI HOFPI Si:Sb BIB detector Bottom View Beam enters at left at f/12.6 Passes through calibration unit Gas cell for spectral calibration Hot chopped blackbody for flatfielding HOFPI in collimated beam to minimize aperture effects on R LOFPI in focus makes parallelizing easy Reimaging optics to match f/# to pixel size Latvakoski, H. 1997 PhD Thesis Cornell Fabry-Perot 27

Fabry-Perot Interferometer in the Mid-IR to Submm Wavelength Regime In the mid-ir ( 25 µm) and up to submm wavelengths Fabry- Perot plates can be made using free-standing metal meshes Scanning and fixed Fabry-Perot Interferometers with freestanding metal meshes have been used in many instruments Fabry-Perot 28

Fixed Wavelength Filters Lugten, J.B. 1986 PhD Thesis, UCB Fixed λ filters are used to sort the orders of the HOFPI: Made from free standing metal mesh Stretched onto stainless steel rings Push and pull screws to align and fix FPI Optically flat to about ¼ HeNe wavelength Finesse typically 30 to 60, orders between 1 and 5, R ~ 30 to 300 Peak transmissions from 25 to 90% Quite robust, cycled dozens of times over many years Fabry-Perot 29

Properties of Mesh FPI: Finesse vs. Wavelength Worked with a variety of mesh grid spacings and optical transmissions Finesse typically scales as λ 2 Select mesh to keep F reasonable ensuring good transmission. λ 2 Lugten, J.B. 1986 PhD Thesis, UCB Fabry-Perot 30

Example of a Fabry-Perot Design: KWIC LOFPI Latvakoski, H. 1997 PhD Thesis Cornell Fabry-Perot 31 KWIC LOFPI Flex vane based translation stage ensures parallelism Mesh rings are magnetic stainless, held in place with magnets Rough adjustment via externally accessible fineadjustment screw Scanning PZT for fine adjustment and scanning Spacing measured with a capacitance bridge fed back to PZTs, and held to < 14 nm Liquid Helium temperature operation Tilt PZT s travel ~ 2 µm