What is in Common for the Following Reactions, and How Do They Work?

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What is in Common for the Following Reactions, and ow Do They Work? You should eventually be able to draw the mechanism for these (and other) reactions 13 Key Intermediate 1 Br-Br Na Br 2 C 3 -I Me NaMe Me C 3 3 NaMe 4 2 Na 5 Me C 3 Me NaMe Me C 3 6 2 C 3 optically active Na C 3 3 C racemic mixture 4 Things in Common KEY: 1. 2. 3. 4.

TYPICAL MECANISM: Via ENLATE Anion 14 = (Aldehyde) = R (Ketone) = R (Ester) R (Base) Br Br C 2 3 -I 2 Me C 3 Enolate Ion 2 Me (original stereo forgotten) Under base conditions, a carbonyl compound with an α-hydrogen can be deprotonated to give a resonance-stablized, delocalized enolate anion, which is nucleophilic at the α-carbon. Normal C- bonds are very non-acidic. But C- bonds α to a carbonyl are much more acidic because the resulting anion is resonance stabilized and is shared by the oxygen. K a = 10-20 K a = 10-50 Stabilized Unstabilized The α-carbon has two other attachments in addition to the carbonyl and the shown in this page. The other attachments will remain attached as spectators, and need to be accounted for in drawing products. α-ydrogens are only slightly less acidic than is water or alcohol hydrogens

15 Acidity Table Class Structure Ka Acid Strength Anion Base Strength Strong Acids -Cl 10 2 Cl Carboxylic Acid R 10-5 R enol 10-10 1,3-Dicarbonyl Me 10-12 Me Water 10-16 Alcohol R 10-17 R Ketones and Aldehydes 10-20 Ester a Me 10-24 Me Amine (N-) (ipr) 2 N- 10-33 (ipr) 2 N Li LDA Alkane (C-) RC 3 10-50 RC 2 -A B A B- Relative stability of anions dictates equilibrium Notes to remember 1. Carbonyls acidify α- s (anion stabilized) 2. 1,3-Dicarbonyls are much more acidic than monocarbonyls (anion is more stabilized) 3. Ketones are more acidic than esters 4. A lower anion on the chart can favorably deprotonate any acid that s higher on chart. Because any acid-base equilibrium will always favor the more stable anion. 5. LDA is strong enough to completely deprotonate ketones, esters, or 1,3-dicarbonyls 6. Na, NaR can completely deprotonate a 1,3-dicarbonyl (but not ketones or esters) 7. Na, NaR do not completely deprotonate ketones or esters, but do provide a usable equilibrium supply of the enolate that can procede to product in some reactions.

1. Rank the acidity of the hydrogens at the labeled positions, 1 being most acidic. Draw the three anions that would result from deprotionation at the three spots, and any pertinent resonance structures. a b c 16 2. For the following compounds, record to what degree they would be deprotonated by NaC 3 or LDA [LiN(iPr) 2 ] respectively. The basic choices are totally (>98%), zero (no enolate whatsoever) or slightly (definitely some equilibrium amount, but <10%). LDA: NaMe: A B C D 3. For the following compounds, rank them according to which would have the greatest amount of enol isomer present at equilibrium, 1 being most enol, 4 being least. A B C D 4. Draw products for the following reactions 2 Br 2, 2Na 2 1 Cl 2, 2 1. 3 I 2, 3 Na, 2 2.

5. Keto-Enol Mechanisms a. Draw the mechanism for conversion of the keto form to the enol form 17 b. Draw the mechanism for conversion of the enol form to the ketone 6. Draw the mechanism for the following 2 Br 2, Na 7. Try to draw the mechanism for the following. NaEt, Et

Draw products for the following alkylation reactions, often involving ester hydrolyses and thermal decarboxylations. 18 8. 1. LDA 2. Me-I 1. LDA 9. 2. Br 1. NaEt 10. Et Et 2. Br 1. NaEt 2. Br 11. Et Et 3. NaEt 4. BrC 2 C=C 2 1. NaEt 2. Br 12. Et Et 3., 2, heat 1. NaEt 2. Br 13. Et 3., 2, heat 1. LDA Et 14. 2. Br

15. Which of A, B, C, or D is the correct product for the following reaction? 1. NaC 3 2. C 3 I C 3 C 3 A B C C 3 3 C D 19 Some Synthetic Strategy Tips Alkylation resulting eventually in an acid: from 1,3-diester, via NaR, then subsequent ester hydrolysis/decarboxylation Alkylation resulting eventually in a mono-ester: from ester using LDA Alkylation resulting eventually in a mono-ketone, where unambiguous deprotonation was possible: from ketone using LDA Alkylation resulting in a mono-ketone, where unambiguous LDA deprotonation would not have been possible: from keto-ester using NaR, then subsequent ester hydrolysis/decarboxylation Provide reagents for the following: 16. Et Et Et Et 17. 18. Which of the following would undergo decarboxylation? And which would go fastest? A B C D 19. Draw the mechanism for the following reaction. 1. LDA C 3 2. C 3 I

Aldol Examples: Aldehydes/Ketones as Electrophiles 20 Na, 2 Na, 2 1. cold warmup 2. Na, 2 cold Na, 2 warmup With aldehydes, you can usually stop at the β-hydroxy carbonyl stage or proceed on to the α,β-unsaturated carbonyl, depending on time and temperature. NaEt, Et NaEt, Et 3. eat With ketones as electrophiles, the aldol reaction to give the β-hydroxy carbonyl is normally reversible with an unfavorable equilibrium. owever, while it is not possible to isolate high yields of the β-hydroxy ketone, further dehydration to give the enone is irreversible and can give good yields of the enone. 4. NaMe Me 0ºC NaMe Me warmup more time With two different carbonyl compounds, one must function selectively as the enolate precursor, and the other as the electrophile. Since aldehydes are much more electrophilic, when mixed with a ketone the aldehyde will always be the electrophile If there are more than one site where an enolate might form, the most acidic site that would give a stabilized anion will form preferentially 5. Et NaEt Et 0ºC Et NaEt Et warmup more time Et Comments Basic ne carbonyl functions as the enolate nucleophile, a second carbonyl as the neutral electrophile. The enolate precursor and the electrophile carbonyl may be the same (examples 1-3) or different (examples 4 and 5) Loss of an α-, replaced by an α,β C-C bond.

21 All of the following molecules can be made by an aldol-type reaction or an aldol-type condensation (aldol followed by loss of 2 ). Draw the carbonyl compound or compounds from which each is derived. example: Strategy: Identify the carbonyl in the product, and mark off which are the α and β carbons. The key bond connection will have been between the α and β carbons. β was originally a carbonyl (the electrophile carbonyl) α originally had s (it was the enolate carbanion) Note: any attachments on the α and β carbons are spectators. If they are there at the end, they must have been attached at the beinning 20. 21. 22. 23. 24. Draw the mechanism for the following reaction. NaMe Me 0ºC

Provide products for the following aldol reactions. 22 Na, 2 Na, 2 25. cold heat NaMe, Me 26. heat 27. NaEt Et 0ºC NaEt Et heat 28. NaEt Et 0ºC NaEt Et heat 29. Na 2 cold Na 2 hot NaC 3 NaC 3 30. C 3 cold C 3 hot 31. Draw the mechanism for phase one and then phase two of the reaction in problem 28.

Provide products for the following Claisen reactions. 23 NaC 3 32. Me C 3 NaEt 33. Et Et 1. NaMe, Me 2. 34. Me 2. NaMe 3. BrC 2 C=C 2 3. 1. NaMe, Me 4. 35. Me 2. NaMe 3. BrC 2 C=C 2 4., 2, heat 36. Me 1. NaC 3, C 3 Me 2., 2, heat 2. 37. Me Me NaMe Me 38. Me NaMe Me

Draw the product, reagent, or starting material for the following Wittig reactions. 24 Combo 1: 39. Combo 2: 40. Br 1. 3 P 2. BuLi 3. Benzaldehyde 1. 2 Cr 4 2. 41. 1. PBr 3 2. P 3 3. BuLi 4. acetone 42.

25 General Routes to Make Alkenes Wittig Reactions. o Very general o Useful for making more elaborate organics, because two subcomponents can be coupled to make a larger product. o Technically longer and more difficult than an aldol condensation, so should not be used to make enones when an aldol condensation could be used instead. Aldol Condensations. o Great for making enones (α,β-unsaturated carbonyls). But limited to making enones. o If you see an enone target, make via aldol condensation. o Useful for making more elaborate organics, because two subcomponents can be coupled to make a larger product. Elimination reactions (from either halides or alcohols). o Not useful for building up carbon chain lengths. Simply involves transforming one functional group into another. 43. For the following alkenes, which method should you use, and what would be the immediate precursors that would be suitable? 44. Synthesis design. Design syntheses of the following products, starting from alcohols of 4 carbons or less. Some key reminder reactions: PCC for oxidizing 1º alcohols to aldehydes 2 Cr 4 for oxidizing 2º alcohols to ketones PBr 3 for converting 1º or 2º alcohols to bromides needed for making Wittig reagents

General: Enones as Electrophiles. Nucleophiles that attack enones must chooe between: Carbonyl addition β-addition 26 Carbonyl Addition Alkoxide Formation versus "-Addition Enolate Formation Carbonyl addition normally dominates with: RMgBr RLi NaB 4 LiAl 4 LiCCR β- addition normally dominates with: enolates of dicarbonyls sometimes enolates of monocarbonyls (but not always) Cuprates (R 2 CuLi) Prep: 2RBr 1. 4 Li 2. 1 CuI R 2 CuLi Draw the Products for the following Michael reactions 45. Et NaEt Et 46. Et Et NaEt Et 47. NaEt Et heat, long time -draw in the initial product, second product, and third product

27 48. Draw the mechanism for the following reaction. (Claisen reaction). NaC 3 Me C 3 Me 49. Draw the mechanism for the following reaction (Michael reaction). Et Et NaEt Et Et Et 50. Draw the mechanism for the following reaction. (Robinson cyclization, involving sequential Michael reaction, aldol reaction, β hydroxyketone dehydration.) NaEt Et heat, long time C via and B A