Remarks on Definitions

Similar documents
Study Guide for Linear Algebra Exam 2

MA 265 FINAL EXAM Fall 2012

LINEAR ALGEBRA 1, 2012-I PARTIAL EXAM 3 SOLUTIONS TO PRACTICE PROBLEMS

Linear Algebra- Final Exam Review

1. Select the unique answer (choice) for each problem. Write only the answer.

1. In this problem, if the statement is always true, circle T; otherwise, circle F.

Remark By definition, an eigenvector must be a nonzero vector, but eigenvalue could be zero.

MATH 1120 (LINEAR ALGEBRA 1), FINAL EXAM FALL 2011 SOLUTIONS TO PRACTICE VERSION

Math 308 Spring Midterm Answers May 6, 2013

235 Final exam review questions

MATH 20F: LINEAR ALGEBRA LECTURE B00 (T. KEMP)

5.) For each of the given sets of vectors, determine whether or not the set spans R 3. Give reasons for your answers.

PRACTICE PROBLEMS FOR THE FINAL

Assignment 1 Math 5341 Linear Algebra Review. Give complete answers to each of the following questions. Show all of your work.

2. Every linear system with the same number of equations as unknowns has a unique solution.

Math 18, Linear Algebra, Lecture C00, Spring 2017 Review and Practice Problems for Final Exam

Definition (T -invariant subspace) Example. Example

MATH 221, Spring Homework 10 Solutions

Math 315: Linear Algebra Solutions to Assignment 7

PRACTICE FINAL EXAM. why. If they are dependent, exhibit a linear dependence relation among them.

MATH 1553 PRACTICE FINAL EXAMINATION

DIAGONALIZATION. In order to see the implications of this definition, let us consider the following example Example 1. Consider the matrix

MATH 240 Spring, Chapter 1: Linear Equations and Matrices

MAT 1302B Mathematical Methods II

Test 3, Linear Algebra

Econ Slides from Lecture 7

Math 301 Test III. Dr. Holmes. November 4, 2004

Remark 1 By definition, an eigenvector must be a nonzero vector, but eigenvalue could be zero.

I. Multiple Choice Questions (Answer any eight)

Math 2114 Common Final Exam May 13, 2015 Form A

Problem 1: Solving a linear equation

(b) If a multiple of one row of A is added to another row to produce B then det(b) =det(a).

EXAM. Exam #3. Math 2360, Spring April 24, 2001 ANSWERS

Solutions to Final Exam 2011 (Total: 100 pts)

Math 4A Notes. Written by Victoria Kala Last updated June 11, 2017

Math 308 Practice Final Exam Page and vector y =

MATH 31 - ADDITIONAL PRACTICE PROBLEMS FOR FINAL

Final Review Sheet. B = (1, 1 + 3x, 1 + x 2 ) then 2 + 3x + 6x 2

1 Last time: least-squares problems

Diagonalization of Matrix

Chapters 5 & 6: Theory Review: Solutions Math 308 F Spring 2015

1. Diagonalize the matrix A if possible, that is, find an invertible matrix P and a diagonal

(a) II and III (b) I (c) I and III (d) I and II and III (e) None are true.

M340L Final Exam Solutions May 13, 1995

PROBLEM SET. Problems on Eigenvalues and Diagonalization. Math 3351, Fall Oct. 20, 2010 ANSWERS

Announcements Wednesday, November 01

Math 308 Midterm Answers and Comments July 18, Part A. Short answer questions

MATH 304 Linear Algebra Lecture 34: Review for Test 2.

Spring 2014 Math 272 Final Exam Review Sheet

ft-uiowa-math2550 Assignment NOTRequiredJustHWformatOfQuizReviewForExam3part2 due 12/31/2014 at 07:10pm CST

Linear Algebra Final Exam Study Guide Solutions Fall 2012

Math Final December 2006 C. Robinson

LINEAR ALGEBRA REVIEW

Cheat Sheet for MATH461

This is a closed book exam. No notes or calculators are permitted. We will drop your lowest scoring question for you.

Glossary of Linear Algebra Terms. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

Problem # Max points possible Actual score Total 120

Math 205, Summer I, Week 4b:

Lecture 15, 16: Diagonalization

Properties of Linear Transformations from R n to R m

Summer Session Practice Final Exam

MATH 220 FINAL EXAMINATION December 13, Name ID # Section #

Chapter 5. Eigenvalues and Eigenvectors

Practice problems for Exam 3 A =

18.06SC Final Exam Solutions

Math 205, Summer I, Week 4b: Continued. Chapter 5, Section 8

MATH 1B03 Day Class Final Exam Bradd Hart, Dec. 13, 2013

80 min. 65 points in total. The raw score will be normalized according to the course policy to count into the final score.

Final A. Problem Points Score Total 100. Math115A Nadja Hempel 03/23/2017

1. What is the determinant of the following matrix? a 1 a 2 4a 3 2a 2 b 1 b 2 4b 3 2b c 1. = 4, then det

1. Let m 1 and n 1 be two natural numbers such that m > n. Which of the following is/are true?

MAC Module 12 Eigenvalues and Eigenvectors. Learning Objectives. Upon completing this module, you should be able to:

MAC Module 12 Eigenvalues and Eigenvectors

Eigenvalues, Eigenvectors, and Diagonalization

Final Exam Practice Problems Answers Math 24 Winter 2012

LINEAR ALGEBRA KNOWLEDGE SURVEY

MAT188H1S LINEAR ALGEBRA: Course Information as of February 2, Calendar Description:

Dimension. Eigenvalue and eigenvector

[Disclaimer: This is not a complete list of everything you need to know, just some of the topics that gave people difficulty.]

Math 308 Midterm November 6, 2009

Math 110 (Fall 2018) Midterm II (Monday October 29, 12:10-1:00)

Final Exam, Linear Algebra, Fall, 2003, W. Stephen Wilson

MATH 223 FINAL EXAM APRIL, 2005

Calculating determinants for larger matrices

Homework sheet 4: EIGENVALUES AND EIGENVECTORS. DIAGONALIZATION (with solutions) Year ? Why or why not? 6 9

IMPORTANT DEFINITIONS AND THEOREMS REFERENCE SHEET

Matrices related to linear transformations

MAT Linear Algebra Collection of sample exams

Conceptual Questions for Review

and let s calculate the image of some vectors under the transformation T.

Announcements Monday, October 29

Examples True or false: 3. Let A be a 3 3 matrix. Then there is a pattern in A with precisely 4 inversions.

TMA Calculus 3. Lecture 21, April 3. Toke Meier Carlsen Norwegian University of Science and Technology Spring 2013

Math Linear Algebra Final Exam Review Sheet

Linear Algebra Practice Problems

The value of a problem is not so much coming up with the answer as in the ideas and attempted ideas it forces on the would be solver I.N.

Solutions to Final Exam

Linear Algebra Practice Problems

ANSWERS. E k E 2 E 1 A = B

YORK UNIVERSITY. Faculty of Science Department of Mathematics and Statistics MATH M Test #1. July 11, 2013 Solutions

Transcription:

Remarks on Definitions 1. Bad Definitions Definitions are the foundation of mathematics. Linear algebra bulges with definitions and one of the biggest challenge for students is to master them. It is difficult. Too many students address that difficulty by complaining that questions on exams asking for precise definitions are not mathematics or more like the questions in an English course than a math course. Other say they understand the concepts but don t know the definitions. The assertion that definitions, or asking students to know them, is not mathematics seems to rest on the fact that prior to linear algebra one s experience of mathematics involves a lot of calculation and the performance of operations that one is trained to do successfully. Mathematics is developed to avoid or simplify calculation. The theorems are powerful tools that allow one to finesse and minimize calculations. The definitions encapsulate the concepts. Enough preaching. Some examples of inadequate definitions appear below. All examples are verbatim answers of real students. I have not changed their wording. The questions had the following format: I wrote the first part of the definition and the students then had to complete the sentence thereby giving the definition. So, below I will give the first part of the sentence that was on the exam, and then I ll follow it by a correct answer, and then by answers given by students, and a brief explanation of what is wrong with each answer. One thing you will often see is the student s response is not the definition as given in the book, but a theorem that says some other condition is either equivalent to the definition or a consequence of it. One must learn to distinguish these three things. You will see examples where a student inserts unnecessary words into the definition. You will see examples where a student has proposed a definition that includes parts of the definitions of other words. 1

2 (1) (This definition is not confined to the context of linear algebra.) Let X and Y be arbitrary sets. A function f : X Y is one-to-one if f(x) f(x ) whenever x x OR f(x) = f(x ) only when x = x. for every value x there is one value y. I don t know what this sentence means. The definition should always be complete. The reader should not have to insert information into the proposed definition to complete it. f(x) = f(x ) when x = x. Every function has this property. f(x) = f(x ) and x = x or f(x) f(x ) and x x. It is difficult to parse this sentence. A definition should be open to only one interpretation. If the definition consists of a single sentence that sentence should has a simple grammatical structure. (2) (This definition is not confined to the context of linear algebra.) Let X and Y be arbitrary sets. The range of a function f : X Y is R(f) := { }. R(f) := {f(x) x X} OR R(f) := {y Y y = f(x) for some x X}. R(f) := {f(x) x R}. The question has nothing to do with R. The word range applies to all functions. That is why we allow X and Y to be arbitrary sets. By restricting X to R the author is destroying the generality of the definition. R(f) = {x X f(x) Y }. In this definition the symbols x and x are used different symbols stand for different things. Is this author wanting x and x to stand for the same thing. Probably, but when we must guess an author s intent the proposed definition is inadequate. Even if we assume that x and x stand for the same thing we can see that the author has no real understanding of what the range is because he has put f(x) after such that. Also, by starting the definition {x X } the author is saying the set being defined is a subset of X whereas the range is a subset of Y. This suggests the writer has tried to remember the definition as a sequence of words/symbols without paying attention to their meaning. There is no picture in the author s head of f sending

3 elements of X to elements of Y and the range being the values f takes. R(f) := f(y ). (3) (This definition is not confined to the context of linear algebra.) Let X and Y be arbitrary sets. A function f : X Y is onto if. R(f) = Y ; OR if y Y, there is an x X such that y = f(x); OR every y Y is equal to f(x) for some x X. OR f(x) = Y. f(x) = Y. The symbol x is not the same as X. Presumably, x denotes an element in X. The notation f(x) denotes the set of all f(x) as x ranges over all elements of X. More sucinctly, f(x) = {f(x) x X}. (4) We call {v 1,..., v d } an orthonormal basis for a subspace W if. it is a basis for W and is an orthogonal set and v i = 1 for all i. {v 1,..., v d } are linearly independent. (5) Let A be an n n matrix. We call λ R an eigenvalue of A if there is a non-zero vector x such that Ax = λx. Ax = λx for some x R. In the definition it is essential that x be non-zero. If the definition fails to exclude the possibility that x is zero, then every λ R would be an eigenvector because A0 = λ0 for all λ R. The next two proposed answers suffer from the same defect. Ax = λx as long as λ R. it satisfies the equation Ax = λx for any x R n. det(a λi) = 0. (6) Let A be an n n matrix. We call x R n an eigenvector for A if Ax = λx for some λ R.

4 there is a non-trivial solution to Ax = λx. (7) Let λ be an eigenvalue for the m n matrix A. The λ-eigenspace for A is the set E λ := { }. E λ := {x Ax = λx}. E λ := {Ax = λx λ R}. (8) Let V and W be subspaces. A function T : V W is a linear transformation if T (au + bv) = at (u) + bt (v) for all u, v V and all a, b R. OR T (u + v) = T (u) + T (v) for all u, v V and T (u) = at (u)for all u V and all a R. T (u+v) = T (u)+t (v) for all u, v V and T (u) = at (u) for all u V and some a R. T (u+v) = T (u)+t (v) for all u, v V and T (u) = at (u) for all u V and some a R. T (u + v) = T (u) + T (v) for u, v V and T (u) = at (u) for u V. The word all in the correct answer is an essential part the definition. To be a linear transformation T must satisfy a certain property with respect to all possible u, v, a, and b. T (v) W. The author does not understand that T must be a special kind of function to be a linear transformation. T (au + bv) = at (u) + bt (v) where u, v V and a, b R. The word where is vague, not even appropriate in this sentence. It does not convey the meaning of for all or whenever. The proposed answer could be read as a statement about a single u, v, a, and b. (9) The range of a linear transformation T : V W is R(T ) := { }. {T (x) x V }

5 (10) The null space of a linear transformation T : V W is {x V T (x) = 0} N (T ) := { }. (11) An n n matrix A is non-singular if the only solution to. solution to Ax = 0 is x = 0. it is linearly independent. Ax = b is Ab 1 A 1 x 1 + A n x n is A 1 = = A n = 0. the characteristic polynomial is zero. (12) A vector w is a linear combination of {v 1,..., v n } if w = a 1 v 1 + + a n v n for some a 1,..., a n R. w = a 1 v 1 + + a n v n. its components are {v i + v j }. (13) The linear span of {v 1,..., v n } consists of all linear combinations of v 1,..., v n. the linear combination of {v 1,..., v n }. (14) A set of vectors {v 1,..., v n } is linearly independent if the only solution to the equation a 1 v 1 + + a n v n = 0 is a 1 = = a n = 0.

6 a 1 v 1,, a n v n = 0 and a 1 = = a n = 0. First, this is not a sentence. Second, there is no equation; well, maybe a n v n = 0 is an equation. Third, there is no information about the solution to any equation: that is probably because the author used the word and when he/she should have used is. no v i is a multiple of v j (15) A subset W of R n is a subspace if it satisfies the following three conditions:. 0 W ; u + v W whenever u W and v W ; au W for all a R and all u W. must contain the zero space; must be open when adding, and open when multiplying. (16) Let W be a subspace of R n. A subset of W is a basis for W if. it is linearly independent and spans W. it is linearly independant (sic) and it is a span of W the subset s columns are linearly independent and span W. the linear combination of the subset spans W. it is an orthogonal set that spans W. it is a linearly independent set of n vectors. (17) The dimension of a subspace W R n is. the number of elements in a basis for it. the number of elements in W ; n the number of elements in the basis for W ; the space spanned by W. (18) Two n n matrices A and B are similar if there is an invertible matrix S such that B = S 1 AS. (19) An n n matrix A is diagonalizable if it is similar to a diagonal matrix OR there is an invertible matrix S such that S 1 AS is diagonal.

7 they have the same row reduced echelon form. (20) An n n matrix Q is orthogonal if Q T = Q 1 its columns form a basis for R n