PROVINCIAL EXAMINATION MINISTRY OF EDUCATION PHYSICS 12 GENERAL INSTRUCTIONS

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INSERT STUDENT I.D. NUMBER (PEN) STICKER IN THIS SPACE AUGUST 1998 PROVINCIAL EXAMINATION MINISTRY OF EDUCATION PHYSICS 12 GENERAL INSTRUCTIONS 1. Insert the stickers with your Student I.D. Number (PEN) in the allotted spaces above and on the back cover of this booklet. Under no circumstance is your name or identification, other than your Student I.D. Number, to appear on this booklet. 2. Ensure that in addition to this examination booklet, you have an Examination Response Form. Follow the directions on the front of the Response Form. 3. Disqualification from the examination will result if you bring books, paper, notes or unauthorized electronic devices into the examination room. 4. All multiple-choice answers must be entered on the Response Form using an HB pencil. Multiple-choice answers entered in this examination booklet will not be marked. 5. For each of the written-response questions, write your answer in the space provided in this booklet. 6. When instructed to open this booklet, check the numbering of the pages to ensure that they are numbered in sequence from page one to the last page, which is identified by END OF EXAMINATION. 7. At the end of the examination, place your Response Form inside the front cover of this booklet and return the booklet and your Response Form to the supervisor. 1998 Ministry of Education

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PHYSICS 12 PROVINCIAL EXAMINATION 1. This examination consists of two parts: Value Suggested Time PART A: 30 multiple-choice questions worth 60 60 two marks each PART B: 9 written-response questions 60 60 Total: 120 marks 120 minutes 2. Aside from an approved calculator, electronic devices, including dictionaries and pagers, are not permitted in the examination room. 3. The last three pages inside the back cover contain the Table of Constants, Mathematical Equations, Formulae, and Rough Work for Multiple-Choice. These pages may be detached for convenient reference prior to writing this examination. 4. Rough-work space has been incorporated into the space allowed for answering each writtenresponse question. You may not need all of the space provided to answer each question. 5. A calculator is essential for the Physics 12 Provincial Examination. The calculator must be a hand-held device designed primarily for mathematical computations involving logarithmic and trigonometric functions. Computers, calculators with a QWERTY keyboard, and electronic writing pads will not be allowed. Students must not bring any external devices to support calculators such as manuals, printed or electronic cards, printers, memory expansion chips or cards, or external keyboards. Students may have more than one calculator available during the examination. Calculators may not be shared, and communication between calculators is prohibited during the examination. In addition to an approved calculator, students will be allowed to use rulers, compasses, and protractors during the examination. 6. a) Final answers must include appropriate units. b) Marks will not be deducted for answers expressed to two or three significant figures. c) In this examination the zero in a number such as 30 shall be considered to be a significant zero. 7. You are expected to communicate your knowledge and understanding of physics principles in a clear and logical manner. Partial marks will be awarded for steps and assumptions leading to a solution. Full marks will not be awarded for providing only a final answer. If you are unable to determine the value of a quantity required in order to proceed, you may assume a reasonable value and continue toward the solution. Such a solution, however, may not be eligible for full marks. 8. The time allotted for this examination is two hours.

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PART A: MULTIPLE CHOICE Value: 60 marks (2 marks per question) Suggested Time: 60 minutes INSTRUCTIONS: For each question, select the best answer and record your choice on the Response Form provided. Using an HB pencil, completely fill in the circle that has the letter corresponding to your answer. 1. The free body diagram shown below represents a crate being dragged towards the left over a rough surface. F 2 F 1 F 3 Which of the vectors represent the normal force and the friction force acting on the crate? F 4 NORMAL FORCE FRICTION FORCE A. F 1 F 2 B. F 2 F 3 C. F 3 F 4 D. F 4 F 1 2. The graph shown below displays velocity v versus time t for a moving object. v The slope of this graph represents the object s A. mass. B. momentum. C. acceleration. D. displacement. t - 1 - OVER

3. The gravitational field strength on planet X is 5.0 N kg. An astronaut of mass 60 kg leaves Earth to visit planet X. What will her mass and weight be when she is on the surface of planet X? MASS WEIGHT A. 60 kg 300 N B. 60 kg 590 N C. 120 kg 300 N D. 120 kg 590 N 4. A girl applies a 140 N force to a 35 kg bale of hay at an angle of 28 above horizontal. The friction force acting on the bale is 55 N. What will be the horizontal acceleration of the bale? F = 140 N 28 A. 0.31 m s 2 B. 2.0 m s 2 C. 2.4 m s 2 D. 2.6 m s 2 5. A 5.0 kg concrete block accelerates down a 34 slope at 4.2 m s 2. Find the coefficient of friction between the block and the slope. A. 0.13 B. 0.16 C. 0.43 D. 0.67 34-2 -

6. What is the minimum power output of a small electric motor that lifts a 0.050 kg mass through 2.0 m in 30 s? A. 0.0017 W B. 0.017 W C. 0.033 W D. 15 W 7. An object travelling due north experiences an impulse due east. The direction of the change in momentum of this object is A. east. B. west. C. north. D. northeast. 8. A 1.5 kg ball falling vertically strikes the floor with a speed of 12 m s and rebounds upward with a speed of 8.0 m s. What is the magnitude and direction of the impulse given to the ball? IMPULSE DIRECTION A. 6.0 N s upward B. 6.0 N s downward C. 30 N s upward D. 30 N s downward 9. A net force of 20 N acts for 1.5 s on a 4.0 kg object initially at rest. What is the final kinetic energy of the object? A. 30 J B. 110 J C. 230 J D. 440 J - 3 - OVER

10. A 900 kg car travelling at 12 m s due east collides with a 600 kg car travelling at 24 m s due north. As a result of the collision, the two cars lock together and move in what final direction? A. 45 N of E B. 53 N of E C. 63 N of E D. 69 N of E 11. What are the units of torque? A. N m B. Nm C. N s D. Ns 12. A uniform 1.60 m board rests on two bricks as shown below. The left brick exerts an upward force of 12 N on the board. 1.20 m 0.40 m What upward force does the right brick exert? A. 3.0 N B. 12 N C. 24 N D. 36 N 13. An object travels with a constant speed in a circular path. The net force on the object is A. zero. B. towards the centre. C. away from the centre. D. tangent to the object s path. - 4 -

14. An object attached to a rotating table is moving in a circular path with a constant speed. Which is the correct free body diagram for the object? A. B. C. D. 15. A 65 kg student is in a car travelling at 25 m s on a hill of radius 110 m. When the car is at the top of the hill, what upward force does the seat exert on the student? A. 270 N B. 370 N C. 640 N D. 910 N 16. A 1 200 kg car can travel without slipping at a maximum speed of 28 m s in a circular path of radius 70 m on a dry horizontal surface. When it rains, the coefficient of friction is reduced to one half its original value. What is the maximum speed under this wet condition? A. 7.0 m s B. 14 m s C. 20 m s D. 28 m s - 5 - OVER

17. Which of the following graphs shows how the gravitational force varies with the distance of separation between two objects? A. F B. F d d C. F D. F d d 18. A 5.2 10 4 kg rocket is initially at rest on the surface of the earth. If 3.0 10 11 J of work is done on this rocket, what maximum altitude h will the rocket reach? (Assume the rocket s mass does not change.) h A. 5.9 10 5 m B. 6.5 10 5 m C. 5.8 10 6 m D. 6.9 10 7 m - 6 -

19. Which of the following correctly describes the polarity of the charges X and Y? X Y POLARITY OF X POLARITY OF Y A. Positive Negative B. Positive Positive C. Negative Negative D. Negative Positive 20. Three positive charges are fixed as shown in the diagram below. Q 1 = 4.0 10 6 C Q 2 = 5.0 10 6 C Q 3 = 8.0 10 6 C + + + 0.20 m 0.50 m Calculate the net electric force on Q 2 due to Q 1 and Q 3. MAGNITUDE OF FORCE DIRECTION OF FORCE A. 3.1 N Left B. 3.1 N Right C. 5.9 N Left D. 5. 9 N Right - 7 - OVER

21. A cathode ray tube beam deflects to the location as shown in Diagram I when a certain voltage is applied to the deflecting plates. CRT Screen CRT Screen 1 2 3 4 Diagram I Diagram II The connections to the deflecting plates are then reversed and the deflecting voltage is reduced. Which location in Diagram II best represents the new beam position? A. Location 1 B. Location 2 C. Location 3 D. Location 4 22. Which of the following correctly labels arrows 1 and 2 and polarities X and Y in the circuit below? X Y 1 2 ARROW 1 ARROW 2 POLARITY X POLARITY Y A. Electron Flow Conventional Current Positive Negative B. Electron Flow Conventional Current Negative Positive C. Conventional Current D. Conventional Current Electron Flow Positive Negative Electron Flow Negative Positive - 8 -

23. Which of the following household electrical appliances has the greatest rate of energy consumption? ITEM VOLTAGE CURRENT A. Video Camera 6.0 V 1.6 A B. Radio 4.5 V 0. 45 A C. Cassette Recorder 6.0 V 2.2 A D. Ghetto Blaster 12 V 1. 4 A 24. Switch S is originally open as shown in the circuit below. V R 1 R 2 S R How does the current through resistors R 1 and R 2 change when switch S is closed? CURRENT THROUGH R 1 CURRENT THROUGH R 2 A. increases increases B. increases decreases C. decreases increases D. decreases decreases 25. In a step-up transformer, how does the secondary voltage V s compare with the primary voltage V p, and the number of turns in the secondary N s compare with the number of turns in the primary N p? VOLTAGE NUMBER OF TURNS A. V s < V p N s > N p B. V s > V p N s > N p C. V s < V p N s < N p D. V s > V p N s < N p - 9 - OVER

26. Two particles Y and Z with equal mass and speed enter a uniform magnetic field and follow the paths as shown. How do their magnitude and polarity of charge compare? Z B Y MAGNITUDE OF CHARGE POLARITY A. Y < Z same charge B. Y < Z opposite charge C. Y > Z same charge D. Y > Z opposite charge 27. A wire carrying a current of 5.0 A is in a uniform 3.2 10 2 T magnetic field as shown. What is the force on the 0.15 m length of wire? 5.0 A 0.25 m 0.15 m B A. 0N B. 1. 6 10 2 N C. 2.4 10 2 N D. 4.0 10 2 N - 10 -

28. A single coil of wire of area 6.0 10 3 m 2 is positioned in a uniform 0.18 T magnetic field as shown. The coil is rotated 90 about axis XY in 4.2 10 3 s. What average emf is induced by the coil? X B Y A. 0V B. 0.13 V C. 0.26 V D. 43 V 29. A part of a coil of wire is placed in a uniform magnetic field as shown. Which two directions of motion would immediately induce an emf in the coil? B 1 4 2 3 A. 1 and 2 B. 1 and 3 C. 2 and 3 D. 2 and 4-11 - OVER

30. An electric motor is connected to a constant source of potential. Considering back emf, which of the following observations is correct? A. At full speed the applied voltage increases. B. At full speed the armature resistance increases. C. If the motor is kept from rotating at full speed, the armature heats up. D. If the motor is kept from rotating at full speed, the armature temperature decreases. This is the end of the multiple-choice section. Answer the remaining questions directly in this examination booklet. - 12 -

Value: 60 marks PART B: WRITTEN RESPONSE Suggested Time: 60 minutes INSTRUCTIONS: 1. Rough-work space has been incorporated into the space allowed for answering each written-response question. You may not need all of the space provided to answer each question. 2. a) Final answers must include appropriate units. b) Marks will not be deducted for answers expressed to two or three significant figures. c) In this examination the zero in a number such as 30 shall be considered to be a significant zero. 3. You are expected to communicate your knowledge and understanding of physics principles in a clear and logical manner. Partial marks will be awarded for steps and assumptions leading to a solution. Full marks will not be awarded for providing a final answer only. 4. If you are unable to determine the value of a quantity required in order to proceed, you may assume a reasonable value and continue toward the solution. Such a solution, however, may not be eligible for full marks. Full marks will NOT be given for the final answer only. - 13 - OVER

1. A rock is thrown from a clifftop at 18 m s, 25 above the horizontal. It lands on the beach 4.2 s later. 18 m s 25 h d a) What is the height h of the cliff? (4 marks) - 14 -

b) How far from the base of the cliff d did the rock land? (3 marks) ANSWER: a) height: b) horizontal distance: - 15 - OVER

2. A 0.030 kg toy car is pushed back against a spring-based launcher as shown in Diagram 1. Diagram 1 0.090 m Diagram 2 shows a graph of the force required to compress the spring 0.090 m. Diagram 2 F (N) 20 15 10 5 0 0 0.02 0.04 0.06 0.08 0.10 d (m) a) What is the work done in compressing the spring? (3 marks) - 16 -

b) Assuming no losses due to heat, what maximum speed is reached by the toy car when it is released? (3 marks) c) If in fact the maximum kinetic energy of the car is 0.18 J, what is the efficiency of the spring-based launcher? (1 mark) ANSWER: a) work: b) maximum speed: c) efficiency: - 17 - OVER

3. Peter exerts a horizontal force F on a 12 kg bucket of concrete so that the supporting rope makes an angle of 20 with the vertical. 20 F a) Find the tension force in the supporting rope. (5 marks) - 18 -

b) Peter now exerts a new force which causes the rope to make a greater angle with the vertical. How will the tension force in the supporting rope change? p The tension force will increase. p The tension force will decrease. p The tension force will remain the same. (Check one response.) (1 mark) c) Using principles of physics, explain your answer to b). (3 marks) ANSWER: a) tension force: - 19 - OVER

4. A 650 kg satellite in circular orbit around Earth has an orbital period of 1. 5 10 4 s. a) What is the satellite s orbital radius? (5 marks) - 20 -

b) What is the gravitational potential energy of this satellite? (2 marks) ANSWER: a) radius: b) potential energy: - 21 - OVER

5. An electron moving at 7.5 10 6 ms enters an electric field between parallel plates by passing through a small hole in one of the plates. 0.050 m 7.5 10 6 ms 0V + 250 V What is the impact speed of the electron on the second plate? (7 marks) - 22 -

ANSWER: speed: - 23 - OVER

6. What is the power dissipated in the 33 Ω resistor in the circuit shown below? (7 marks) 10 Ω 12 V 10 Ω 100 Ω 10 Ω 33 Ω - 24 -

ANSWER: power dissipated: - 25 - OVER

7. A motor is connected to a constant 120 V source and draws a current of 38.0 A when it first starts up. At its normal operating speed, the motor draws a current of 2.50 A. a) What is the resistance of the armature coil? (3 marks) - 26 -

b) What is the back emf at normal speed? (4 marks) ANSWER: a) resistance: b) back emf: - 27 - OVER

8. A power supply was connected to a resistor and a student plotted the graph of current, I, flowing through the resistor versus time, t, as shown below. I (A) 10 8 6 4 2 0 0 5 10 15 20 25 30 t (s) a) Calculate the area under the graph between t = 0s and t = 30 s. (2 marks) b) What does this area represent? (1 mark) - 28 -

c) The same power supply is connected to a resistor of greater resistance. For this new set-up, sketch a possible graph on the axes below and label it c). (2 marks) I (A) 10 8 6 4 2 0 0 5 10 15 20 25 30 t (s) ANSWER: a) area: - 29 - OVER

9. a) In a cathode ray tube, the purpose of the coils is to coils p focus the beam of electrons. p deflect the beam of electrons. p decrease the speed of the electrons. (Check one response.) (1 mark) b) Using the principles of electromagnetism, explain how this effect on the electrons is achieved by the coils. (3 marks) END OF EXAMINATION - 30 -

TABLE OF CONSTANTS Gravitational constant... G = 6.67 10 11 N m 2 kg 2 Acceleration due to gravity at the surface of Earth (for the purposes of this examination)... g = 9.80 m s 2 Earth Moon Sun radius... radius of orbit about Sun... period of rotation... period of revolution about Sun... mass... radius... radius of orbit about Earth... period of rotation... period of revolution about Earth... mass... mass... = 6.38 10 6 m = 1. 50 10 11 m = 8.61 10 4 s = 3.16 10 7 s = 5.98 10 24 kg = 1. 74 10 6 m = 3.84 10 8 m = 2.36 10 6 s = 2.36 10 6 s = 7.35 10 22 kg = 1. 98 10 30 kg Constant in Coulomb s Law... k = 9.00 10 9 N m 2 C 2 Elementary charge... e = 1. 60 10 19 C Mass of electron... m e = 9.1110 31 kg Mass of proton... m p = 1. 67 10 27 kg Mass of neutron... m n = 1. 68 10 27 kg Permeability of free space... µ o = 4π10 7 T ma Speed of light... You may detach this page for convenient reference. Exercise care when tearing along perforations. c = 3.00 10 8 ms i

MATHEMATICAL EQUATIONS For Right-angled Triangles: a 2 + b 2 = c 2 c b θ a sinθ= b c cosθ= a c tanθ= b a area = 1 2 ab For All Triangles: b C a area = 1 2 base height A c B sin2a = 2sin A cosa Sine Law: sin A a = sin B b = sinc c Cosine Law: c 2 = a 2 + b 2 2 ab cosc Circle: Circumference = 2πr Sphere: Surface area = 4πr 2 Area =πr 2 Volume = 4 3 πr3 Quadratic Equation: If ax 2 + bx + c = 0, then x = b ± b2 4ac 2a ii

Vector Kinematics in Two Dimensions: v = v 0 + at v = v + v 0 2 v 2 = v 0 2 + 2ad Vector Dynamics: F net = ma F fr =µf N Work, Energy, and Power: W = Fd Momentum: E k = 1 2 mv2 p = mv Equilibrium: τ=fd Circular Motion: Gravitation: a c = v2 r = 4π2 r T 2 F g = mg d = v 0 t + 1 2 at2 E p = mgh P = W t p = F t F = G m 1 m 2 r 2 E p = G m 1 m 2 r FORMULAE You may detach this page for convenient reference. Exercise care when tearing along perforations. iii

Electrostatics: F = k Q 1 Q 2 r 2 E = F Q V = E p Q E = V d E p = k Q 1 Q 2 r V = kq r Electric Circuits: I = Q t V = IR V terminal = ε ± Ir P = IV Electromagnetism: F = BIl F = QvB B =µ 0 ni =µ 0 N l Φ=BA I ε = Blv ε = N Φ t V back = ε Ir V s V p = N s N p = I p I s iv

v ROUGH WORK FOR MULTIPLE-CHOICE You may detach this page for convenient reference. Exercise care when tearing along perforations.

ROUGH WORK FOR MULTIPLE-CHOICE vi

INSERT STUDENT I.D. NUMBER (PEN) STICKER IN THIS SPACE PHYSICS 12 August 1998 Course Code = PH

FOR OFFICE USE ONLY PHYSICS 12 August 1998 Course Code = PH Score for Question 1: 1. (7) Score for Question 2: 2. (7) Score for Question 3: 3. (9) Score for Question 8: 8. (5) Score for Question 9: 9. (4) Score for Question 4: 4. (7) Score for Question 5: 5. (7) Score for Question 6: 6. (7) Score for Question 7: 7. (7)