IE1206 Embedded Electronics

Similar documents
3. Alternating Current

IE1206 Embedded Electronics

Basic Circuit Elements Professor J R Lucas November 2001

AC Circuits AC Circuit with only R AC circuit with only L AC circuit with only C AC circuit with LRC phasors Resonance Transformers

Introduction to AC Power, RMS RMS. ECE 2210 AC Power p1. Use RMS in power calculations. AC Power P =? DC Power P =. V I = R =. I 2 R. V p.

Phys1112: DC and RC circuits

Chapter 4 AC Network Analysis

Voltage/current relationship Stored Energy. RL / RC circuits Steady State / Transient response Natural / Step response

Chapter 7 Response of First-order RL and RC Circuits

Chapter 10 INDUCTANCE Recommended Problems:

CHAPTER 2 Signals And Spectra

RC, RL and RLC circuits

Lab 10: RC, RL, and RLC Circuits

Reading from Young & Freedman: For this topic, read sections 25.4 & 25.5, the introduction to chapter 26 and sections 26.1 to 26.2 & 26.4.

Electrical Circuits. 1. Circuit Laws. Tools Used in Lab 13 Series Circuits Damped Vibrations: Energy Van der Pol Circuit

EE 101 Electrical Engineering. vrect

CHAPTER 12 DIRECT CURRENT CIRCUITS

SINUSOIDAL WAVEFORMS

( ) = Q 0. ( ) R = R dq. ( t) = I t

Lecture 2-1 Kinematics in One Dimension Displacement, Velocity and Acceleration Everything in the world is moving. Nothing stays still.

LabQuest 24. Capacitors

EE100 Lab 3 Experiment Guide: RC Circuits

Direct Current Circuits. February 19, 2014 Physics for Scientists & Engineers 2, Chapter 26 1

ES 250 Practice Final Exam

INDEX. Transient analysis 1 Initial Conditions 1

9. Alternating currents

dv 7. Voltage-current relationship can be obtained by integrating both sides of i = C :

Section 3.8, Mechanical and Electrical Vibrations

8. Basic RL and RC Circuits

EECE251. Circuit Analysis I. Set 4: Capacitors, Inductors, and First-Order Linear Circuits

CHAPTER 6: FIRST-ORDER CIRCUITS

Name: Total Points: Multiple choice questions [120 points]

University of Cyprus Biomedical Imaging and Applied Optics. Appendix. DC Circuits Capacitors and Inductors AC Circuits Operational Amplifiers

- If one knows that a magnetic field has a symmetry, one may calculate the magnitude of B by use of Ampere s law: The integral of scalar product

5.2. The Natural Logarithm. Solution

2.9 Modeling: Electric Circuits

Chapter 9 Sinusoidal Steady State Analysis

copper ring magnetic field

( ) ( ) if t = t. It must satisfy the identity. So, bulkiness of the unit impulse (hyper)function is equal to 1. The defining characteristic is

EEEB113 CIRCUIT ANALYSIS I

Traveling Waves. Chapter Introduction

23.2. Representing Periodic Functions by Fourier Series. Introduction. Prerequisites. Learning Outcomes

EE 224 Signals and Systems I Complex numbers sinusodal signals Complex exponentials e jωt phasor addition

i L = VT L (16.34) 918a i D v OUT i L v C V - S 1 FIGURE A switched power supply circuit with diode and a switch.

KINEMATICS IN ONE DIMENSION

3, so θ = arccos

L1, L2, N1 N2. + Vout. C out. Figure 2.1.1: Flyback converter

Some Basic Information about M-S-D Systems

The problem with linear regulators

Physics for Scientists & Engineers 2

Designing Information Devices and Systems I Spring 2019 Lecture Notes Note 17

Week 1 Lecture 2 Problems 2, 5. What if something oscillates with no obvious spring? What is ω? (problem set problem)

Basic Principles of Sinusoidal Oscillators

Circuit Variables. AP 1.1 Use a product of ratios to convert two-thirds the speed of light from meters per second to miles per second: 1 ft 12 in

R.#W.#Erickson# Department#of#Electrical,#Computer,#and#Energy#Engineering# University#of#Colorado,#Boulder#

MEMS 0031 Electric Circuits

V L. DT s D T s t. Figure 1: Buck-boost converter: inductor current i(t) in the continuous conduction mode.

Electromagnetic Induction: The creation of an electric current by a changing magnetic field.

Chapter 5-4 Operational amplifier Department of Mechanical Engineering

Homework-8(1) P8.3-1, 3, 8, 10, 17, 21, 24, 28,29 P8.4-1, 2, 5

EECE 301 Signals & Systems Prof. Mark Fowler

Chapter 28 - Circuits

ECE 2100 Circuit Analysis

Chapter 8 The Complete Response of RL and RC Circuits

Pulse Generators. Any of the following calculations may be asked in the midterms/exam.

Lecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits

ECE 2100 Circuit Analysis

Chapter 16: Summary. Instructor: Jean-François MILLITHALER.

Chapter Q1. We need to understand Classical wave first. 3/28/2004 H133 Spring

Math 2142 Exam 1 Review Problems. x 2 + f (0) 3! for the 3rd Taylor polynomial at x = 0. To calculate the various quantities:

Math 333 Problem Set #2 Solution 14 February 2003

Comparative study between two models of a linear oscillating tubular motor

(b) (a) (d) (c) (e) Figure 10-N1. (f) Solution:

EE 315 Notes. Gürdal Arslan CLASS 1. (Sections ) What is a signal?

Chapter 1 Fundamental Concepts

Biol. 356 Lab 8. Mortality, Recruitment, and Migration Rates

Inductor Energy Storage

Lecture -14: Chopper fed DC Drives

Physics 1502: Lecture 20 Today s Agenda

Problem Set #1. i z. the complex propagation constant. For the characteristic impedance:

Decimal moved after first digit = 4.6 x Decimal moves five places left SCIENTIFIC > POSITIONAL. a) g) 5.31 x b) 0.

Physics 180A Fall 2008 Test points. Provide the best answer to the following questions and problems. Watch your sig figs.

Lab #2: Kinematics in 1-Dimension

Matlab and Python programming: how to get started

Physical Limitations of Logic Gates Week 10a

15. Vector Valued Functions

d 1 = c 1 b 2 - b 1 c 2 d 2 = c 1 b 3 - b 1 c 3

Sub Module 2.6. Measurement of transient temperature

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Spring Experiment 9: Faraday s Law of Induction

Guest Lectures for Dr. MacFarlane s EE3350 Part Deux

EE202 Circuit Theory II

Homework: See website. Table of Contents

6.2 Transforms of Derivatives and Integrals.

Chapter 2: Principles of steady-state converter analysis

In this chapter the model of free motion under gravity is extended to objects projected at an angle. When you have completed it, you should

Hall effect. Formulae :- 1) Hall coefficient RH = cm / Coulumb. 2) Magnetic induction BY 2

Signal and System (Chapter 3. Continuous-Time Systems)

From Complex Fourier Series to Fourier Transforms

Electrical and current self-induction

Chapter 15 Oscillatory Motion I

Transcription:

E06 Embedded Elecronics Le Le3 Le4 Le Ex Ex P-block Documenaion, Seriecom Pulse sensors,, R, P, serial and parallel K LAB Pulse sensors, Menu program Sar of programing ask Kirchhoffs laws Node analysis Two-erminals RR AD Le5 Ex3 K LAB Two-erminals, AD, omparaor/schmi Le6 Le8 Ex6 Le3 Ex4 Ex5 Le0 Le7 Le9 Le Le Ex7 Display Wrien exam K3 LAB3 Transiens PWM Phasor PWM P AP/ND-sensor K4 LAB4 LP-filer Trafo Sep-up, R-oscillaor L-osc, D-moor, P PWM Display of programing ask Trafo, Eherne conac

Easy o generae a sinusoidal volage Our enire power grid works wih sinusoidal volage. When he loop roaes wih consan speed in a magneic field a sine wave is generaed. So much easier, i can no be

The sine wave wha do you remember? y T period Y Y ˆ op, RMS ampliude ime y ( Yˆ sin( ω ω πf f Y T Yˆ

f a sine curve does no begin wih 0 he funcion expression has a phase angle ϕ. (. Phase ϕ y( Yˆ sin( ω + ϕ Specify his funcion mahemaically: y u( 6sin( π 000 + ϕ 3 u( 0 3 6sin( ϕ ϕ arcsin 0,5 rad ( 30 6 u( 6sin(683 + 0,5

Apples and pears? n circui analyses i is common (eg. in exbooks o expresses he angle of he sine funcion mixed in radians ω [rad] and in degrees ϕ [ ]. This is obviously improper, bu pracical (!. The user mus "conver" phase angle o radians o calculae he sine funcion value for any given ime. (You have now been warned u( 6sin(683 + 30?? onversion: x[ ] x[rad] 57,3 x[rad] x[ ]0,07

Mean and effecive value All pure A volages, has he mean value 0. More ineresing is he effecive value roo mean square, rms. med T 0 T u( d 0 0 T u( T d

(. Example. RMS. The rms value is wha is normally used for an alernaing volage.,63 V effecive value gives he same power in a resisor as a,63 V pure D volage would do. RMS, effecive value T u( d 3 3 0 ( 3 T + ( + 0 50 3 50 850 50,63 V

Sine wave effecive value Ex..3 sin has he mean value ½ Therefore: ˆ sin ( x RMS, effecive value sin ( x dx Effecive value is ofen called RMS ( Roo Mean Square.

Addiion of sinusoidal quaniies y ˆ A sin( ω + ϕ y ˆ A sin( ω + ϕ y + y?

Addiion of sinusoidal quaniies When we shall apply he circui laws on A circuis, we mus add he sines. The sum of wo sinusoidal quaniies of he same frequency is always a new sine of his frequency, bu wih a new ampliude and a new phase angle. ( Ooops! The resul of he raher laborious calculaions are shown below. + + + + + + + + cos( Â cos( Â sin( Â sin( Â arcan sin cos( Â Â Â Â ( ( ( sin( Â ( sin( Â ( ϕ ϕ ϕ ϕ ω ϕ ϕ ϕ ω ϕ ω y y y y y

Sine wave as a poiner A sinusoidal volage or curren, y( Yˆ sin( ω can be represened by a poiner ha roaes (counerclockwise wih he angular velociy ω [rad/sec]. Wikipedia Phasors

Simpler wih vecors f you ignore he "revoluion" and adds he poiners wih vecor addiion, as hey sand a he ime 0, i hen becomes a whole lo easier! Wikipedia Phasors hp://en.wikipedia.org/wiki/phasors

Poiner wih complex numbers A A volage 0 V ha has he phase 30 is usually wrien: maginary axis 0 30 ( Phasor Once he vecor addiions require more han he mos common geomerical formulas, i is insead preferable o represen poiners wih complex numbers. z a + jb Real axis 0 30 0e j30 0cos30 + 0 jsin 30 n elecriciy one uses j as imaginary uni, as i is already in use for curren.

Phasor Sinusoidal alernaing quaniies can be represened as poiners, phasors. amoun phase A poiner (phasor can eiher be viewed as a vecor expressed in polar coordinaes, or as a complex number. is imporan o be able o describe alernaing curren phenomena wihou necessarily having o require ha he audience has a knowledge of complex numbers - hence he vecor mehod. The complex numbers and -mehod are powerful ools ha faciliae he processing of A problems. They can be generalized o he Fourier ransform and Laplace ransform, so he elecro engineer s use of complex numbers is exensive.

peak/effecive value - phasor maginary axis z a + The phasor lenghs corresponds o sine peak values, bu since he effecive value only is he peak value scaled by / so i does no maer if you coun wih peak values or effecive values - as long as you are consisen! jb Real axis

The inducor and capacior couneracs changes The inducor and capacior couneracs changes, such as when connecing or disconnecing a source o a circui. Wha if he source hen is sinusoidal A which is hen changing coninuously??

Alernaing curren hrough resisor A sinusoidal curreni R ( hrough a resisor R provides a proporional sinusoidal volage drop u R ( according o Ohm's law. The curren and volage are in phase. No energy is sored in he resisor. Phasors R and R become parallel o each oher. i R ( R sin( ω ur ( ir ( R ur ( R R sin( ω R ˆ R R Vecor phasor ˆ R R R omplex phasor The phasor may be a peak poiner or effecive value poiner as long as you do no mix differen ypes.

Alernaing curren hrough inducor L L L L L L L u i L u i + ω π ω ω ω ω ω sin( ˆ cos( ˆ ( d ( d ( sin( ˆ ( L L L L L A sinusoidal curren i L ( hrough an inducor provides, due o self-inducion, a voage drop u L ( which is 90 before he curren. Energy sored in he magneic field is used o provide his volage. When using complex poiners one muliplies ωl wih j, his roaes he volage poiner +90 (in complex plane. The mehod auomaically keeps rack of he phase angles! L L L L j j X L ω Vecor phasor omplex phasor The phasor L will be ωl L and i is 90 before L. The eniy ωl is he amoun of he inducor s A resisance, reacance X L [Ω].

Alernaing curren hrough capacior sin( ˆ cos( ˆ ( sin( ˆ ( d ( ( ( d d d ( d π ω ω ω ω ω u i i u i q u Q A sinusoidal curren i ( hroug a capacior will charge i wih he volage drop u ( ha lags 90 behind he curren. Energy is sorered in he elecric field. Vecor phasor Phasor is /(ω and i lags 90 afer. The eniy /(ω is he amoun of he capacior s A resisance, reacance X [Ω]. ω

omplex phasor and he sign of reacance f you use complex phasor you ge he -90 phase by dividing (/ω wih j. The mehod wih complex poiner auomaically keeps rack of he phase angles if we consider he capacior reacance X as negaive, and hence he inducor reacance X L as posiive. - j X omplex phasor ω ω

L+ in series 5jΩ 4jΩ + jω L 4jΩ 5jΩ jω

Reacance frequency dependency X L [Ω] X L [Ω] f [Hz] f [Hz] X L ω L X ω ω π f

log LOG LOG plo ( X L scale [ Ω] log( scale [ Ω] X log( f scale [Hz] log( f scale [Hz] Ofen elecronics engineers use log-log scale. The inducor and capacior reacances will hen boh be "linear" relaionship in such chars.

R L n general, our circuis are a mixure of differen R L and. The phase beween and is hen no ±90 bu can have any inermediae value. Posiive phase means ha he inducances dominaes over capaciances, we have inducive characer ND. Negaive phase means ha he capaciance dominaes over he inducances, we have capaciive characer AP. The raio beween he volage and curren, he A resisance, is called impedace Z [Ω]. We hen have OHM s A law: AP Z

Phasor diagrams n order o calculae he A resisance, he impedance, Z, of a composie circui one mus add currens and volages phasors o obain he oal curren and he oal volage. Z The phasor diagram is our "blind sick" in o he A World!

Ex. Phasor diagram (.5 Elemenary diagrams for R L and A a cerain frequency f he capacior has he reacance X and he resisor R has he same amoun (absolue value, R [Ω]. se he elemenary diagrams for R and as building blocks o draw he whole circui phasor diagram (for his acual frequency f.

Try i your self

Example. Phasor diagram. reference phase ( horizonal 3 R R R + 4 R 5 R R 6 +

mpedance Z The circui A resisance, impedance Z, one ge as he raio beween he lengh of and phasors. The impedance phase ϕ is he angle beween and phasors. The curren is before he volage in phase, so he circui has a capaciive characer, AP. ( Somehing else had hardly been o wai since here are no coils in he circui

omplex phasors, -mehod + 90 arg(j j arg( j j 90 arg(j j j 0 arg( L L L L R R X L L X R R ω ω ϕ ω ω ϕ ω ϕ omplex phasors. OHM s law for R L and. omplex phasors. OHM s law for Z. ] m[ ] m[ arcan ] Re[ ] m[ arcan arg( ] Re[ ] Re[ arg( arg( arg arg( Z R X Z Z Z Z Z Z Z ϕ n fac, here will be four useful relaionships! Re, m, Abs, Arg

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz jπ f jπ 50300 6 0 j

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j Z + Z R // 0-0 j+ (5-5 j 4-3 j ( + 3 j ( + 3 j 0,4 +, j 0, 4 +, j 0,4 +,,6

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j 4 j (0,4 +, j (-0 j 4 j + ( 4,65

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. Volage divider: 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j Z R // + Z R // 0 5-5 j -0 j+ (5-5 j j 0-3 j (+ 3 j (+ 3 j 8 + 4 j 8 + 4 j 8 + 4 8,94

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j 8 + 4 j -0 j 0,4 + 0,8 j 0,4 + 0,8 j 0,4 + 0,8 0,89

Ex. omplex phasors. R 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j

Ex. omplex phasors. R 0 V 30 µf R 0 Ω f 50 Hz Z R// jπ f jπ 50300 6 0 j R 0( 0 j (0 + 0 j 5 5 j R + 0 0 j (0 + 0 j R R 8 + 4 j 0 0,8 + 0,4 j R 0,8 + 0,4 j 0,8 + 0,4 0,89

You ge he phasor char by ploing he poins in he complex plane!

Roae diagram When we draw he phasor diagram i was naural o have as reference phase (horizonal, wih he mehod was he naural choice of reference phase (real. Because i is easy o roae he char, so, in pracice, we have he freedom of choosing any eniy as he reference. arg( arg(8 + 4j arcan (cos( 6,7 + jsin( 6,7 4 8 6,7 Muliply he all complex numbers by his facor and he roaion will ake effec!

Summary Sinusoidal alernaing quaniies can be represened as poiners, phasors, amoun phase. A poiner (phasor can eiher be seen as a vecor expressed in polar coordinaes, or as a complex number. alculaions are usually bes done wih he complex mehod, while phasor diagrams are used o visualize and explain alernaing curren phenomena.

Noaion x Xˆ X X X nsan value Top value omplex phasor Absolue value, he amoun