STRAND J: TRANSFORMATIONS, VECTORS and MATRICES

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Mathematics SKE, Strand J STRAND J: TRANSFORMATIONS, VECTORS and MATRICES J4 Matrices Text Contents * * * * Section J4. Matrices: Addition and Subtraction J4.2 Matrices: Multiplication J4.3 Inverse Matrices: Solving Linear Equations J4.4 Geometrical Transformations

J4 Matrices J4. Matrices: Addition and Subtraction The numbers shown in a matrix can be in many different shapes and sizes; for example, (a) 2 4 (b) 2 0 32 (c) 5 3 (d) 2 5 4 2 3 We describe these shapes and sizes by giving the dimension of the matrix. The dimension is (number of rows in the matrix) by (number of columns) (Rows are along the horizontal; columns are vertical.) Worked Example What is the dimension of each of the matrices shown above? (a) (b) by 3 (c) 2 by (d) 3 by 2 2 by 2 (as it has 2 rows and 2 columns) In general, if a matrix has m rows and n columns, its dimension is We often write this as m by n m n but the ' ' sign does not mean multiply; you read this as "m by n". You can add and subtract matrices by adding and subtracting their corresponding elements. Matrices have to have the same dimensions in order to be added or subtracted. Worked Example 2 Calculate (a) 5 5 + 2 0 2 5

J4. (b) 4 3 0 2 5 6 4 4 5 8 (a) 5 5 + = 2 0 2 5 5 + 5 + 2 + 2 0 5 + (b) = 0 0 0 5 4 3 0 2 5 = 6 4 4 5 8 4 0 3 2 5 6 4 5 4 8 = 6 6 2 6 2 Matrices are equal if they have the same dimensions and corresponding elements are equal. Worked Example 3 Given that a 3 4 b d c 5 0 = 5, find the values of a, b, c and d. 0 5 a 3 4 b d c 5 0 = 5 0 5 That is, a 4 3 c = d b + 5 0 5 0 5 As the matrices are equal, each element must be equal; that is a 4 = 5 a = 9 3 c = 0 c = 3 d = 0 d = b + 5 = 5 b = 0 2

J4. Exercises. What is the dimension of each of the following matrices? (a) 4 2 0 (b) 3 6 (c) 2 3 0 (d) ( 2 ) (e) 3 6 2 0 0 0 0 2. For the matrices, find A = 3 2 0 (a) A + B (b) A B (c) A + B C (d) C A B 2 B = 0 4 C = 7 0 0 5 3. For the matrices 2 A = B = ( ) C = ( ) D = 0 0 E = 0 ( ) F = ( 5 2) find, where possible, (a) A + B (b) E A (c) F D C (d) B + C (e) F D C (f) A F (g) C ( F + D) 3

J4. 4. Given that a 2 5 4 + b d c 0 0 = 4 0 find the value of the constants a, b, c and d. 5. Given that 2 5 + a b c = 3 4 d e f 4 0 7 3 0 find the value of the constants a, b, c, d, e and f. J4.2 Matrices: Multiplication There are two types of multiplication defined for matrices. (A) SCALAR multiplication Here each element of the matrix is multiplied by a scalar (number). For example, 2 4 3 = 2 4 2 3 2 2 = 8 6 2 2 Worked Example If A = 5 2 and B = 6 0 what are (a) 2A (b) 5 2 (a) 2 A = 2 = 6 0 2 A (c) ( 4) B? 2 5 2 2 = 2 6 2 0 0 4 2 0 (b) A = 2 5 2 = 2 6 0 5 2 5 2 2 2 6 0 2 2 = 3 0 (c) ( 4) B = ( 4) ( ) = ( 4) ( 4) ( ) ( 4) = ( 4 4 4) 4

J4.2 (B) MATRIX multiplication You can multiply two matrices, A and B, together and write C = AB (or A B) only if the number of columns of A = number of rows of B; that is, A has dimension m n, B has dimension n k. The resulting matrix, C, has dimensions m k. To find C, we multiply corresponding elements of each row of A by elements of each column of B and add. The following examples show you how the calculation is done. Worked Example 2 If A = B = and, find AB. 2 3 2 First check the dimension: A is 2 2 and B is 2, so C = AB is defined. (The number of columns of A = the number of rows of B) and C is a 2 matrix: C = 2 3 2 = + ( ) + 2 ( 2) 3 2 = 2 2 + 6 = 3 8 Worked Example 3 If A = 2 B = 2 and, calculate AB and BA. 0 5 0 A is 2 2 and B is 2 2, so AB is defined and AB = 2 0 2 5 0 = + + + ( ) + ( ) 2 5 2 2 0 0 5 0 2 0 = 2 + 5 4 + 0 0 5 0 + 0 = 3 4 5 0 5

J4.2 Similarly, BA is defined and BA = 2 5 0 2 0 = ( ) 2 + 2 0 ( ) + 2 5 2 + 0 0 5 + 0 = 2 + 0 2 0 + 0 5 + 0 = 2 3 0 5 Note AB BA and this shows that matrix multiplication is not commutative (that is, the calculation cannot be reversed with the same result). Worked Example 4 Given that A = 0, B = ( 2 2 ), C = 2 4 ( ) determine whether or not the following multiplications are defined, and, if they are, find the resulting matrix. (a) AB (b) BC (c) AC (d) CA (e) BCA (a) AB is not defined, as A is 3 and B is 2, and 3. (b) BC is defined. As B is 2 and C is 2, BC is. That is BC = 2 2 2 4 = ( 2 2 2 4) = ( 4 8) = ( 4) (c) AC is not defined, as A is 3 and C is 2. 6

J4.2 (d) CA is defined; C is 2 and A is 3 so CA is 2 3. That is 2 4 ( 0 ) = 2 2 0 2 4 4 0 4 = 2 0 2 4 0 4 (e) We already know that BC is a matrix and A is 3, so BCA is defined and is 3. That is BCA = Worked Example 5 0 3 5 Let A =, B =. 2 3 2 Calculate (a) A + B ( 4) ( 0 ) = 4 0 4 (b) AB (c) BA 2 2 (d) A B A means AA 0 3 5 (a) A + B = + = 2 3 2 4 5 3 5 0 (b) AB = 2 3 3 5 = 2 ( ) + ( ) ( ) + 3 + 0 5 0 2 2 3 + 3 2 5 3 2 3 5 = 9 6 (c) BA = 3 5 0 = 2 2 3 ( ) + ( ) + 3 + 5 2 3 0 5 3 + 2 2 0 2 3 3 5 = 5 6 7

J4.2 (d) A 2 0 B = 2 3 0 3 5 2 3 2 = + + + 0 2 0 0 3 2 + 3 2 2 0 3 3 3 5 2 0 3 5 = 8 9 2 = 2 5 7 7 Exercises 2 0. For the matrices A = B =,, find 4 6 (a) 3A (b) A (c) 2B 2 2. Find the value of k and the value of x so that 0 0 2 0 7 + = 2 0 0 k x 0 3. Find the values of a, b, c and d so that a 2 0 3 c 3 3 b d = 4 4 4. Find the values of a, b, c and d so that 5 b a c 2 9 2 = 0 3 d 5. Given the dimensions of the following matrices, Matrix A B C D E Dimension 2 2 2 3 3 2 2 3 give the dimensions of these matrix products: (a) BA (b) DE (c) CD (d) ED (e) AE (f) DA 8

J4.2 6. Find these products: (a) 2 3 4 2 (b) 2 3 4 0 5 2 7. The matrix A = 2 and the matrix B = 0 3 0 0. Find: (a) AB (b) A 2 8. The matrices A, B and C are given by A = 2, b = 3 2, C = 3 2 Determine whether or not the following products are possible and find the products of those that are. (a) AB (b) AC (c) BC (d) BA (e) CA (f) CB 9. Find in terms of a, 2 a 3 0. 0 2 0. Find in terms of x, 3 2 x x 2. 3. The matrix A = 2 0 Find: (a) A 2 (b) A 3 J4.3 Inverse Matrices: Solving Linear Equations In this section, we will restrict ourselves to square matrices, that is, matrices in which the number of rows = number of columns ( m = n). For example, 3 2 4 A = B = C = D 4 3, 4 2,, 2 4 3 0 = ( 5) 9

J4.3 We will concentrate on 2 2 matrices (examples A and C above). We start by defining the determinant of a 2 2 matrix. a b If M =, its determinant is defined by c d det M = ad cb Note that it is just a number, So, for the examples above, det A = 4 ( 2) = 4 + 2 and = 6 det C = 4 3 4 3 = 2 2 = 0 For matrix M, if det M = 0 we call it singular and if det M 0, it is non-singular. Hence A is non-singular and C is singular. Worked Example 4 x M is the matrix. 0 5 Calculate the value of x which would make M a singular matrix. M is singular if det M = 0. det M ( ) ( ) = 4 5 x 0 So det M = 0 when 20 + 0x = 0 = 20 + 0x 0x x = 20 = 2 For a 2 2 matrix, we will define its inverse, denoted by M, as the matrix that satisfies XM = MX = I Here I is the identity matrix, defined as 0, and we denote X by M. 0 It is not always possible to find an inverse, as we will see in the following result. 0

J4.3 Theorem The inverse of M = a b is given by c d M = d det M c b a and only exists if det M 0. d b The matrix is called the adjoint matrix and in denoted by adj A. Note that, c a on one diagonal the numbers are reversed and on the other they are multiplied by. Proof We will show that M M = I. Note that det M d c b a a c b = d det M da bc db bd ca + ac cb + ad = ad bc 0 det M 0 ad bc ad bc = det M 0 0 ad bc det M = 0 (since det M = ad bc) 0 = I So M M = I and you can show that MM = I in the same way. Thus we can find the inverse of a 2 2 matrix provided that det M 0; that is, it is non-singular. Worked Example 2 Find the inverse of A = 5 3 3 2 and show that AA = A A = I.

J4.3 Since det A = 5 2 3 3 = 0 9 =, A is non-singular and A 2 3 = = det A 3 5 2 3 = 3 5 2 3 3 5 We now check this by calculating and similarly, AA = 5 3 3 2 A 2 3 = 0 3 5 0 2 3 A = 5 3 = 0 3 5 3 2 0 Note We can use this concept of finding the inverse to solve simultaneous equations. For example, if 5x + 3y = 4 3x + 2y = 2 then this can be written as AX = B x when A = X B 5 3 = y = 4,, 3 2 2 Check: AX x = 5 3 y = 3 2 5x + 3y = x + y 4 = 3 2 2 B Multiply AX = B by A to give A AX = A B But A A = I from the result above, so IX = A B But IX x x = 0 y = y = 0 X giving X = A B = 2 3 4 3 5 2 That is, x y = 2 2 2

J4.3 So the solution is x = 2, y = 2. We will check these values in the original equation: and this verifies the solution. Worked Example 3 5x + 3y = 5 2 + 3 2 = 0 6 = 4 3x + 2y = 3 2 + 2 2 = 6 4 = 2 Given that M = 2 5 7 5 (a) Show that M is a non-singular matrix. (b) Write down the inverse of M. (c) Write down the 2 2 matrix which is equal to the product of M M (d) Pre-multiply both sides of the following matrix equation by M 2 5 7 5 x = y Hence solve for x and y. (a) det M = 2 5 7 5 = 2 5 5 7 = 30 35 = 5 3 7 So det M 0 and M is non-singular. (b) M = det M (c) M M = 5 adj M 5 5 7 2 = 3 7 2 5 5 = = 0 I 0. (d) M x y = 3 7 Multiply by M to give M M x M y = 7 3 3

J4.3 x I y = 3 3 7 2 5 5 7 x y 26 = So x = 26 and y =. Exercises. Determine which of these matrices are singular and which are non-singular. For those that are non-singular find the inverse matrix. (a) 3 4 2 (b) 3 3 (c) 2 5 0 0 (d) 2 3 5 (e) 6 3 4 2 (f) 4 3 6 2 2. Find the value of a for which these matrices are singular. (a) a + a 3 2 (b) + a 3 a a + 2 a (c) 2 + a a a a 3. Given that AB = C, (a) find an expression for B 2 (b) find B when A = C = 3 6 and 4 3 22 4. Use inverse matrices to solve these simultaneous equation. (a) 4x y= 2x + 3y = 8 (b) 4x y= 3x + 2y = 0 (c) 5x + 2y = 3 3x + 4y = 3 5. Solve, using matrix methods, 3x 2y = 3 x + 4y = 8 4

J4.3 6. Solve, using matrix methods as far as possible, each of the following sets of simultaneous equations. (a) x + y = 2 (b) x + y = 2 (c) x + y = 2 2x + 3y = 5 2x + 2y = 4 2x + 2y = 5 7. (a) Find the matrix P if PQ = QP = I where Q is the matrix 2. 4 5 (b) Using part (a), solve the equation 2x + y = 4x + 5y = J4.4 Geometrical Transformations In earlier units in this strand we met transformations, including rotations, reflections and enlargements. A convenient way to define these is by using a matrix approach. For example, consider a reflection in the line x = y. The point A, (4, 2) is transformed to A' (2, 4) as shown opposite. Similarly, the point P (x, y) is transformed to P' (y, x). We can write the new coordinates in matrix form as X' = MX or x' x = y' 0 0 y y (2, 4) A' y = x A (4, 2) x as multiplying out the matrix on the right hand side gives x' = y y' = x that is, the coordinates of P' are (x, y). So the matrix M = 0 0 defines the transformation "reflection in the line y = x". 5

J4.4 Similarly for other reflections; all are summarised below. Reflection In the line y = x Matrix Transformation 0 0 In the line y In the y-axis In the x-axis = x 0 0 0 0 0 0 A similar process is used for rotations. Consider a rotation of 90 in the clockwise direction about the origin, O, as shown opposite for the point y (4, 2) Similarly, ( 4, 2) ( 2, 4) ( x, y) ( y, x) O 90 x for any point of the shape, and in matrix (2, -4) form, X = MX, or x' 0 x = y' 0 y y = x That is, x' = y y' = x So the coordinates of P x, y shown, ( 0, 2) ( 2, 0) ( 4, 0) ( 0, 4) ( 0, 0) ( 0, 0) become P' ( y, x) and for the rotation of the shape 6

J4.4 The matrix 0 M = 0 corresponds to a rotation of 90 in the clockwise direction. Similarly for other rotations; all are summarised below. Rotation 90 clockwise 90 anticlockwise 80 (clockwise or anticlockwise) Matrix Transformation 0 0 0 0 0 0 Enlargements can be treated in a similar way. For an enlargement of the shape shown, centre O and scale factor 2, the diagram opposite shows that and similarly ( 4, 2) ( 8, 4) ( x, y) ( 2x, 2y) y O A (4, 2) A' (8, 4) x For example, ( 0, 2) ( 0, 4) ( 4, 0) ( 8, 0) ( 0, 0) ( 0, 0) In matrix terms, X = MX when x y = 2 0 0 2 x y = 2x 2y That is, x = 2x y = 2y so that the coordinates of P x, y become P' 2x, 2y. 7

J4.4 The matrix M = 2 0 0 2 represents an enlargement of scale factor 2. For scale factor n, with centre of enlargement being the origin, the matrix will be M n = 0 0 n For the CXC examination, you do need to know these matrix transformations, as you will see in the Worked Examples. Note Points that do not change position after transformation are called invariant points. For example, points on the line y = x remain in the same position after reflection in the line y = x. These are the invariant points for the transformation "reflective in the line y = x". Finally, we can look at translations in a similar way. y If we move x x + 3 and y y + 2 then for the point A (4, 2), A (4, 2) (7, 4) A' is (7, 4) and P( x, y) is translated where to P' x', y' x' = x + 3 y' = y + 2 O x In matrix form, we have x' x X' = M + X X' =, M, X = y' 3 when = 2 y In general, for the translation x x + a, y y + b, then a X' = M + X where M = b 8

J4.4 Worked Example The matrix, K, maps the point S,4 onto S' (, ) T' ( 5, 3). Given that K = a b c d, (a) Express as a matrix equation, the relationship between (i) K, S and S' (ii) K, T and T'. 4 and the point T3,5 onto (b) Hence, determine the values of a, b, c and d. (c) Describe COMPLETELY the geometric transformation which is represented by the matrix K. (a) (i) a c b d = 4 4 (ii) a c b d 3 = 5 5 3 (b) a + 4b = 4 c + 4d = 2 3a + 5b = 5 3 3c + 5d = 3 4 We can solve for a and b from and 3 : Multiply by 3 to give 3a + 2b = 2 Taking 3 from this gives 7b = 2 + 5 = 7 b =. From, = = a + 4 4 a 0 and a = 0, b = satisfies 3. Multiply 2 by 3 to give 3c + 2d = 3 Taking 4 from this equation gives 7d = 0 d = 0 9

J4.4 and substituting in 2 gives c =. Hence, 0 K = 0 (c) This is a reflection in the line y = x. Worked Example 2 A triangle XYZ, with coordinates X (4, 5), Y ( 3, 2) and Z (, 4) is mapped onto triangle XYZ ' ' ' by a transformation M = 0 0. (a) Calculate the coordinates of the vertices of triangle XYZ ' ' '. 0 (b) A matrix N = 0 maps triangle XYZ ' ' ' onto triangle X'' Y'' Z'''. Determine the 2 2 matrix, Q, which maps triangle XYZ onto X'' Y'' Z''. (c) Show that the matrix which maps triangle X'' Y'' Z'' back onto triangle XYZ is equal to Q. (a) X' = MX = 0 4 0 5 = 4 5 i.e. X' 4, 5 Y' = MY = 0 0 3 2 = 3 2 i.e. Y' ( 32, ) Z' = MZ = 0 0 4 = 4 i.e. Z' ( 4, ) (b) X'' = NX' = NMX, so X'' = QX where Q = NM = 0 0 0 = 0 0 0 (c) Check: 0 2 QX'' = Q X and Q 2 = 0 0 0 = 0 0 Hence QX'' = X and similarly for Y'' and Z''. 20

J4.4 Worked Example 3 (a) Write down the matrix (i) M y that represents reflection in the y-axis (ii) R l that represents a rotation of 80 about the origin. (b) (c) Determine the single matrix, U, that represents a transformation, M y, followed by another transformation, R l. Describe geometrically the transformation represented by (i) R p = 0 0 (ii) E = 2 0 0 2 (d) (e) On graph paper, using a scale of cm to represent unit on each axis, draw the pentagon ABCDE with vertices A (, 2), B (4, 2), C (4, 5), D (2, 6) and E (, 5). Draw the image of ABCDE under the transformation represented by (i) R p, and label that image ABCDE ' ' ' ' ' (ii) E, and label that image A'' B'' C'' D'' E''. (a) (i) M y = 0 0 (ii) R l = 0 0 (b) U = 0 0 0 = 0 0 0 (c) (i) Rotation, about origin, of 90, anticlockwise. (ii) Enlargement with scale factor 2. (d) (e) Shown on graph (see next page). Shown on graph (see next page). 2

J4.4 s for Worked Example 3 (d) and (e). y 6 4 2 D'' 0 E'' C'' 8 D' 6 D C' E' E C 4 A'' B'' B' A' 2 A B -8-6 -4-2 0 2 4 6 8 x -2-4 22

J4.4 Worked Example 4 (a) Using the graph paper below, perform the following transformations: (i) Reflect triangle P in the y-axis. Label its image Q. (ii) Draw the line y = x and reflect triangle Q in this line. Label its image R. (iii) (iv) Describe, in words, the single geometric transformation which maps triangle P onto triangle R. Reflect triangle Q in the x-axis. Label its image S. y 8 7 6 5 P 4 3 2-8 -7-6 -5-4 -3-2 - 2 3 4 5 6 7 8 x - -2-3 -4-5 -6-7 -8 23

J4.4 (v) Write down the 2 2 matrix for the transformation which maps triangle P onto triangle S. (b) (i) Write down the 2 2 matrices for a) a reflection in the y-axis b) a reflection in the line y = x. (ii) Using the two matrices in (b) (i) above, obtain a SINGLE matrix for a reflection in the y-axis followed by a reflection in the line y = x. (a) (i) and (ii) See diagram below. y 8 7 y = x 6 P 5 4 Q 3 2 R -8-7 -6-5 -4-3 -2-2 3 4 5 6 7 8 x - -2-3 -4 S -5-6 -7-8 (iii) (iv) (v) Rotation about origin of 90 in clockwise direction See diagram above. 0 0 24

J4.4 (b) (i) a) b) 0 0 0 0 (ii) 0 0 0 = 0 0 0 Exercises. (a) Write down the 2 2 matrix, R, which represents a reflection in the y-axis. (b) Write down the 2 2 matrix, N, which represents a clockwise rotation of 80 about the origin. (c) Write down the 2 matrix, T, which represents a translation of 3 units parallel to the x-axis and 5 units parallel to the y-axis. (d) The point P (6, ) undergoes the following combined transformations such that RN( P) maps P to P' T( P) maps P to P'' Determine the coordinates of P' and P''. 2. The vertices of triangle ABC have coordinates A (, ), B (2, ) and C (, 2). Matrix T transforms triangle ABC into triangle ABC ' ' '. The coordinates of the vertices of triangle ABC ' ' ' are A' (3, 3), B' (6, 3) and C' (3, 6). (a) Express the transformation matrix, T, in the form s u t. v (b) Write a complete geometrical description of the transformation T. (c) State the ratio of the areas of triangle ABC to ABC ' ' '. 3. (a) Using a scale of cm to represent unit on BOTH the x and the y-axes, draw on graph paper the triangle PQR and PQR ' ' ' such that P( 3, 2), Q( 2, 2), R( 2, 4) and P' ( 6, 4), Q' ( 4, 4) and R' ( 4, 8). (b) Describe FULLY the transformation, G, which maps triangle PQR onto triangle PQR ' ' '. 25

J4.4 (c) The transformation, M, is a reflection in the line y = x. On the same diagram, draw and label the triangle P'' Q'' R'', the image of triangle PQR ' ' ' under the transformation M. (d) Write down the 2 2 matrix for (i) (ii) transformation G transformation M (iii) transformation G followed by M. 0 4. The matrix R = 0 (a) Give a geometrical interpretation of the transformation represented by R. (b) Find R. (c) Give a geometrical interpretation of the transformation represented by R. 5. The transformations L, M and N are defined by 0 L = M = N 2 0,, = 0 0 2 (a) Explain the geometrical effect of the transformation M followed by L. (b) Show that N = LM. 6. R = S 0 0 and = 0 0 (a) Find R 2. (b) (c) Find RS. Describe the geometrical transformation represented by RS. 2 7. The matrix R is given by R = 2 2 2 (a) Find R 2. (b) Describe the geometrical transformation represented by R 2. (c) Describe the geometrical transformation represented by R. 26