LP03 Chapter 5. A prime number is a natural number greater that 1 that has only itself and 1 as factors. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29,

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LP03 Chapter 5 Prime Numbers A prime number is a natural number greater that 1 that has only itself and 1 as factors. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, Question 1 Find the prime factorization of 120. You must write 120 as a product using only prime numbers. So, start dividing it by 2, 2, 2, 3, and then 5. The prime factorization of 120 is: 2 3 3 5 1

Finding the Least Common Multiple Using Prime Factorizations To find the least common multiple of two or more numbers, 1. Write the prime factorization of each number. 2. Select every prime factor that occurs, raised to the greatest power to which it occurs, in these factorizations. 3. Form the product of the numbers from step 2. The least common multiple is the product of these factors. Question 2 Find the Least Common Multiple of 500 and 360. 500 = 2 2 5 3 360 = 2 3 3 2 5 Now choose the numbers that you see in any factorizations with their largest exponents (I see the numbers 2 3, 3 2, and 5 3 ) and multiply them: LCM = 2 3 3 2 5 3 = 9000 2

Question 3 A relief worker needs to divide 120 bottles of water and 45 cans of food into groups that each contain the same number of items. Also, each group must contain the same type of item (bottled water or canned food). What is the largest number of relief supplies that can be put in each group? The problem is about finding the Greatest Common Divisor. Question 4 120 = 2 3 3 5 45 = 3 2 5 Now choose only the numbers that you see in both factorizations with their smallest exponents (I see 3 and 5 in both factorizations) and multiply: GCD = 3 5 = 15 So 15 is the largest number that goes into both 120 and 45. 15 is the largest number of supplies that can be put in each group. Express the following number as a decimal. 1 2 You can use long division or the calculator to divide 1 2 = 0.5 3

Question 5 The list of ingredients for chocolate brownies given will make 16 brownies. 1 3 cup butter 3 ounces chocolate 3 4 1 1 2 cups sugar 2 eggs 2 3 teaspoons vanilla cup flour How much of each ingredient is needed to make 12 brownies? So, you need only 12 brownies out of 16. You will have to multiply each of these quantities by the fraction 12 16. Also, it would be easier, if you reduce it first: Now start multiplying each quantity by 3 4. 12 16 = 12 4 16 4 = 3 4 1 3 3 4 = 1 4 3 3 4 = 3 1 3 4 = 9 4 = 2 1 4 3 4 3 4 = 9 16 1 1 2 3 4 = 3 2 3 4 = 9 8 = 1 1 8 Cup butter Ounces chocolate Cups sugar Teaspoons vanilla 2 3 4 = 2 1 3 4 = 6 4 = 3 2 = 1 1 2 Eggs 2 3 3 4 = 1 2 Cup flour 4

Question 6 If you walk 5 mile and then jog 1 mile, what is the total distance covered? How much farther 6 5 did you walk than jog? Find the total distance: Now find the difference: 5 6 + 1 5 = 5 5 6 5 + 1 6 5 6 = 25 30 + 6 30 = 31 30 = 1 1 30 5 6 1 5 = 5 5 6 5 1 6 5 6 = 25 30 6 30 = 19 30 5

A perfect square is a number that is a square of a rational number. Examples of Perfect Squares 1 2 = 1 2 2 = 4 3 2 = 9 4 2 = 16 5 2 = 25 6 2 = 36 7 2 = 49 8 2 = 64 9 2 = 81 10 2 = 100 11 2 = 121 12 2 = 144 13 2 = 169 14 2 = 196 15 2 = 225 16 2 = 256 17 2 = 289 18 2 = 324 19 2 = 361 20 2 = 400 Question 7 Evaluate the expression. 169 169 = 13 Question 8 Simplify: ( 4x 5 y 7 )(5x 1 y) ( 4x 5 y 7 )(5x 1 y) = 20x 5+( 1) y 7+1 = 20x 4 y 6 = 20x4 y 6 6

Question 9 Write the number in decimal notation without using positive exponents. Move the decimal point two places to the left. Question 10 3.85 10 2 3.85 10 2 = 0.0385 Express the number in scientific notation. 0.00000293 Move the decimal point 6 places to the right. Question 11 0.00000293 = 2.93 10 6 Write the first six terms of the arithmetic sequence with the first term, a 1, and common difference, d. a 1 = 200, d = 20 a 1 = 200 a 2 = 200 + 20 = 220 a 3 = 220 + 20 = 240 a 4 = 240 + 20 = 260 a 5 = 260 + 20 = 280 a 6 = 280 + 20 = 300 7

Question 12 Write the first six terms of the geometric sequence with the first term, a 1, and common ratio, r. a 1 = 3, r = 2 a 1 = 3 a 2 = 3 ( 2) = 6 a 3 = 6 ( 2) = 12 a 4 = 12 ( 2) = 24 a 5 = 24 ( 2) = 48 a 6 = 48 ( 2) = 96 Question 13 Find the prime factorization of 120 of the composite number. You must write 120 as a product using only prime numbers. So, start dividing it by 2, 2, 2, 3, and then 5. The prime factorization of 120 is: 2 3 3 5 8

Finding the Greatest Common Divisor Using Prime Factorizations To find the greatest common divisor of two or more numbers, 1. Write the prime factorization of each number. 2. Select each prime factor with the smallest exponent that is common to each of the prime factorizations. 3. Form the product of the numbers from step 2. The greatest common divisor is the product of these factors. Question 14 Find the Greatest Common Divisor of 120 and 45. Find the prime factorization for each number. 120 = 2 3 3 5 45 = 3 2 5 Now choose only the numbers that you see in both factorizations with their smallest exponents (I see 3 and 5 in both factorizations) and multiply them: GCD = 3 5 = 15 So 15 is the largest number that goes into both 120 and 45. 9

Question 15 A store owner wishes to stack books into equal piles, each pile containing only one title. There are 39 books of one title and 91 books of another title in the shipment. What is the largest number of books that can be stacked in each pile? Find the prime factorization of each number. 39 = 3 13 91 = 7 13 The largest number that goes into both 39 and 91 is 13. So, the largest number of books that can be stacked in each pile is 13 books. Question 16 Insert < or > in the area between the integers to make the statement true. 23 15 23 < 15 because on the number line, -23 is to the left of -15. Absolute Value The absolute value of an integer a, denoted by a, is the distance from 0 to a on the number line. Because absolute value describes a distance, it is never negative. Examples: 4 = 4 4 = 4 4 = 4 4 = 4 10

Question 17 Find the absolute value. 10 10 = 10 Rules for Addition of Integers Rule If the integers have the same sign, 1. Add their absolute values. 2. The sign of the sum is the same as the sign of the two numbers. If the integers have different signs, 1. Subtract the smaller absolute value from the larger absolute value. 2. The sign of the sum is the same as the sign of the number with the larger absolute value. Example 3 + 5 = 8 3 + ( 5) = 8 12 + 5 = 7 12 + ( 5) = 7 Rules for Multiplying Integers Rule The product of two integers with different signs is found by multiplying their absolute values. The product is negative. The product of two integers with the same sign is found by multiplying their absolute values. The product is positive. Examples 7( 5) = 35 7(5) = 35 4 5 = 20 ( 4)( 5) = 20 The product of 0 and any integer is 0. 7(0) = 0 If no number is 0, a product with an odd number of negative factors is found by multiplying absolute values. The product is negative. If no number is 0, a product with an even number of negative factors is found by multiplying absolute values. The product is positive. ( 2)( 4)( 5) = 40 2(4)( 5) = 40 11

Rules for Dividing Integers Rule The quotient of two integers with different signs is found by dividing their absolute values. The quotient is negative. Examples 80 4 = 20 15 5 = 3 The quotient of two integers with the same sign is found by dividing their absolute values. The quotient is positive. Zero divided by any nonzero integer is zero. 27 9 = 3 45 3 = 15 0 5 = 0 (because 5(0) = 0) Division by 0 is undefined. 7 is undefined 0 (because 0 cannot be multiplied by an integer to obtain 7) Question 18 Add. 1 + ( 7) 1 + ( 7) = 6 Question 19 Subtract. 12 15 12 15 = 27 12

Question 20 Evaluate the exponential expression. 5 2 5 2 = 5 5 = 25 Question 21 Evaluate the exponential expression. ( 5) 2 ( 5) 2 = ( 5)( 5) = 25 Order of Operations 1. Perform all operations within grouping symbols. 2. Evaluate all exponential expressions. 3. Do all multiplications and divisions in the order in which they occur, working from left to right. 4. Finally, do all additions and subtractions in the order in which they occur, working from left to right. Question 22 Use the order of operations to find the value of the expression. 9 4(8 6) 10 9 4(8 6) 10 = 9 4(2) 10 = 9 8 10 = 9 13

Question 23 Use the order of operations to find the value of the expression. 4( 5) 2 5( 3) 2 4( 5) 2 5( 3) 2 = 4(25) 5(9) = 100 45 = 55 Question 24 Reduce the rational number to its lowest terms. 12 18 Divide the numerator and the denominator by 6. 12 6 18 6 = 2 3 Converting a Positive Mixed Number to an Improper Fraction 1. Multiply the denominator of the rational number by the integer and add the numerator to this product. 2. Place the sum in step 1 over the denominator in the mixed number. Question 25 Convert the mixed number to an improper fraction. 4 3 5 4 3 5 = 4 5 + 3 5 = 23 5 14

Question 26 Express the rational number as a decimal. 3 8 You can use long division or you can use a calculator. 3 8 = 0.375 Question 27 Perform the indicated operations. Where possible, reduce the answer to the lowest terms. ( 2 9 ) ( 7 8 ) Simplify first, by dividing 2 and 8 by 2. Then multiply the numerators together, and the denominators together. Dividing Rational Numbers ( 2 9 ) ( 7 8 ) = ( 1 9 ) ( 7 4 ) = 7 36 The quotient of two rational numbers is the product of the first number and the reciprocal of the second number. If a b and c d are rational numbers and c d is not 0, then a b c d = a b d c = a d b c 15

Question 28 Perform the indicated operations. Where possible, reduce the answer to the lowest terms. 3 8 4 9 3 8 4 9 Question 29 = 3 8 9 4 = 27 32 Find the indicated term for the arithmetic sequence with first term, a 1, and common difference, d. Find a 6, when a 1 = 13, d = 4. Use formula: a n = a 1 + (n 1)d a 6 = 13 + (6 1) 4 = 13 + 5 4 = 13 + 20 = 33 16

Question 30 Find the indicated term for the geometric sequence with the first term, a 1, and the common ratio, r. Find a 6, when a 1 = 18, r = 2. Use the formula a n = a 1 r n 1 a 6 = 18 ( 2) 6 1 = 18 ( 2) 5 = 18 ( 32) = 576 17