Teflon lid. O ring. Catalyst. Catalyst Chamber. Electrolyte (H 2 SO 4 + de-ionized H 2 0)

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Transcription:

Pt lead wires Pt lead wires Teflon lid Teflon lid O ring O ring Catalyst Chamber Catalyst (0.5% Pd on Al 2 O 3 pellets) Catalyst Chamber Catalyst (0.5% Pd on Al 2 O 3 pellets) 50mm Electrolyte (H 2 SO 4 + de-ionized H 2 0) Electrolyte (H 2 SO 4 + D 2 0) Pt electrodes Pt electrode Pd electrode

Pt Flow from positive to negative O 2- SO 4 2- H + D + Pd H 2 SO 4 is mixed with H 2 0, and H 2 0 is ionized Electric current flows through and splits water Oxygen goes to Platinum anode Hydrogen goes to Palladium cathode Some hydrogen is absorbed into Palladium s face center cubic structure, called interstitial solid solution Rest of hydrogen turns into gas and rises Oxygen turns into gas and rises O 2 and H 2 rise to catalyst (0.5% Pd on Alumina pellets) and recombines to form H 2 0. Electrolyte contains: Hydrogen ions goes to cathode (right) Deuterium ions Oxygen ions Sulfate ions goes to anode (left)

Palladium Hydrogen Palladium s face center cubic structure allows hydrogen's to be absorbed into spaces in its crystal lattice.

The final setup Many changes made throughout summer: Changes in methods of temperature readings Current Power supplies

Pd before electrolysis Pd after electrolysis and polarity reversal. The cathode has grown a beard

Power Input vs. Time (7/22/03) There is more power going into the C cell Power Input (watts) 12.8 12.6 12.4 12.2 12 11.8 11:00 12:12 13:24 14:36 15:48 17:00 Time Cell C2 Cell S3 Temperature vs. Time (7/22/03) Temperature (c) 45 40 35 30 25 20 11:00 12:12 13:24 14:36 15:48 17:00 Time but the S cell is has an equal or higher temperature. Cell C2 Cell S3 Ambient

dh e = 223.699 * W e dt Time (min) dh c = 207.477 * W c dt Time (min) dh e = T e (V c * I -dh c ) + (dh e -V e * I ) dt (excess) T c dt dt dh c = watts lost from mass in control cell dh e = watts lost from mass in experimental cell W = change in mass T = change in temperature V * I = power input

Excess heat and transmutation are both evidence of Cold Fusion The SEM is used to search for evidence of transmutation. Using two programs, X-X Ray Analysis and AutoImaging, we can detect just how much and exactly where transmutation has occurred.

Liquid Nitrogen Tank Electron Gun and Chamber X-Ray detectors Sample Holder Viewing Screen

Uses high energy electron beam to detail the sample. The electron beam comes from a filament. Voltage is applied to the filament and the corresponding anode helps create a powerful attractive force for the electrons. This causes the electrons to accelerate down towards the anode. Some however, go right by the anode and down into the sample to read and classify it.

Near the bottom, a set of scanning coils moves the focused beam back and forth across the specimen, row by row. As the electron beam hits each spot on the sample, secondary electrons are knocked loose from its surface. A detector counts these electrons and sends the signals to an amplifier. The final image is built up from the number of electrons emitted from each spot on the sample.

Inside of the SEM s sample chamber Undersea saltwater Plankton Unknown metal samples Liverwort

Silver was found here. A sample of our cathode where silver was found. Transmutation is the transformation of one element into another by one or a series of nuclear reactions. Biological transmutation has also been noted. Isotopic transmutation has also been noted -- i.e., it stays the same element, but has a different nuclear mass.

electron nucleus Pd+n 109 Pd, 108 Pd+n then 109 Pd 109 109 Pd, 109 Ag + β This is a palladium atom. Its electron structure is quite large and transmutation occurs when an electron leaves the nucleus (or a neutron becomes a proton).

Program that locates and labels various elements and isotopes in a sample. Top graph shows evidence of silver, whereas the bottom graph does not; it does show many other elements though.

PdLα PdLβ Presence of transmutated silver (Ag) is measured by a PdLβ/PdL /PdLα ratio. Sample Calculation of PdLβ/PdL /PdLα α If PdLb is 3.8cm, and PdLa is 5.1cm, 3.8 / 4.7 = 74.5% 74.5% > 40.0% YES!

Non-metallic, non-conductive object. Collects electrons but can t release them so it becomes very bright. The SEM can take pictures at multiple magnifications, but sometimes it is necessary to just get one large overall shot of the metal from which you can then go off of. This is a Palladium cathode from a very similar experiment. We were unable to analyze ours because we ran out of time because we had run the experiment so long.

This is an original image of one of the Palladium cathodes we analyzed. It has been imaged at three different magnifications and each time, the small red square is what we were looking at. 0.0x mag 910x mag 1300x mag

While we are no closer to solving the mystery of cold fusion, transmutation will play a definite role in solving this puzzle.

We consistently had excess heat and we also discovered evidence of transmutation. Overall, we had a relatively successful experiment, and as the mystery m of Cold Fusion slowly unravels, we hope to one day see just how our research has turned out. Thanks for everything Dr. Dash!

Dr. John Dash, Mentor Abhay Ambadkar, Co-mentor Portland State University Apprenticeships in Science and Engineering program, with funding provided by the Academy of Applied Science s REAP Program and the Engineering and Technology Industry Council