Economics 620, Lecture 15: Introduction to the Simultaneous Equations Model

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Transcription:

Economics 620, Lecture 15: Introduction to the Simultaneous Equations Model Nicholas M. Kiefer Cornell University Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 1 / 16

The statistics framework for the simultaneous equations model (SEM) is the multivariate regression. For example, let E(yjX ; ) = X and V (yjx ; ) = P where y: 2 1 P X : 3 1 : 2 3 : 2 2: There are really 5 variables (y; X ) but we condition on X. modelling choice. This is a Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 2 / 16

Suppose y = (q; p), a quantity and a price, and X = (x 1 ; x 2 ; x 3 ) where x 3 = 1 with Eq = 11 x 1 + 12 x 2 + 13 and (I ) Ep = 21 x 1 + 22 x 2 + 23 : Perhaps, x 1 is weather and x 2 is income and we are modeling an agricultural market. Economically, q S = 11 p + 11 x 1 + 13 q D = 21 p + 22 x 2 + 23 q S = q D : 9 = ; (II ) This is more natural - a demand and supply equation and an equilibrium condition determining q and p. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 3 / 16

De nition: De nition: Equation system (II) is the structural form. Multivariate regression (I) is the reduced form. Note: Restrictions on structure like 12 = 0, impose nonlinear restrictions on the reduced form. The reduced form model achieves the reduction in data dimension possible through statistical modeling. Thus, a reduced form parametrization is in 1 1 correspondence with the su cient statistic. Additional reduction in dimension is possible with the use of theoretical models; these lead to structural models (or structural parametrizations). Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 4 / 16

Indirect Least Squares: Solving the structure for p and q yield q = 11 21 11 21 x 1 11 22 11 21 x 2 + 11 23 21 13 11 21 p = 11 11 21 x 1 22 11 21 x 2 + 23 13 11 21 : These equations determine in terms of and. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 5 / 16

Given 12 11 = ; 21 = 11 ; 22 21 11 = 21 ( 11 21 ), etc. There are 6 elements of and 6 and. Thus, can be estimated by the LS method and we can solve for and. This is the Indirect Least Squares method. Why not estimate 11, 11 and 13 by regressing q on p and x 1? Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 6 / 16

Identi cation: Underidenti cation: Suppose 22 = 0. Then q = 11 x 1 + 13 p = 21 x 1 + 23 is the implied reduced form. Then the 4 reduced form parameters determine 12 and 23 (the demand curve) but no more. This supply curve is underidenti ed. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 7 / 16

Overidenti cation: Suppose we still have 22 = 0 and 12 6= 0. Then q S = 11 p + 11 x 1 + 12 x 2 + 13 q D = 21 p + 21 x 1 + 22 x 2 + 23 q S = q D : In reduced form, q = 11 21 x 1 + 12 21 x 2 + constant 11 21 11 21 p = 11 x 1 + 12x 2 + constant. 11 21 12 11 Now 21 = 11 = 21 = 12 = 22. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 8 / 16

If is esimated, the 2 estimates of 21 will not usually be equal. case, 21 is overidenti ed. In this It is natural to estimate 21 by a weighted average. The whole point of SEM estimation is nding the right weights to use to combine the reduced form estimates. Underidenti caiton as (exact) collinearity: q S = 11 p + 11 x 1 + 13 (underidenti cation) q D = 21 p + 23 (identi cation) q S = q D Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 9 / 16

The weighted average of q S and q D is q = ( 11 + (1 ) 21 )p + 11 x 1 + 13 + (1 ) 23. This is indistinguishable from q S when parameters are unknown. The point is that if we t an equation like q S, we can t say what the paremeters are other than a mix of demand and supply parameters. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 10 / 16

Classical identi cation conditions: First, restrict attention to a 2-equation system. Make a table of which variables are in which equations. following table does this for the original model: For example, the q p x 1 x 2 constant q S p p p p q D p p p p Order condition: There is at least one blank space in the row of the identi ed equation. This is a necessary condition. Rank condition: The variable left out of the equation considered must appear in the other. This is a necessary condition. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 11 / 16

The order condtion and the rank condition together are both necessary and su cient. Note that we are considering only the class of exclusion restrictions on the structure. Rank and order condition are not necessary when broader restrictions are permitted. Consider the identi cation of the rst equation in the following G-equation table. Note that y is G 1 and X is K 1. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 12 / 16

Eq.1 Eq.2...... Eq. G y 1 y 2...... y G x 1 x 2...... x p p p p K A 1 A 2 Order condition: If the number of blank spaces in row 1 is greater than or equal to the number of endogenous variables minus one (i.e., G 1), then equation 1 is identi ed. (Why?) Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 13 / 16

Rank condition: The matrix formed by taking coe cients corresponding to blanks in row 1, that is, the matrix has rank G 1. Other sources of identi cation: A = [A 1.A 2.?], Consider the following structural model: q S = 11 p + 11 x 1 + 13 + u q D = 21 p + 23 + v q S = q D. Assume that Euv = 0. Note that this is a restriction. Assume further that Eu = Ev = 0, Eu 2 = 2 u and Ev = 2 v. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 14 / 16

Consider the following equation: q = ( 11 + (1 ) 21 )p + 11 x 1 + constant +u + (1 )v q = 11 p + 11 x 1 + constant +u. This equation is distinguishable from q S since u is correlated with v for 6= 1. In reduced form: q = 11 x 1 + 12 + W 1 p = 21 x 1 + 22 + W 2 W 1 = ( 21 u 11 v)=( 21 11 ) W 2 = (u v)=( 21 11 ). Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 15 / 16

Now can be estimated by the LS method and so can EW 2 1 = 11 = ( 2 21 2 u + 11 2 v )=( 21 11 ) 2 EW 2 2 = 22 = ( 2 u + 2 v )=( 21 11 ) 2 EW 1 W 2 = 12 = ( 21 2 u + 11 2 v )=( 21 11 ) 2. These equations and our earlier formulas can be used to solve for all the structural parameters. Note that the rank and order conditions are not satis ed, illustrating that the conditions are not necessary once the set of allowable restrictions is expanded. Professor N. M. Kiefer (Cornell University) Lecture 15: SEM I 16 / 16