Solving Equations. Examples

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Solving Equations Solving an equation means figuring out what value the variable represents. Recall that variables are letters or symbols used to represent unknown numbers. There are several different ways to solve equations, including the guess and check method, and paper and pencil method. Examples A) 7 + n = 12 Guess and check method: 7 + 0 = 7 7 + 1 = 8 7 + 2 = 9 7 + 3 = 10 7 + 4 = 11 7 + 5 = 12 Paper and pencil method: 7 + n = 12 n = 12 7 n = 5 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 1/14

B) Mike and a friend are getting together for a movie marathon weekend. Mike has coupons to rent 8 free movies, and together they have enough coupons to rent 13 movies. How many coupons does Mike s friend have? Set up an equation: 8 + n = 13. Solve for n. Guess and Check Method: 8 + n = 13 Think: 8 + 1 = 9 8 + 2 = 10 8 + 3 = 11 8 + 4 = 12 8 + 5 = 13 8 + 5 = 13, n = 5 Pencil/Paper Method: 8 + n = 13 8 8 + n = 13 8 n = 13 8 n = 5 Check: 8 + 5 = 13, 13 = 13 The steps for solving different kinds of equations using the paper and pencil method are described on the following pages. Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 2/14

Solving Type 1 Equations Addition Goal: find the missing number (x) in the equation. To figure out what the missing number is, you have to change the equation so it ends up looking like: x = number To do that, get rid of all of the numbers on the left side except one x: Example x + 8 = 33 is the same as writing? + 8 = 33 or + 8 = 33 To get rid of a number that is added, just do the opposite subtract it again! x + 8 = 33 8 = 8 Remember, just like in fractions, whatever you do on one side of the = sign, you have to do on the other side. x + 8 = 33 8 = 8 25 x = 25 On the left side, the numbers cancel themselves out, leaving only one x that s your goal! Check your Work Put the missing number (what x is) into the original equation and solve it make sure the answer is the one they gave you in the first equation. x + 8 = 33 25 + 8 = 33 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 3/14

Solving Type 1 Equations Subtraction Goal: find the missing number (x) in the equation. To figure out what the missing number is, you have to change the equation so it ends up looking like: x = number To do that, get rid of all of the numbers on the left side except one x: Example x 9 = 13 is the same as writing? 9 = 13 or 9 = 13 To get rid of a number that is subtracted, just do the opposite add it back! x 9 = 13 +9 =+9 Remember, just like in fractions, whatever you do on one side of the = sign, you have to do on the other side. Check your Work x 9 = 13 +9 =+9 x = 22 On the left side, the numbers cancel themselves out, leaving only one x that s your goal! Put the missing number (what x is) into the original equation and solve it make sure the answer is the one they gave you in the first equation. x 9 = 13 22 9 = 13 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 4/14

Type 1 Equations Multiplication Goal: find the missing number (x) in the equation. 6x = 24 is the same as writing? 6 = 24 or 6 = 24 To figure out what the missing number is, you have to change the equation so it ends up looking like: x = number Example To do that, get rid of all of the numbers on the left side except one x: To get rid of a number that is multiplied, just do the opposite divide it again! Check your Work 6x = 24 6 6 6x = 24 6 6 x = 4 Remember, just like in fractions, whatever you do on one side of the = sign, you have to do on the other side. On the left side, the numbers cancel themselves out, leaving only one x that s your goal! Put the missing number (what x is) into the original equation and solve it make sure the answer is the one they gave you in the first equation. 6x = 24 6(4) = 24 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 5/14

Type 1 Equations Division Goal: find the missing number (x) in the equation. x = 10 is the same as writing? 9 = 10 or 9 = 10 9 To figure out what the missing number is, you have to change the equation so it ends up looking like: x = number Example To do that, get rid of all of the numbers on the left side except one x: To get rid of a number that is divided, just do the opposite multiply it again! 9 x 9 = 10 9 9 x 9 = 10 9 x = 90 Remember, just like in fractions, whatever you do on one side of the = sign, you have to do on the other side. On the left side, the numbers cancel themselves out, leaving only one x that s your goal! Check your Work Put the missing number (what x is) into the original equation and solve it make sure the answer is the one they gave you in the first equation. x 9 = 10 90 9 = 10 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 6/14

Type 2 Equations Goal: find out what the missing number (x) in the equation is. The goal is the same as it was for type one equations, but there is one more step to do to get the answer. The good news is, after that first extra step, the equation becomes just like a type one again. So type 2 equations become type 1 equations, and you already know how to do those! 5x 7 = 8 Notice that this equation involves multiplication and subtraction. That s why there s an extra step. To figure out what the missing number is, you have to change the equation so it ends up looking like: x = number Example To do that, get rid of all of the numbers on the left side except one x: Start with the regular numbers (those without the x) because they re just easier! Now we re back to a type one equation phew! 5x 7 = 8 + 7 + 7 5x 7 = 8 + 7 + 7 5x = 15 Remember, just like in fractions, whatever you do on one side of the = sign, you have to do on the other side. On the left side, the numbers cancel themselves out, leaving 5x you re getting close! 5x 5 = 15 5 Check: x = 3 Finished! 5x 7 = 8 5(3) 7 = 8 15 7 = 8 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 7/14

Example x 8 + 3 = 12 Notice this equation involves division and addition and that s why there s an extra step. Get rid of all of the numbers on the left side except one x: Start with the regular numbers (those without the x) because they re just easier! x 8 + 3 = 12 Remember, just like in fractions, whatever you do on one side of the = sign, you have to do on the other side. Now we re back to a type one equation phew! x 8 x 8 + 3 = 12 3 3 = 9 On the left side, the numbers cancel themselves out, leaving x divided by 8 you re getting close! 8 x = 9 8 8 x = 72 Finished! Check: x 8 + 3 = 12 72 8 + 3 = 12 9 + 3 = 12 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 8/14

Type 3 Equations Goal: find the missing number (x) in the equation. The goal is the same as it was for type one and two equations, but there is one more step to do to get the answer. So type 3 equations eventually become type 1 equations, and you already know how to do those! 4x + 3x = 7 Notice this equation has more than one number with an x beside it and that s why there s an extra step. To figure out what the missing number is, you have to change the equation so it ends up looking like: x = number Begin by figuring out how many xs there are altogether: Example Now we re back to a type one equation phew! 4x + 3x = 7 7x = 7 7x 7 = 7 7 Add up all of the x s. x = 1 Finished! Check: 4x + 3x = 7 4(1) + 3(1) = 7 4 + 3 = 7 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 9/14

Example 9x + 2 = 5x + 30 Notice this equation has numbers with x s on both sides of the = sign and that s why there s an extra step. Begin by getting all of the xs on the same side of the = sign: 9x + 2 = 5x + 30 5x 5x 4x Remember, just like in fractions, whatever you do on one side of the = sign, you have to do the same on the other side. Now we re back to a type two equation phew! Now we re back to a type one equation phew! 4x + 2 = 30 2 2 28 4x = 28 4 4 On the right side, the numbers cancel themselves out, leaving x divided by 8 you re getting close! x = 7 Finished! Check: 9x + 2 = 5x + 30 9(7) + 2 = 5(7) + 30 63 + 2 = 35 + 30 65 = 65 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 10/14

Practice: Solving Equations 1. Use the guess and check method and the paper/pencil method to solve the following. Harnaik gets 100 free minutes of Internet time per month. He has already used 64 minutes. How many minutes does he have left? Write out an equation: Guess and Check Method Think: 64 + 1 = (your answer is way off pick a larger number) 64 + 10 = (you are still way off) 64 + 25 = (you are getting closer) 64 + 35 = (very close) 64 + = 64 + = 100 Harnaik has minutes of free Internet time left. Pencil/Paper Method Known information: Harnaik gets 100 minutes of Internet time. He has used 64 minutes. What is being asked? How much Internet time does Harnaik have left? Let m be Minutes he has left. 64 + m = 100 64 + m = 100 m = 100 m = Harnaik has minutes of free Internet time left. Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 11/14

2. Jules is helping organize a volleyball tournament. He calls 5 of his friends and has 8 friends left to call. How many friends did Jules call in total? Let = the number of friends Jules called in total. Solve for. n = 8 + 5 Jules called friends. Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 12/14

3. Balance the equations using a variety of methods, such as pencil and paper, and diagrams. a) + 6 = 13 b) 7 + = 17 c) 2 + 9 = d) + 12 = 15 e) 14 9 = f) 8 = 3 g) 13 = 6 h) 20 8 = i) 9 2 = 6 j) 4 8 = 3 + 2 k) 30 6 = 20 l) 56 7 = 2 Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 13/14

4. Solve for x in the following equations. a) x + 5 = 24 x = b) 4 + x = 19 x = c) x 10 = 12 x = d) 32 x = 15 x = e) x + 7 = 34 x = f) x 14 = 3 x = g) x + 45 = 126 x = h) 37 + x = 213 x = i) x 47 = 56 x = j) 327 x = 68 x = k) x + 239 = 547 x = l) x 159 = 218 x = 5. Solve for x in the following equations. a) 4x = 36 x = b) 2x = 56 x = c) 3x = 21 x = d) 8x = 56 x = e) 12x = 144 x = f) 15x = 210 x = g) 5x 7 = 8 x = h) 4x 6 = 38 x = i) 3x + 9 = 27 x = j) 7x + 12 = 47 x = k) 21 + 6x = 75 x = l) 8x 24 = 136 x = Alberta Education, Alberta, Canada (www.learnalberta.ca) Solving Equations 14/14