Oscillations. The Force. The Motion

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Team Oscillations Oscillatory motion is motion that repeats itself. Oscillations are everywhere: guitar string, pendulum, piston, neutron star (pulsar), drumhead, nuclear magnetic resonance (NMR), alternating current, neutrino oscillations, electron cloud in an atom, vibration of atoms in a solid (heat), vibration of molecules in air (sound), vibration of electric and magnetic fields in space (light), and the oscillating universe (big bang-big crunch). The Force The dynamical trademark of all oscillatory motion is that the net force causing the motion is a restoring force. If the oscillator is displaced away from equilibrium in any direction, then the net force acts so as to restore the system back to equilibrium. Definition: A simple harmonic oscillator is an oscillating system whose restoring force is a linear force a force F that is proportional to the displacement x : F = kx. The force constant k determines the strength of the force and measures the springiness or elasticity of the system. Slinkys, long pendula, and loose drumheads have small k values. Car coils, short pendula, and tight drumheads have large k values. The Motion The motion of all mechanical systems is determined by Newton s law of motion F = ma. For any simple harmonic oscillator system, characterized by mass m and force constant k, the equation of motion is kx = ma, or a = (k/m) x. The solution of this equation of motion is x(t) = A sin k m t. To see that this is the solution, note that the second derivative of x(t) with respect to time, which is the acceleration a(t), is equal to (k/m) x(t). The ratio of the inertia (m) of the system to the elasticity (k) of the system has units of [seconds] 2 and sets the scale of time for all simple harmonic motion. It follows from this sinusoidal x(t) function that the period of the motion the time required to complete one oscillation is T= 2π m / k.

Summary: The Essence of Simple Harmonic Motion IF the force acting on mass m has the linear (simple) form: THEN the motion of the mass will be sinusoidal (harmonic): F = kx x = Asin(2πt/T) AND the period T depends solely on the mass/force ratio: T= 2π m / k Part I. The Pendulum Oscillator A simple pendulum consists of a mass m suspended from a lightweight cord of length L in a gravitational field g, A. Galileo s Discovery Galileo made the first quantitative observations of pendulum motion in 1583 by observing the swing of a chandelier hanging from the cathedral ceiling in Pisa, Italy. He used his pulse to measure the period. His observations and theory led to the construction of the first pendulum clock by Christiaan Huygens in 1650. The Galilean Question: How does the period T of a pendulum the time required to complete one back and forth swing depend on 1. The size s of the arc? 2. The mass m of the weight? 3. The length L of the cord? θ L m For example, if a pendulum takes 1 sec to swing through a 10 cm arc, then shouldn t the same pendulum take 2 sec to swing through a 20 cm arc? In Experiments 1, 2, and 3, you will discover the answers to Galileo s questions. *Apparatus Note: To set the length of the pendulum, simply slide the string between the metal brackets until you achieve the desired length and then tighten the screw. No need to cut string. Experiment 1. Quadruple the Size of the Arc Construct a pendulum with m = 200 grams and L = 1.0 meter. Remember to measure L from the pivot point to the center of mass of the weight. Pull the pendulum sideways so the cord makes an angle θ with the vertical and release. Use a stopwatch to measure the period T for θ = 5 o and 20 o. For accuracy, measure the time for five back-and-forth swings and then divide by five to get the period. Results: s Conclusion: 2

Experiment 2. Quadruple the Mass of the Weight Keep L = 1.0 meter. Measure T for m = 100 grams and 400 grams. Results: Conclusion: Experiment 3. Quadruple the Length of the Cord. Keep m = 200 gram. Measure T for L = 1/4 meter and 1 meter. Results: Which formula best fits your experimental result on the relation between period and length: T L T 1/L T L 1/2 T L 3/4 T L 2 Justify your formula selection: B. The Springiness of a Pendulum Finding the force constant of an oscillatory system is an important quest for scientists and engineers. If you know the k value of a system, then you know almost everything about the system! Measure k. Here you will measure the force constant k of a pendulum. Construct a pendulum of mass m = 200 grams and length L = 1.0 meter. Lay the meter stick on the table. The mass should hang directly above and almost touch the stick. Use a spring scale (properly zeroed in the horizontal direction) to displace the mass a distance x = 5 cm away from its equilibrium position. While you keep the mass at rest in its displaced position at 5 cm, read the value of the force F on the scale. Since the mass is at rest, the restoring force of gravity pulling the mass back to equilibrium is equal and opposite to the pulling force of the scale. Repeat for x = 10 cm and x = 15 cm. For each displacement x, record the corresponding force F: x (m) 0.05 0.10 0.15 F (N) F x 3

According to the theoretical definition of simple harmonic oscillator on page 1, is your pendulum a simple harmonic oscillator within experimental error? Carefully explain your answer. What is the force constant k that characterizes the springiness of your pendulum? k = N/m. What is the m-over-k parameter of your pendulum? m/k =. (Don t forget to state the units) Compute T. Use your measured m/k parameter to calculate the period T of your pendulum according to the theoretical m/k formula derived in the introduction. T theory = seconds. In part A, you directly measured the period of a pendulum (m = 0.20 kg, L = 1.0 m) using a stopwatch. Compare this measured value with your calculated value T theory. C. The Famous L over g Formula for a Pendulum The formula that reveals how the period T of a simple pendulum depends on its length L (for small arcs) is This pendulum formula is a special case of the general formula: This m/k formula is valid for ALL harmonic oscillators. T = 2π L g In order to derive the L/g formula from the m/k formula, what must be the force constant k of a pendulum in terms of m, L, and g? k =. Show that this theoretical expression for k is consistent with your measured value of k in part B.. T = 2π m k. 4

Part II. The Mass-Spring Oscillator Suspend the 50-gram weight hanger from the end of the narrow silver spring. Place the 100-gram slotted brass cylinder on the hanger platform. Place the motion sensor on the table directly under the oscillator. The distance between the sensor and the resting oscillator should be about 25 cm. Open Logger Pro file DisVelAcc. With the mass in the resting (equilibrium) position, zero the motion sensor by clicking Experiment on the menu bar and selecting Zero. Pull the mass about 10 cm away from the equilibrium position (x = 0) and release. Record the oscillations with the motion sensor. If needed, change the scales on your graph so that you can clearly see the sinusoidal variations. 50 gram Weight Hanger 100 gram Slotted Brass Cylinder Motion Sensor A. x(t) and a(t) are In Sync. Finding T from x(t) /a(t). According to the motion equation on page 1, the kinematic trademark of simple harmonic motion is that the position x(t) and the acceleration a(t) are proportional to each other, and opposite in direction, for all time t: a(t) = ω 2 x(t). The proportionality constant between a(t) and x(t) is the square of the angular frequency ω = 2π/T of the system. When x is zero, a is zero. When x is maximum (minimum), a is minimum (maximum). Note that the velocity is completely out of sync (out of phase) with x and a. When x is zero, v is max. Examine your graphs to be a first-hand witness to this in-sync dance between x and a. Do your x(t) and a(t) curves satisfy the motion equation a(t) = ω 2 x(t)? Change the time scale to go from 0 to 3 s. Use the Examine Icon [x =?] to find the values of x(t) and a(t) at the six times t = a, b, c, d, e, f shown below. Any six points that are approximately equally-spaced within one period of the sine curve are perfectly fine. a b c d e f time Record your measured values of x and a along with the ratio x/a in the following table: 5

t x(t) (m) a(t) (m/s 2 ) x(t) / a(t) (s 2 ) a b c d e f According to the theory, x(t) and a(t) both vary in time, but the ratio x(t)/a(t) is independent of t! Your experimental data should support this theoretical fact. Based on your data, what is the constant value of x(t)/a(t) that characterizes your mass-spring system? x(t) / a(t) = ± s 2. Calculate the period T of your oscillator from your measured value of x(t)/a(t). Remember, a(t) = ω 2 x(t) and ω = 2π/T. Show your calculation. T = s. B. Finding T from m/k The mass of your mass-spring system is m = 0.150 kg Measure the force constant k of the system: hang a weight (F) from the spring and measure the stretch (x). Report your k value. Find the m-over-k value of your oscillator. k = N/m. m/k = s 2. Calculate the period of your oscillator from your measured value of m/k. Show your calculation. C. Summary T = s. You have measured the period of a mass-spring oscillator using two different methods. As a third method, measure the period directly with a stopwatch. Summarize your results by listing all three of your T-values below. Motion Method. Measure x(t) and a(t), compute x(t)/a(t) : T = s. Force Method. Measure m and k, compute m/k : T = s. Timing Method. Measure time directly with clock : T = s. 6

Part III. Damped Oscillator So far, we have neglected the effect of friction on the motion. In physics, an oscillator subject to friction is called a damped oscillator. Friction causes the motion to decay. The amplitude of the oscillations decreases as time goes on. In this experiment, you will study the effect of air friction on the motion of your mass-spring oscillator Any object moving through the air experiences a viscous drag force due to the myriad of impacts between the object and the air molecules. As a result of the air-object collisions, the object slows down and the air molecules speed up (the air gets hotter). Mechanical energy of the object is transformed into thermal energy of the air. The System Attach a cardboard surface of area A to your oscillator. Unscrew the bottom disk from the weight hanger rod. Put the rod through the hole in the board. Screw the disk back onto the rod. Place the 100 gram slotted brass cylinder on top of the board. You now have a damped harmonic oscillator. Scientists and engineers use similar models to study the aerodynamic design of cars, planes and rockets, and the hydrodynamic design of ships. A As your oscillator moves up and down, imagine the cardboard surface pushing through the sea of air. The numerous collisions (about 10 22 per second!) between the surface and the air molecules (tiny balls of nitrogen and oxygen) are the mechanical source of the air friction. The Experiment Creating a Work of Graphic Art Place the motion sensor directly under your oscillator. The distance between the sensor and the resting oscillator should be about 25 cm. Open Logger Pro file Damped Oscillator. With the oscillator at rest, zero the motion sensor [click on Experiment and select Zero]. Pull the mass away from the equilibrium position (x = 0) about 10 cm and release. Record the motion x(t). PRINT the graph. Title the graph: Oscillator Art. Look at the worldline graphs generated by other teams to see the effect of different surface areas. On your graph, label the characteristic features of damped harmonic motion that you feel are informative and interesting. 7

Part IV. Design Project Your goal is to design the new Mega Pendulum Ride at Cedar Point so that the riders feel a huge stomach-turning gee-force during the motion. As a prototype, you first design a smallscale model: a pendulum of length L and mass m = 200 grams. The design specs require that the mass experience an acceleration a = 1.5 m/s 2 when it is at a distance x = 0.10 m from equilibrium. Theory 1. Calculate the net force F on the mass when it is at x = 0.10 m. m L x a 2. Calculate the force constant k of the pendulum system. F =. 3. Calculate the length L of the pendulum. k =. L =. Experiment Build the pendulum. Measure the acceleration a at the point x = 0.10 m two different ways: 1. Force Method. Use the force (spring) scale to pull the mass 0.10 m away from equilibrium. Record the force. Compute the acceleration. F =. a =. 2. Motion Method. Use the motion sensor to measure x(t) and a(t) of the pendulum mass. Note: you must orient the sensor to see the horizontal (x) motion of the mass. Open the file Changing Velocity 1. Change the v(t) graph to a(t). Zero the sensor when the pendulum is at rest. Pull the mass to x = 10 cm and release. Use Autoscale to fill your screen with the x and a curves. Print the screen showing both the x and a graphs. Based on your x and a graphs, When x = ± 0.10 m, the corresponding acceleration is a =. Draw a vertical line through the corresponding x and a points on your graph. Conclusion. Based on your experimental results using two methods, how well does your pendulum prototype satisfies the theoretical design specs? 8

Part V. Coupled Oscillators and Normal Modes If you couple together two or more oscillators, then the resulting motion gets very interesting. Many systems in nature (mechanical, electrical, atomic) are coupled oscillators. The concept of a normal mode simplifies the analysis of the motion of coupled oscillators. It allows you to understand complicated non-sinusoidal vibrational motion in terms of a sum or superposition of simple sinusoidal (harmonic) vibrations. The whole motion is broken down into a set of more manageable parts. These simple parts are the normal modes. What exactly is a normal mode? A normal mode is a pattern of vibration in a system of particles in which every particle vibrates sinusoidally with the same frequency f (the amplitude A can be different). Mathematical trademark: The displacement of the n th particle is A n sin2πft. Normal Modes A and B. Examine the coupled pendula system on display in the lab. Note that the spring serves as the coupling mechanism. This system may look simple, but it exhibits a rich variety of motions. There are two normal modes: mode A and mode B. To excite mode A, pull both masses away from the vertical (equilibrium) in the same direction and release at the same time. To excite mode B, pull both masses away from the vertical (equilibrium) in opposite directions and release at the same time. Note that in each normal mode, both masses oscillate with the same frequency. Measure the period T and compute the frequency f of each mode: Mode A Mode B T A = s. T B = s. f A = Hz. f B = Hz. Energy Exchange Motion = Mode A + Mode B. Pull mass 1 away from the vertical (do not touch mass 2) and release. 1 2 Observe this energy exchange motion. Note that the total amount of energy in the system remains constant, but it is constantly being passed between the two pendula. Pendulum 2 speeds up at the expense of pendulum 1 slowing down, and vice versa. The energy sloshes back and forth between the two parts of the system. The spring provides the transfer mechanism. If there were no friction, then this exchange would go on forever! This simple system models the complex energy transfers that occur in nature. 9

Measure the period of the energy exchange, i.e. the time it takes for 2, which starts with zero energy, to gain all the energy from 1, and then give it all back to 1. In other words, find the time it takes for pendulum 2 to complete the cycle rest moving rest. Since the energy exchange motion is a combination of the A and B modes, we will label this motion AB. Report your measured values of the period T AB and frequency f AB of this energy exchange (AB) motion: T AB = s. f AB = Hz. Relation Between f A, f B, f AB. Why is the energy exchange motion a superposition of mode A and mode B? The following picture illustrates how the A and B displacements add to give the energy-exchange displacement: Mode A + Mode B = A+B According to the theory (normal mode analysis), the frequency of the energy-exchange motion (AB) is related in a simple way to the frequency of the constituent modes (A and B): f AB = f B f A. How close (percent difference) do your experimental values of f AB, f B, and f A obey this theoretical relation? Music, Atoms, & Photons. There exists many systems and processes in nature where three frequencies are related via the normal mode rule f AB = f B f A. Most notably are beats in music and photons in quantum mechanics. When two musical notes (sound waves) of slightly different frequency f A and f B are played together (superimposed), the result is a sound wave that pulsates at the frequency f AB = f B f A. When an electron in an atom makes a quantum jump from a high-energy state B, where it orbits at frequency f B, to a low-energy state A where it orbits at frequency f A, the atom emits a light wave of frequency f AB = f B f A. During the quantum jump, the electron is in a superposition of quantum states (modes): state A + state B. In music, the superposition of sound waves results in beats. In quantum mechanics, the superposition of quantum waves results in a photon. One of the great triumphs of quantum mechanics was to discover the precise connection between the orbital frequencies (f A, f B ) of the electron in an atom and the optical frequency (f AB ) of the emitted light. The coupled pendulum system that you studied in this lab provides insight into how two tuning forks make sound (beats) and how two atomic states make light (photons)! 10