7a. Structure Elucidation: IR and 13 C-NMR Spectroscopies (text , , 12.10)

Similar documents
Principles of Molecular Spectroscopy: Electromagnetic Radiation and Molecular structure. Nuclear Magnetic Resonance (NMR)

Infrared Spectroscopy: Identification of Unknown Substances

Lecture 2 nmr Spectroscopy

Chapter 13 Spectroscopy

Introduction. The analysis of the outcome of a reaction requires that we know the full structure of the products as well as the reactants

William H. Brown & Christopher S. Foote

Nuclear Magnetic Resonance (NMR) Spectroscopy Introduction:

Chapter 13: Molecular Spectroscopy

Lecture 11. IR Theory. Next Class: Lecture Problem 4 due Thin-Layer Chromatography

E35 SPECTROSCOPIC TECHNIQUES IN ORGANIC CHEMISTRY

11. Proton NMR (text , 12.11, 12.12)

Nuclear Magnetic Resonance (NMR)

Nuclear Magnetic Resonance H-NMR Part 1 Introduction to NMR, Instrumentation, Sample Prep, Chemical Shift. Dr. Sapna Gupta

Infrared Spectroscopy

Chem 325 NMR Intro. The Electromagnetic Spectrum. Physical properties, chemical properties, formulas Shedding real light on molecular structure:

Unit 11 Instrumentation. Mass, Infrared and NMR Spectroscopy

Radiant energy is proportional to its frequency (cycles/s = Hz) as a wave (Amplitude is its height) Different types are classified by frequency or

Welcome to Organic Chemistry II

- 1/2. = kb o = hνν + 1/2. B o increasing magnetic field strength. degenerate at B o = 0

Chapter 15 Lecture Outline

NMR Spectroscopy. for 1 st B.Tech INTRODUCTION Lecture -1 Indian Institute of Technology, Dhanbad

February 8, 2018 Chemistry 328N

Chapter 14. Nuclear Magnetic Resonance Spectroscopy

William H. Brown & Christopher S. Foote

Química Orgânica I. Nuclear Magnetic Resonance Spectroscopy (I) Ciências Farmacêuticas Bioquímica Química AFB QO I 2007/08 1 AFB QO I 2007/08 2

12. Structure Determination: Mass Spectrometry and Infrared Spectroscopy

3.15 Nuclear Magnetic Resonance Spectroscopy, NMR

Lecture 3 NMR Spectroscopy. January 26, 2016 Chemistry 328N

NMR = Nuclear Magnetic Resonance

Chapter 13. R.F.----µ-wave----I.R. (Heat)------Visible------U.V X-Ray------γ-Ray SPECTROSCOPY. Definition: Types to Be Covered:

16.1 Introduction to NMR Spectroscopy. Spectroscopy. Spectroscopy. Spectroscopy. Spectroscopy. Spectroscopy 4/11/2013

Chapter 12 Mass Spectrometry and Infrared Spectroscopy

NMRis the most valuable spectroscopic technique for organic chemists because it maps the carbon-hydrogen framework of a molecule.

Structure Determination: Nuclear Magnetic Resonance Spectroscopy

4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.

Chapter 14 Spectroscopy

NMR Spectroscopy. Chapter 19

NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY

January 29, 2019 Chemistry 328N

NMR Nuclear Magnetic Resonance Spectroscopy p. 83. a hydrogen nucleus (a proton) has a charge, spread over the surface

Nuclear Magnetic Resonance Spectroscopy

ORGANIC - CLUTCH CH ANALYTICAL TECHNIQUES: IR, NMR, MASS SPECT

Lecture 13 Organic Chemistry 1

4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.

Chapter 16 Nuclear Magnetic Resonance Spectroscopy

Structure Determination

Lecture Notes Chem 51A S. King

ORGANIC - CLUTCH CH ANALYTICAL TECHNIQUES: IR, NMR, MASS SPECT

CHM 223 Organic Chemistry I Prof. Chad Landrie. Lecture 10: September 20, 2018 Ch. 12: Spectroscopy mass spectrometry infrared spectroscopy

Nuclear Magnetic Resonance

Chapter 13 Structure t Determination: Nuclear Magnetic Resonance Spectroscopy

Spectroscopy. Empirical Formula: Chemical Formula: Index of Hydrogen Deficiency (IHD)

The Use of NMR Spectroscopy

Instrumental Chemical Analysis

Chapter 9. Nuclear Magnetic Resonance. Ch. 9-1

SECOND YEAR ORGANIC CHEMISTRY - REVISION COURSE Lecture 2 MOLECULAR STRUCTURE 2: SPECTROSCOPIC ANALYSIS

HWeb27 ( ; )

ORGANIC - BRUICE 8E CH MASS SPECT AND INFRARED SPECTROSCOPY

Increasing energy. ( 10 4 cm -1 ) ( 10 2 cm -1 )

Infrared Spectroscopy An Instrumental Method for Detecting Functional Groups

CHEM 3.2 (AS91388) 3 credits. Demonstrate understanding of spectroscopic data in chemistry

NUCLEAR MAGNETIC RESONANCE AND INTRODUCTION TO MASS SPECTROMETRY

Nuclear Magnetic Resonance Spectroscopy: Tools for Structure Determination

4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.

Nuclear magnetic resonance spectroscopy

Structure Determination. How to determine what compound that you have? One way to determine compound is to get an elemental analysis

NMR spectra of some simple molecules. Effect of spinning: averaging field inhomogeneity (nmr1.pdf pg 2)

Department of Chemistry SUNY/Oneonta. Chem Organic Chemistry I

Spectroscopy and Chromatography

ORGANIC - BROWN 8E CH INFRARED SPECTROSCOPY.

CHAPTER 8 ISOLATION AND CHARACTERIZATION OF PHYTOCONSTITUENTS BY COLUMN CHROMATOGRAPHY

CH Exam #4 (Take Home) Date Due: 11/25,26/2013

CHEM6416 Theory of Molecular Spectroscopy 2013Jan Spectroscopy frequency dependence of the interaction of light with matter

ORGANIC SPECTROSCOPY NOTES

Lecture 14 Organic Chemistry 1

16.1 Introduction to NMR. Spectroscopy

Chapter 13 Nuclear Magnetic Resonance Spectroscopy

CHE 325 SPECTROSCOPY (A) CHAP 13A ASSIGN CH 2 CH CH 2 CH CHCH 3

Experiment 2 - NMR Spectroscopy

13.24: Mass Spectrometry: molecular weight of the sample

4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.

Symmetric Stretch: allows molecule to move through space

More information can be found in Chapter 12 in your textbook for CHEM 3750/ 3770 and on pages in your laboratory manual.

10.3 NMR Fundamentals

Introduction to Organic Spectroscopy

All measurement has a limit of precision and accuracy, and this must be taken into account when evaluating experimental results.

Chemistry 213 Practical Spectroscopy

Objective 4. Determine (characterize) the structure of a compound using IR, NMR, MS.

(2) Read each statement carefully and pick the one that is incorrect in its information.

C h a p t e r S i x t e e n: Nuclear Magnetic Resonance Spectroscopy. An 1 H NMR FID of ethanol

CHEM Chapter 13. Nuclear Magnetic Spectroscopy (Homework) W

MRI Homework. i. (0.5 pt each) Consider the following arrangements of bar magnets in a strong magnetic field.

ORGANIC - EGE 5E CH UV AND INFRARED MASS SPECTROMETRY

Module 13: Chemical Shift and Its Measurement

Can you differentiate A from B using 1 H NMR in each pair?

MOLECULAR SPECTROSCOPY AND PHOTOCHEMISTRY

where, c is the speed of light, ν is the frequency in wave numbers (cm -1 ) and µ is the reduced mass (in amu) of A and B given by the equation: ma

Spectroscopy. Fourier Transform Infrared (FT-IR) Spectroscopy

Lecture 6: Physical Methods II. UV Vis (electronic spectroscopy) Electron Spin Resonance Mossbauer Spectroscopy

Nuclear Magnetic Resonance Spectroscopy (NMR)

Transcription:

2009, Department of Chemistry, The University of Western Ontario 7a.1 7a. Structure Elucidation: IR and 13 C-NMR Spectroscopies (text 11.1 11.5, 12.1 12.5, 12.10) A. Electromagnetic Radiation Energy is transmitted through space in the form of electromagnetic radiation, which are oscillating waves of electric and magnetic fields, and this is term used to describe all the component waves found in a continuous spectrum known as the electromagnetic spectrum. The spectrum stretches from the very short wavelength (high energy) gamma rays to the very long wavelength (low energy) radio waves. Humans can see the 400 700 nm visible region (colour).

Regardless of wavelength, all electromagnetic radiation propagates through space at the speed of light (c). Radiation is characterized its wavelength (λ in metres) and frequency (vibrations per second, ν in s 1 ). The shorter the λ, the higher the ν (more waves go by per second if the wavelength is shorter). Of interest are three regions: Spectral region λ (cm) E (kcal mol 1 ) Infrared 10 4 to 10 2 5 Visible 4 10 5 to 8 10 5 50 Ultraviolet 2 10 5 to 4 10 5 100 Compare these values to the energies of molecules o Average C-C bond 83 kcal mol 1 (absorb UV) o Average π bond 60 (absorbs visible) 7a.2 o ΔE for conformations 5 10 (absorbs IR) This suggests that the absorption of infrared light causes results in conformational changes (movement of bonds). However, the energy of IR light that is absorbed must correspond to the energy of the conformational change.

A. IR Spectroscopy 7a.3 As we have seen in first-year chem, the absorption of IR light causes the vibrational excitation of bonds. The energy of the IR light absorbed depends on the functional group. Recall the functional group region and the fingerprint region of IR spectra, which are normally scanned from 4000 to 600 cm 1 (wavenumbers, reciprocal of λ when measured in cm). Absorption appears as peaks of lowered transmittance.

7a.4 Aspirin 1. IR spectra of alkanes, alkenes, and alkynes a. alkanes Saturated alkanes have relatively simple spectra, with peaks originating from C H bonds o Strong peak with multiple peaklets between 2850 3000 cm 1 (C H stretch) o Medium peak around 1450 cm 1 (CH 2 bend) o Weak peak around 1400 cm 1 (CH 3 bend) These peaks are common to all organic compounds that contain saturated alkyl groups (i.e. not very useful!).

b. alkenes 7a.5 Peaks due to C=C can be difficult to notice in IR. They are: o A weak/medium peak around 1600 1680 cm 1 (C=C stretch) o A weak/medium peak around 3000 3100 cm 1 (=C H stretch); only present if there is an H on the C c. alkynes Characteristic alkyne absorptions are: o Weak peak between 2100 2160 cm 1 (C C stretch) o A weak/medium peak around 3300 cm 1 for alkynes with an H on the C C atoms ( C H stretch).

Question: The IR shown is for which compound, H 2 C=CH 2 CH 2 CH 2 CH 2 CH 3 or HC CH 2 CH 2 CH 2 CH 2 CH 3 7a.6 d. haloalkanes C X bonds have no characteristic IR-absorption bands that are useful. Their IR spectra resemble the corresponding alkanes. IR spectrum of 1-chlorodecane:

C. Nuclear Magnetic Resonance Spectroscopy 7a.7 1. Energy absorption of nuclei Similarly to the spin of electrons, protons and neutrons can have spin quantum numbers of ± ½. This number depends on the total number of protons and neutrons in the nucleus. Atomic nuclei will have an overall nuclear spin and a spin number (I). All nuclei with an odd mass number (odd number of total neutrons and protons) can have two states, I = ± ½. That is, two energy spin states, ½ and ½. o Examples include 1 H, 13 C, 19 F, 31 P For nuclei with states I = ± ½, the spinning nucleus can be viewed as a spinning bar magnet. If such nuclei are placed in a magnetic field (B 0 ), the two spin values assume two different energy states. The lower-energy spin state (+ ½) aligns its magnetic moment with the external field applied, and the higherenergy state ( ½) is aligned opposed to the applied field.

Therefore, in a strong magnetic field, nuclei with spin will absorb radiation of energy equal to the energy difference between the two states. o Absorption of radiation by nuclei in a magnetic field is called nuclear magnetic resonance, NMR. o For organic chemists, the two most useful types are 1 H, termed proton NMR ( 1 H NMR), which we will examine later on 13 C, termed carbon NMR ( 13 C NMR) For all types of NMR, the stronger the magnetic field (B 0 ), the greater the energy separation between the two states. Very strong magnetic fields are required to make the separation large enough to be useful. For example, 13 C o At B 0 = 7.5 T (Tesla), ΔE = 0.0072 cal/mol o This energy separation corresponds to an electromagnetic frequency of 75 MHz and a wavelength of 1000 m (radiofrequency waves). Most commercial NMR instruments consist of a fixed magnetic field, a radiofrequency generator to radiate the nuclei, a receiver to detect the absorption, and a recorder. 7a.8

7a.9 The sample is dissolved in a solvent that does not interfere with the magnetic field. The sample is placed in a tube and spun rapidly in the machine s field. The solvent chosen must be not contain nuclei with spin, so no hydrogens! Common solvents used are CCl 4 and CDCl 3. 2. 13 C NMR The most abundant isotope of carbon is 12 C (98.9%), which has no nuclear spin. But all substances containing carbon will contain the 13 C isotope (1.1%), which does have spin and will give a signal in an NMR instrument. The local magnetic fields of carbon atoms in a molecule are affected by all neighbouring atoms. This makes the actual magnetic field around a specific atom slightly different than the applied field.

7a.10 Therefore, every different carbon environment in a molecule leads to the absorption of a different radiofrequency We can determine the number of different C atoms (and thus 13 C signals) by looking at molecular symmetry. O O O 1 signal 3 signals HO O HO O OH O citric acid 4 signals OH Instead of plotting signals on the x-axis of radiofrequency energy, absorption signals are plotted relative to a single 13 C absorption signal of a reference compound, TMS. tetramethylsilane (TMS) Si The signal of the TMS is arbitrarily set at zero, and all the signals of the molecule being analyzed absorb at different chemical shifts (units of delta δ). o δ is measured in parts per million. Each ppm corresponds to one part per million in the frequency of radiation absorbed (e.g. 75 Hz in a 75 MHz machine). EWG s, and greater s-character in hybrid C orbitals, shift 13 C signals to the left of TMS. This is termed downfield.

Therefore, C with different magnetic environments will have a different chemical shift relative to TMS. In all 13 C-NMR spectra, if a signal is visible at 0 ppm, it corresponds to the TMS signal. 7a.11 Thus, 13 C-NMR spectra reveal the number of magnetically non-equivalent C atoms and their identity (chemical shifts).

Question: Predict the number of signals for the following compounds. Do the spectra agree with their structure? 7a.12 1-pentene Cl 4-chlorophenol OH Important note: signal heights on 13 C-NMR spectra do not correspond with the number of C atoms they represent (see 1-pentene). However, higher signals usually result from greater numbers of equivalent nuclei (see 4-chlorophenol). The analysis of IR and 13 C-NMR spectra, together with info about units of unsaturation, often gives enough information to elucidate molecular structure (see assigned problems). Summary: o C11: 304 312. C12: 329 334 and 342 346. o Problems: 11.9 11.12, 11.20, 12.9, 12.10, 12.14 o Dec 05: 16 18. Dec 06: 14, 15, 17. Dec 07: 14 16. Dec 08: 14 16.

Example question: Which one functional group is present in the compound that gives the following IR spectrum? 7a.13 R C C R R 2 C=CR 2 RCH 2 CH 2 R R C C H R 2 C=CH 2 The molecule shown below has how many signals in its 13 C-NMR spectrum? OH CH 3 CH 3 CHCH 2 CCH 3 CH 3 1 2 3 4 5

The IR and 13 C-NMR spectra below correspond to which compound? 7a.14

7a.15 MCAT questions o What change occurs in a molecule when IR irradiation is absorbed? The spin of the electron flips The vibrations of the bonds change The rotation around the bond axes change The translational motion changes o What causes a peak in an NMR spectrum? A deflection of a molecule by a magnetic field The absorption of electromagnetic radiation The reorientation of a molecule in a magnetic field A reflection of a frequency of electromagnetic radiation o A stretch at 1700 cm 1 in an IR spectrum indicates the presence of which functional group? ketone alcohol alkene alkyne