ABOUT THIS BOOK THIS BOOK IS COMPLIANT WITH THE BOSTES NSW MATHEMATICS STAGE 5.3 SYLLABUS.

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YEAR 9 MATHS MAX SERIES VOL.1 ABOUT THIS BOOK THIS BOOK IS COMPLIANT WITH THE BOSTES NSW MATHEMATICS STAGE 5.3 SYLLABUS. Content in the Year 9 Maths Max Series TM Volume 1 covers the topics Algebraic Techniques and Surds & Indices from the Number & Algebra strand of the NSW Mathematics Stage 5. and 5.3 Syllabus. STRAND TOPICS CONTENT Number and Algebra Algebraic Techniques Add and subtract algebraic fractions. Expand binomial products. Factorise quadratic expressions. Surds & Indices Define rational and irrational numbers. Simplify expressions involving surds by addition, subtraction, multiplication, and division. Rationalise the denominator of surds. For detailed information including the contents of the topics, please visit the BOSTES website link available on https:///bostes THIS BOOK IS NOT YOUR ORDINARY TEXTBOOK. Are you constantly surprised to find your school exam questions differ from the textbook questions you spent hours perfecting? Do you find those practice papers your teacher provided for you didn t quite prepare you for the exam? Textbooks provide course content in a way that helps students gain a sound knowledge and understanding of the fundamental concepts. But this is insufficient to achieve exam success at school as students are required to: demonstrate extensive knowledge and skills apply maths concepts to unfamiliar questions/situations use sophisticated multi-step reasoning exhibit excellent problem solving skills THIS IS THE LAST PLACE TO LOOK BEFORE YOUR EXAM. The Year 9 Maths Max Series TM Volume 1 is designed for exam preparation, as well as, providing students the opportunity to further develop and practice the fundamental concepts. When it is used correctly, students will gain a significant advantage in their school exams. The Year 9 Maths Max Series TM Volume 1 works by: exposing students to exam-style questions to reduce the chance of encountering unfamiliar problems. effectively preparing students for school exams by bridging the knowledge and skills gap between their textbooks and exam questions. improving students problem solving skills by sharing the techniques not published in textbooks.

YEAR 9 MATHS MAX SERIES VOL.1 HOW TO USE THIS BOOK Students should only use this book after gaining a sound knowledge and understanding of the key concepts of the mathematics course content. This book will effectively prepare students for school exams when the following steps are closely followed. STEP 1 Review theory contents At the beginning of each topic, a concise summary of the key concepts is provided. Be sure to read and understand it before attempting any questions. Various examples have been carefully curated to expose students to different exam-style questions. A concise summary of the key concepts are provided at the beginning of each section. A step-by-step worked solution is provided for each example to enhance your understanding. STEP Study the examples and its solutions to gain clarity The examples expose students to various exam-style questions. The step-by-step worked solution for each example provides clear multi-step reasoning to enhance your understanding and provide a structure for maximising marks in exams.

STEP 3 Attempt practice questions to improve problem solving skills Questions are organised in a progressive manner to facilitate independent learning. If you have difficulty, the NOTES TO STUDENTS section provides you with hints to encourage problem solving without referring to the solution. The common errors section helps you remember what not to do in exams. The LEVEL of difficulty is a useful tool to assess your ability to solve new, unseen and difficult problems. Refer to the section title for the relevant Theory. Students can use hints from NOTES TO STUDENTS to solve a problem without viewing at the solution. Questions are organised in a progressive manner to help students build their confidence. Questions are categorised into 4 levels of difficulty: 1: Basic : Fundamental 3. Difficult 4. Challenging Spacing provided is a good indication of the amount of working required.

YEAR 9 MATHS MAX SERIES VOL.1 CONTENTS ALGEBRAIC 01 SIMPLE ALGEBRAIC EXPRESSIONS P07 TECHNIQUES Expansions of the form: ab ^ + ch Expansions of expressions with multiple brackets 0 BINOMIAL PRODUCTS P11 Binomial expressions and products The Distributive Law The FOIL Method Binomial product: ^x+ ah^x+ bh 03 SPECIAL PRODUCTS P15 Product of a sum and difference ^a+ bh^a-bh Perfect Squares: ^a! bh 04A FACTORISATION OF ALGEBRAIC EXPRESSIONS 1 Extracting the highest common factor (HCF) Extracting the highest common factor (HCF) involving a term in a bracket Factorising by grouping in pairs 04B FACTORISATION OF ALGEBRAIC EXPRESSIONS Factorising difference of two squares in the form a - b Factorising difference of two squares in the form ab x - acy 4 4 Factorising difference of two squares in the form x - y 04C FACTORISATION OF ALGEBRAIC EXPRESSIONS 3 Quadratic trinomial Factorising monic quadratic trinomials 04D FACTORISATION OF ALGEBRAIC EXPRESSIONS 4 Factorising non-monic quadratic trinomials Factorising quadratic trinomials using the Pairing Method Factorising quadratic trinomials using the Fraction Method Factorising quadratic trinomials using the Cross Method 05A REDUCING, MULTIPLYING AND DIVIDING ALGEBRAIC FRACTIONS Introduction to algebraic fractions Reducing algebraic fractions (Cancelling) Multiplying and dividing algebraic fractions P1 P6 P3 P35 P4 04

05B ADDING AND SUBTRACTING ALGEBRAIC FRACTIONS 1 Same numerical denominators Different numerical denominators 05C ADDING AND SUBTRACTING ALGEBRAIC FRACTIONS Same pronumeral denominators Pronumeral denominators that differ by a negative sign Different pronumeral denominators Quadratic denominators SURDS AND 06 INDEX LAWS AND STANDARD NOTATION P61 INDICES Expanded vs. Index form SOLUTIONS Index laws for multiplication Index laws for division Raising to a power A power of zero Negative powers 07 RATIONAL AND IRRATIONAL NUMBER SETS AND FRACTIONAL INDICES P70 Surds are irrational numbers Fractional powers 08 THE REAL NUMBER SYSTEM P76 Types of numbers Terminating and recurring decimals 09 SIMPLIFYING AND MULTIPLYING SURDS P80 Multiplying surds Simplifying entire surds Converting mixed surds to entire surds Dividing surds 10 ADDITION AND SUBTRACTION OF SURDS P90 Adding and subtracting like surds Adding and subtracting unlike surds 11 BINOMIAL PRODUCTS AND SURDS P94 The Distributive Law Product of a sum and difference (Special Product) 1 RATIONALISING THE DENOMINATOR P98 Fractions involving surds Denominators with a single term Denominators with two terms P49 P53 P105 05

TOPIC ALGEBRAIC TECHNIQUES 01 SIMPLE ALGEBRAIC EXPRESSIONS Expansions of the form: ab ^ + ch Expansions of expressions with multiple brackets 0 BINOMIAL PRODUCTS 0 Binomial expressions and products The Distributive Law The FOIL Method Binomial product: ^x+ ah^x+ bh 03 SPECIAL PRODUCTS Product of a sum and difference ^a+ bh^a-bh Perfect Squares: ^a! bh 04A FACTORISATION OF ALGEBRAIC EXPRESSIONS 1 Extracting the highest common factor (HCF) Extracting the highest common factor (HCF) involving a term in a bracket Factorising by grouping in pairs 04B FACTORISATION OF ALGEBRAIC EXPRESSIONS Factorising difference of two squares in the form a - b Factorising difference of two squares in the form ab x - acy 4 4 Factorising difference of two squares in the form x - y 04C FACTORISATION OF ALGEBRAIC EXPRESSIONS 3 Quadratic trinomial Factorising monic quadratic trinomials 04D FACTORISATION OF ALGEBRAIC EXPRESSIONS 4 Factorising non-monic quadratic trinomials Factorising quadratic trinomials using the Pairing Method Factorising quadratic trinomials using the Fraction Method Factorising quadratic trinomials using the Cross Method 05A REDUCING, MULTIPLYING AND DIVIDING ALGEBRAIC FRACTIONS Introduction to algebraic fractions Reducing algebraic fractions (Cancelling) Multiplying and dividing algebraic fractions 05B ADDING AND SUBTRACTING ALGEBRAIC FRACTIONS 1 Same numerical denominators Different numerical denominators 05C ADDING AND SUBTRACTING ALGEBRAIC FRACTIONS Same pronumeral denominators Pronumeral denominators that differ by a negative sign Different pronumeral denominators Quadratic denominators 06

TOPIC ALGEBRAIC TECHNIQUES THEORY 01 SIMPLE ALGEBRAIC EXPRESSIONS Expansions of the form: ab ^ + c Parentheses or brackets are used to group terms together and imply multiplication. To expand an algebraic expression with a bracket, multiply each term in the bracket by the term immediately outside the bracket, taking care with negative terms. ab ^ + ch = ab+ ac ab ^ - ch = ab- ac - ab ^ + ch =-ab- ac -ab ^ - ch =- ab+ ac After expanding, simplify the expression by collecting like terms. h (a) 4^a- 3bh+ 3^b+ 4ah [Remove the brackets] = 8a- 1b+ 6b+ 1a [Collect like terms and simplify] = 0a-6b [Express in the alphabetical order] (b) x-^3x-5h [Note: -( 3x- 5) =-1# ( 3x- 5) ] = x- 3x+ 5 =- x + 5 Example 1 Expand the following (a) 4^x+ 3yh (b) x^3x- 5h (c) x-^5y-1h (d) ^x+ y+ 1h (e) -( x+ y- z) (a) 4^x+ 3yh = 4# x+ 4# 3y = 8x+ 1y (b) x^3x- 5h = 3x - 5x (c) x-^5y- 1h = x- 5y+ 1 [Note: -^a- bh =- a+ b] (d) ^x+ y+ 1h = x+ y+ (e) - ^x+ y- zh =-x- y+ z [Note: - ^a+ bh =-a- b] (c) 3x^x-7h-5^x - 7h [Remove the brackets. Be careful of the product of negative signs] = 6x -1x- 10x + 35 = 6x - 31x+ 35 Expansions of expressions with multiple brackets To expand algebraic expressions with multiple sets of brackets, always begin with the innermost brackets. Example Expand and simplify the following " 5a + 3^a-3a h, " 5a + 3^a-3a h, [Remove the innermost brackets first] Example Expand and simplify the following algebraic expressions (a) 4^a- 3bh+ 3^b+ 4ah (b) x-^3x-5h (c) 3x^x-7h-5^x - 7h = " 5a + 6a- 9a, [Collect like terms in the bracket] = " - 4a + 6a, [Remove the remaining brackets] =- 8a + 1a [Collect like terms and simplify] 07

3( x + ) a^b+ ch = ab+ ac 5 ( - 5x) a^b- ch = ab- ac 3aa ( - b + 1) 3a 3x-5( x-7) -# +=- -#-=+ 3x^x+ yh+ y^3x- 5y h y# 3x = 3xy 7a^a- 3b+ 4c h -a^b- c+ dh =- ab + ac - ad aa ^ - b+ 3h-a^-3a- 4b+ 5h -a^-b- c+ dh =+ ab + ac -ad 5a^a- 3b+ ch-4ba ^ - b+ 3ch- c( a+ 5b-c)

4 7 5 a ^a - a + 1h # a = a + a x y x y 8ab ^- 3ab 3 + 4ab 5 6 h -xy ( xy -5xy 3 ) a -8a-" 5a + ^a-3a h, 3a-4b-" a-7b-^5a- 3bh,

4" x-6y- ^x+ yh, -" 5x-3 ^ x-7yh, 7x -3[ x--{ 5-3x+ 4x( x- 1) + 9x}] 9x-65x-3y-" 4x-^y-3xh, @ - x+ 5y -( y- 3x) =- y+ 3x

TOPIC ALGEBRAIC TECHNIQUES THEORY 0 BINOMIAL PRODUCTS Binomial expressions and products A binomial expression is an expression with two terms. An example of a binomial expression is x+ y. The product of two binomial expressions is called a binomial product. An example of a binomial product is( x+ y)( 3x- y). The FOIL Method The Distributive Law method of expanding binomial products can be shortened into what is called the FOIL Method. FOIL stands for: F - First in each bracket are multiplied O - Outsides in each bracket are multiplied The Distributive Law Binomial products can be expanded using the Distributive Law: ^ax + bh^cx+ dh= ax^cx + dh+ b^cx + dh = acx + adx + bcx+ bd Example Use the Distributive Law to expand and simplify the following (a) ^x+ 9h^x+ 4h (b) ^5-xh^3 -xh (c) ^x+ h^x - x + 4h (a) ^x+ 9h^x+ 4h = x^x+ 4h + 9^x + 4h = x + 8x+ 9x + 36 = x + 17x+ 36 (b) Be very careful when there is a negative sign before the bracket. Don t forget to change the signs of all the terms in the bracket when you expand. ( 5-x)( 3 -x) = 5( 3-x) -x( 3- x) = 15-5x- 6x+ x = x - 11x+ 15 (c) The second bracket has three terms. Multiply each term in the second bracket by x and then by +. Then simplify by collecting like terms. ^x+ h^x - x + 4h = x^x - x+ 4h + ^x - x + 4h 3 = x - x + 4x+ x - 4x + 8 3 = x + 8 I - Insides in each bracket are multiplied L - Last in each bracket are multiplied F O ( ax + b)( cx+ d) I L F O I L = ( ax # cx) + ( ax # d) + ( b# cx) + ( b# d) ( ax - b)( cx+ d) = ( ax # cx) + ( ax # d) + (- b# cx) + (-b# d) Example Use the FOIL Method to expand and simplify the following (a) ^x+ 9h^x+ 4h (b) ^5-xh^3 -xh (c) ^x+ h^x - x + 4h F O F O I L (a) ( x+ 9)( x+ 4) = x# x+ x# 4+ 9# x+ 9# 4 (b) (c) I L ( x+ 9)( x+ 4) = x + 8x+ 9x + 36 = x + 17x+ 36 ^5-xh^3 -xh = ( 5# 3) + ( 5# - x) + (- x# 3) + (-x#-x) = 15-5x- 6x+ x = x - 11x+ 15 ^x+ h^x - x + 4h = ( x# x ) + ( x# - x) + ( x # 4) + ( # x ) + ( # - x) + ( # 4) 3 = x - x + 4x+ x - 4x+ 8 3 = x + 8 Which method, the Distributive Law or the FOIL Method, do you prefer? 11

Binomial product: ( x+ a)( x+ b) Binomial products in the form of ( x+ a)( x+ b) can be expanded more efficiently if you use the rule below: x+ ah x+ bh= x + a+ bx h + ab ^ ^ ^ This rule can only be used if each bracket starts with the same term. Example 1 Expand ^p- 4h^p+ 8h Since each bracket starts with p we can use the special product rule. ( p- 4)( p+ 8) = p + (- 4+ 8) p+ (-4# 8) = p + 4p- 3 ^p+ ah^p+ bh= p + ^a+ bp h + ab ^q+ ah^q+ bh= q + ^a+ bq h + ab ^x + ah^x + bh= ( x ) + ^a+ bx h + ab Example Expand ^m-8nh^m-9nh Study the solutions to the following expansions: ( x+ 3)( x+ 5) = x + ( 3+ 5) x+ ( 3# 5) = x + 8x+ 15 ( x+ 9)( x- 7) = x + ( 9+- 7) x+ ( 9# -7) = x + x- 63 ( x- )( x+ 11) = x + (- + 11) x+ (-# 11) = x + 9x- Since each bracket starts with m we can use the special product rule. ( m-8n)( m-9n) = m + (-8n- 9n) m+ (-8n#-9n) = m - 17nm+ 7n [Express in the alphabetical order] = m - 17mn+ 7n [Note: Always express pronumerals in the alphabetical order] ( x-6)( x- 5) = x + (- 6+- 5) x+ (-6#-5) = x - 11x+ 30 ( x+ 7y)( x+ 11y) = x + ( 7y+ 11yx ) + ( 7y# 11y) = x + 18xy+ 77y ( x+ 9y)( x- 1y) = x + ( 9y+- 1yx ) + ( 9y# -1y) = x -3xy- 108y ( xy + 8)( xy - 3) = ( xy) + ( 8+- 3) xy + ( 8# -3) = xy+ 5xy - 4 Consider the numbers in the brackets, the coefficient of x and the constant term in the expansion. Do you see a connection between these values? Example 3 Expand ^x + 5yh^x -1yh Since each bracket starts with x we can use the special product rule. ^x + 5yh^x -1yh = ( x ) + x ( 5y- 1y) + ( 5y# -1y) 4 = x -7yx - 60y 4 = x -7x y- 60y [Express in the alphabetical order] 1

^x+ ah^x+ bh= x + ^a+ bx h + ab ^x+ 3h^x-7h ^x+ ah^x- bh= x + ^a-bhx-ab ^x-3h^x-8h ( a-3bc)( a-5bc) ( mk + 6)( mk -9) ^xy + ah^xy- bh= ( xy) ^a-bhxy - ab + ^3x+ 1h^x-1h ( a+ b)( c- d) = ( a# c) + ( a# - d) + ( b# c) + ( b# -d) = ac - ad + bc -bd ( x-7y)( 4x-9y) ( a- b)( c- d) = ( a# c) + ( a# - d) + (- b# c) + (-b#-d) = ac -ad - bc + bd ^p-5qh^3p-4qh ^a+ bh^c+ d+ eh ^7x-1h^x - 9x + 5h = a( c+ d+ c) + b( c+ d+ e) = ac + ad + ae + bc + bd + be