Alg 1B Chapter 7 Final Exam Review

Similar documents
Name: Chapter 7: Exponents and Polynomials

Chapter 5: Exponents and Polynomials

Polynomials Practice Test

AFM Review Test Review

PERT Practice Test #2

ALGEBRA 2 FINAL EXAM REVIEW

Say it with Symbols - Unit Test Review Shet

Algebra 2 Matrices. Multiple Choice Identify the choice that best completes the statement or answers the question. 1. Find.

MathB65 Ch 4 IV, V, VI.notebook. October 31, 2017

Review for Mastery. Integer Exponents. Zero Exponents Negative Exponents Negative Exponents in the Denominator. Definition.

A field trips costs $800 for the charter bus plus $10 per student for x students. The cost per student is represented by: 10x x

Honors Algebra 2 Quarterly #3 Review

Midterm Review. Name: Class: Date: ID: A. Short Answer. 1. For each graph, write the equation of a radical function of the form y = a b(x h) + k.

Algebra 1 First Semester Exam Answer Section

Lesson 3 Algebraic expression: - the result obtained by applying operations (+, -,, ) to a collection of numbers and/or variables o

CHAPTER 1 POLYNOMIALS

Beginning Algebra MAT0024C. Professor Sikora. Professor M. J. Sikora ~ Valencia Community College

Exponents Unit Assessment Review

Chapter 7 Rational Expressions, Equations, and Functions

Chapter 6. Polynomials

Algebra I Unit Report Summary

Section September 6, If n = 3, 4, 5,..., the polynomial is called a cubic, quartic, quintic, etc.

Algebra 1B Final Review

Algebra II: Chapter 5 Review

Name: Class: Date: A. 70 B. 62 C. 38 D. 46

P.1 Prerequisite skills Basic Algebra Skills

Math 0320 Final Exam Review

MATH98 Intermediate Algebra Practice Test Form A

5.3. Polynomials and Polynomial Functions

Sect Definitions of a 0 and a n

Answers of the MATH97 Practice Test Form A

I CAN classify polynomials by degree and by the number of terms.

Adding & Subtracting Polynomial Expressions

Algebra 2 Honors: Final Exam Review

North Caroline Math 2 Transition Edition Unit 3 Assessment: Radical and Rational Functions

Chapter 12 Final Review

Day 131 Practice. What Can You Do With Polynomials?

Unit 13: Polynomials and Exponents

When you square a binomial, you can apply the FOIL method to find the product. You can also apply the following rules as a short cut.

Algebra 2 Summer Math Answer Section

Chapter 5 Rational Expressions

Section 2.4: Add and Subtract Rational Expressions

Trigonometric Identity Practice

Math 46 Final Exam Review Packet

MATH 0960 ELEMENTARY ALGEBRA FOR COLLEGE STUDENTS (8 TH EDITION) BY ANGEL & RUNDE Course Outline

LESSON 9.1 ROOTS AND RADICALS

Accentuate the Negative - Unit Test Review Sheet

Test # 3 Review. È 3. Compare the graph of n 1 ÎÍ. Name: Class: Date: Short Answer. 1. Find the standard form of the quadratic function shown below:

Quadratics Unit Review

Simplify each numerical expression. Show all work! Only use a calculator to check. 1) x ) 25 ( x 2 3) 3) 4)

Beginning Algebra. 1. Review of Pre-Algebra 1.1 Review of Integers 1.2 Review of Fractions

Algebra 2 Midterm Review

Ready To Go On? Skills Intervention 7-1 Integer Exponents

27 Wyner Math 2 Spring 2019

Chapter 1 Test Review

Lesson 2. When the exponent is a positive integer, exponential notation is a concise way of writing the product of repeated factors.

Distributive Property, Expressions, and Equations Study Guide

Basic Equation Solving Strategies

Real Numbers. Real numbers are divided into two types, rational numbers and irrational numbers

Introduction. Adding and Subtracting Polynomials

Pre-Algebra 2. Unit 9. Polynomials Name Period

Algebra 1, Absolute Value Functions Review

Linear Equations & Inequalities Definitions

Sect Properties of Real Numbers and Simplifying Expressions

review To find the coefficient of all the terms in 15ab + 60bc 17ca: Coefficient of ab = 15 Coefficient of bc = 60 Coefficient of ca = -17

Unit 2: Polynomials Guided Notes

POLYNOMIAL EXPRESSIONS PART 1

Polynomials. Exponents. End Behavior. Writing. Solving Factoring. Graphing. End Behavior. Polynomial Notes. Synthetic Division.

L1 2.1 Long Division of Polynomials and The Remainder Theorem Lesson MHF4U Jensen

John L. Lehet

1. Simplify. 2. Simplify. 3. Simplify. 4. Solve the following equation for x.

1. f(x) = f(x) = 3. y 2-3y p - 4 8p2. Math 0312 EXAM 3 Review Questions. Name. Find all numbers not in the domain of the function.

Chapter 1 Review - Challenge Pre-algebra

Never leave a NEGATIVE EXPONENT or a ZERO EXPONENT in an answer in simplest form!!!!!

Section 1.3 Review of Complex Numbers

Study Guide for Math 095

Section 2.1: Reduce Rational Expressions

Algebra III and Trigonometry Summer Assignment

Lynch 2017 Page 1 of 5. Math 150, Fall 2017 Exam 1 Form A Multiple Choice

L1 2.1 Long Division of Polynomials and The Remainder Theorem Lesson MHF4U Jensen

Note: A file Algebra Unit 09 Practice X Patterns can be useful to prepare students to quickly find sum and product.

Unit 2: Polynomials Guided Notes

PreCalculus: Semester 1 Final Exam Review

Polynomial comes from poly- (meaning "many") and -nomial (in this case meaning "term")... so it says "many terms

Answers to Sample Exam Problems

Summer Prep Packet for students entering Algebra 2

MATH98 Intermediate Algebra Practice Test Form B

LESSON 6.1 EXPONENTS LESSON 6.1 EXPONENTS 253

5.1 Monomials. Algebra 2

Properties of Real Numbers

Math 101 Study Session Spring 2016 Test 4 Chapter 10, Chapter 11 Chapter 12 Section 1, and Chapter 12 Section 2

Sections 7.2, 7.3, 4.1

Chapter 1.6. Perform Operations with Complex Numbers

6.4 Division of Polynomials. (Long Division and Synthetic Division)

Simplifying Radical Expressions

P.1: Algebraic Expressions, Mathematical Models, and Real Numbers

Geometry Summer Assignment 2018

2.3 Differentiation Formulas. Copyright Cengage Learning. All rights reserved.

Math 2 Variable Manipulation Part 2 Powers & Roots PROPERTIES OF EXPONENTS:

Intermediate Mathematics Assessment. Sampler

Transcription:

Name: Class: Date: ID: A Alg B Chapter 7 Final Exam Review Please answer all questions and show your work. Simplify ( 2) 4. 2. Simplify ( 4) 4. 3. Simplify 5 2. 4. Simplify 9x0 y 3 z 8. 5. Simplify 7w0 r 8 t 7. 6. Simplify 8w0 r 2 t 5. 7. Simplify (x 2 ) 6 x 2.

Name: ID: A 8. Simplify (x 5 ) 8 x 4. 9. Simplify (x 4 ) 7 x 2. 0. Simplify b 3 p 6 (bp) 2.. Simplify a 8 b 9 (ab) 3. 2. Simplify y5 z 8 (yz) 2. 3. Find the degree of the polynomial 9x 4 y 5 + 2xy + x 2. 4. Find the degree of the polynomial 2x 2 y 6 + 4.5xy + x 2. 5. Find the degree of the polynomial 5x 2 y 5 + 3.5xy + x 4. 2

Name: ID: A 6. Write the polynomial 7x 3 + 3 + 4x 4 + x 2 5x 5 5x in standard form. Then give the leading coefficient. 7. Write the polynomial 8x 2 + 4x 4x 5 0x 3 + 9x 4 + 8 in standard form. Then give the leading coefficient. 8. Write the polynomial 9x 3 + 5 5x 5 3x 2 3x 4 7x in standard form. Then give the leading coefficient. 9. Add. (2b 5 b 2 ) + (b 5 + 4b 2 3) 20. Add. (6d 5 d 3 ) + (d 5 + 5d 3 ) 2. Add. (7e 3 e ) + (e 3 + 3e ) 22. Subtract. (7e 5 e 3 ) (e 5 + 4e 3 2) 23. Subtract. (0e 3 e ) (e 3 + 6e 2) 3

Name: ID: A 24. Subtract. (3c 4 c ) (c 4 + 6c ) 25. Multiply. (x )(x 3) 26. Multiply. (2m + )(m 2) 27. Multiply. (x + 5)(x + ) 28. Multiply. (x 2) 2 29. Multiply. (p 3) 2 30. Multiply. (z 7) 2 4

Alg B Chapter 7 Final Exam Review Answer Section SHORT ANSWER. ANS: 6 ( 2) 4 = ( 2) 4 The reciprocal of 2 is ( 2). = 6 ( 2) 4 = 6. PTS: DIF: Average REF: Page 447 OBJ: 7-.2 Zero and Negative Exponents NAT: 2...d TOP: 7- Integer Exponents KEY: negative exponent evaluate power exponent 2. ANS: 256 ( 4) 4 = ( 4) 4 The reciprocal of 4 is ( 4). = 256 ( 4) 4 = 256. PTS: DIF: Average REF: Page 447 OBJ: 7-.2 Zero and Negative Exponents NAT: 2...d TOP: 7- Integer Exponents KEY: negative exponent evaluate power exponent 3. ANS: 25 5 2 = 5 2 The reciprocal of 5 is 5. = 25 5 2 = 25. PTS: DIF: Average REF: Page 447 OBJ: 7-.2 Zero and Negative Exponents NAT: 2...d TOP: 7- Integer Exponents KEY: negative exponent evaluate power exponent

4. ANS: 9z 8 y 3 9x 0 y 3 z 8 = 9 y 3 = 9 = 9 = 9z8 y 3 z 8 y 3 z 8 y 3 z8 z 8 = z8. 9x 0 y 3 Rewrite z 8 without negative or zero exponents. Simplify each part of the expression. y 3 = y 3. PTS: DIF: Advanced REF: Page 448 OBJ: 7-.4 Simplify Expressions with Zero and Negative Exponents NAT: 2.5.3.d TOP: 7- Integer Exponents 5. ANS: 7t 7 r 8 7w 0 r 8 t 7 = 7 r 8 = 7 = 7 = 7t7 r 8 r 8 t 7 t 7 7w 0 r 8 Rewrite t 7 without negative or zero exponents. Simplify each part of the expression. r 8 = r 8. r 8 t7 t 7 = t7. PTS: DIF: Advanced REF: Page 448 OBJ: 7-.4 Simplify Expressions with Zero and Negative Exponents NAT: 2.5.3.d TOP: 7- Integer Exponents 2

6. ANS: 8t 5 r 2 8w 0 r 2 t 5 = 8 r 2 = 8 = 8 = 8t5 r 2 t 5 r 2 t 5 8w 0 r 2 Rewrite t 5 without negative or zero exponents. Simplify each part of the expression. r 2 = r 2. r 2 t5 t 5 = t5. PTS: DIF: Advanced REF: Page 448 OBJ: 7-.4 Simplify Expressions with Zero and Negative Exponents NAT: 2.5.3.d TOP: 7- Integer Exponents 7. ANS: x 0 (x 2 ) 6 x 2 x 2 6) x 2 Use the Power of a Power Property. x 2 x 2 Simplify the exponent of the first term. x 2 + 2 Add the exponents since the powers have the same base. x 0 x 0 Write with a positive exponent. PTS: DIF: Advanced REF: Page 462 OBJ: 7-3.3 Finding Powers of Powers NAT: 2.5.3.c TOP: 7-3 Multiplication Properties of Exponents 3

8. ANS: x 36 (x 5 ) 8 x 4 x 5 8) x 4 Use the Power of a Power Property. x 40 x 4 Simplify the exponent of the first term. x 40 + 4 Add the exponents since the powers have the same base. x 36 x 36 Write with a positive exponent. PTS: DIF: Advanced REF: Page 462 OBJ: 7-3.3 Finding Powers of Powers NAT: 2.5.3.c TOP: 7-3 Multiplication Properties of Exponents 9. ANS: x 26 (x 4 ) 7 x 2 x 4 7) x 2 Use the Power of a Power Property. x 28 x 2 Simplify the exponent of the first term. x 28 + 2 Add the exponents since the powers have the same base. x 26 x 26 Write with a positive exponent. PTS: DIF: Advanced REF: Page 462 OBJ: 7-3.3 Finding Powers of Powers NAT: 2.5.3.c TOP: 7-3 Multiplication Properties of Exponents 0. ANS: b p 4 First, use the Power of a Product Property to rewrite the denominator. Then, for each power with the same base, keep the base and subtract the exponents. PTS: DIF: Average REF: Page 467 OBJ: 7-4. Finding Quotients of Powers NAT: 2.5.3.c TOP: 7-4 Division Properties of Exponents KEY: exponent power division base 4

. ANS: a 5 b 6 First, use the Power of a Product Property to rewrite the denominator. Then, for each power with the same base, keep the base and subtract the exponents. PTS: DIF: Average REF: Page 467 OBJ: 7-4. Finding Quotients of Powers NAT: 2.5.3.c TOP: 7-4 Division Properties of Exponents KEY: exponent power division base 2. ANS: y 3 z 6 First, use the Power of a Product Property to rewrite the denominator. Then, for each power with the same base, keep the base and subtract the exponents. PTS: DIF: Average REF: Page 467 OBJ: 7-4. Finding Quotients of Powers NAT: 2.5.3.c TOP: 7-4 Division Properties of Exponents KEY: exponent power division base 3. ANS: 9 9x 4 y 5 : degree 9, 2xy: degree 2, and x 2 : degree 2 The degree of the polynomial is 9. PTS: DIF: Average REF: Page 476 OBJ: 7-5.2 Finding the Degree of a Polynomial TOP: 7-5 Polynomials 4. ANS: 8 2x 2 y 6 : degree 8, 4.5xy: degree 2, and x 2 : degree 2 The degree of the polynomial is 8. PTS: DIF: Average REF: Page 476 OBJ: 7-5.2 Finding the Degree of a Polynomial TOP: 7-5 Polynomials 5. ANS: 7 5x 2 y 5 : degree 7, 3.5xy: degree 2, and x 4 : degree 4 The degree of the polynomial is 7. PTS: DIF: Average REF: Page 476 OBJ: 7-5.2 Finding the Degree of a Polynomial TOP: 7-5 Polynomials NAT: 2.5.2.b NAT: 2.5.2.b NAT: 2.5.2.b 5

6. ANS: 5x 5 + 4x 4 + 7x 3 + x 2 5x + 3 The leading coefficient is 5. The standard form is written with the terms in order from highest to lowest degree. PTS: DIF: Basic REF: Page 477 OBJ: 7-5.3 Writing Polynomials in Standard Form TOP: 7-5 Polynomials 7. ANS: NAT: 2.5.3.d 4x 5 + 9x 4 0x 3 + 8x 2 + 4x + 8 The leading coefficient is 4. The standard form is written with the terms in order from highest to lowest degree. PTS: DIF: Basic REF: Page 477 OBJ: 7-5.3 Writing Polynomials in Standard Form TOP: 7-5 Polynomials 8. ANS: NAT: 2.5.3.d 5x 5 3x 4 9x 3 3x 2 7x + 5 The leading coefficient is 5. The standard form is written with the terms in order from highest to lowest degree. PTS: DIF: Basic REF: Page 477 OBJ: 7-5.3 Writing Polynomials in Standard Form TOP: 7-5 Polynomials 9. ANS: 3b 5 + 3b 2 3 (2b 5 b 2 ) + (b 5 + 4b 2 3) = (2b 5 + 4b 2 ) + ( b 2 + b 5 ) + ( 3) = 3b 5 + 3b 2 3 NAT: 2.5.3.d Identify like terms. Rearrange terms to get like terms together. Combine like terms. PTS: DIF: Basic REF: Page 485 OBJ: 7-6.2 Adding Polynomials NAT: 2.5.3.c TOP: 7-6 Adding and Subtracting Polynomials 20. ANS: 7d 5 + 4d 3 (6d 5 d 3 ) + (d 5 + 5d 3 ) = (6d 5 + 5d 3 ) + ( d 3 + d 5 ) + ( ) = 7d 5 + 4d 3 Identify like terms. Rearrange terms to get like terms together. Combine like terms. PTS: DIF: Basic REF: Page 485 OBJ: 7-6.2 Adding Polynomials NAT: 2.5.3.c TOP: 7-6 Adding and Subtracting Polynomials 6

2. ANS: 8e 3 + 2e (7e 3 e ) + (e 3 + 3e ) = (7e 3 + 3e ) + ( e + e 3 ) + ( ) = 8e 3 + 2e Identify like terms. Rearrange terms to get like terms together. Combine like terms. PTS: DIF: Basic REF: Page 485 OBJ: 7-6.2 Adding Polynomials NAT: 2.5.3.c TOP: 7-6 Adding and Subtracting Polynomials 22. ANS: 6e 5 5e 3 + 2 (7e 5 e 3 ) (e 5 + 4e 3 2) = (7e 5 e 3 ) + ( e 5 4e 3 + 2) = (7e 5 e 5 ) + ( e 3 4e 3 ) + ( 2) = 6e 5 5e 3 + 2 Rewrite subtraction as addition of the opposite. Identify like terms. Rearrange terms to get like terms together. Combine like terms. PTS: DIF: Average REF: Page 485 OBJ: 7-6.3 Subtracting Polynomials NAT: 2.5.3.c TOP: 7-6 Adding and Subtracting Polynomials 23. ANS: 9e 3 7e + 2 (0e 3 e ) (e 3 + 6e 2) = (0e 3 e ) + ( e 3 6e + 2) = (0e 3 e 3 ) + ( e 6e ) + ( 2) = 9e 3 7e + 2 Rewrite subtraction as addition of the opposite. Identify like terms. Rearrange terms to get like terms together. Combine like terms. PTS: DIF: Average REF: Page 485 OBJ: 7-6.3 Subtracting Polynomials NAT: 2.5.3.c TOP: 7-6 Adding and Subtracting Polynomials 7

24. ANS: 2c 4 7c + (3c 4 c ) (c 4 + 6c ) = (3c 4 c ) + ( c 4 6c + ) = (3c 4 c 4 ) + ( c 6c ) + ( ) = 2c 4 7c + Rewrite subtraction as addition of the opposite. Identify like terms. Rearrange terms to get like terms together. Combine like terms. PTS: DIF: Average REF: Page 485 OBJ: 7-6.3 Subtracting Polynomials NAT: 2.5.3.c TOP: 7-6 Adding and Subtracting Polynomials 25. ANS: x 2 4x + 3 (x )(x 3) Use FOIL. x(x 3) (x 3) Distribute x and. x(x) + x( 3) (x) ( 3) Distribute x and again. x 2 3x x + 3 Multiply. x 2 4x + 3 Combine like-terms. PTS: DIF: Basic REF: Page 494 OBJ: 7-7.3 Multiplying Binomials NAT: 2.5.3.c TOP: 7-7 Multiplying Polynomials 26. ANS: m 2 m 2 (m + )(m 2) Use FOIL. m(m 2) + (m 2) Distribute m and. m(m) + m( 2) + (m) + ( 2) Distribute m and again. m 2 2m + m 2 Multiply. m 2 m 2 Combine like-terms. PTS: DIF: Basic REF: Page 494 OBJ: 7-7.3 Multiplying Binomials NAT: 2.5.3.c TOP: 7-7 Multiplying Polynomials 8

27. ANS: x 2 + 6x + 5 (x + 5)(x + ) Use FOIL. x(x + ) + 5(x + ) Distribute x and 5. x(x) + x(+) + 5(x) + 5(+) Distribute x and 5 again. x 2 + x + 5x + 5 Multiply. x 2 + 6x + 5 Combine like-terms. PTS: DIF: Basic REF: Page 494 OBJ: 7-7.3 Multiplying Binomials NAT: 2.5.3.c TOP: 7-7 Multiplying Polynomials 28. ANS: x 2 4x + 4 (x 2) 2 ( a b) = a 2 2ab + b 2 Use the rule for ( a b). (x 2) 2 = x 2 2(x)(2) + 2 2 Use the FOIL method, and then combine like terms. x 2 4x + 4 Simplify. PTS: DIF: Basic REF: Page 502 OBJ: 7-8.2 Finding Products in the Form (a b)2 TOP: 7-8 Special Products of Binomials 29. ANS: p 2 6p + 9 (p 3) 2 NAT: 2.5.3.c ( a b) = a 2 2ab + b 2 Use the rule for ( a b). (p 3) 2 = p 2 2(p)(3) + 3 2 Use the FOIL method, and then combine like terms. p 2 6p + 9 Simplify. PTS: DIF: Basic REF: Page 502 OBJ: 7-8.2 Finding Products in the Form (a b)2 TOP: 7-8 Special Products of Binomials NAT: 2.5.3.c 9

30. ANS: z 2 4z + 49 (z 7) 2 ( a b) = a 2 2ab + b 2 Use the rule for ( a b). (z 7) 2 = z 2 2(z)(7) + 7 2 Use the FOIL method, and then combine like terms. z 2 4z + 49 Simplify. PTS: DIF: Basic REF: Page 502 OBJ: 7-8.2 Finding Products in the Form (a b)2 TOP: 7-8 Special Products of Binomials NAT: 2.5.3.c 0