Chapter 5: Uniform Circular Motion

Similar documents
PS113 Chapter 5 Dynamics of Uniform Circular Motion

Chapter 5. Uniform Circular Motion. a c =v 2 /r

Objective Notes Summary

Physics 111 Lecture 5 Circular Motion

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Chap 5. Circular Motion: Gravitation

Uniform Circular Motion

Chapter 8. Accelerated Circular Motion

Physics 201 Homework 4

Physics 101 Lecture 6 Circular Motion

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1

Centripetal Force. Lecture 11. Chapter 8. Course website:

Sections and Chapter 10

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Uniform Circular Motion

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Uniform Circular Motion

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

ω = θ θ o = θ θ = s r v = rω

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

CHAPTER 5: Circular Motion; Gravitation

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section

DYNAMICS OF UNIFORM CIRCULAR MOTION

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Motion in a Plane Uniform Circular Motion

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

1) Consider a particle moving with constant speed that experiences no net force. What path must this particle be taking?

Universal Gravitation


Midterm Exam #2, Part A

PHYS 1114, Lecture 21, March 6 Contents:

( ) ( ) 1.4 m ( ) Section 3.2: Centripetal Acceleration Tutorial 1 Practice, page Given: r = 25 km = m; v = 50.0 m/s. Required: a!

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible)

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

Physics 1114: Unit 5 Hand-out Homework (Answers)

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving.

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Between any two masses, there exists a mutual attractive force.

Physics 111. Lecture 14 (Walker: Ch. 6.5) Circular Motion Centripetal Acceleration Centripetal Force February 27, 2009

b) (5) What average force magnitude was applied by the students working together?

Introduction to Mechanics Centripetal Force

m1 m2 M 2 = M -1 L 3 T -2

Describing Circular motion

Orbits. Newton suggested that an object could be put into orbit if it were launched from a high hill at a high speed

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

Spring 2001 Physics 2048 Test 3 solutions

A car of mass m, traveling at constant speed, rides over the top of a circularly shaped hill as shown.

Circular Motion. x-y coordinate systems. Other coordinates... PHY circular-motion - J. Hedberg

Chapter 5. Applying Newton s Laws. Newton s Laws. r r. 1 st Law: An object at rest or traveling in uniform. 2 nd Law:

Pearson Physics Level 20 Unit III Circular Motion, Work, and Energy: Chapter 5 Solutions

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

Understanding the Concepts

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1

Name. Date. Period. Engage Examine the pictures on the left. 1. What is going on in these pictures?

Niraj Sir. circular motion;; SOLUTIONS TO CONCEPTS CHAPTER 7

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit:

Circular Orbits. and g =

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

Physics 2001 Problem Set 5 Solutions

= v 2. a c. = G m m 1 2. F g G = Review 5: Gravitation and Two-Dimensional Motion

Chapter 13 Gravitation

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn

OSCILLATIONS AND GRAVITATION

PROBLEM (page 126, 12 th edition)

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

As observed from the frame of reference of the sidewalk:

Chapter 12. Kinetics of Particles: Newton s Second Law

History of Astronomy - Part II. Tycho Brahe - An Observer. Johannes Kepler - A Theorist

Motion in Two Dimensions

Answers to test yourself questions

3.3 Centripetal Force

Circular Motion. Mr. Velazquez AP/Honors Physics

Physics 231 Lecture 17

Kinematics in 2-D (II)

3.2 Centripetal Acceleration

Escape Velocity. GMm ] B

Potential Energy and Conservation of Energy

Physics 107 TUTORIAL ASSIGNMENT #8

Circular motion. Objectives. Physics terms. Assessment. Equations 5/22/14. Describe the accelerated motion of objects moving in circles.

Lab #9: The Kinematics & Dynamics of. Circular Motion & Rotational Motion

Unit 4 Circular Motion and Centripetal Force

ΣF = r r v. Question 213. Checkpoints Chapter 6 CIRCULAR MOTION

Chapter 7. Rotational Motion Angles, Angular Velocity and Angular Acceleration Universal Law of Gravitation Kepler s Laws

Chapter 13: Gravitation

7 Circular Motion. 7-1 Centripetal Acceleration and Force. Period, Frequency, and Speed. Vocabulary

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

Ch 13 Universal Gravitation

2013 Checkpoints Chapter 6 CIRCULAR MOTION

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

2013 Checkpoints Chapter 7 GRAVITY

Chapter 4: The laws of motion. Newton s first law

PHYSICS NOTES GRAVITATION

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion

Transcription:

Chapte 5: Unifom Cicula Motion Motion at constant speed in a cicle Centipetal acceleation Banked cuves Obital motion Weightlessness, atificial gavity Vetical cicula motion

Centipetal Foce Acceleation towad cente of a cicula path of adius : v a c Foce needed to maintain the centipetal acceleation = centipetal foce: F c v m a c m ˆ Foce povided by tension in a sting, fiction, hoizontal component of aiplane s lift, gavity... Note: Centifugal foce is the foce you feel towad the outside of a cuve when going aound a cone. It s not eally a foce, but a consequence of Newton s fist law that says that things tavel at constant velocity unless a foce is applied.

Ca A uses ties with coefficient of static fiction 1.1 with the oad on an unbanked cuve. The maximum speed at which ca A can go aound this cuve is 5 m/s. Ca B has ties with fiction coefficient 0.85. What is the maximum speed at which ca B can negotiate the cuve?

Flying aound in cicles m g The Plane banks to tun in a hoizontal cicula path of adius m g

Poblem 5.5 A jet (m = 00,000 kg), flying at 13 m/s, banks to make a hoizontal tun of adius 3810 m. Calculate the necessay lifting foce. m g

Diving aound in cicles banked oad (no fiction) As fo plane but with lift foce eplaced by nomal foce:

Diving aound in cicles banked oad If you dive slowly, you slide down the slope. If you dive fast, you skid up the slope. If = 31 and = 316 m and thee is no fiction, what is the best speed to dive aound the banked cuve? = 316 m no fiction

Poblem 5.0 Two banked cuves have the same adius. Cuve A is banked at 13, cuve B at 19. A ca can tavel aound cuve A without elying on fiction at a speed of 18 m/s. At what speed can this ca tavel aound cuve B without elying on fiction?

Poblem 5.18 A ca tavels at 8 m/s aound a cuve of adius 150 m. A mass is suspended fom a sting fom inside the oof.

Obiting Eath The secet to flying is to thow youself at the eath and miss. Hitch Hike s Guide to the Galaxy The centipetal foce on the satellite is povided by the gavitational foce fom the eath. F c m a c v m ˆ GME m ˆ So: v GM E The smalle the adius, the geate the speed. Synchonous obit: peiod = 4 hous satellite stays above same pat of eath (above the equato) used by communications satellites what is the adius of the obit?

Synchonous obit what is the adius? The peiod of an obit is: Fom pevious page: So: T GM E v T GM 3/ E cicumfee nce speed v 1 GM E 3 T GME Keple s 3d law of planetay motion: T 3 With T = 4 3600 s, = 4.3 10 7 m = 4,300 km fom cente of eath, The speed of the satellite is: v 3070 m/s 11, 000km/h T

Poblem 5.3 The eath obits the sun once pe yea at a distance of 1.5 10 11 m. Venus obits the sun at a distance of 1.08 10 11 m. What is the length of the yea on Venus?

Poblem 5.3 A satellite has a mass of 5850 kg and is in cicula obit 4.1 10 5 m above the suface of a planet. The peiod of the obit is hous. The adius of the planet is 4.15 10 6 m. What is the tue weight of the satellite when it is at est on the planet s suface?

Fee Fall Weightlessness An obiting satellite is in fee fall thee s nothing hold it up. Only its fowad speed lets it miss the eath and keep obiting. Eveything in the satellite is acceleated towad the cente of the eath at the same ate. An object exets no foce on the bathoom scales as the scales ae also being acceleated towad the cente of the eath.

Atificial Gavity A space station is otating about its axis to povide an atificial gavity. At what speed must the suface of the space station move so that the astonaut expeiences a push on his feet equal to his weight on eath? The adius is 1700 m. F c v m mg Solve fo the velocity v g. 1700 m 9 80m s 19 m s

Atificial Gavity Poblem 5.8: Poblems of motion sickness stat to appea in a otating envionment when the otation ate is geate than evolutions / minute. Find the minimum adius of the station to allow an atificial gavity of one g (a c = 9.8 m/s) while avoiding motion sickness. v m mg v g a c mete v t 60sec 30 900ac 3m 4 F c a c

v1 F N 1 mg m v m F N v3 F N 3 mg m v4 m F N 4 Vetical Cicula Motion 1) foce towad cente weight lage than mg ) foce towad cente 3) foce towad cente ide falls off if 4) foce towad cente v3 mg m The ide falls off if v 3 F N 3 0 g

Poblem 5.40: A motocycle is taveling up one side of a hill and down the othe side. The cest is a cicula ac with a adius of 45 m. Detemine the maximum speed that the motocycle can have while moving ove the cest without losing contact with the oad. The net downwad foce on the bike at the cest of the hill allows the motobike to emain in contact with the gound. Then F N 0. That is: net downwad foce = centipetal foce, mv /.