Mathematics TASKS. GCSE to ASIA-level BRIDGING. tangent lines at a drffarent paint on the surface

Similar documents
LECTURE 21 Mohr s Method for Calculation of General Displacements. 1 The Reciprocal Theorem

ˆ (0.10 m) E ( N m /C ) 36 ˆj ( j C m)

Section 8.3 Polar Form of Complex Numbers

Complex Numbers Alpha, Round 1 Test #123

International Mathematical Olympiad. Preliminary Selection Contest 2012 Hong Kong. Outline of Solutions

Physics 4B. A positive value is obtained, so the current is counterclockwise around the circuit.

COMPLEX NUMBERS AND QUADRATIC EQUATIONS

Physics 4B. Question and 3 tie (clockwise), then 2 and 5 tie (zero), then 4 and 6 tie (counterclockwise) B i. ( T / s) = 1.74 V.

(c) (cos θ + i sin θ) 5 = cos 5 θ + 5 cos 4 θ (i sin θ) + 10 cos 3 θ(i sin θ) cos 2 θ(i sin θ) 3 + 5cos θ (i sin θ) 4 + (i sin θ) 5 (A1)

1. Estimation, Approximation and Errors Percentages Polynomials and Formulas Identities and Factorization 52

One-sided finite-difference approximations suitable for use with Richardson extrapolation

Formulas for the Determinant

PhysicsAndMathsTutor.com

Math1110 (Spring 2009) Prelim 3 - Solutions

The Fundamental Theorem of Algebra. Objective To use the Fundamental Theorem of Algebra to solve polynomial equations with complex solutions

AS-Level Maths: Statistics 1 for Edexcel

2 Finite difference basics

Module 14: THE INTEGRAL Exploring Calculus

WINTER 2017 EXAMINATION

Rao IIT Academy/ SSC - Board Exam 2018 / Mathematics Code-A / QP + Solutions JEE MEDICAL-UG BOARDS KVPY NTSE OLYMPIADS SSC - BOARD

Scatter Plot x

The Number of Ways to Write n as a Sum of ` Regular Figurate Numbers

MAE140 - Linear Circuits - Fall 13 Midterm, October 31

Section 3.6 Complex Zeros

Richard Socher, Henning Peters Elements of Statistical Learning I E[X] = arg min. E[(X b) 2 ]

Affine transformations and convexity

= z 20 z n. (k 20) + 4 z k = 4

arxiv: v1 [math.ho] 18 May 2008

Chapter 9: Statistical Inference and the Relationship between Two Variables

UNIT 3 EXPRESSIONS AND EQUATIONS Lesson 4: Fundamental Theorem of Algebra. Instruction. Guided Practice Example 1

MAE140 - Linear Circuits - Fall 10 Midterm, October 28

C/CS/Phy191 Problem Set 3 Solutions Out: Oct 1, 2008., where ( 00. ), so the overall state of the system is ) ( ( ( ( 00 ± 11 ), Φ ± = 1

8.1 Arc Length. What is the length of a curve? How can we approximate it? We could do it following the pattern we ve used before

Problem Solving in Math (Math 43900) Fall 2013

Unit 5: Quadratic Equations & Functions

Example: Suppose we want to build a classifier that recognizes WebPages of graduate students.

NUMERICAL DIFFERENTIATION

Polynomial Regression Models

HMMT February 2016 February 20, 2016

Quantum Runge-Lenz Vector and the Hydrogen Atom, the hidden SO(4) symmetry

MARKOV CHAIN AND HIDDEN MARKOV MODEL

Foundations of Arithmetic

Section 8.1 Exercises

1 Matrix representations of canonical matrices

CALCULUS CLASSROOM CAPSULES

Causal Diamonds. M. Aghili, L. Bombelli, B. Pilgrim

Statistics Chapter 4

MAE140 - Linear Circuits - Winter 16 Midterm, February 5

Linear Feature Engineering 11

Math 217 Fall 2013 Homework 2 Solutions

Solution of Linear System of Equations and Matrix Inversion Gauss Seidel Iteration Method

MOUNT SAINT JOSEPH MILPERRA

Week3, Chapter 4. Position and Displacement. Motion in Two Dimensions. Instantaneous Velocity. Average Velocity

Graph Reconstruction by Permutations

Review of Taylor Series. Read Section 1.2

Physics 114 Exam 3 Spring Name:

Experiment 1 Mass, volume and density

Economics 130. Lecture 4 Simple Linear Regression Continued

Numerical integration in more dimensions part 2. Remo Minero

x yi In chapter 14, we want to perform inference (i.e. calculate confidence intervals and perform tests of significance) in this setting.

What would be a reasonable choice of the quantization step Δ?

Module 2. Random Processes. Version 2 ECE IIT, Kharagpur

INDETERMINATE STRUCTURES METHOD OF CONSISTENT DEFORMATIONS (FORCE METHOD)

Associative Memories

#64. ΔS for Isothermal Mixing of Ideal Gases

For example, if the drawing pin was tossed 200 times and it landed point up on 140 of these trials,

APPENDIX 2 FITTING A STRAIGHT LINE TO OBSERVATIONS

U.C. Berkeley CS294: Beyond Worst-Case Analysis Luca Trevisan September 5, 2017

Workshop: Approximating energies and wave functions Quantum aspects of physical chemistry

AGC Introduction

The topics in this section concern with the second course objective. Correlation is a linear relation between two random variables.

3 Basic boundary value problems for analytic function in the upper half plane

Modelli Clamfim Equazione del Calore Lezione ottobre 2014

1 Generating functions, continued

5 The Rational Canonical Form

Pulse Coded Modulation

NAME and Section No.

Analytical Chemistry Calibration Curve Handout

Statistics MINITAB - Lab 2

ACTM State Calculus Competition Saturday April 30, 2011

Gravitational Acceleration: A case of constant acceleration (approx. 2 hr.) (6/7/11)

Summary with Examples for Root finding Methods -Bisection -Newton Raphson -Secant

Difference Equations

Chapter Newton s Method

= = = (a) Use the MATLAB command rref to solve the system. (b) Let A be the coefficient matrix and B be the right-hand side of the system.

k p theory for bulk semiconductors

Strain Energy in Linear Elastic Solids

Indeterminate pin-jointed frames (trusses)

Mathematics Intersection of Lines

Correlation and Regression. Correlation 9.1. Correlation. Chapter 9

For all questions, answer choice E) NOTA" means none of the above answers is correct.

The line method combined with spectral chebyshev for space-time fractional diffusion equation

Remark: Positive work is done on an object when the point of application of the force moves in the direction of the force.

How Strong Are Weak Patents? Joseph Farrell and Carl Shapiro. Supplementary Material Licensing Probabilistic Patents to Cournot Oligopolists *

More metrics on cartesian products

The Schrödinger Equation

Line Drawing and Clipping Week 1, Lecture 2

Exercises. 18 Algorithms

Thermodynamics II. Department of Chemical Engineering. Prof. Kim, Jong Hak

Important Instructions to the Examiners:

Transcription:

Mathematcs GCSE to ASA-eve BRDGNG TASKS tangent nes at a drffarent pant on the surface

Pease compete one ne from the task st eow. A students must compete the mdde task: worked examp :!car task *Topc st Factorsng Smutaneous Laws of ndces Quadratc Equatons Equatons Equaton of a ne Manpuatng Surds

The suject knowedge audt on the next two pages are a coecton of questons that w chaenge yo-ur mathematca sks. You w need to e confdent on these sks as they w e needed n your ASA-Leve course. There are a tota of 26 questons. You w need to compete a tota of 20 questons wth fu workng out shown. You have aso een provded wth one of the chapters you can expect to earn more aout n your course. Ths chapter s caed 'The noma Theorem'. Rea fe uses of the Bnoma Theorem e n engneerng, economcs, archtecture, physcs, weather forecast and many other feds. Your task s to use these notes to teach yoursef ths chapter. Use the exampes, questons and fnd other resources to hep you wth ths. You w e assessed on ths n Septemer.

F3w C]" 5 3 e 4 5. Q e-. ; F S B v, 'P.g -2 5. E E K E 09, G;. 0 W G' 0 B 7 - +3 2 W O 0 % m. g: 0. 2. 3 0 0 a 3 9 g + F P. C A -- 0." " Eg - + A 2 "2 V G;' g. 7 m B

Fnd the vaue off:. A cynder has ase radus X cm and heght h cm. A cone has ase radus X cm and heght h cm. The voume of the cynder and the voume of the cone are equa. Fnd h n terms of X. Gve your answer n ts smpest form. _ On the grd, sketch the graph of y = cos X for 0' & X & 360' _. @ T~e dagram shows a sod wax cynder. @ Rearrange - + - = - u v f to make u the suject of the formua. Gve your answer n ts smpest form. The cynder has ase radus hand heght 9x. The cynder s meted down and made nto a sphere of radus r. ABCD s a square. Fnd an expresson for r n terms of X. -.. -- P and D are ponts on the y-axs. A s a pont on the x-axs. PAB s a straght ne. @ The equaton of the ne that passes through the ponts A and D s y = -2x + 5 Fnd the ength of PD. - -- A Q The dagram shows a sod cone and a sod hemsphere. The cone has a ase of radus X cm and a heght of h cm.. The hemsphere has a ase of radus X cm. The surface area of the cone s equa to the surface area of the hemsphere. A C Fnd an expresson for h n terms of X. -F_- - 6 - cm -----t.- - -...- X 2 The dagram shows an equatera hange ABC wth sdes of ength 6 cm. P s the mdpont of AB. -. -. -. Q s the mdpont O~AC. APQ s a sector of a crce, centre A. Cacuate the area of the shaded regon. Gve Your answer correct to 3 sgnfcant fgures. -.. E 0 22 Sove the equaton - - =! Here s a quadratc sequence. 2 x+ 2 4 3 6 68 ~ The expresson for the nth term of ths sequence spd + qn...-. -.-..... Fnd the vaue ofp and the vaue ofq. AC=7cm. AB=3 cm.de= 9cm.. / A+3 cm -4 D. j 25. (-2, ), B(6,5) and C(4, k) are the vertces of a rght-anged trangeabc. Ange ABC s the rght ange. Fnd an equaton of the ne that passes through A and C. Gve your answer n.the form ay + x = c where 0, and c are ntegers... -. Ange ABC = ange CBD = ange BDE = 900 AngeBDE = 48" Cacuate the ength of CD Gve your answer correct to 3 sgnfcant fgures. @ dam the co-o~c turnng pont ofthe graph ofy =x2 + OX + 29..-.-.. ----

Dn.mnm;-r "nr thn kn--;- +hanrnm Thn h;nnrno thnnmm You can expand ( + X)" where n = 0,, 2,3,... EXPANSON COEFFCENTS ( + x)o = (+~)~~+ x (+~)~=+2x+x~ 2 (+~)~=+3x+3~~+~~ 3 3 (+~)~~+4~+6~~+4x~+x~ 4 6 4 (+x)5=+5x+0x2+0x3+5x4+xs 5 0 0 5 The coeffcents form a pattern known as Pasca's trange. Each coeffcent n the trange s the sum of the two coeffcents aove t., Pasca's Trange was pushed n 4 654, ut was known j ; to the Chnese and the Persans n the th century. -, Use Pasca's trange to wrte the expanson of ( + 2 ~ n ) ~ - ascendng powers of y. 5, - The coeffcents are, 6.5,20,5,6, (,! 8 E,.-. - - ( + ( 2~))~ E + 6(2y) + 5(2~)~ + ZO(ZY)~ + 5(2~)~ + 6 (2~)~ + ( 2~)~ = +2y+60~+60~+2403p+92f'+64y6 Wrte down the 6th row of Pasca's trange. Use the expanson of ( + X)", susttutng 2y for X ; Repacng wth a and x wth gves the noma expanson (a + )" where n = 0,, 2,3,... As n ncreases you can see that agan the coeffcents form Pasca's trange. expresson has two terms. exampes (a + ) E of the ~non~~a expansan. (a (a + )3=

n each expanson, the power of a starts at n and decreases y each term, so the powers are n, n -, The power of starts at 0 and ncreases y each term, so the powers are 0,,2,..., n?he sum of the powers of any ndvdua term s aways n ' m Expand (2 + 3t)4 2 =24+4x23x(3t)+6x22~(3t)2+4x2x(3t)3+(3t)4 W =6+96t+26t2+26t3+8t4.------a- -.-* Use Pasca's trange and the expanson of (a + )' susttutng 2 for a and 3tfor W-.. ---p---!, t woud e mpractca to use Pasca's trange every tme you need to work out a coeffcent-'say, for exampe, you want to fnd the coeffcent of XG n (X + a)o There s a genera rue for fndng ths coeffcent wthout needng to wrte out Pasca's trange up to the tenth row. n: stands for the product of a ntegers from to n. ' You read t as n factora. : "C, s the choose functon and you read t as 'n choose L t gves! the numer of posse ways of choosng r eements from a set of n [ eements when the order of choosng does not matter. For exampe,! ' the numer of comnatons n whch you can choose 2 as from a ;- ag of 5 as s 5C2 C - YOU use the choose functon ecause there are severa ways of gettng certan powers from an expanson. For exampe, there are 3 ways of gettng a2 from the expanson of (a + 3: a from ether the frst, second or thrd racket and from the other two rackets n / each case. The term n a2 for the expanson of (a + ) s therefore j 3Ca2 = 3a2 J p----.aly-.-.-_ Note that the frst coeffcent n each row s the 0th coeffcent. GC- s sometmes wrtten as (:) or,,c. ' Look for the factora utton on your cacuator. t may e denoted X! ),

Povnomas and the noma theorem The noma theorem A term n the expanson of (y + s gven y ky3x6 Fnd the vaue of k Use your cacuator to 9C6xgx (2x)"=84x3x64x6 fnd OC, and work out 26 ~5376Yx6 Smpfy to fnd the k = 5376 vaue of k The formua for the noma expanson of (a + )"s sometmes caed the noma theorem. For the expanson of ( + X)" ths gves Wrte the term n 2 n the expresson (22 - )5. Smpfy your answer.! a Take a = 2zand =- so the second power! 5~~~(2~)5-(-) must e. Use the coeffcent Sc., Cacuate the vaues of a S! 7! c! 2 Cacuate the vaues of a 5C, 9C, c "C, d 3C8 3 Work out the vaues of a () (:D) C 5 Fnd the frst four terms of these noma expansons n ascendng powers of x a (+x)' (-3~)~ C (+2~)' d (2-3~) e (X-2)' f (2x- ) 6 Use Pasca's trange to expand each of (:3) (7) these expressons. a (2-4y) (3+5)' c (42-:) 4 Use Pasca's trange to fnd the expansons of each of these expressons. 7 Fnd the frst three terms of these noma expansons n descendng powers of x a ( + 3 ~ ) ~ (-;)' a (2+x)' (-2x)' c (-g C (3-4' d (~+4)~ e (2x+3) f (;+4J

8 Use the noma theorem to expand each of these expressons. 2 Expand and smphfy each of these expressons. a 3x(2~-5)' (2+~)~(+~) 3 Expand and smpfy each of these expressons. + (3 + 2x)' a (5-2 ~ ) ~ 9 Fnd the terms ndcated n each of these expansons and smpfy your answers. a (P + 55 term n p2 (4 +y9 term n $ C (3+q)2 term n q7 d (4-3m)5 term n m3 e (22 - )5 term n 9 g (3x + 4y)' term n y h (2a - 3) terms n a5 and 4 (4p+f) term n p2 j (4a-$) terms n a5 and 5 k (:-$) terms n a7 and 5 0 Use the noma theorem to expand each of these expressons. 4 Expand and fuy smpfy each of these expressons. Show your workng. a [2+~)~+(-&Y [- - (2& + 33 5 Wrte down the frst four terms of the expanson of each of these n ascendng powers of X a (+2x)" (-3x)" 6 a Expand (+ 4 ~ n ascendng ) ~ powers of x up to and ncudng the term n 2 Use your answer to part a to estmate the vaue of (.04)~ 7 a Expand ( -2~)~ n ascendng powers of X up to and ncudng the term n x3 Use your answer to part a to estmate the vaue of (0.99)~ 8 Use the noma expanson to smpfy each of these expressons. Gve your fna soutons n the form a + f a (+&) (-&) Use the noma theorem to expand each, of these rackets. 9 Use the noma expanson to fuy smpfy each of these expressons. Gve your fna answers n surd form.

-P Pnvnnmnc nnr tp hnnma thenrpm T ~ hnnrnn P thenrpm @ Create an expresson n the form ( + X)" or (a + )" @ Use Pasca's trange or the noma theorem to fnd the requred terms of the noma expanson., @ Use your expanson to answer the queston n context. K; n CL ' E {! A foota squad conssts of 3 payers. Use the formua "C, = to show that there are (n-r)!r! 78 posse comnatons of choosng a team of payers from ths squad. m' j! an" 3 = (3- )!! 3x2~ xox... x2x -! 2!x X 0x... x 2x 3x2-2! Cance the common factor! ( a Usng the frst three terms of the noma expanson, estmate the vaue of.003' - a, By cacuatng the'fourth term n the expanson show that the estmate from part a s D. accurate to 3 decma paces. E a.0038 = ( + 0.003)' Rewrte n the form ( +A) Frst 3 terms f! "("-x2. = +nx+- Use the frst 3 terms of 2! genera expanson. = + 0.024 + 0.000252 =.024252 (=.024to 35f) Susttute vaues and "("-)(n-2) X 3 = 56(0.003)~ 3! smpfy. - Addng ths term w not affect the frst three decma paces.

How many posse ways are there to pck a 7's rugy team from a squad of 0 payers? 4 n the expanson of +- a postve P 2 How many posse ways are there to choose haf of the peope n a group of 20? - 3 A cue has sde ength (2s- 3w). Use the noma expanson to fnd ts voume. Use Pascas trang fnd the vaue of p a.05= correct to sx decma paces.96' correct to four decma paces. 5 Use the noma theorem to work out the vaue of a.055 correct to 4 decma paces, (g)'' correct to L sgnfcant fgmes. 6 Use the noma theorem to work out the (3 vaue of - correct to fve decma paces. ; 7 Work out the exact vaue of the mdde term ' n the expanson of (&+&)0 8 a Fnd the coeffcent ofx4 n the expanson of ( + X ) (2x - 3)5 Fnd the coeffcent of x3 n the expanson of (X - 2) (3x + 5)4 9 Fnd, n the expanson of coeffcent of 0 Fnd, n the expanson of coeffcent of f me frst three termsn the expanson of (+ax)" are +35x+490x2. Gven that n s a, postve nteger fnd the vaue of <. a n a 2 Gventhat(+xr =-24x+252xZ+ for a 7 postve nteger n fnd the vaue of ' 8 '3 n the expanson of (+2x): n a postve 6. nteger, the coeffcent of x2 s eght tmes 6. the coeffcent of X. Fnd the vaue of n A' ( 3 nteger, the coeffcents of x4 and x5 are equa. Cacuate the vaue of n 5 Fnd an expresson for Wrte your answers as poynomas n n wth smpfed coeffcents. 6 Fuy smpfy these expressons. n! (n + 3)! a - - (n + )! n(n+)! 7 Fnd the constant term n the expanson of (2 + 3x)3 ($ - 4r 8 Fnd the coeffcent of y3 n the expanson of (Y + 53 (2 - Y 5 Chaenge 9 A test nvoves 6 questons. For each queston there s a 25% chance that a,student w answer t correcty. a How many ways are there ' of gettng exacty two of the questons correct? c d What s the proaty of gettng the frst two questons correct then the next four questons ncorrect? What s the proaty of gettng exacty two questons correct? What s the proaty of gettng exacty haf of the questons correct?

You can expand ( + X)" where n = 0,,2,3,... ( +x)o= ( +X)'= + x EXPANSON (+~)~=+2x+ x2 (+~)~=+3~+3x~+x~ COEFFCENTS 2 3 3 The coeffcents form a pattern known as Pasca's trange. Each coeffcent n the trange s the sum of the two coeffcents aove t. was pushed n 654, ut was known to the Chnese and the Persans n the Use Pasca's trange to wrte the expanson of ( + 2 ~ n ) ~ ascendng powers of y. The coeffcents are, 6,5,20,5,6, ' ( + (2~))" E + 6(2y) + 5(2~/)~ + ZO(ZY)~ + 5(2~)~, +2y+60f+60~+2403p+92y5+64~ + 6(2y5 + ( 2 ~ ) ~ Wrte down the 6th row of Pasca's trange. Use the expanson of ( + X)", susttutng 2yfor X Repacng wth a and xwth gves the noma expanson (a + )" where n = 0,,2,3,... As n ncreases you can see that agan the coeffcents form Pasca's trange. expresson has two terms. m (a+)oc For ore exampes (a + ) E o te nona a+ expanson. (a + ' Z ' a2 + 2a + 2 (a + 3= a3 + 3a2 + 3a2 + 3

.--U. n each expanson, the power of a starts at n and decreases y each term, so the powers are n, n -, n-2,..., 0 The power of starts at 0 and ncreases y each term, so the powers are 0,,2,..., n The sum of the powers of any ndvdua term s aways n Expand (2 + 3t)" Use Pasca's trange and the expanson of (a + )4 :: susttutng 2 for a and B =24+4~23x(3t)+6~22~(3t)2+4x2x(3t)3+(3t)4 3tfor ~6+96t+26t2+26t3+8t4 t woud e mpractca to use Pasca's trange every tme you need to work out a coeffcent-say, for exampe, you want to fnd the coeffcent of 9 n (X + a) frst coeffcent n each row s the 0th There s a genera rue for fndng ths coeffcent wthout needng to coeffcent. out Pasca's trange up to the tenth row. --- ----S f "Cr s sometmes n! 3 rth coeffcent n the nth row s "Cr = (n-r)!r! j wrtten.s (") R k or "C r A--. ~,. ---.--. -. -..-.- tands for the product of a ntegers from to n. ; @g - ~ookfor the read t as n factora. : factora utton on For exampe,6!=6x5x4x3x2x=720 h your cacuator. t r :,. may e denoted X! L "C, s ; the choose functon and you read t as 'n choose r: t gves the r umer of posse ways of choosng r eements from a set of n eements when the order of choosng does not matter. For exampe, the numer of comnatons n whch you can choose 2 as from a ag of 5 as s 5C, You use the choose functon ecause there are severa ways of gettng certan powers from an expanson. For exampe, there are 3 ways of gettng a2 from the expanson of (a + )3: a from ether the frst, second or thrd racket and from the other two rackets n each case. The term n a2 for the expanson of (a + )3 s therefore 3C, a2 = 3a2 ' ' z.-7

Pnvnnmas and the hnnma theorem The hnom theorem A term n the expanson of (y + 2 ~ s ) gven ~ y ky3x6 Fnd the vaue of k! Use your cacuator to / 9C6xy'x ( 2 ~ ) ~ = 0 4 ~ ~ ~ 6 4 x ~ fnd 9C, and work out 26 g L! k = 5376 vaue of X ( The formua for the noma expanson of (a + )"s sometmes caed the noma theorem. (a + )" = an + "Can- + "C,U"-~~~ +... + "Cpn-'Lf +... + " For the expanson of ( +X)" ths gves Wrte the term n 2 n the expresson (225 - )5. Smpfy your answer. Take a = 2zand =- 5C,(2z)5-'(-) * 365~ 69~(-) The powers add to 5 so the second power must e. Use the coeffcent 5C E -2 8409 (2~)~ E 24~4 Cacuate the vaues of 5 Fnd the frst four terms of these noma expansons n ascendng powers of x a S! 7! c! 2 Cacuate the vaues of a (+x)' (-3x)' C (+2~)' d (2-3~) a 5C, 9C, c "C, d "C, 3 e (X-2)'' f (2x- ) Work out the vaues of 6 Use Pasca's trange to expand each of a ( ) ( ) d ( ) theseexpressons. / 3, \5 a (2-4y) (3 + 5)' 4 Use Pasca's trange - to fnd the expansons of each of these expressons. 7 Fnd the frst three terms of these noma expansons n descendng powers of X a ( + 3 ~ ) ~ [-;)5 a (2+~)~ (-2x)' C (-:)( [+$)5 c (3-x~ d (x+~)~ e (2x+3y0 f (:+4T C (42 - $)

' Use the noma theorem to expand each of these expressons. a (2+3t4 (3-2p4 2 Expand and smpfy each of these expressons. a 3x(2~-5)~ (2+~)~(+~) 3 Expand and smpfy each of these expressons. a (5-2 ~ + (3 ) + ~ 2x) Fnd the terms ndcated n each of these expansons and smpfy your answers. a (P + 55 term n (4 + Y ) ~ term n f C (3+q)2 term n q7 d (4-3m)5 term n m3 e (22 - )5 term n 2 g (3x + 4 ~ ) term ~ n y h (2a- 3) terms n a5 and 4 3 (.p+$) term n p2 j (4a-$) terms n a5 and V ; 0 Use the noma theorem to expand each of these expressons. a (L~+cP)~ (3 - w')~ C (2s2 + 5P)3 d (2s'- 4 Expand and fuy smpfy each of these expressons. Show your workng. a (2+,6)4+(-&)4 (- &) - (2& + 3 r 5 Wrte down the frst four terms of the expanson of each of these n ascendng powers of x a (+2x)" (-3x)" 6 a ~xpand ( + 4 ~ n ascendng ) ~ powers of x up to and ncudng the term n 2 Use your answer to part a to estmate the vaue of (.04)~ 7 a Expand (-24' n ascendng powers of xup to and ncudng the term n x3 Use your answer to part a to estmate the vaue of (0.99)~ 8 Use the noma expanson to smpfy each of these expressons. Gve your fna soutons n the form a + & a (+&)' (-6) Use the noma theorem to expand each, of these rackets. 9 Use the noma expanson to fuy smpfy each of these expressons. Gve your fna answers n surd form. a (+&r (-&) C (5-f) d (2&+5) e (&+C)' ' f (6-6)"

.?.L Poynomas and the noma theorem The noma theorem @ Create an expresson n the form ( + x ) or ~ (a + )" @Use Pasca's trange or the noma theorem to fnd the requred terms of the noma expanson. @ Use your expanson to answer the queston n context. n!, A foota squad conssts of 3 payers. Use the formua "C, = to show that there are -- (n-r)!r! - 78 posse comnatons of choosng a team of payers from ths squad. c- L >- - 3x2~ x0x... x2x 2!x X O X... x2x. 3x2 Cance the common =----- 2! factor! 56 - - 78, 2 B 'CO. a Usng the frst three terms of the noma expanson, estmate the vaue of.003a!?! By cacuatng the fourth term n the expanson show that the estmate from part a s (?- 3 accurate to 3 decma paces. -, :. 5!?< " a a.0038 = ( + 0.003)~ L.- Frst 3 terms n(n - ) = +nx+- x2 2! L Rewrte n the form ( + x) Use the frst 3 terms of the genera expanson. r = + a(0.003) + 20(0.003)' = + 0.024 + 0.000252 =.024252 (=.024to 3 sf) n(n-)(n-2) X 3 = 56(0.003)~ = 0.00000 5 2 Addng ths term w not affect the frst three decma paces. Susttute vaues and smpfy. 3!

S How many posse ways are there to pck a 7's rugy team from a squad of 0 payers? ( 3 2 How many posse ways are there to choose haf of the peope n a group of 20? ". 3 A cue has sde end (2s- 3w. Use the noma expanson to fnd ts voume. 4 Use Pasca's trange to fnd the vaue of a.056 correct to sx decma paces.963 correct to four decma paces. 5 Use the noma theorem to work out the vaue of a (E)".055 correct to 4 decma ~aces. correct to he sgnfcant fgures. (3. 6 Use the noma theorem to work out the vaue of - correct to fve decma paces. 7 Work out the exact vaue of the mdde term. n the expanson of (&+&)0 8 a Fnd the coeffcent ofx4 n the expanson of ( + X) (2x - 3)5 Fnd the coeffcent of x3 n the expanson of (X - 2) (3x + 5)' 9 Fnd, n the expanson of coeffcent of 0 Fnd, n the expanson of ($ + t3 r coeffcent of the The frst three terms n the expanson of (+ax)" are +35x+490x2. Gven that n s a postve nteger fnd the vaue of 2 Gventhat(+x)"-24x+252x2+... fora postve nteger n fnd the vaue of.3 n the expanson of (+2x)", n a postve nteger, the coeffcent of x2 s eght tmes the coeffcent of X. Fnd the vaue of n 4 n the expanson of + - n a postve nteger, the coeffcents of x4 and xs are equa. Cacuate the vaue of n 5 Fnd an expresson for Wrte your answers as poynomas n n wth smpfed coeffcents. 6 Fuy smpfy these expressons. n! (n + 3)! a - --- (n + )! n(n+)! 7 Fnd the constant term n the expanson of 8 Fnd the coeffcent of y3 n the expanson of (U + 53 (2 - Y 5 Chaenge 9 A test nvoves 6 questons.,. For each queston there s a 25% chance that a,student w answer t correcty. a HO& many ways are there of gettng exacty two of the questons correct? What s the proaty of gettng the frst two questons correct then the next four questons ncorrect? c d What s the proaty of gettng exacty two questons correct? What s the proaty of gettng exacty haf of the questons correct?