If you're given a mass percent, you can use it as a conversion factor between the element and the compound

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Announcements Wednesday, September 23, 2009 MasteringChemistry due dates (all at 11:59 pm): Ch 3: Fri, Sep 25 Exam 1: next Mon, Sep 28. 20-25 multiple choice questions Short answer (naming, chemical equations) 2 show your work problems For exam practice: Practice exams on webpage End-of-chapter problems (check answers in back of book) Rework MasteringChemistry exercises for practice (without using hints) Mass percent as a conversion factor If you're given a mass percent, you can use it as a conversion factor between the element and the compound A 3.5 kg sample is found to contain 2.6% Pb. How many grams of lead are present? Mass percent = per 100 grams 100 g sample : g Pb ch3d Page 1 ch3d Page 2

Conversion factors from chemical formulas Chemical formulas give the ratio of atoms in a compound This can also be used to construct mole ratios 1 mol Fe 2 (SO 4 ) 3 contains: mol Fe mol S mol O How many O atoms are in 8.6 mol Fe 2 (SO 4 ) 3? How many grams S are in 2.50 mol Fe 2 (SO 4 ) 3? 1. Determining a chemical formula from element masses the elements present in a compound masses OR mass percentages of elements You can calculate: The empirical formula A compound made of C, H, and O is found to contain 68.8% C, 5.0% H, and 26.2% O. What is the empirical formula? If given percentages, convert them to grams per 100 g sample. If you're missing one element's mass, subtract from a given total mass. How many grams Fe are in 18.25 g Fe 2 (SO 4 ) 3? to convert from mass compound to g element, use mass cpd mol cpd mol element mass element 2. Convert each mass to moles using the molar mass of elements 3. Use moles to make a formula, divide by smallest numbe 4. Make the subscripts whole numbers by multiplying all by 2, 3, 4, or 5. ch3d Page 3 ch3d Page 4

Calculating molecular formulas empirical formula molar mass You can calculate: molecular formula Molecular formulas are always whole-number multiples of empirical formulas Molecular: C 3 H 6 Empirical: ( ) x n= C n H 2n -For this molecule, n= C 3 H 6 formula mass = 47.028 g/mol CH 2 formula mass = 14.026 g/mol = n= Mass spectrometry can be used to determine molar mass of a compound experimentally. A compound with empirical formula of CH 2 O has a molar mass of 60.05 g/mol. What is its molecular formula? n= molar mass empirical formula mass = 1. 2. Combustion analysis Combustion: compound + O 2 CO 2 + H 2 O masses of CO 2 and H 2 O produced which elements are in the sample total sample mass (if elements other than C and H present) You can calculate: empirical formula (molecular formula if a molar mass is given) A 4.30 mg sample containing C, H, and O produces 8.59 mg CO 2 and 3.52 mg H 2 O upon combustion. What is its empirical formula? Convert masses of CO 2 and H 2 O to mol C and mol H If elements other than C and H, calculate masses of C and H, subtract from the total to get mass of other element, and calculate moles of the other element. 3. Use moles of each element to calculate the empirical formula as before. ch3d Page 5 ch3d Page 6

Difficult combustion problem A 6.54 mg sample of a compound containing C, H, N, and O produced 8.29 mg CO 2, 4.53 mg H 2 O, and 1.76 mg N 2 upon combustion. Its molar mass was found to be 208.2 g/mol. What is the molecular formula of this compound? Chemical equations A chemical equationrepresents a chemical reaction with chemical formulas. Phase/state labels: (s) (l) (g) (aq) Reactants: substances that will react (on left side of equation) Products: substances resulting from reaction (on right side of equation) Write the chemical equation with phase labels: Solid calcium reacts with chlorine gas to produce solid calcium chloride: ch3d Page 7 ch3d Page 8

Balancing chemical equations Balancing chemical equations:add coefficients in front of formulas so that the number of each type of atom is the same on the reactants side and products side 1. Only add coefficients, never change subscripts 2. Save elements (O 2, Cl 2, Na, etc) for last 3. Multiply fractions through so coefficients are simplest whole numbers 4. Count polyatomic ions together if they don't react, but count atoms if the polyatomic ion does react C 4 H 10 + O 2 CO 2 + H 2 O Fe + O 2 Fe 2 O 3 Write a balanced chemical equation: Sodium carbonate solid reacts with aluminum chloride to form aluminum carbonate and sodium chloride. ch3d Page 9