International GCSE in Mathematics A - Paper H mark scheme 1 5 or 5 or 5 or two of 0, 40, 60 0, 60, 90 45, 90, 105 5 and 5 and 5 or all of 0, 40, 60, 80 180 0, 60, 90 180 45, 90, 105 180 for one of 0, 0, 45 written as product of prime factors or list of at least multiples of any two of 0, 0, 45 M1 180 A1 for 180 or 5 oe for 7n + k (k may be zero) 7n 5 oe A1 1 (10 14) 9 oe (= 108) AO M1 for area of cross section 108 6 (=648) M1 (dep on previous M1) for volume of prism 648 0.7 M1 (independent) 45.6 4 A1 accept 454 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs) 1
4 a p 9 1 AO1 B1 b m 1 1 AO1 B1 c 1 1 AO1 B1 d 1 1 AO1 B1 e 5x + 5 = x 10 or for removing bracket or dividing all terms by 5 x 10 x 7 5 5 eg. 5x x = 10 5 or M1 for isolating x terms in a correct equation 10 x 7 x 5 5 15 A1 dep on M1 5 14000 4 (=56000) NB. multiplication by 4 may occur before or after percentage decrease 0.075 56000 (=400) or 0.075 14000 (=1050) 56000 4000 or 14000 1050 M1 51 800 4 A1 M1 (dep) 14 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs)
6 a triangle with vertices (, -1) (, -4) (5, -4) 1 AO B1 b Rotation AO B1 centre (-, 0) B1 90 o anticlockwise B1 accept +90 0, 70 o clockwise, 70 o NB. If more than one transformation then no marks can be awarded 7 a 4 15 (=60) or ab c d 4 15 or 4 15 9 b d a = 10 or a = 11 or a = 1 10 or b + c = 9 11 = 8 AO M1 1 A1 AO M1 ft from (a) (can be implied by 11, b c, 1 OR a, b, c, d with b + c = 8) 14 A1 cao 8 0.0 40 000 (=800) or 1.0 40 000 (=40800) or 400 "40800" 0.0(=816) and "41616" 0.0(=8.) OR 448. M1 (dep) method to find interest for year and year 4448. A1 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs) 15
9 x + y = 1 or 6x + y = 6 x 6y = 7 + x y = 9 multiplication of one equation with correct operation selected or rearrangement of one equation with substitution into second eg. x = 1 or 15 + y = 1 M1 (dep) correct method to find second variable 5, A1 for both solutions dependent on correct working 10 14 9 14 or 9 16 96 or 7 7 4 9 9 M1 answer given A1 correct answer from correct working 11 (6 ) 180 (=70) AO M1 complete method to find sum of interior angles 70 (86 + 1 + 140 + 105) (=66) or 70 454 (=66) M1 dep on 1 st method mark 66 M1 dep on 1 st method mark 1 4 A1 16 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs)
1 a 8, 5, 50, 90, 11, 10 b Plotting points from table at ends of interval Points joined with curve or line segments c 60 (or 60.5) indicated on cf graph or stated 1 AO B1 cao AO M1 + ½ sq ft from sensible table ie clear attempt to add frequencies A1 ft from points if 4 or 5 correct or if all points are plotted consistently within each interval at the correct heights Accept cf graph which is not joined to the origin NB A bar chart, unless it has a curve going consistently through a point in each bar, scores no points. AO M1 for 60 (or 60.5) indicated on cf axis or stated approx A1 If M1 scored, ft from cf graph If no indication of method, ft only from correct curve & if answer is correct (+ ½ sq tolerance) award M1 A1 1 Pc 1 ab ( P c) b a b ( P c) a Isolate term in b M1 Isolate b A1 oe with b as the subject Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs) 17
14 a correct points plotted eg (0, 4) and (, 0) 4x + y = 1 drawn A1 b AO1 B Correct region Correct region B for x = 4 and y = drawn and consistent shading correct for at least two inequalities B1 for x = 4 and y = drawn 15 a AO1 B Correct diagram A 14 M B for over-lapping circles with 7 in intersection and at least 8 1 other correct numbers 7 16 B1 for over-lapping circles with 7 in intersection 5 18 D 0 b 4 100 oe 1 AO B1 ft from diagram c 1 AO B1 ft from diagram oe 46 18 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs)
16 a k M g k M g or 4 k oe or (k = 75).5 M 75 g A1 M1 implies first M1 k accept M with k = 75 stated elsewhere in question g b 1 ( ) g 75 9 oe or 75 15 A1 17 a 1 AO1 B1 b 1 AO1 B1 c g() = 6 0.75 oe A1 18 correct length scale factor AO M1 eg 84 864 or or 457 78 A1 M1 for complete method Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs) 19
19 E, B, D, A AO1 B All correct B for correct B1 for correct 0 a 4 9 8 b 5 4 4 5 or 0 0 oe 9 8 9 8 7 7 1 6 5 9 AO M1 A1 oe, eg AO M Allow 0.16(666...) rounded or truncated to at least dp M1 for 4 5 or 5 4 or 0 oe 9 8 9 8 7 or oe 4 5 4 1 or 9 8 9 8 1 '1' 5 4 6 9 8 Accept fractions evaluated 0 7, 1 0.77 7 0.166 A1 rounded or truncated to at least dp oe, e.g. 40 7 0 or 6 10 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs)
1 sin 47 sin MLN 1.8 8.5 MLN sin 1 sin 47 8.5 1.8 AO M1 Or method using a right angled triangle to find length MX (MX is perpendicular to LN) sin 47 MLN = 6.7(7...) A1 LMX= 6. LMN = 180 47 6.7... or 106(.606 ) M1 Or cos MX 8.5 1 8.5sin 47 1.8 M1 LMN = 6. + (180 (90+47)) or 106(.606 ) 1 8.5 1.8 sin("106") M1 56. 6 A1 Accept an answer that rounds to 56. or 56.4 unless clearly obtained from incorrect working. a (x 4x ) + 9 or (x 4x + 9 ) ((x ) ) + 9 or M1 ((x ) + 9 ) (x ) + 1 A1 b explanation 1 AO1 B1 E.g. Because minimum is at (, 1) Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs) 11
BC BA AC or AO M1 9 4 or 7 1 '7' '1' 4 1 1 1 1 4 50 oe M1 dep A1 accept 7.07(06 ) method to rationalise M1 correct expansion of brackets 1 B1 may be seen before expansion shown 4 A1 answer from fully correct working with all steps seen 5 (v = ) t 5 t 8 for out of terms differentiated correctly t 10t 8 = 0 A1 correct equation (t + )(t 4) = 0 M1 for method to solve quadratic 4 4 A1 t = 4 only 1 Pearson Edexcel International GCSE in Mathematics (Specification A) Sample Assessment Materials (SAMs)