How much air is required by the people in this lecture theatre during this lecture?

Similar documents
Q.28 Q.29 Q.30. Q.31 Evaluate: ( log x ) Q.32 Evaluate: ( ) Q.33. Q.34 Evaluate: Q.35 Q.36 Q.37 Q.38 Q.39 Q.40 Q.41 Q.42. Q.43 Evaluate : ( x 2) Q.

Integration by Guessing

PREPARATORY MATHEMATICS FOR ENGINEERS

ASSERTION AND REASON

COLLECTION OF SUPPLEMENTARY PROBLEMS CALCULUS II

page 11 equation (1.2-10c), break the bar over the right side in the middle

SOLVED EXAMPLES. Ex.1 If f(x) = , then. is equal to- Ex.5. f(x) equals - (A) 2 (B) 1/2 (C) 0 (D) 1 (A) 1 (B) 2. (D) Does not exist = [2(1 h)+1]= 3

National Quali cations

National Quali cations

Section 3: Antiderivatives of Formulas

Lectures 2 & 3 - Population ecology mathematics refresher

IX. Ordinary Differential Equations

[ ] Review. For a discrete-time periodic signal xn with period N, the Fourier series representation is

Chapter 2 Infinite Series Page 1 of 11. Chapter 2 : Infinite Series

Calculus Cheat Sheet. ( x) Relationship between the limit and one-sided limits. lim f ( x ) Does Not Exist

Section 5.1/5.2: Areas and Distances the Definite Integral

Chapter 3 Fourier Series Representation of Periodic Signals

PhysicsAndMathsTutor.com

Quantum Mechanics & Spectroscopy Prof. Jason Goodpaster. Problem Set #2 ANSWER KEY (5 questions, 10 points)

INTEGRALS. Chapter 7. d dx. 7.1 Overview Let d dx F (x) = f (x). Then, we write f ( x)

Calculus Summary Sheet

1985 AP Calculus BC: Section I

Integration Continued. Integration by Parts Solving Definite Integrals: Area Under a Curve Improper Integrals

Chapter 9 Infinite Series

Linear Algebra Existence of the determinant. Expansion according to a row.

Limits Indeterminate Forms and L Hospital s Rule

Chapter 8 Approximation Methods, Hueckel Theory

Vtusolution.in FOURIER SERIES. Dr.A.T.Eswara Professor and Head Department of Mathematics P.E.S.College of Engineering Mandya

Math 3B Midterm Review

1 Tangent Line Problem

k m The reason that his is very useful can be seen by examining the Taylor series expansion of some potential V(x) about a minimum point:

Review Handout For Math 2280

terms of discrete sequences can only take values that are discrete as opposed to

The z-transform. Dept. of Electronics Eng. -1- DH26029 Signals and Systems

( a n ) converges or diverges.

PhysicsAndMathsTutor.com

CONTINUITY AND DIFFERENTIABILITY

PhysicsAndMathsTutor.com

IIT JEE MATHS MATRICES AND DETERMINANTS

MM1. Introduction to State-Space Method

Chapter 16. 1) is a particular point on the graph of the function. 1. y, where x y 1

TOPIC 5: INTEGRATION

Probability & Statistics,

Some Common Fixed Point Theorems for a Pair of Non expansive Mappings in Generalized Exponential Convex Metric Space

Chapter 7 Infinite Series

Multiplicative Versions of Infinitesimal Calculus

LE230: Numerical Technique In Electrical Engineering

Linford 1. Kyle Linford. Math 211. Honors Project. Theorems to Analyze: Theorem 2.4 The Limit of a Function Involving a Radical (A4)

, between the vertical lines x a and x b. Given a demand curve, having price as a function of quantity, p f (x) at height k is the curve f ( x,

10.5 Power Series. In this section, we are going to start talking about power series. A power series is a series of the form

CIVL 8/ D Boundary Value Problems - Rectangular Elements 1/7

Math 1272 Solutions for Fall 2004 Final Exam

# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths.

Solutions to Problem Set 7

+ x. x 2x. 12. dx. 24. dx + 1)

Lectures 5-8: Fourier Series

The Reimann Integral is a formal limit definition of a definite integral

(HELD ON 22nd MAY SUNDAY 2016) MATHEMATICS CODE - 2 [PAPER -2]

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best

TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS

Instructions for Section 1

SOLVED EXAMPLES. be the foci of an ellipse with eccentricity e. For any point P on the ellipse, prove that. tan

National Quali cations SPECIMEN ONLY

u x v x dx u x v x v x u x dx d u x v x u x v x dx u x v x dx Integration by Parts Formula

TRANSFORMS AND PARTIAL DIFFERENTIAL EQUATIONS

Topic 4 Fourier Series. Today

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right:

On Gaussian Distribution

The Theory of Small Reflections

Extension Formulas of Lauricella s Functions by Applications of Dixon s Summation Theorem

 n. A Very Interesting Example + + = d. + x3. + 5x4. math 131 power series, part ii 7. One of the first power series we examined was. 2!

Exponential and Logarithmic Functions (4.1, 4.2, 4.4, 4.6)

CLASS XI CHAPTER 3. Theorem 1 (sine formula) In any triangle, sides are proportional to the sines of the opposite angles. That is, in a triangle ABC

GUC (Dr. Hany Hammad) 4/20/2016

Lecture 4 Recursive Algorithm Analysis. Merge Sort Solving Recurrences The Master Theorem

Definition Integral. over[ ab, ] the sum of the form. 2. Definite Integral

EXERCISE - 01 CHECK YOUR GRASP

National Quali cations AHEXEMPLAR PAPER ONLY

Option 3. b) xe dx = and therefore the series is convergent. 12 a) Divergent b) Convergent Proof 15 For. p = 1 1so the series diverges.

Lectures 9 IIR Systems: First Order System

Integration by Parts

Mathematical Notation Math Calculus & Analytic Geometry I

The limit comparison test

CITY UNIVERSITY LONDON

Periodic Structures. Filter Design by the Image Parameter Method

1 Introduction to Modulo 7 Arithmetic

[Q. Booklet Number]

Math 104: Final exam solutions

ECE COMBINATIONAL BUILDING BLOCKS - INVEST 13 DECODERS AND ENCODERS

Lecture 38 (Trapped Particles) Physics Spring 2018 Douglas Fields

Winter 2016 COMP-250: Introduction to Computer Science. Lecture 23, April 5, 2016

INTEGRATION TECHNIQUES (TRIG, LOG, EXP FUNCTIONS)

CREATED USING THE RSC COMMUNICATION TEMPLATE (VER. 2.1) - SEE FOR DETAILS

MSLC Math 151 WI09 Exam 2 Review Solutions

Where k is either given or determined from the data and c is an arbitrary constant.

f(t)dt 2δ f(x) f(t)dt 0 and b f(t)dt = 0 gives F (b) = 0. Since F is increasing, this means that

Eigenfunction Expansion. For a given function on the internal a x b the eigenfunction expansion of f(x):

MAHESH TUTORIALS SUBJECT : Maths(012) First Preliminary Exam Model Answer Paper

Lecture 4 Recursive Algorithm Analysis. Merge Sort Solving Recurrences The Master Theorem

Ch 1.2: Solutions of Some Differential Equations

Transcription:

3 NTEGRATON tgrtio is us to swr qustios rltig to Ar Volum Totl qutity such s: Wht is th wig r of Boig 747? How much will this yr projct cost? How much wtr os this rsrvoir hol? How much ir is rquir y th popl i this lctur thtr urig this lctur? t is s o th cocpt of summtio of ifiitsimls. this lctur w will look t th o vril cs oly. Nt trm w will look t multipl itgrtio.

3. Dfiit tgrls Oft cll Rim itgrls ftr Brhr Rim (85-866). Th fiit itgrl of fuctio f () from to is fi s: y y f() f ( ) Ar ou y th curv y f ( ) lis y, (, r limits) y Rmmr tht rs low th is r gtiv v -v

This r c clcult y iviig it ito strips of with δ y y f() δ Cosir th r of th strip tw r A pproimtio to th r is δa f ( f ( ). r ( ) ) r r r r δ r r δ. ζ r r r Thr will som vlu of This pproimtio will gt ttr s δ. ζ such tht δ A f ( ζ ) δ r r r Th th r S r f ( ζ ) δ ctly s δ, ζ r r, w fi r f ( ) lim δ r f ( ζ ) δ r 3

Cosir th r, A( ) f ( ) f ( t) t i which t is ummy vril of itgrtio. (w us t to voi cofusio with, th uppr limit i this cs) y f(ζ) Cosir δ A( δ) f ( t) t A δa A() δa Agi, thr is som ζ such tht < ζ < δ, for which δ A( ) f ( ζ ) δ (s δ, f ( ζ ) f ( ) ). δ t() By fiitio, ζ A( ) lim A( δ) A( ) lim f ( ζ ) δ f ( ) δ δ δ δ i.. tgrtio is th rvrs procss to Diffrtitio 4

Cosir y fuctio F ( ) A( ) C itgrt tw,. Th F( ) A( ),, sic A ( ), C F() Th f ( t)t F( ) F( ) For, th fiit itgrl is f ( t)t F( ) F( ). Empl: Th vlocity of cclrtig cr is giv y v t ) 5 t ( m/s. 5 v(t) How fr os it trvl from t to t 6s? Sic istc is oti from v t 6 5

So 6 6 t v( t)t 5 t Not tht 5 t t 5 t t t Th, puttig ( t ) 5 t, 6 Distc ( 6) () 5 6 5( ) 499 m.499 km. This is th sis of Dfiit tgrls. F( ) Th rltioship tw f ( ) F( ) F( ) f ( t) t c grlis. 6

3. fiit tgrls W c fi itgrtio s th ivrs of iffrtitio: F( ) f f ( ), th th ifiit itgrl of f () with rspct to is fi y f ) F( ) C ( whr C is ipt of. prctic, th two forms of itgrtio giv th sm rsult, with f ) f ( t)t ( D, whr D is ipt of. (For fuctios of o vril, C D r costts, ut this coms ltr i th cours.) 3 Dfiit itgrls such s t t t giv vlu s rsult. fiit itgrls such s t t t t C giv fuctios 7

3.4 qulitis for tgrls () f ( ) f ( ) f() f() - () f ( ) g( ), if f ( ) g( ) for < <. g() f() 8

3.6 TECHNQUES FOR NTEGRATON Rcogitio f you kow iffrtitio, you kow itgrl / 3 / 3, 3 3 3.g. sic ( ) ( ) 3 3 / 3 3 Th ( ) ( ) / 3 C So r th tls of iffrtils i HLT p.8. ckwrs Sustitutio to Rcogisl Form.g. Put sihy, hc coshy y 9

sih y cosh y coshy y y coshy Th y c sih C T hlf gl formul - spcil sustitutio Tious ut usful: w fi t t θ th θ θ t sc θ t θ ( t )θ so θ t ( t ) Similrly θ t θ θ t siθ si cos or θ sc t t tθ t cosθ cos θ si θ ( t ( t ) )

.g. t t cos - t t t t t c t c Similrly, cot c cos Try t hlf gl formul wh ll ls fils

- SYMMETRY O Fuctios f ( ) f ( ) f Oviously ( ) yf() - Ev Fuctios f ( ) f ( ) yf() - So f ( ) f ( )

vrs Fuctios y y f () or f ( ) From th igrm So, f ( y)y y y f ( ) f ( y) y y c f ( ) ( crful with costts of itgrtio, i.. c ov) c y c c y f - (y) y f() f - (y) y f() Empl y ; ly Th l y y y c (l y) y y (l y ) c c 3

Prtil Frctios Sic l( ) C ( ) Prtil frctios c simplify itgrls..g. ( )( ) A B C D Put ( ) ( ) ( )( ) ( ) Multiplyig out th umrtor: A ( )( ) B( ) C( )( ) D( ) 4

5 Collctig powrs of : : 3 C B A A : D B A 4 B : D C B A 4 3 C : A D So ) ( ) 4( 3 ) 4( C ) ( ) l( 4 3 ) l( 4 l ( ) ( ) C ) ( l 4 3 / 4 /

6 tgrtio y Prts Th Prouct rul for iffrtitio, u v v u uv ) ( c rwritt s u v uv v u ) ( tgrtig u v uv v u ) ( i.. u v uv v u This c us to tur itgrl ito sir form.

Empl cos Put u, v cos, v si Th si si () Put v u, si si [ ( cos ) ()( cos ) ] si cos si C Tip: f t first you o t succ try it th othr wy rou 7

Rcursio Empl: cos (si) si si Try th othr wy rou?? [ ] cos cos si ( si ) cos Solutio : ( si cos ) This c us to grt Ructio Formul 8

9 Empl ( ) ( ) - ( ) ( ) Dos this hlp?

Sic C w c grt ll th othr :- C ) ( ( ) ( ) C ) ( ( ) C tc. Tip: Alwys chck y iffrtitig th swr

Furthr mpls: π π () si θ θ si π [ si θ cosθ ] ( ) π si θ ( ) ( ). θ (-cosθ )θ θ π ( si θ ) Hc. ( )si θ θ cos θ θ π m, m () (for you to try ) cos si. Show tht m, m,. m