The Derivative of a Function Measuring Rates of Change of a function. Secant line. f(x) f(x 0 ) Average rate of change of with respect to over,

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The Derivative of a Function Measuring Rates of Change of a function y f(x) f(x 0 ) P Q Secant line x 0 x x Average rate of change of with respect to over, " " " " - Slope of secant line through, and, 71

Instantaneous rate of change of with respect to at point Tangent line y f(x) f(x 0 ) P Q Secant line I x 0 x lim x - Slope of tangent line at, [provided the limit exists] 72

Slope of Tangent Lines Definition: So, lim lim [provided the limit exists] Since the tangent line passes through,, its equation is Alternate notation: x 0 ; lim 73

What is a Derivative Definition: The function [ prime of ] derived from and defined by lim is called the derivative of with respect to (wrt) 74

Exercise: Find, if 1 75

Solution: lim lim 1 1 lim 1 2 1 2 1 lim 2 76

Exercise: Let check that the tangent slope of is "" everywhere 77

Solution: lim lim 1 lim 1 lim 78

Functions: Differentiable (or not!) at a single point? We say: is differentiable at [has a derivative at if ) exists. The process of finding derivatives of function is called differentiation If a function has a derivative at a point it is said to be differentiable at that point e.g. is differentiable at every point in its domain except 0 Geometric reason: 79

A function differentiable at a point is continuous at that point Theorem: If is differentiable at then is continuous at Proof: Since is differentiable at we know exists lim To show is continuous at we must show [definition of a continuous function] We can rewrite: lim lim 0 80

Rewriting once more, we need to show with lim 0 lim lim lim 0 0 So, if is not continuous at, then is not differentiable at 81

can fail to be differentiable! Here are the ways in which can fail to be differentiable at Example: is not differentiable at 0 which does not exist because 0 0 lim lim 1, 0 1, 0 82

Functions Differentiable on an Interval On open intervals: a function must be differentiable at each point (2-sided limit) On interval with endpoints: a function must be differentiable at each point on the open interval (2-sided limit) and have a left/right hand limits at the end points Definition: Left Hand Derivative Right Hand Derivative lim lim 83

Other Derivative Notations If, At So, lim lim 84

Finding Derivatives 1. Differentiation technique: lim 2. The derivative of any constant function is zero 0 Obvious: Horizontal line has a horizontal tangent at each point 85

3. The Power Rule: For any real number Proof for positive integers, 0, 1,2, Recall: 86

lim lim 1 lim 87

Examples: function 1. derivative 2 2 3 3 88

Constance Multiple, Sum and Difference Rules Theorem: If, are differentiable at and is any real number Then 89

Exercise: Find 2, 5 3 6 90

Solution: function 2, 1. derivative 0,5, 0,5, 5 3 10 3 6 6 6 18 9 2 91

The Product Rule Observe: Example: 1, 0, 1, 0 1 0 1 0 92

Theorem: If, are differentiable at then 93

Proof: lim lim lim lim lim lim lim lim 94

Sometimes we write Generalized Product Rule: 95

Example: 2 1 Solution: 3 2 1 2 1 6 6 2 8 6 or: 2 4 2 3 8 6 96

The Quotient Rule Observe: Example: 1, 0, 1, 1 1 0 0 1 0 97

Theorem: If, are differentiable at, Then We also write: 98

Handy fact: 1 0 1 99

Example: 3 5 Solution 3 25 3 1 5 30 6 3 5 3 30 5 100

The Chain Rule: Derivatives of Composition of functions Motivating example: 1. Find Our only technique is to multiply this out weary tedious. Instead, think of 1 as the composition of two functions. Suppose 1 Then 1 1 We can use the derivatives of and 1 to calculate the derivative of 1 101

Rewrite as 1, 1 Then To get we multiply 100, 2 100 1 2 200 1 102

Theorem [The Chain Rule] If is differentiable at and is differentiable at Then is differentiable at 103

Exercise: Find 4 1 Solution: 4 1 4 ; 1 4 2 12 16 16 16 1 104

Derivatives of Trigonometric Functions Recall: Then lim 1; lim 1 0 sin lim sin lim 1 lim 1 lim lim 105

1 1 106

Exercises: Find function 2 1. derivative 22 sin 2 2 107

Derivatives of Inverse Trigonometric Functions 1 1 1 1 1 1 1 1 108

Derivatives Involving Logarithms We find For 0 [Domain of ] We need two facts to recall: 1. is continuous So, at any we have: The limit moves through the lim lim 109

2. Definition: is that number which 1 approaches, as 2,71828 lim 1 1 Let, so 0 0 Thus [Limit is two-sided] lim 1 110

So, ln lim lim 1 ln lim 1 ln 1 Let so 0, 0 lim 1 ln1 1 lim ln1 1 ln lim 1 1 1 111

So, 1, 0 Generalized version: 1, 0 112

So, 1, 0 log, 0 log 113

Exercises: function 2 1 1. derivative 1 2 1 2 1 0,5 1 1 1 3 3 114

Derivatives of Exponential Functions What is, 0, 0, 1? 115

Development: Since 1 1 116

Important case: If 117

Exercises: function 1. derivative 5 5 2 5 2 2 1 2 22 2 322 2 2 322 118

Notation for Derivatives of Derivatives [Higher order Derivatives] 1 st Derivative: 2 nd Derivative:,,,,,, The second derivative of wrt For higher derivatives, The differentiations rules are the same 119

Exercise: 3 2 4 2 12 6 2 4 36 12 2 72 12 72 0 5,6,7 120