Nuclear Structure V: Application to Time-Reversal Violation (and Atomic Electric Dipole Moments)

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T Symmetry EDM s Octupole Deformation Other Nuclei Nuclear Structure V: Application to Time-Reversal Violation (and Atomic Electric Dipole Moments) J. Engel University of North Carolina June 16, 2005

T Symmetry EDM s Octupole Deformation Other Nuclei Outline 1 T Symmetry T is Different Observed T Violation 2 EDM s Connection with T Violation Shielding 3 Octupole Deformation Why It Enhances Atomic EDM s 225 Ra 4 Other Nuclei

T Symmetry EDM s Octupole Deformation Other Nuclei T is Different Observed T Violation Outline 1 T Symmetry T is Different Observed T Violation 2 EDM s Connection with T Violation Shielding 3 Octupole Deformation Why It Enhances Atomic EDM s 225 Ra 4 Other Nuclei

T Symmetry EDM s Octupole Deformation Other Nuclei T is Different Observed T Violation The T Operator in QM is Different. Not linear: T [x, p]t 1 = [x, p] so i is odd under T. Has no eigenstates in the conventional sense: T a = a T (α a ) = α T a = α a α a for α complex Typical physical states J, M not even close to eigenstates of T As a result, T violation doesn t show up as mixing of states with opposite T

T Symmetry EDM s Octupole Deformation Other Nuclei T is Different Observed T Violation Is T Violated in the Real World? Yup! Violation is seen in decay of K-mesons (direct) and B-mesons (through CP violation). And we strongly believe that T ( CP) violation played an important role in the early universe, causing excess of matter over antimatter.

T Symmetry EDM s Octupole Deformation Other Nuclei T is Different Observed T Violation What is the Source of T -Violation? K and B phenomena almost certainly due to a phase in the 3 3 CKM matrix, which converts (d, s, b) to weak eigenstates that couple to W and Z. But this can t be responsible for baryogenesis, which must arise outside the standard model, e.g. through supersymmetry heavy neutrinos Higgs sector... To confuse things more, there s the strong CP problem. We need to see T -violation outside mesonic systems to understand its sources. EDM s are not sensitive to CKM T violation, but are to other sources. They re already putting pressure on supersymmetry.

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding Outline 1 T Symmetry T is Different Observed T Violation 2 EDM s Connection with T Violation Shielding 3 Octupole Deformation Why It Enhances Atomic EDM s 225 Ra 4 Other Nuclei

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding What Do EDM s Have to Do With T Consider nondegenerate ground state g : J, M. Symmetry under rotations R y (π) for a vector operator like d i e i r i, g : J, M d g : J, M = g : J, M d g : J, M. T takes M to M, like R y (π). But d is odd under R y (π) and even under T, so for T conserved g : J, M d g : J, M = + g : J, M d g : J, M. Together with the first equation, this implies d = 0. If T is violated, argument fails because T can take g : JM to a different state with J, M.

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding There are EDM Experiments on Neutrons, Atoms... Basic principle: B E B E f f H = µ B d E and there is a change in precession frequency (linear in E) when E is flipped.

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding How Do Things Get EDM s? N _ g π Underlying theory generates T -violating πnn vertex: A neutron gets a EDM from a diagram like this: N? g q q π γ _ g π g n p n A nucleus can get one from a nucleon EDM or through a T -violating nucleon-nucleon interaction, e.g. N g H T (12) ḡ g isopsin ops. ( σ 1 σ 2 ) ( 1 2 ) exp( m π r 1 r 2 ) r 1 r 2 Finally, nuclear EDM induces atomic EDM. The goal of the atomic experiments discussed here is to constrain (or determine) the three ḡ s.

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding Shielding by Electrons Unfortunately for atomic experiments: Theorem (Schiff) The nuclear dipole moment causes the atomic electrons to rearrange themselves so that they develop a dipole moment opposite that of the nucleus. In the limit of nonrelativistic electrons and a point nucleus the electrons dipole moment exactly cancels the nuclear moment, so that the net atomic dipole moment vanishes! Skip proof

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding Shielding by Electrons Proof Consider atom with nonrelativistic constituents (with dipole moments d k ) held together by electrostatic forces. The atom has a bare edm d k d k and a Hamiltonian H = k p 2 k 2m k + k V ( r k ) k dk E k = H 0 + k = H 0 +i k (1/e k ) d k V ( r k ) [ ] (1/e k ) dk p k, H 0 K.E. + Coulomb dipole perturbation

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding Shielding by Electrons The perturbing Hamiltonian H d = i k [ ] (1/e k ) dk p k, H 0 shifts the ground state 0 to 0 = 0 + m m m H d 0 E 0 E m = 0 + m m i k (1/e k) d k p k 0 (E 0 E m ) E m 0 E m ( = 1 + i ) (1/e k ) d k p k 0 k

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding Shielding by Electrons The induced dipole moment d is d = 0 j e j r j 0 = 0 (1 i k (1/e k) ) ( ) d k p k j e j r j (1 + i k (1/e k) ) d k p k 0 [ = i 0 j e j r j, k (1/e k) ] d k p k 0 = 0 k dk 0 = k dk = d So the net EDM is zero!

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding All is Not Lost, Though... The nucleus has finite size. Shielding is not complete, and nuclear T violation can still induce atomic EDM d. Post-screening nucleus-electron interaction doesn t explicitly involve the nuclear EDM D, but rather a related quantity: The nuclear Schiff moment S e p rp 2 r p. p If, as you d expect, S R 2 N D, then d is down from D by ( R 2 ) O N RA 2 10 8. Ughh! Fortunately the large nuclear charge and relativistic wave functions offset this factor by 10Z 2 10 5. Overall suppression of D is only about 10 3.

T Symmetry EDM s Octupole Deformation Other Nuclei Connection with T Violation Shielding Comparing Limits Limit on the neutron EDM: Limit on the 199 Hg EDM: d N < 6 10 26 e cm d < 2 10 28 e cm So neutron measurements still more sensitive, assuming d N and D are comparable. But conclusion depends on cause of T violation; sometimes D > d N and 199 Hg provides better limits. And in certain other atoms: S >> R 2 N D making them much better places to look. Why? Collective nuclear effects (i.e. funny shape deformation)

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Outline 1 T Symmetry T is Different Observed T Violation 2 EDM s Connection with T Violation Shielding 3 Octupole Deformation Why It Enhances Atomic EDM s 225 Ra 4 Other Nuclei

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Nuclear Deformation

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Analogy: Collective Quadrupole Moments Ψ JM DMK J (θ, φ) χintr. K, where K is the projection of J on the symmetry axis. The intrinsic states are deformed. When K = 0, the quadrupole operator can be written as Q µ = D 2 µ0q intr. 0 so that matrix elements within a rotational band look like: Ψ JM Q µ Ψ J M = ( ) three D functions χ intr. Q0 intr. χ intr. So the quadrupole moment and E 2 transition rates are proportional to the intrinsic quadrupole moment, which can be large/collective.

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Now What About Schiff Moments? Need a T-violating nuclear interaction H T to get one. Treating H T as perturbation: S = m 0 S m m H T 0 E 0 E m + c.c. where 0 is the unperturbed nuclear ground state. S will not be enhanced if nucleus is only quadrupole deformed. Need octupole deformation too. Then, two collective effects help you out: 1 Parity doubling 2 Large and robust intrinsic Schiff moments

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Point 1: Parity Doublets When the intrinsic state is asymmetric, it breaks parity (spontaneously) because and are degenerate, with P =. Physical states must have good parity: χ intr. (±) = 1/ 2 ( ± ) These will be nearly degenerate if the deformation is rigid. So our expression for the Schiff moment becomes S 0 S 0 0 H T 0 E 0 E 0 + c.c. where 0 and 0 form a parity doublet.

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Spectrum of 225 Ra

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Point 2: Large Intrinsic Schiff Moment 0 S 0 S intr. S intr. just like in quadrupole transitions, so that and furthermore S 2/3 S intr. H T E 0 E 0 S intr. > R 2 N D intr.. Dipole moments in these nuclei are collective also, but subject to a cancellation: they vanish in the limit ρ neutron = ρ proton. Net result: S is enhanced in an octupole-deformed nucleus like 225 Ra by 2 or 3 orders of magnitude over 199 Hg, according to collective-model estimates. Skip 225 Ra calculation

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra 2 or 3 orders? The Issue of H T An order of magnitude uncertainty can deter experimentalists. Why is it there and can it be reduced? The matrix element of H T depends on spin, and so is very sensitive to the state of the valence particles. For heavy pions: H T a σ n ρ n + b σ n ρ p +... In simple collective models one valence nucleon carries all the spin. But in reality the valence nucleon can polarize the core. (This quenches magnetic moments and E1 transitions.) To treat delicate spin-dependent Hamiltonian accurately, need a good self-consistent mean-field wave function with which to start. Much of core polarization is then automatically accounted for.

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Calculation in 225 Ra P- and T -Breaking Odd-A Hartree-Fock We break all possible symmetries. Core polarization of all kinds automatically included. For the effective NN interaction we used a Skyrme force SkO specially fitted to spin excitations (Gamow-Teller resonances) All this is accomplished with the program HFODD (Dobaczewski et al).

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Existing Forces and GT Resonances Quality of forces in GT channel more or less random.

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Fitting the Spin-Dependent Parameters

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Results of the Calculation Density distributions of the Radium isotopes

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Binding and Separation Energies Single-Particle Energies

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra...... Octupole, Dipole, Schiff Stuff

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra Resuts for Schiff Moment We can write S z as S z = a 0 ḡ 0 + a 1 ḡ 1 + a 2 ḡ 2, where the a s are what we calculate. With SkO : a 0 a 1 a 2 zero-range (direct only) 5.1 10.4 10.1 finite-range (direct only) 1.9 6.3 3.8 finite-range + src (direct only) 1.7 6.0 3.5 finite-range + src (direct + exchange) 1.5 6.0 4.0

225 T Symmetry EDM s Octupole Deformation Other Nuclei Why It Enhances Atomic EDM s Ra What It All Means For 225 Ra, get S z Ra = 1.5 gḡ 0 + 6.0 gḡ 1 4.0 gḡ 2 (e fm 3 ) The best calculation in 199 Hg (RPA polarization of a spherical even-even core) by Dmitriev and Sen kov gives S z Hg = 0.0004 gḡ 0 + 0.06 gḡ 1 + 0.009 gḡ 2 (e fm 3 ) If the three ḡ s are comparable, the Schiff moment in Ra is larger by over 100, on average. Dzuba et al. [PRA66, 012111 (2002)] find further enhancement of the Ra EDM by a factor of 3 in the atomic physics. Looks good for the Ra experiment!

T Symmetry EDM s Octupole Deformation Other Nuclei Outline 1 T Symmetry T is Different Observed T Violation 2 EDM s Connection with T Violation Shielding 3 Octupole Deformation Why It Enhances Atomic EDM s 225 Ra 4 Other Nuclei

T Symmetry EDM s Octupole Deformation Other Nuclei 199 Hg Obviously important. Calculations exist but but have problems. Just completed Skyrme-QRPA calculation In 199 Hg, there is no parity doublet. Lots of states contribute to sum. But the isoscalar Schiff ( = isoscalar E1) strength distribution is actually measured in some nuclei (like 208 Pb). 36 Strength (10 3 fm 6 /MeV) 30 24 18 12 6 E X1 E X2 SkP SIII SkO 0 0 6 12 18 24 30 36 42 Energy (MeV)

T Symmetry EDM s Octupole Deformation Other Nuclei The 199 Hg Schiff Moment Calculation by J.H. de Jesus 1 Obtained ground and excited states of 198 Hg core in spherical HFB+QRPA. 2 Included effects of core polarization on S in 199 Hg. T odd RPA T odd x + x RPA Strong +...

T Symmetry EDM s Octupole Deformation Other Nuclei Results Early result of Flambaum et al S z Hg = 0.09 gḡ 0 + 0.09 gḡ 1 + 0.2 gḡ 2 (e fm 3 ) Dmitriev and Sen kov: Landau-Migdal RPA S z Hg = 0.0004 gḡ 0 + 0.06 gḡ 1 + 0.009 gḡ 2 (e fm 3 ) Small isoscalar coefficient would mean that Hg no longer sets best limit on θ QCD. Our result with SkO S z Hg = 0.006 gḡ 0 + 0.07 gḡ 1 + 0.009 gḡ 2 (e fm 3 ) Results with other Skyrme interactions are the same to within factors of 2 or 3. Finally... It s possible to improve these calculations, but not easy!

T Symmetry EDM s Octupole Deformation Other Nuclei THE END