Lecture 7: Damped and Driven Oscillations

Similar documents
Lecture 6: Phase Space and Damped Oscillations

Lecture 5: Equilibrium and Oscillations

Lab 11 LRC Circuits, Damped Forced Harmonic Motion

ECE 2100 Circuit Analysis

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

Dispersion Ref Feynman Vol-I, Ch-31

Chapter 3 Kinematics in Two Dimensions; Vectors

PHYS 314 HOMEWORK #3

Plan o o. I(t) Divide problem into sub-problems Modify schematic and coordinate system (if needed) Write general equations

Physics 321 Solutions for Final Exam

Chapter 2 GAUSS LAW Recommended Problems:

CHAPTER 8b Static Equilibrium Units

MODULE 1. e x + c. [You can t separate a demominator, but you can divide a single denominator into each numerator term] a + b a(a + b)+1 = a + b

Exercise 3 Identification of parameters of the vibrating system with one degree of freedom

Physics 2B Chapter 23 Notes - Faraday s Law & Inductors Spring 2018

Solution to HW14 Fall-2002

Lecture 2: Single-particle Motion

Interference is when two (or more) sets of waves meet and combine to produce a new pattern.

ENGI 4430 Parametric Vector Functions Page 2-01

39th International Physics Olympiad - Hanoi - Vietnam Theoretical Problem No. 1 /Solution. Solution

L a) Calculate the maximum allowable midspan deflection (w o ) critical under which the beam will slide off its support.

AP Physics Kinematic Wrap Up

Thermodynamics Partial Outline of Topics

Part a: Writing the nodal equations and solving for v o gives the magnitude and phase response: tan ( 0.25 )

Function notation & composite functions Factoring Dividing polynomials Remainder theorem & factor property

Harmonic Motion (HM) Oscillation with Laminar Damping

37 Maxwell s Equations

Lead/Lag Compensator Frequency Domain Properties and Design Methods

Three charges, all with a charge of 10 C are situated as shown (each grid line is separated by 1 meter).

CHAPTER 6 -- ENERGY. Approach #2: Using the component of mg along the line of d:

Corrections for the textbook answers: Sec 6.1 #8h)covert angle to a positive by adding period #9b) # rad/sec

Sections 15.1 to 15.12, 16.1 and 16.2 of the textbook (Robbins-Miller) cover the materials required for this topic.

LHS Mathematics Department Honors Pre-Calculus Final Exam 2002 Answers

Revision: August 19, E Main Suite D Pullman, WA (509) Voice and Fax

We can see from the graph above that the intersection is, i.e., [ ).

This section is primarily focused on tools to aid us in finding roots/zeros/ -intercepts of polynomials. Essentially, our focus turns to solving.

Trigonometric Ratios Unit 5 Tentative TEST date

LEARNING : At the end of the lesson, students should be able to: OUTCOMES a) state trigonometric ratios of sin,cos, tan, cosec, sec and cot

PHYSICS 151 Notes for Online Lecture #23

Chapter 10. Simple Harmonic Motion and Elasticity. Example 1 A Tire Pressure Gauge

ELECTRON CYCLOTRON HEATING OF AN ANISOTROPIC PLASMA. December 4, PLP No. 322

Differentiation Applications 1: Related Rates

2. Find i, v, and the power dissipated in the 6-Ω resistor in the following figure.

CHAPTER 5. Solutions for Exercises

20 Faraday s Law and Maxwell s Extension to Ampere s Law

SPH3U1 Lesson 06 Kinematics

Computational modeling techniques

NUMBERS, MATHEMATICS AND EQUATIONS

Kinematic transformation of mechanical behavior Neville Hogan

1 PreCalculus AP Unit G Rotational Trig (MCR) Name:

ECE 2100 Circuit Analysis

Q x = cos 1 30 = 53.1 South

Computational modeling techniques

Admin. MDP Search Trees. Optimal Quantities. Reinforcement Learning

OTHER USES OF THE ICRH COUPL ING CO IL. November 1975

Section 5.8 Notes Page Exponential Growth and Decay Models; Newton s Law

Department of Economics, University of California, Davis Ecn 200C Micro Theory Professor Giacomo Bonanno. Insurance Markets

Mathacle PSet ---- Algebra, Trigonometry Functions Level Number Name: Date:

Physics 401 Classical Physics Laboratory. Torsional Oscillator. Contents

Section I5: Feedback in Operational Amplifiers

Physics 2010 Motion with Constant Acceleration Experiment 1

Introduction: A Generalized approach for computing the trajectories associated with the Newtonian N Body Problem

Example 1. A robot has a mass of 60 kg. How much does that robot weigh sitting on the earth at sea level? Given: m. Find: Relationships: W

Chapter 2 SOUND WAVES

Lecture 17: The solar wind

Dead-beat controller design

Review Problems 3. Four FIR Filter Types

Calculus Placement Review. x x. =. Find each of the following. 9 = 4 ( )

Determining the Accuracy of Modal Parameter Estimation Methods

Chapter 9 Vector Differential Calculus, Grad, Div, Curl

Cop yri ht 2006, Barr Mabillard.

Medium Scale Integrated (MSI) devices [Sections 2.9 and 2.10]

Thermodynamics and Equilibrium

Materials Engineering 272-C Fall 2001, Lecture 7 & 8 Fundamentals of Diffusion

EEO 401 Digital Signal Processing Prof. Mark Fowler

Fall 2013 Physics 172 Recitation 3 Momentum and Springs

February 28, 2013 COMMENTS ON DIFFUSION, DIFFUSIVITY AND DERIVATION OF HYPERBOLIC EQUATIONS DESCRIBING THE DIFFUSION PHENOMENA

CLASS XI SET A PHYSICS

Spring Pendulum with Dry and Viscous Damping

MATHEMATICS SYLLABUS SECONDARY 5th YEAR

ANSWER KEY FOR MATH 10 SAMPLE EXAMINATION. Instructions: If asked to label the axes please use real world (contextual) labels

Supplementary Course Notes Adding and Subtracting AC Voltages and Currents

CHAPTER 24: INFERENCE IN REGRESSION. Chapter 24: Make inferences about the population from which the sample data came.

General Chemistry II, Unit I: Study Guide (part I)

Lecture 20a. Circuit Topologies and Techniques: Opamps

[COLLEGE ALGEBRA EXAM I REVIEW TOPICS] ( u s e t h i s t o m a k e s u r e y o u a r e r e a d y )

Supplementary Course Notes Adding and Subtracting AC Voltages and Currents

ECE 5318/6352 Antenna Engineering. Spring 2006 Dr. Stuart Long. Chapter 6. Part 7 Schelkunoff s Polynomial

CHEM Thermodynamics. Change in Gibbs Free Energy, G. Review. Gibbs Free Energy, G. Review

Examiner: Dr. Mohamed Elsharnoby Time: 180 min. Attempt all the following questions Solve the following five questions, and assume any missing data

Lyapunov Stability Stability of Equilibrium Points

Power Flow in Electromagnetic Waves. The time-dependent power flow density of an electromagnetic wave is given by the instantaneous Poynting vector

Cambridge Assessment International Education Cambridge Ordinary Level. Published

Physics 212. Lecture 12. Today's Concept: Magnetic Force on moving charges. Physics 212 Lecture 12, Slide 1

Distributions, spatial statistics and a Bayesian perspective

Einstein's special relativity the essentials

Physics 101 Math Review. Solutions

Chapter 5: Diffusion (2)

Transcription:

Lecture 7: Damped and Driven Oscillatins

Last time, we fund fr underdamped scillatrs: βt x t = e A1 + A csω1t + i A1 A sinω1t A 1 and A are cmplex numbers, but ur answer must be real Implies that A 1 and A are cmplex cnjugates Can write them as: We nw have: ( ) ( ) ( ) A = Ae A = Ae i δ 1 Since we can always redefine the cnstant A t get rid f the in frnt f the equatin, the general slutin is: iδ βt ( ) = ( + + ) x t e A csδ i sinδ csδ i sinδ csω1t ( cs sin cs sin ) sin βt [ csδ csω sinδ sinω ] + ia δ + i δ δ + i δ ω1t = Ae t t βt = Ae cs( ω t + δ ) 1 βt ( ) 1 1 1 x t = Ae cs( ω t + δ )

Prperties f underdamped mtin An underdamped system still scillates: 1 1 8 6 4 - -4-6 -8 4 6 8 1 Nte, thugh, that the mtin is nt peridic it never returns t the same pint with the same velcity as befre The quantity ω 1 can still be related t the time interval between crssings f the x axis Fr light damping, ω 1 is very clse t ω

Underdamped Mtin in Phase Space Since the mtin is nt peridic, we n lnger get clsed lps. In additin t amplitude, path depends n β: ω ο =.5, Α = 1 β =.5 v 5 4 3 1-1 -5-1 5 x 1 - -3-4 -5 β =.1 v 5 4 3 1-1 -5-1 5 x 1 - -3-4 -5 β =.5 v 5 4 3 1-1 -5-1 5 x 1 - -3-4 -5

Mre Damping If the damping parameter is large enugh that the system is called critically damped β ω = In this case expressins f the frm te βt als satisfy the equatin f mtin, s the general slutin is: t x ( t) = ( A + Bt) e β Frm this we see that A is the initial psitin and B-βA is the initial velcity In this case the slutins d nt scillate, but can crss the x-axis nce if there is a large initial velcity tward equlibrium

The mtin may lk like any f the fllwing: 35 3 5 15 1 5-5 4 6 8 1-1 -15 Initial velcity negative 35 3 5 15 1 5 Initial velcity zer 4 6 8 1 5 15 1 5 Initial velcity psitive 4 6 8 1 N matter what the initial cnditins are, the system settles t within a given distance f equilibrium faster with critical damping than with any ther chice f damping parameter Autmbile shck absrbers, fr example, shuld be critically damped

Overdamped Mtin If β is even larger the system is verdamped The quantity ω β ω is real, s the psitin as a functin f time is given by: Features: βt ωt ω ( ) = + x t e A1 e A e N hint f scillatry mtin here (ω can t be interpreted as an angular frequency) Psitin always appraches equilibrium fr large t But nt as quickly as a critically-damped system wuld System can crss x = nce (as in critically damped case) t

Driven Oscillatins There are many examples in which an external agent applies a frce t an scillatr Smetimes essential t intended functin (e.g., a radi), smetimes an annyance (e.g., wind gusts hitting a skyscraper) This external frce can have any frm, but we ll cnsider the particular case f a sinusidal frce: F = F sinωt This ω can be anything we chse it s nt related t the natural scillatin frequency ω This means the equatin f mtin is: mx + bx + kx = F sinωt

After dividing thrugh by m and redefining the cnstants, this becmes: x + β x + ω x = A ωt sin This is knwn as a linear inhmgeneus equatin T slve it, let s assume that the slutin has a frm similar t what appears n the right-hand side: x ( t) = C sin ( ωt + δ ) Substituting this int the equatin f mtin gives: Cω sin ( ωt + δ ) + Cβω cs( ωt + δ ) + ω C sin ( ωt + δ ) = Asinωt

Expanding gives: Cω [ csωt sinδ + csδ sinωt] + Cβω [ csωt csδ sinωt sinδ ] + ω C [ csωt sinδ + csδ sinωt] Asinωt ω ω δ + βω δ + ω δ cs t C sin C cs C sin + + = sinωt A Cω csδ Cβω sinδ ω C csδ The nly way this can be true fr all t is if C and δ are chsen such that bth terms in [] are zer =

Starting with the csine term, we need: βω csδ + ω ω sinδ = ( ) βω tanδ = ( ω ω ) Frm this, we can determine sinδ and csδ, and then find C: ( ) A C ω csδ βω sinδ + ω csδ = C = = = ( ) ω ω csδ + βω sinδ ( ) ( ) A ω ω + 4β ω A ω ω ω ω βω + βω ω ω + β ω ω ω + β ω A ( ) ( ) 4 4

Putting all f this tgether, we have the slutin: x ( t) A 1 βω = sin ωt tan + ( ω ) ( ) ω 4β ω ω ω Lks great, but yu may ntice a prblem there s n freedm here (recall that A = F /m) and surely the mtin depends smehw n initial cnditins, desn t it? T see where these cme in, cnsider what happens if we add a term t ur slutin: x ( t) = x ( t) + x ( t) c where: x + β x + ω x = c c c

This new functin als satisfies the equatin f mtin: ( ) ( ) ( x ) x + β x + ω x = x + x + β x + x + ω x + c c c = x + β x + ω x + x + β x + ω x = Asinωt + c c c But the equatin that x c (t) satisfies is just the equatin fr an undriven scillatr S all the slutins we ve already explred are part f the slutin fr driven scillatrs as well Linear inhmgeneus differential equatins in general have this prperty Slutin is the sum f a particular slutin that depends n the right-hand side f the equatin and a cmplementary slutin that gives zer n the right-hand side

Sme ther features f the slutin: 1. The cmplementary functin ges as e βt. The initial cnditins affect nly the cmplementary slutin, nt the particular slutin Bth f these facts tell us that the cmplementary slutin gives transient effects After a lng time has passed, the scillatr will mve as described by the particular slutin, n matter what the initial cnditins are

Resnance The amplitude attained by a driven scillatr depends strngly n the driving frequency The maximum ccurs at the resnance frequency : da dω ω R ( ) 1 4ω R ω ωr + 8β ωr = = 3/ ( ω ωr ) 4β ω + R ω ω = β ω R = ω β R The sharpness f the resnance depends n the strength f the damping

Q Factr Actually, it s the rati f the resnance frequency t the damping parameter that determines the sharpness f the resnance. We define: Q ω ω β R = = β β A.5.4.3..1 Q = Q = 5 Q = 1 4 6 8 1 Omega A.5..15.1.5 4 6 8 1 Omega A.5.4.3..1 4 6 8 1 Omega