Maths for Computer Graphics

Similar documents
Continuity and Differentiability of the Trigonometric Functions

1 Solutions to the in class part

INTRODUCTION AND MATHEMATICAL CONCEPTS

INTRODUCTION AND MATHEMATICAL CONCEPTS

Exam 1 Review Solutions

= 0 and states ''hence there is a stationary point'' All aspects of the proof dx must be correct (c)

Preview from Notesale.co.uk Page 2 of 42

b 1 A = bh h r V = pr

Review for Exam IV MATH 1113 sections 51 & 52 Fall 2018

6.2 TRIGONOMETRY OF RIGHT TRIANGLES

SFU UBC UNBC Uvic Calculus Challenge Examination June 5, 2008, 12:00 15:00

Recall we measure angles in terms of degrees or radians: 360 = 2π radians

Pre-Calculus Review Preemptive Strike

1 Calculus. 1.1 Gradients and the Derivative. Q f(x+h) f(x)

1watt=1W=1kg m 2 /s 3

1. Which one of the following expressions is not equal to all the others? 1 C. 1 D. 25x. 2. Simplify this expression as much as possible.

Lecture XVII. Abstract We introduce the concept of directional derivative of a scalar function and discuss its relation with the gradient operator.

Math Test No Calculator

Chapter 6. Trigonometric Functions of Angles. 6.1 Angle Measure. 1 radians = 180º. π 1. To convert degrees to radians, multiply by.

(a) At what number x = a does f have a removable discontinuity? What value f(a) should be assigned to f at x = a in order to make f continuous at a?

Excerpt from "Calculus" 2013 AoPS Inc.

5.1 We will begin this section with the definition of a rational expression. We

Recall from our discussion of continuity in lecture a function is continuous at a point x = a if and only if

Combining functions: algebraic methods

1 The concept of limits (p.217 p.229, p.242 p.249, p.255 p.256) 1.1 Limits Consider the function determined by the formula 3. x since at this point

WYSE Academic Challenge 2004 Sectional Mathematics Solution Set

Math 34A Practice Final Solutions Fall 2007

Derivatives of trigonometric functions

University Mathematics 2

Section 15.6 Directional Derivatives and the Gradient Vector

Fundamentals of Mathematics (MATH 1510)

Models and Applications

A = h w (1) Error Analysis Physics 141

A: Derivatives of Circular Functions. ( x) The central angle measures one radian. Arc Length of r

JUST THE MATHS SLIDES NUMBER 3.1. TRIGONOMETRY 1 (Angles & trigonometric functions) A.J.Hobson

Solution. Solution. f (x) = (cos x)2 cos(2x) 2 sin(2x) 2 cos x ( sin x) (cos x) 4. f (π/4) = ( 2/2) ( 2/2) ( 2/2) ( 2/2) 4.

Continuity and Differentiability Worksheet

Practice Test - Chapter 4

HOMEWORK HELP 2 FOR MATH 151

1. Trigonometry.notebook. September 29, Trigonometry. hypotenuse opposite. Recall: adjacent

Excursions in Computing Science: Week v Milli-micro-nano-..math Part II

Analytic Functions. Differentiable Functions of a Complex Variable

MATH 1A Midterm Practice September 29, 2014

Work with a partner. a. Write a formula for the area A of a parallelogram.

Chapter 3. Radian Measure and Circular Functions. Copyright 2005 Pearson Education, Inc.

MATH 155A FALL 13 PRACTICE MIDTERM 1 SOLUTIONS. needs to be non-zero, thus x 1. Also 1 +

Stepped-Impedance Low-Pass Filters

Lecture Notes Di erentiating Trigonometric Functions page 1

SECTION 1.10: DIFFERENCE QUOTIENTS LEARNING OBJECTIVES

Click here to see an animation of the derivative

Given an arc of length s on a circle of radius r, the radian measure of the central angle subtended by the arc is given by θ = s r :

2.3 More Differentiation Patterns

Given an arc of length s on a circle of radius r, the radian measure of the central angle subtended by the arc is given by θ = s r :

Numerical Differentiation

Mathematics 123.3: Solutions to Lab Assignment #5

Unit Circle. Return to. Contents

3.1 Extreme Values of a Function

4 The Trigonometric Functions

Solutions to the Multivariable Calculus and Linear Algebra problems on the Comprehensive Examination of January 31, 2014

Test 2 Review. 1. Find the determinant of the matrix below using (a) cofactor expansion and (b) row reduction. A = 3 2 =

4. The slope of the line 2x 7y = 8 is (a) 2/7 (b) 7/2 (c) 2 (d) 2/7 (e) None of these.

Trigonometric Functions () 1 / 28

Trigonometry.notebook. March 16, Trigonometry. hypotenuse opposite. Recall: adjacent

Equilibrium and Pareto Efficiency in an exchange economy

Math Section 4.3 Unit Circle Trigonometry

Quantum Numbers and Rules

Name: Answer Key No calculators. Show your work! 1. (21 points) All answers should either be,, a (finite) real number, or DNE ( does not exist ).

A.P. CALCULUS (AB) Outline Chapter 3 (Derivatives)

Math 141: Trigonometry Practice Final Exam: Fall 2012

Practice Test - Chapter 4

Section 2.4: Definition of Function

2.3 Algebraic approach to limits

As we know, the three basic trigonometric functions are as follows: Figure 1

Math 1241 Calculus Test 1

Mathematics. Sample Question Paper. Class 10th. (Detailed Solutions) Mathematics Class X. 2. Given, equa tion is 4 5 x 5x

MA119-A Applied Calculus for Business Fall Homework 4 Solutions Due 9/29/ :30AM

A. Incorrect! For a point to lie on the unit circle, the sum of the squares of its coordinates must be equal to 1.

Precalculus Lesson 6.1: Angles and Their Measure Lesson 6.2: A Unit Circle Approach Part 2

Minimal surfaces of revolution

Chapter Primer on Differentiation

SECTION 3.2: DERIVATIVE FUNCTIONS and DIFFERENTIABILITY

Walrasian Equilibrium in an exchange economy

2.3 Product and Quotient Rules

( ( ) cos Chapter 21 Exercise 21.1 Q = 13 (ii) x = Q. 1. (i) x = = 37 (iii) x = = 99 (iv) x =

Lone Star College-CyFair Formula Sheet

Intermediate Math Circles November 5, 2008 Geometry II

Calculus I, Fall Solutions to Review Problems II

Sin, Cos and All That

Geometry The Unit Circle

MAT244 - Ordinary Di erential Equations - Summer 2016 Assignment 2 Due: July 20, 2016

MTH-112 Quiz 1 Name: # :

Math Spring 2013 Solutions to Assignment # 3 Completion Date: Wednesday May 15, (1/z) 2 (1/z 1) 2 = lim

REVIEW: MORE FUNCTIONS AP CALCULUS :: MR. VELAZQUEZ

LIMITATIONS OF EULER S METHOD FOR NUMERICAL INTEGRATION

1 2 x Solution. The function f x is only defined when x 0, so we will assume that x 0 for the remainder of the solution. f x. f x h f x.

3.4 Worksheet: Proof of the Chain Rule NAME

MVT and Rolle s Theorem

Solve exponential equations in one variable using a variety of strategies. LEARN ABOUT the Math. What is the half-life of radon?

The derivative function

Electromagnetism Physics 15b

Transcription:

Trigonometry Is concerned wit te analysis of triangles. Degrees and radians Te degree (or sexagesimal unit of measure derives from defining one complete rotation as 360. Eac degree divides into 60 minutes, and eac minute divides into 60 seconds. Te radian is te angle created y a circular arc wose lengt is equal to te circle s radius. Te perimeter of a circle equals πr, terefore π radians correspond to one complete rotation. 360 correspond to π radians, terefore radian corresponds to π 80, approximately 57.3. Try to memorie te following relationsips etween radians and degrees π 3π 90, π 80, 70, π 360

Te trigonometric ratios Te Hindu word arda-jya meaning alf-cord was areviated to jya ( cord, wic was translated y te Aras into jia, and corrupted to j. Oter translators converted tis to jai, meaning cove, ulge or ay, wic in Latin is us. Today, te trigonometric ratios are known as,, tan, ec, sec and cot. Te trigonometric ratios are given y ( β ( β tan( β ec ( β opposite ypotenuse ( β sec ( β adjacent ypotenuse ( β cot ( β opposite adjacent tan ( β ypotenuse opposite β adjacent

0 Example Given a triangle were te ypotenuse and one angle are known. Te oter sides are calculated as follows: (50 0 0 (50 0 0.7660 7.66 (50 0 0 (50 0 0.679 θ 6.79

Inverse trigonometric ratios Te, and tan functions convert angles into ratios, and te inverse functions -, - and tan - convert ratios into angles. For example, (5 0.707, terefore - (0.707 5. Altoug e and coe functions are cyclic functions (i.e. tey repeat indefinitely te inverse functions return angles over a specific period tan - - ( x θ were (x θ were π θ π and (x θ were 0 θ π and ( θ x ( θ π θ π and tan( θ x x

Trigonometric relationsips Tere is an intimate relationsip etween te and definitions and are formally related y ( β ( β 90 Te Teorem of Pytagoras can e used to derive oter formulae suc as ( β tan( β ( β ( β ( β tan cot ( β sec ( β ( β ec ( β

( β ( β tan ( β y β x (β y (β x ( β ( β y x y x tan( β ( β ( β tan ( β

( β ( β y β y x x y x y x ( β ( β

tan ( β sec ( β y β x ( β ( β ( β ( β ( β ( β ( β tan ( β sec ( β

cot ( β ec ( β y β x ( β ( β ( β ( β ( β ( β ( β cot ( β ec ( β

Te Sine Rule c B a A C a ( A ( B c ( C Example A 50, B 30, a 0, find (30 0 (50 0(30 (50 5 0.766 6.57

Te Coe Rule c B a A C a c c ( A c a ca ( B c a a( C a c c a ( C c ( B ( A a ( C ( B ( A

Compound angles Two sets of compound trigonometric relationsips sow ow to add and sutract two different angles and multiples of te same angle. Te following are some of te most common relationsips ( A± B ( A ( B ( A ( B A± B ( A ( B m ( A ( B ± ( tan ( A± B tan m tan ( A ± tan( B ( A tan( B ( β ( β ( β ( β ( β ( β ( β ( β ( β ( β 3 ( 3β 3( β ( β 3 β ( β 3( β ( β ( ( β (3 ( β ( ( β

Perimeter relationsips c B a A ( a c s C A ( ( c c B ( c( a ca C ( a( a

Perimeter relationsips c B a A ( a c s C A s( a c B s( ca C s( c a

Perimeter relationsips c B a A ( a c s C c ( A s( a( ( c ca ( B s( a( ( c a ( C s( a( ( c

By te way. K! 3!!! 3 e e.g. 7.389 70 6 0 3 6 6 8! 3!!! 3 e e e K K ut K K 8! 6!!! ( 9! 7! 5! 3! ( 8 6 9 7 5 3 Euler's formula ( ( i e i

e and compound interest P te sum of money in a deposit account. R te % rate of interest for monts. If interest is awarded eac monts At te end of monts te alance is P R P P( R 5 00 e.g. 00 00 0 If interest is awarded eac 6 monts At te end of te st 6 monts te alance is P R P P( R At te end of te nd 6 monts te alance is P ( R R( R P(

If interest is awarded eac 3 monts At te end of te st 3 monts te alance is P R P P( R At te end of te nd 3 monts te alance is P ( R R( R P( At te end of te 3 rd 3 monts te alance is P ( R 3 R ( R P( At te end of te t 3 monts te alance is P ( R 3 R ( R P( In te limit, te alance is P ( R k k But e k ( k and x x k e ( k In te limit, te alance is R Pe

Let P 5,000 and R 0% alance P Ug e we get ( R k k k Balance 5,500.00 5,5.50 5,59.06 5,53.57 365 5,53.57 5,55.85 alance Pe R 0. 5000e alance 5000.057 555.85

Compound interest Wat interest rate do I need to turn 5,000 into 5,700 in one year? alance R Pe R 5000 e 5700 R e 5700. 5000 ln( e R ln(. R 0.30 R 3.%