On a conjugation and a linear operator

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On a conugation and a linear operator by Muneo Chō, Eungil Ko, Ji Eun Lee, Kôtarô Tanahashi 1 Abstract In this note, we introduce the study of some classes of operators concerning with conugations on a complex Hilbert space. 2 Definition Let H be a complex Hilbert space and LH) be the set of all bounded linear operators on H. For T LH), let σt ), σ p T ), σ a T ), σ s T ), σ e T ), σ w T ) be the spectrum, the point spectrum, the approximate point spectrum, the surective spectrum, the essential spectrum and the Weyl spectrum, respectively. Definition 1. For T LH), ) we define α m T ) and β m T ) as follows; 1) α m T ) = 1) m T m T, =0 ) 2) β m T ) = 1) m T m T m. =0 1) T is said to be m-symmetric if α m T ) = 0. Then i) m 1 α m 1 T ) 0 and σt ) R. 2) T is said to be m-isometric if β m T ) = 0. Then β m 1 T ) 0 and σ a T ) T = {z C : z = 1}. It holds that 1) T α m T ) α m T ) T = α m+1 T ), 2) T β m T ) T β m T ) = β m+1 T ). Proposition 1 Proposition 1.23, [1]) Let T be m-isometric. invertible, then T is m 1)-isometric. If m is even and T is

When m is odd, we have the following: Proposition 2 Theorem 1, [7]) If m is any odd number, then there exists an invertible m-isometric which is not m 1)-isometric. Proposition 3 Theorem 3.4, [13]) If T is m-symmetric and m is even, then T is m 1)- symmetric. 1) Let T be 1-symmetric. Then T T = 0. So T is Hermitian clearly. 2) Let T be 2-symmetric. By Proposition 3, T is 1-symmetric. Hence T is Hermitian. 3) Let T be m-symmetric. For sequences of unit vectors {x n }, {y n }, if T a)x n 0 and T b)y n 0 a b), then x n, y n 0. Hence if T x = ax, T y = by a b), then x, y = 0. If Q is 2-nilpotent, then Q is 3-symmetric. In [11], J. W. Helton introduced m-symmetric for the study of Jordan operators. If T is 1-isometric, then T T I = 0 and T is an isometry. In [1], J. Agler and M. Stankus studied m-isometric for the research of Dirichlet Differential operators. We have many results of m-isometric operators. Bermúdes, Martinón and etc. Researchers are Agler, Stankus, Gu, 3 Conugation Definition 2 C : H H is said to be antilinear if Cax + by) = ā Cx + b Cy, for all a, b C, x, y H. An antilinear operator C is said to be a conugation if C 2 = I, Cx, Cy = y, x for all x, y H. If C is a conugation, then Cx = x for all x H.

4 Example Example 1 Typical Example of Conugation: Let H = C n. 1) Jz 1, z 2,..., z n ) = z 1, z 2,..., z n ), 2) Cz 1, z 2,..., z n ) = z n, z n 1,..., z 1 ). Then J, C are conugations. Example 2 T is said to be complex symmetric if there exists a conugation C such that CT C = T. Typical Example of a complex symmetric operator T : Let H = C n and T be a 0 a 1 a n 1) a 1 a 0 a n 2) T =........ a n 1 a n 2 a 0 Toeplitz matrix). Then CT C = T. Hence every Toeplitz matrix is complex symmetric C-symmetric). T. Takagi first showed this. He studied antilinear eigen-value problem. There is the following result. Takagi Factorization Theorem. Let T be a symmetric and C-symmetric matrix. Then there exist a unitary U and normal and symmetric N such that T = UN t U. 5 Symmetric operators In [12] S. Jung, E. Ko and J. E. Lee showed several results about complex symmetric operators. We only set the following theorem. Theorem 1. Let C be a conugation and T LH). Then σct C) = σt ), σ p CT C) = σ p T ), σ a CT C) = σ a T ), σ s CT C) = σ s T ), σ e CT C) = σ e T ), σ w CT C) = σ w T ). It is not need CT C = T. It is the relation between spectra of T and CT C.

6 m, C)-symmetric operator Definition 3. Let C be a conugation and T LH). Then ) m T ; C) = 1) m T CT m C. =0 T is said to be m, C)-symmetric if m T ; C) = 0. In [2] and [3], it is said to be m-complex symmetric.) We have T m T ; C) m T ; C) CT C) = m+1 T ; C). Hence if T is m, C)-symmetric, then T is n, C)-symmetric for every n m). At the last year RIMS Conference, in [5] we already had a talk of this class. m, C)- symmetric means m-complex symmetric. Please see [5]. 7 [m, C]-symmetric operator Definition 3. Let C be a conugation and T LH). Then ) α m T ; C) = 1) m CT m C) T. =0 T is said to be [m, C]-symmetric if α m T ; C) = 0. We have CT C α m T ; C) α m T ; C) T = α m+1 T ; C). Hence if T is [m, C]-symmetric, then T is [n, C]-symmetric for every n m). Theorem 2. Let C be a conugation and T LH). a) T is [m, C]-symmetric if and only if so is T. b) If T is [m, C]-symmetric, then so is T n for every n N. c) If T is [m, C]-symmetric and invertible, then T 1 is [m, C]-symmetric. Theorem 3. Let T be [m, C]-symmetric. Then σt ) = σt ), σ p T ) = σ p T ), σ a T ) = σ a T ), σ s T ) = σ s T ).

A pair T, S) is said to be C-doubly commuting if T S = ST and CSC T = T CSC. Lemma 1. Let T, S) be C-doubly commuting. Then it holds ) m α m T + S; C) = α T ; C) α m S; C). =0 Theorem 4. Let T be [m, C]-symmetric and S be [n, C]-symmetric. If T, S) is C-doubly commuting, then T + S is [m + n 1, C]-symmetric. Theorem 4. Let Q be n-nilpotent. Then Q is [2n 1, C]-symmetric for every conugation C. Theorem 5. Let T be [m, C]-symmetric and Q be n-nilpotent. If T, Q) is C-doubly commuting, then T + Q is [m + 2n 2, C]-symmetric. Lemma 2. Let T, S) be C-doubly commuting. Then it holds ) m α m T S; C) = α T ; C) T m CS C α m S; C). =0 Theorem 6. Let T be [m, C]-symmetric and S be [n, C]-symmetric. If T, S) is C-doubly commuting, then T S is [m + n 1, C]-symmetric. Theorem 7. Let T be [m, C]-symmetric and S be [n, D]-symmetric. Then T S is [m + n 1, C D]-symmetric. Proof. It is clear that C D is a conugation on H H. And it is easy to see that T I is [m, C D]-symmetric and I S is [n, C D]-symmetric. Also it is clear that T I, I S) is C D-doubly commuting. Since T S = T I)I S), by the previous theorem we have T S is [m + n 1, C D]-symmetric. Q.E.D. 8 m, C)-isometric operator Definition 4. Let C be a conugation and T LH). Then ) Λ m T ; C) = 1) m T m CT m C). =0

T is said to be m, C)-isometric if Λ m T ; C) = 0. We have T Λ m T ; C) CT C) Λ m T ; C) = Λ m+1 T ; C). Hence if T is m, C)-isometric, then T is n, C)-isometric for every n m). Theorem 8. Let T be m, C)-isometric. Then; a) T is bounded below, b) 0 σ a T ), c) T is inective and RT ) is closed, d) if z σ a T ), then 1 z σ at ), e) if there exists T 1, then T 1 is m, C)-isometric. Theorem 9. Let T be m, C)-isometric. If T has SVEP, then σt ) = σ a T ) = σ s T ). Theorem 10. Let T be m, C)-isometric. If T is power bounded and T CT C I is normaloid, then T is 1, C)-isometric, i.e., T CT C = I. Of course, if T is m-isometric and power bounded, then T is isometric. A pair T, S) is said to be C- doubly commuting if T S = ST and S CT C = CT C S. Lemma 3. Let T, S) be C- doubly commuting. Then it holds Λ m T + S; C) = m 1 +m 2 +m 3 =m ) m m 1, m 2, m 3 T + S ) m 1 S m 2 Λ m3 T ; C) CT m 2 C) CS m 1 C). It follows from the following equation: a + b)c + d) 1 ) m = ac 1) + a + b)d + bc ) m = m 1 +m 2 +m 3 =m m m 1, m 2, m 3 ) a + b) m 1 b m 2 ac 1) m 3 c m 2 d m 1.

Hence we have the following result. Theorem 11. Let T be m, C)-isometric, Q be n-nilpotent and T, Q) be a commuting pair. Then T + Q is m + 2n 2, C)-isometric. Lemma 4. Let T, S) be C- doubly commuting. Then it holds Λ m T S; C) = =0 m It follows from the following equation: ) T Λ m T ; C)CT C) Λ S; C). abcd 1 ) m = ab 1) + acd 1)b ) m = =0 m Hence we have the following result. ) a ab 1) m b cd 1). Theorem 12. Let T be m, C)-isometric and S be n, C)-isometric. If T, S) is C- doubly commuting, then T S is m + n 1, C)-isometric. Theorem 13. Let T be m, C)-isometric and S be n, D)-isometric. Then T S is m + n 1, C D)-isometric. Proof. It is easy to see that T I is m, C D)-isometric and I S is n, C D)-isometric. Also it is clear that T I, I S) is C D- doubly commuting. Since T S = T I)I S), by the previous theorem we have T S is m + n 1, C D)-isometric. Q.E.D. References [1] J. Agler and M. Stankus, m-isometric transformations of Hilbert space I, Integr. Equat. Oper. Theory, 211995) 383-429. [2] M. Chō, E. Ko and J. E. Lee, On m-complex symmetric operators, Mediterr. J. Math. 132016) 2025-2038. [3] M. Chō, E. Ko and J. E. Lee, On m-complex symmetric operators II, Mediterr. J. Math. 132016) 3255-3264. [4] M. Chō, E. Ko and J. E. Lee, On m, C)-isometric operators, Complex Anal. Oper. Theory, 42016) 1679-1694. [5] M. Chō, E. Ko and J. E. Lee, On m-complex symmetric operators, RIMS Kôkyûroku

1996 2016) April, 23-33. [6] M. Chō, J. E. Lee and K. Tanahashi, On [m, C]-symmetric operators, preprint. [7] M. Chō, S. Ôta and K. Tanahashi, Invertible weighted shift operators which are m- isometries, Proc. Amer. Math. Soc. 1412013) 11701-6. [8] C. Gu and M. Stankus, Some results on higher order isometries and symmetries: Products and sums with a nilpotent operators, Linear Algebra Appl., 4692015) 500-509. [9] S. R. Garcia and M. Putinar, Complex symmetric operators, Trans. Amer. Math. Soc. 3582005) 1285-1315. [10] S. R. Garcia and M. Putinar, Complex symmetric operators II, Trans. Amer. Math. Soc. 3592007) 3913-3931. [11] J. W. Helton, Infinite dimensional Jordan operators and Strum-Liouville conugate point theory, Trans. Amer. Math. Soc. 1701972) 305-331. [12] S. Jung, E. Ko and J. E. Lee, On complex symmetric operators, J. Math. Anal. Appl. 406 2013) 373-385. [13] S. McCullough and L. Rodman, Hereditary classes of operators and matrices, Amer. Math. Monthly, 1041997) 415-430. Muneo Chō Department of Mathematics, Kanagawa University, Hiratsuka 259-1293, Japan e-mail: chiyom01@kanagawa-u.ac.p Eungil Ko Department of Mathematics, Ewha Womans University, Seoul 120-750, Korea e-mail: eiko@ewha.ac.kr Ji Eun Lee Department of Mathematics-Applied Statistics, Seong University, Seoul 143-747, Korea e-mail: ieun7@ewhain.net; ieunlee7@seong.ac.kr Kôtarô Tanahashi Department of Mathematics, Tohoku Medical and Pharmaceutical University, Sendai 981-8558, Japan e-mail: tanahasi@tohoku-mpu.ac.p