ID : in-5-fractions [] Class 5 Fractions For more such worksheets visit wwwedugaincom Answer t he quest ions () The table below shows the number of books read by f ive children in one month Name Number of books Divya? Shweta 9 Archana 20 Radha Neha 26 If Divya read books more than 3 of the total number of books read by the other f our children, then how many books did Divya read in a month? (2) Convert the f raction 95 2 00 to decimal number (3) If sum of both diagonals are same, f ind the missing value 6 3 5 3 3 6 3 () Shade the images to show the f ollowing f raction addition 3 + 3 + 2 2 2 2 and and makes
(5) Sonia and Vinayak have bookshelves of the same size and holding books of the same sizes ID : in-5-fractions [2] Sonia's shelf is 2 f ull and Vinayak's shelf is 5 f ull If 28 more books of the same size are distributed among them, then they can f ill their shelves completely How many books does Vinayak have today? (6) Convert 598 as mixed f raction (simplif ication is not required) Choose correct answer(s) f rom given choice () Pranav's aunt lives 95 kilometers away f rom his house When he wants to visit his aunt, he travels of this distance by train and the rest by bus How many kilometers does he travels 5 by bus? a 3 b 82 c 2 d (8) Which kind of f raction can never be represented using the f ollowing type of f igure a Proper Fractions b Improper Fractions c Unlike f ractions d Like Fractions (9) The parking lot of the Fairground has a capacity of 66 cars On Sundays the ratio of occupied spots to empty spots in the parking lot was 5:6 The number of additional cars that could park there is a 32 b 336 c 32 d 3 (0) What is the multiplicative inverse of 53? a 53 b c 53 d 53
() Find the f ollowing: ID : in-5-fractions [3] 3 2 of 6 6 3 a 5 c 22 3 b 2 3 d 23 3 Fill in the blanks (2) Write the f ollowing f ractions in the simplest f orm: A) B) C) 60 26 8 8 D) E) F) 0 90 28 6 8 (3) Balvinder had to pickup a f riend while going to school Balvinder walked 3 0 of a kilometer to his f riend's house Af ter that he walked 0 of a kilometer to reach school In all Balvinder walked kilometers () Following shape is made of several small cubes f raction of cubes are visible in the picture shown below (5) Add the f ollowing f ractions and reduce them to the simplest f orm: A) + 2 B) 5 + 8 C) 2 2 + 5 6
ID : in-5-fractions [] D) 9 + 2 E) 9 + 6 6 F) 8 5 + 3 206 Edugain (wwwedugaincom) All Rights Reserved Many more such worksheets can be generated at wwwedugaincom
Answers ID : in-5-fractions [5] () 2 Step Total number of books read by Shweta, Archana, Radha and Neha, 9 + 20 + + 26 69 It is given that Divya reads books more than 3 of 69 Theref ore number of books read by Divya, 3 69 + 23 + 2 books (2) 952 Step 95 2 is a mixed f raction A mixed f raction is a combination of a whole number and a 00 proper f raction In the mixed f raction 95 2 00, 95 is a whole number and 2 00 is a proper f raction To convert the mixed f raction into decimal, we shall f irst convert the proper f raction into a decimal number and add it to the whole number 95 2 00 Step The proper f raction 2 00 can be written as a decimal number as 02 Adding the whole number 95 to the decimal number 02, we get 952 Step 5 Theref ore, the answer is 952
(3) 5 ID : in-5-fractions [6] 3 Step Lets f ind sum of top-right to bottom-lef t diagonal where all terms are known, 5 + + 6 5 3 3 3 3 Now lets f ind sum of all available terms in top-lef t to bottom-right diagonal, 6 + 0 3 3 3 Since it is given that sum of both diagonals are same, missing terms must be equal to dif f erent of above two sum Theref ore missing term 5-0 5 3 3 3 () 3 + 3 + 2 2 2 2 and and makes
(5) 32 ID : in-5-fractions [] Step We f irst need to f ind out the total amount of empty space in both these shelves together Sonia has a 2 f ull shelf So, we need to f igure out what f raction is empty We can calculate that as - 2 Similarly Vinayak has - 5 f raction of his shelf empty Step Now we need to add these two together to f ind out the total f raction empty in these two shelves together - + - 2 5 0 Step 5 Now we are also told that if we distribute 28 among Sonia and Vinayak then the shelves will be f illed So the f raction of the shelves can be f illed using 28 books 0 Step 6 So we see that the total number of books that can be held in a shelf is 28 0 0 So each shelf can hold 0 books Step We also know Vinayak has 5 of her shelf f illed So it's just a matter of f inding out the value of 0 x 5 32
(6) 5 98 000 ID : in-5-fractions [8] Step In order to convert 598 as improper f raction, let us f irst look at its two parts: the whole number part which is 5 and the f ractional part which is 98 In the f ractional part 98, the decimal point is on the lef t of two digits Thus we can write it as proper f raction 98 000 The number 598 can be written as a mixed f raction by combining the whole number 5 with the proper f raction 98 000 as 5 98 000 Step Thus 598 can be written as mixed f raction 5 98 000 () b 82 Step The total distance between Pranav's house and his aunt s house 95 km : The distance Pranav travels by train 95 km 5 3 km 5 of 95 km In order to f ind the distance travelled by bus, let us subtract the total distance and the distance he traveled by train: 95-3 82 Step Theref ore, Pranav traveled 82 km by bus to reach his aunt s house (8) b Improper Fractions
(9) b 336 ID : in-5-fractions [9] Step It is given that ratio of occupied spots to empty spots is 5:6, which means if there are ( 5 + 6) spots, 5 are occupied and 6 are empty But is given that total number of parking spots are 66 Theref ore total number of spots are 56 times ( 66/) of Theref ore available spots will also be 56 times of 6 Theref ore available parking spots, 6 56 336 (0) d 53 Step Two number f ractions whose product is are called multiplicative inverse of each other Let us f irst write the whole number 53 into f ractions as 53 To get the multiplicative inverse, let us interchange the numerator and the denominator as 53 Step Hence, the multiplicative inverse of 53 is 53 A way to verif y our answer is to see that 53 53 () b 2 3
ID : in-5-fractions [0] (2) A) 60 26 5 8 Step A f raction is said to be in the simplest/lowest f orm if its numerator and the denominator have no common f actor higher than In other words, we can say that a f raction is said to be in the simplest/lowest f orm if the HCF of its numerator and denominator is equal to If f or any f raction, both the numerator and the denominator are divided by their HCF, the HCF of the new numerator and denominator will be This means that the new f raction will be in its simplest/lowest f orm In order to write the f raction HCF of 60 and 26: 2 60 2 30 3 5 5 5 60 26 in the simplest/lowest f orm, let us f ind the Factors of 60 2 2 3 5 2 26 2 08 2 5 3 2 3 9 3 3 Factors of 26 2 2 2 3 3 3 The HCF of 60 and 26 is 2 2 3 2 Step Now, let us divide both the numerator and denominator of the f raction its HCF 2 in order to bring it into its simplest/lowest f orm: 60 60 2 5 26 26 2 8 60 26 by Step 5
ID : in-5-fractions [] Hence, the simplest/lowest f orm of 60 26 is 5 8
ID : in-5-fractions [2] B) 9 Step A f raction is said to be in the simplest/lowest f orm if its numerator and the denominator have no common f actor higher than In other words, we can say that a f raction is said to be in the simplest/lowest f orm if the HCF of its numerator and denominator is equal to If f or any f raction, both the numerator and the denominator are divided by their HCF, the HCF of the new numerator and denominator will be This means that the new f raction will be in its simplest/lowest f orm In order to write the f raction HCF of and : Factors of 3 3 2 Factors of 3 3 The HCF of and is Step in the simplest/lowest f orm, let us f ind the Now, let us divide both the numerator and denominator of the f raction its HCF in order to bring it into its simplest/lowest f orm: 9 Step 5 by Hence, the simplest/lowest f orm of is 9
ID : in-5-fractions [3] C) 8 8 2 9 Step A f raction is said to be in the simplest/lowest f orm if its numerator and the denominator have no common f actor higher than In other words, we can say that a f raction is said to be in the simplest/lowest f orm if the HCF of its numerator and denominator is equal to If f or any f raction, both the numerator and the denominator are divided by their HCF, the HCF of the new numerator and denominator will be This means that the new f raction will be in its simplest/lowest f orm In order to write the f raction 8 8 HCF of 8 and 8: 2 8 in the simplest/lowest f orm, let us f ind the 3 9 3 3 Factors of 8 2 3 3 3 8 3 2 3 9 3 3 Factors of 8 3 3 3 3 The HCF of 8 and 8 is 3 3 9 Step Now, let us divide both the numerator and denominator of the f raction 8 its HCF 9 in order to bring it into its simplest/lowest f orm: 8 8 8 9 8 9 2 9 8 by Step 5 Hence, the simplest/lowest f orm of 8 8 is 2 9
ID : in-5-fractions []
ID : in-5-fractions [5] E) 28 9 Step A f raction is said to be in the simplest/lowest f orm if its numerator and the denominator have no common f actor higher than In other words, we can say that a f raction is said to be in the simplest/lowest f orm if the HCF of its numerator and denominator is equal to If f or any f raction, both the numerator and the denominator are divided by their HCF, the HCF of the new numerator and denominator will be This means that the new f raction will be in its simplest/lowest f orm In order to write the f raction 28 HCF of 28 and : 2 28 in the simplest/lowest f orm, let us f ind the 2 Factors of 28 2 2 3 3 2 Factors of 3 3 The HCF of 28 and is Step Now, let us divide both the numerator and denominator of the f raction 28 its HCF in order to bring it into its simplest/lowest f orm: 28 28 9 by Step 5 Hence, the simplest/lowest f orm of 28 is 9
ID : in-5-fractions [6] F) 6 8 3 Step A f raction is said to be in the simplest/lowest f orm if its numerator and the denominator have no common f actor higher than In other words, we can say that a f raction is said to be in the simplest/lowest f orm if the HCF of its numerator and denominator is equal to If f or any f raction, both the numerator and the denominator are divided by their HCF, the HCF of the new numerator and denominator will be This means that the new f raction will be in its simplest/lowest f orm In order to write the f raction HCF of 6 and 8: 2 6 3 3 Factors of 6 2 3 2 8 3 9 3 3 Factors of 8 2 3 3 6 8 in the simplest/lowest f orm, let us f ind the The HCF of 6 and 8 is 2 3 6 Step Now, let us divide both the numerator and denominator of the f raction its HCF 6 in order to bring it into its simplest/lowest f orm: 6 6 6 8 8 6 3 Step 5 6 8 by Hence, the simplest/lowest f orm of 6 8 is 3
(3) Balvinder had to pickup a f riend while going to school Balvinder walked 3 0 ID : in-5-fractions [] of a kilometer to his f riend's house Af ter that he walked 0 of a kilometer to reach school In all Balvinder walked 0 kilometers Step The distance covered by Balvinder to his f riend's house 3 0 of a kilometer The distance covered by Balvinder to school 0 of a kilometer Total distance covered by Balvinder while going to school 3 0 + 0 3 + 0 0 Theref ore, he walked 0 kilometer in all () 26 36 (5) A) + 2 3 B) 5 + 8 5 C) 2 2 + 5 6 6 D) 9 + 2 8
ID : in-5-fractions [8] E) 9 + 6 6 3 9 F) 8 5 + 3 29 5