UNIT 3 CIRCLES AND VOLUME Lesson 1: Introducing Circles Instruction

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Prerequisite Skills This lesson requires the use of the following skills: performing operations with fractions understanding slope, both algebraically and graphically understanding the relationship of the slope of perpendicular lines understanding how to write an equation of a line using point-slope form knowing that the sum of the angles of a triangle is 180º performing calculations using the Pythagorean Theorem performing calculations using the distance formula understanding intercepted arcs Introduction Circles and tangent lines can be useful in many real-world applications and fields of study, such as construction, landscaping, and engineering. There are many different types of lines that touch or intersect circles. All of these lines have unique properties and relationships to a circle. Specifically, in this lesson, we will identify what a tangent line is, explore the properties of tangent lines, prove that a line is tangent to a circle, and find the lengths of tangent lines. We will also identify and use secant lines, as well as discuss how they are different from tangent lines. Key Concepts A tangent line is a line that intersects a circle at exactly one point. Tangent lines are perpendicular to the radius of the circle at the point of tangency. Point of tangency Radius Tangent line U3-46

You can verify that a line is tangent to a circle by constructing a right triangle using the radius, and verifying that it is a right triangle by using the Pythagorean Theorem. The slopes of a line and a radius drawn to the possible point of tangency must be negative reciprocals in order for the line to be a tangent. If two segments are tangent to the same circle, and originate from the same exterior point, then the segments are congruent. The angle formed by two tangent lines whose vertex is outside of the circle is called the circumscribed angle. BAC is a circumscribed angle. A B O C The length of tangent AB is equal to the length of tangent AC. The angle formed by two tangents is equal to one half the positive difference of the angle s intercepted arcs. U3-47

A secant line is a line that intersects a circle at two points. Secant line An angle formed by a secant and a tangent is equal to the positive difference of its intercepted arcs. Common Errors/Misconceptions assuming that a radius and a line form right angles at the possible point of tangency simply by relying on observation assuming that two tangent lines are congruent by observation making incorrect calculations (usually sign errors) when using the slope formula making incorrect calculations when using formulas such as the Pythagorean Theorem and the distance formula confusing secant lines and tangent lines U3-48

Guided Practice 3.1.3 Example 1 Determine whether BC is tangent to A in the diagram below. C 41 40 A 9 B 1. Identify the radius. The radius of the circle is the segment from the center of the circle to a point on the circle. AB is the radius of A. 2. Determine the relationship between AB and BC at point B in order for BC to be tangent to A. AB must be perpendicular to BC at point B in order for BC to be tangent to A. U3-49

3. Show that ABC is a right angle by using the converse of the Pythagorean Theorem. The converse of the Pythagorean Theorem states that when the sum of the squares of two sides of a triangle is equal to the square of the third side of the triangle, the triangle is a right triangle. a 2 + b 2 = c 2 Pythagorean Theorem (AB) 2 + (BC) 2 = (AC) 2 Substitute segment names for a, b, and c. 9 2 + 40 2 = 41 2 Substitute values for AB, BC, and AC. 81 + 1600 = 1681 Simplify, then solve. 1681 = 1681 The result is a true statement; therefore, ABC is a right angle. 4. State your conclusion. Since the converse of the Pythagorean Theorem is true, ABC is a right triangle; therefore, ABC is a right angle. This makes AB perpendicular to BC ; therefore, BC is tangent to A. U3-50

Example 2 Each side of ABC is tangent to circle O at the points D, E, and F. Find the perimeter of ABC. A 7 F D O 5 B E 16 C 1. Identify the lengths of each side of the triangle. AD is tangent to the same circle as AF and extends from the same point; therefore, the lengths are equal. AD = 7 units BE is tangent to the same circle as BD and extends from the same point; therefore, the lengths are equal. BE = 5 units To determine the length of CE, subtract the length of BE from the length of BC. 16 5 = 11 CE = 11 units CF is tangent to the same circle as CE and extends from the same point; therefore, the lengths are equal. CF = 11 units U3-51

2. Calculate the perimeter of ABC. Add the lengths of AD, AF, BD, BE, CE, and CF to find the perimeter of the polygon. 7 + 7 + 5 + 5 + 11 + 11 = 46 units The perimeter of ABC is 46 units. Example 3 A landscaper wants to build a walkway tangent to the circular park shown in the diagram below. The other walkway pictured is a radius of the circle and has a slope of 1 on the grid. If the walkways 2 should intersect at (4, 2) on the grid, what equation can the landscaper use to graph the new walkway on the grid? y 10 9 8 7 6 5 4 3 2 1-10 -9-8 -7-6 -5-4 -3-2 -1 0-1 1 2 3 4 5 6 7 8 9 10-2 -3-4 -5-6 -7-8 -9-10 x U3-52

1. Determine the slope of the walkway. One of the properties of tangent lines states that if a line is tangent to a circle, then it is perpendicular to the radius at the point of tangency. Since the slope of the radius is 1, then the slope of the new walkway will 2 be 2 because perpendicular lines have slopes that are negative reciprocals. Example 4 2. Determine the equation that represents the walkway. Recall that the point-slope form of a line is y y = mx ( x ). 1 1 Since the new walkway is tangent to the circle at (4, 2), then the point (4, 2) is on the tangent line, so it can be used to write the equation. y ( 2) = 2( x 4) y+ 2= 2( x 4) This equation can be rearranged into slope-intercept form, y= 2x 10, for easier graphing. AB is tangent to C at point B as shown below. Find the length of AB as well as m BD. B 8 D C 28 17 A U3-53

1. Find the length of AB. Since AB is tangent to C, then ABC is right angle because a tangent and a radius form a right angle at the point of tangency. Since ABC is a right angle, ABC is a right triangle. Use the Pythagorean Theorem to find the length of AB. a 2 + b 2 = c 2 Pythagorean Theorem 8 2 + (AB) 2 = 17 2 Substitute values for a, b, and c. 64 + (AB) 2 = 289 Simplify. (AB) 2 = 225 AB = 15 The length of AB is 15 units. 2. Find m BD. First, determine the unknown measure of ACB. Recall that the sum of all three angles of a triangle is 180º. ABC is a right angle, so it is 90º. BAC is 28º, as shown in the diagram. Set up an equation to determine the measure of ACB. 28 + 90 + m ACB = 180 118 + m ACB = 180 m ACB = 62 Since m ACB = 62, then m BCD= 118 because ACB and BCD are a linear pair. BCD is a central angle, and recall that the measure of a central angle is the same as its intercepted arc, so BD is 118º. U3-54