PMT. Version 1.0. General Certificate of Education (A-level) June 2013 MPC1. Mathematics. (Specification 6360) Pure Core 1. Final.

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Version 1.0 General Certificate of Education (A-level) June 01 Mathematics MPC1 (Specification 660) Pure Core 1 Final Mark Scheme

Mark schemes are prepared by the Principal Eaminer and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation events which all eaminers participate in and is the scheme which was used by them in this eamination. The standardisation process ensures that the mark scheme covers the students responses to questions and that every eaminer understands and applies it in the same correct way. As preparation for standardisation each eaminer analyses a number of students scripts: alternative answers not already covered by the mark scheme are discussed and legislated for. If, after the standardisation process, eaminers encounter unusual answers which have not been raised they are required to refer these to the Principal Eaminer. It must be stressed that a mark scheme is a working document, in many cases further developed and epanded on the basis of students reactions to a particular paper. Assumptions about future mark schemes on the basis of one year s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular eamination paper. Further copies of this Mark Scheme are available from: aqa.org.uk Copyright 01 AQA and its licensors. All rights reserved. Copyright AQA retains the copyright on all its publications. However, registered schools/colleges for AQA are permitted to copy material from this booklet for their own internal use, with the following important eception: AQA cannot give permission to schools/colleges to photocopy any material that is acknowledged to a third party even for internal use within the centre. Set and published by the Assessment and Qualifications Alliance. The Assessment and Qualifications Alliance (AQA) is a company limited by guarantee registered in England and Wales (company number 67) and a registered charity (registered charity number 107). Registered address: AQA, Devas Street, Manchester 5 6EX.

Key to mark scheme abbreviations M mark is for method m or dm mark is dependent on one or more M marks and is for method A mark is dependent on M or m marks and is for accuracy B mark is independent of M or m marks and is for method and accuracy E mark is for eplanation or ft or F follow through from previous incorrect result CAO correct answer only CSO correct solution only AWFW anything which falls within AWRT anything which rounds to ACF any correct form AG answer given SC special case OE or equivalent A,1 or 1 (or 0) accuracy marks EE deduct marks for each error NMS no method shown PI possibly implied SCA substantially correct approach c candidate sf significant figure(s) dp decimal place(s) No Method Shown Where the question specifically requires a particular method to be used, we must usually see evidence of use of this method for any marks to be awarded. Where the answer can be reasonably obtained without showing working and it is very unlikely that the correct answer can be obtained by using an incorrect method, we must award full marks. However, the obvious penalty to candidates showing no working is that incorrect answers, however close, earn no marks. Where a question asks the candidate to state or write down a result, no method need be shown for full marks. Where the permitted calculator has functions which reasonably allow the solution of the question directly, the correct answer without working earns full marks, unless it is given to less than the degree of accuracy accepted in the mark scheme, when it gains no marks. Otherwise we require evidence of a correct method for any marks to be awarded.

MPC1 - AQA GCE Mark Scheme 01 June 1(a) p( p) 5 0 condone omission of brackets or one sign error p (b) 5 y rearranging into form y c (gradient AB =) condone slips in rearranging if gradient is correct. k (c) (gradient AC =) or 51 k (condone one sign error) 1 5 k their 1 OE m1 product of grads = 1 in terms of k 6 k 10 (d) y + 5 = 0 and 5y = 6 must use correct pair of equations and P Q or R y = S attempt to eliminate y (or ) (generous) 7 y ( 7, ) Total 10

MPC1 - AQA GCE Mark Scheme 01 June (a)(i) 8 B1 1 condone n=. No ISW. (ii) 1 and 8 (FT their n) 7 7 correct quotient unsimplified or correct equation in integers eg 6 = 1 1 = cso accept 1.5 but not 9 6 etc alternative 1 7 8 1 1 1 integer terms 1 = (b) 11 5 5 5 5 (numerator =) 15 11 15 5 correct unsimplified but must simplify, 5 and 5 correctly (denominator = 1 5 =) 7 B1 must be seen or identified as denominator 56 7 15 giving 7 (Answer =) 8 15 cso m = 8 Total 8

MPC1 - AQA GCE Mark Scheme 01 June (a) ( 5) ( y 7) one term correct both terms correct and added ( 5) ( y7) 9 cao must see 9 not just 7 condone ( 5) ( y7) 9 (b)(i) (Centre is ) (5, 7) B1 1 correct or FT their a and b (ii) Radius = 7 B1 1 condone 9 but not 7 or 9 correct or FT their k provided k > 0 (c)(i) y 5 freehand circle with centre in correct quadrant or FT from their (b)(i) must have both aes shown clearly correct position cutting negative y-ais twice and touching -ais at = 5 5 must be marked on -ais or centre clearly marked as (5, 7) must have correct centre and radius in (b) (ii) 5 B1 y 1 B1 (5, 1) (d) Translation E1 and no other transformation 6 through * 6 7 cso both components correct for ; may describe in words or use a column vector Total 1

MPC1 - AQA GCE Mark Scheme 01 June (a) f ( ) ( ) 15 f( ) attempted not long division f 7 1 15 = 0 is a factor shown = 0 plus statement (ii) Quadratic factor 5 (b) (i) f( ) 5 d y d or + 5 term by inspection or full long division attempt must see correct product 16 60 one of these terms correct another term correct all correct ( no +c etc) (ii) 1660 0 must see this line OE 150 B1 1 AG (iii) Discriminant of quadratic = 5 discriminant of their quadratic or b ac = 11 (or b ac 0) therefore quadratic has no (real )roots correct use of quad eqn formula correct discriminant evaluated correctly (or shown to be < 0 ) with appropriate conclusion Hence only stationary point is when = plus final statement (iv) d y d 1 16 B1 = 1( ) 16 (or 19 16 etc) sub = into their = 9 d y d (v) Minimum since d y 0 d (or 9 > 0 etc) E1 1 Total 1 FT appropriate conclusion from their value from (iv) plus reason treat parts (iv) & (v) holistically

MPC1 - AQA GCE Mark Scheme 01 June 5(a)(i) 1.5 OE 1.5 0.5 (ii) (Minimum value is) 0.5 B1 1 ft their q OE 1 (b)(i) 95 AB condone one sign error inside one bracket () 9 16 B1 OE AB 6 99 1610 0 5 AB 5( 6 5) cso AG (ii) Either 5 ' their '(a)(ii) or 5 ' their '(a)(ii) using their minimum value from (a)(ii) and 5 provided their (a)(ii) > 0 ( Minimum length of AB = ) 1 10 cso 6(a) d y d 5 Total 8 5( 1) ( 1) 9 Tangent has equation y ' their 9' c and 6 ' their 9' ( 1) c c... m1 y 915 5 one of these terms correct all correct ( no +c etc) tangent using their gradient, and attempt to find c using = 1 and y = 6 equation must be seen in this form (b)(i) When =, 5 be convinced that they are using y 9 8 9 curve equation (k = ) B1 1 NMS k = scores B0 (ii) When =, y = 9 15 so lies on tangent B1 1 be convinced that they are using tangent equation and have statement

MPC1 - AQA GCE Mark Scheme 01 June 6(c)(i) 6 one of these terms correct 9 another term correct 6 all correct (may have +c) 6 6 ( 1) ( 1) 9 9 ( 1) 6 6 6 16 1 18 9 6 6 = 1.5 189 or etc 6 m1 F() F( 1) unsimplified FT their terms from integration 70 9 6 5 condone single fraction (ii) Area of trapezium = 1 (6 ' their ' k ) B1 = 58.5 when k = Shaded area = Trapezium their (c)(i) value = 7 16 OE eg 6 Total 15 7(a) ( k ) (k 7)( k ) discriminant condone one slip condone omission of brackets k k (k 6k 7k 1) their 7k 8k 80 0 B1 real roots condition ; f(k) 0 must appear before final line 7k 8k 80 0 cso AG (all working correct with no missing brackets etc) (b) 7k 8k 80 (7k 0)( k ) correct factors critical values are y 0 and 7 accept (or roots unsimplified) 56 0, 1 1 etc here 8 6 1 sketch or sign diagram including values + + 0 7 0 k 7 Take their final line as their answer cao fractions must be simplified here Total 8 TOTAL 75