Calculus II Homework: The Comparison Tests Page 1. a n. 1 n 2 + n + 1. n= n. n=1

Similar documents
1 Introduction to Sequences and Series, Part V

9.3 The INTEGRAL TEST; p-series

5.6 Absolute Convergence and The Ratio and Root Tests

In this section, we show how to use the integral test to decide whether a series

Math 25 Solutions to practice problems

E. Incorrect! Plug n = 1, 2, 3, & 4 into the general term formula. n =, then the first four terms are found by

INFINITE SEQUENCES AND SERIES

Arkansas Tech University MATH 2924: Calculus II Dr. Marcel B. Finan

M17 MAT25-21 HOMEWORK 5 SOLUTIONS

n n 2 n n + 1 +

Are the following series absolutely convergent? n=1. n 3. n=1 n. ( 1) n. n=1 n=1

10.5 Positive Term Series: Comparison Tests Contemporary Calculus 1

Definition An infinite sequence of numbers is an ordered set of real numbers.

6.3 Testing Series With Positive Terms

Math 113 Exam 3 Practice

Part I: Covers Sequence through Series Comparison Tests

JANE PROFESSOR WW Prob Lib1 Summer 2000

Math 132, Fall 2009 Exam 2: Solutions

MATH 312 Midterm I(Spring 2015)

10.6 ALTERNATING SERIES

10.1 Sequences. n term. We will deal a. a n or a n n. ( 1) n ( 1) n 1 2 ( 1) a =, 0 0,,,,, ln n. n an 2. n term.

Please do NOT write in this box. Multiple Choice. Total

Review for Test 3 Math 1552, Integral Calculus Sections 8.8,

d) If the sequence of partial sums converges to a limit L, we say that the series converges and its

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +

2.4.2 A Theorem About Absolutely Convergent Series

Solutions to Practice Midterms. Practice Midterm 1

SCORE. Exam 2. MA 114 Exam 2 Fall 2017

Practice Test Problems for Test IV, with Solutions

Math 140A Elementary Analysis Homework Questions 3-1

Mathematics 116 HWK 21 Solutions 8.2 p580

MAT1026 Calculus II Basic Convergence Tests for Series

Physics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing

Math 113 Exam 4 Practice

Series III. Chapter Alternating Series

11.6 Absolute Convrg. (Ratio & Root Tests) & 11.7 Strategy for Testing Series

Section 11.6 Absolute and Conditional Convergence, Root and Ratio Tests

8.3. Click here for answers. Click here for solutions. THE INTEGRAL AND COMPARISON TESTS. n 3 n 2. 4 n 5 1. sn 1. is convergent or divergent.

The Interval of Convergence for a Power Series Examples

Quiz No. 1. ln n n. 1. Define: an infinite sequence A function whose domain is N 2. Define: a convergent sequence A sequence that has a limit

n=1 a n is the sequence (s n ) n 1 n=1 a n converges to s. We write a n = s, n=1 n=1 a n

Testing for Convergence

SCORE. Exam 2. MA 114 Exam 2 Fall 2016

= lim. = lim. 3 dx = lim. [1 1 b 3 ]=1. 3. Determine if the following series converge or diverge. Justify your answers completely.

Infinite Sequence and Series

Topics. Homework Problems. MATH 301 Introduction to Analysis Chapter Four Sequences. 1. Definition of convergence of sequences.

Calculus II Homework: The Integral Test and Estimation of Sums Page 1

Chapter 10: Power Series

Series Review. a i converges if lim. i=1. a i. lim S n = lim i=1. 2 k(k + 2) converges. k=1. k=1

Sequences. A Sequence is a list of numbers written in order.

Fall 2018 Exam 2 PIN: 17 INSTRUCTIONS

Carleton College, Winter 2017 Math 121, Practice Final Prof. Jones. Note: the exam will have a section of true-false questions, like the one below.

Infinite Sequences and Series

PLEASE MARK YOUR ANSWERS WITH AN X, not a circle! 1. (a) (b) (c) (d) (e) 3. (a) (b) (c) (d) (e) 5. (a) (b) (c) (d) (e) 7. (a) (b) (c) (d) (e)

Ma 530 Introduction to Power Series

1. Do the following sequences converge or diverge? If convergent, give the limit. Explicitly show your reasoning. 2n + 1 n ( 1) n+1.

Sec 8.4. Alternating Series Test. A. Before Class Video Examples. Example 1: Determine whether the following series is convergent or divergent.

Alternating Series. 1 n 0 2 n n THEOREM 9.14 Alternating Series Test Let a n > 0. The alternating series. 1 n a n.

INFINITE SEQUENCES AND SERIES

Sequences. Notation. Convergence of a Sequence

MA131 - Analysis 1. Workbook 9 Series III

MIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS

11.6 Absolute Convergence and the Ratio and Root Tests

An alternating series is a series where the signs alternate. Generally (but not always) there is a factor of the form ( 1) n + 1

Notice that this test does not say anything about divergence of an alternating series.

NATIONAL UNIVERSITY OF SINGAPORE FACULTY OF SCIENCE SEMESTER 1 EXAMINATION ADVANCED CALCULUS II. November 2003 Time allowed :

sin(n) + 2 cos(2n) n 3/2 3 sin(n) 2cos(2n) n 3/2 a n =

THE INTEGRAL TEST AND ESTIMATES OF SUMS

7 Sequences of real numbers

Convergence: nth-term Test, Comparing Non-negative Series, Ratio Test

Chapter 6: Numerical Series

Seunghee Ye Ma 8: Week 5 Oct 28

The Ratio Test. THEOREM 9.17 Ratio Test Let a n be a series with nonzero terms. 1. a. n converges absolutely if lim. n 1

Series Solutions (BC only)

SCORE. Exam 2. MA 114 Exam 2 Fall 2016

Lecture 2 Appendix B: Some sample problems from Boas, Chapter 1. Solution: We want to use the general expression for the form of a geometric series

SUMMARY OF SEQUENCES AND SERIES

CHAPTER 10 INFINITE SEQUENCES AND SERIES

MH1101 AY1617 Sem 2. Question 1. NOT TESTED THIS TIME

Section 11.8: Power Series

MTH 142 Exam 3 Spr 2011 Practice Problem Solutions 1

Chapter 6 Infinite Series

10. 3 The Integral and Comparison Test, Estimating Sums

5 Sequences and Series

Quiz. Use either the RATIO or ROOT TEST to determine whether the series is convergent or not.

Solutions to Tutorial 5 (Week 6)

Math 113 Exam 3 Practice

Read carefully the instructions on the answer book and make sure that the particulars required are entered on each answer book.

BC: Q401.CH9A Convergent and Divergent Series (LESSON 1)

MTH 246 TEST 3 April 4, 2014

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics:

MATH 2300 review problems for Exam 2

Solutions to Homework 7

Chapter 7: Numerical Series

B U Department of Mathematics Math 101 Calculus I

Real Variables II Homework Set #5

INFINITE SERIES PROBLEMS-SOLUTIONS. 3 n and 1. converges by the Comparison Test. and. ( 8 ) 2 n. 4 n + 2. n n = 4 lim 1

1 Lecture 2: Sequence, Series and power series (8/14/2012)

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

MATH2007* Partial Answers to Review Exercises Fall 2004

Transcription:

Calculus II Homework: The Compariso Tests Page Questios l coverget or diverget? + 7 3 + 5 coverget or diverget? Example Suppose a ad b are series with positive terms ad b is kow to be coverget. a If a > b for all, what ca you say about a? Why? b If a < b for all, what ca you say about a? Why? Example Determie whether the series coverges or diverges. + +. + coverget or diverget? Example Determie whether the series coverges or diverges. +. Example Suppose that a ad b are series with positive terms ad b is coverget. Prove that if a lim = 0 b the a is coverget. Note: This is a more difficult problem tha most, sice it is a proof that ivolves the defiitio of limit. Example Suppose that a ad b are series with positive terms ad b is diverget. Prove that if a lim = b the a is diverget. Note: This is a more complicated problem tha most, ad ivolves usig a proof by cotradictio. Solutios l coverget or diverget? Let s try to use the Compariso Test. How do we kow what series to compare to? Well, we try somethig, ad use a series which we kow somethig about. We usually try to pick our compariso series based o attributes of the give

Calculus II Homework: The Compariso Tests Page series. Sice l > for 3 a = l > = b for 3 =3 is diverget it is a p-series with p =, we kow + 7 3 + 5 coverget or diverget? Let s try to use the Limit Compariso Test. For large, l is diverget by the compariso test. + 7 3 + 5 3 So let s take a = + 7 3 + 5 b = 3 = 3 The series b = 3 is a coverget geometric series sice a = /3, r = /3 <. 3 + 7 a 3 + 5 lim b 3 + 7 3 3 + 5 + 7 + 5 + 7/ + 5/ / = > 0 ad fiite. Sice b coverges, a coverges by the limit compariso test. Example Suppose a ad b are series with positive terms ad b is kow to be coverget. a If a > b for all, what ca you say about a? Why? b If a < b for all, what ca you say about a? Why?

Calculus II Homework: The Compariso Tests Page 3 a If a > b for all, ad b is coverget, the we caot say aythig about a sice it is ot bouded above by b. b Sice a is positive, the series a must be icreasig sice we are always addig a positive quatity to the partial sum i other words, s + > s. If a < b for all, ad b is coverget, the a is coverget sice it is bouded above by b which coverges. Example.4.3 Determie whether the series coverges or diverges. + +. Let s try to use the Compariso Test. Let s try to pick our compariso series based o attributes of the give series. + + > for a = < + + = b for ote chage i the relatio Sice b = compariso test. is coverget it is a p-series with p =, we kow a = + coverget or diverget? Let s try to use the Limit Compariso Test. For large, + + is coverget by the + So let s take a = + b = = The series b = a lim b is a coverget geometric series sice a = /, r = / <. + + + + / = > 0 ad fiite.

Calculus II Homework: The Compariso Tests Page 4 Sice b coverges, a coverges by the limit compariso test. Example Determie whether the series coverges or diverges. +. Let s try to use the Compariso Test. Let s try to pick our compariso series based o attributes of the give series. + > for a = + < = b for ote chage i the relatio Sice b = is diverget it is a p-series with p = /, this does t tell us aythig about a see... Sice this does t help us, we ll have to try somethig else. Let s try the limit compariso test with the compariso series b = a + lim b + + + / = > 0 ad fiite.. Sice b diverges, a diverges by the limit compariso test. Example Suppose that a ad b are series with positive terms ad b is coverget. Prove that if a lim = 0 b the a is coverget. Note: This is a more difficult problem tha most, sice it is a proof that ivolves the defiitio of limit. a Sice lim = 0, by the defiitio of limit we kow there exists a N > 0 such that a /b 0 < for all > N. b Sice a ad b are positive, a /b 0 < a < b. Therefore, sice b coverges, a coverges by the compariso test.

Calculus II Homework: The Compariso Tests Page 5 Example Suppose that a ad b are series with positive terms ad b is diverget. Prove that if a lim = b the a is diverget. Note: This is a more complicated problem tha most, ad ivolves usig a proof by cotradictio. Assume a coverges. a b Sice lim = lim = 0. b a Usig the result from Problem.4.40 a, we kow that if a coverges the b coverges as well. But we are told that b diverges cotradictio. diverges. Therefore, the assumptio we made must be wrog, ad a