Electricity and Magnetism

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MISN-0-504 REVIEW OF ELECTROSTATICS Electricity and Magnetism REVIEW OF ELECTROSTATICS by R. D. Young 1. Introduction.............................................. 1 2. Procedures................................................ 1 3. Supplementary Notes.................................... 4 Acknowledgments............................................6 Project PHYSNET Physics Bldg. Michigan State University East Lansing, MI 1

ID Sheet: MISN-0-504 Title: Review of Electrostatics Author: R.D. Young, Dept. of Physics, Ill. State Univ. Version: 10/18/2001 Length: 2 hr; 12 pages Input Skills: Evaluation: Stage B0 1. Vocabulary: conservative force, potential energy (MISN-0-21); conductivity (MISN-0-118). 2. Perform basic vector analysis (MISN-0-503). 3. Expand binomial denominators using the binomial theorem. 4. Represent tensor elements using standard matrix notation (MISN- 0-491). Output Skills (Knowledge): K1. Vocabulary: volume charge density, electric dipole moment, surface charge density, electric monopole moment, electric uadrupole moment. K2. State the formal expressions for the electrostatic field and potential of an arbitrary distribution of charge, and the relationship between the field and the potential. K3. State Gauss s law in both integral and differential form. Derive each form of Gauss s law from the other by use of the divergence theorem. K4. Derive the approximate forms (to first order in the dipole separation) of the electrostatic field and potential produced by a dipole beginning with the exact forms of each uantity. Output Skills (Rule Application): R1. Compute the monopole, dipole and uadrupole moments of a given charge distribution. R2. For a given set of multipole moments, compute the approximate form of the electrostatic potential far from the charge distribution. External Resources (Reuired): 1. J. Reitz, F. Milford and R. Christy, Foundations of Electromagnetic Theory, 4th Edition, Addison-Wesley (1993). THIS IS A DEVELOPMENTAL-STAGE PUBLICATION OF PROJECT PHYSNET The goal of our project is to assist a network of educators and scientists in transferring physics from one person to another. We support manuscript processing and distribution, along with communication and information systems. We also work with employers to identify basic scientific skills as well as physics topics that are needed in science and technology. A number of our publications are aimed at assisting users in acuiring such skills. Our publications are designed: (i) to be updated uickly in response to field tests and new scientific developments; (ii) to be used in both classroom and professional settings; (iii) to show the prereuisite dependencies existing among the various chunks of physics knowledge and skill, as a guide both to mental organization and to use of the materials; and (iv) to be adapted uickly to specific user needs ranging from single-skill instruction to complete custom textbooks. New authors, reviewers and field testers are welcome. PROJECT STAFF Andrew Schnepp Eugene Kales Peter Signell Webmaster Graphics Project Director ADVISORY COMMITTEE D. Alan Bromley Yale University E. Leonard Jossem The Ohio State University A. A. Strassenburg S. U. N. Y., Stony Brook Views expressed in a module are those of the module author(s) and are not necessarily those of other project participants. c 2001, Peter Signell for Project PHYSNET, Physics-Astronomy Bldg., Mich. State Univ., E. Lansing, MI 48824; (517) 355-3784. For our liberal use policies see: http://www.physnet.org/home/modules/license.html. 3 4

MISN-0-504 1 REVIEW OF ELECTROSTATICS by R. D. Young 1. Introduction You have already studied most of the physical concepts introduced in this unit. For example, the concepts of charge, charge distribution, Coulomb s Law, the electrostatic field E, the electrostatic potential, Gauss Law, and simple electric dipoles. You have also performed numerical calculations using all of these concepts. In this unit you will review those concepts. However, the treatment is more mathematically sophisticated than the previous treatment to which you were exposed. For example, vector analysis will be used more extensively. Also, expressions for Coulomb s Law, the electrostatic field E, and the electrostatic potential will be written with respect to an arbitrary coordinate system rather than having the origin at the position where the electrostatic force, field, or potential is being calculated. In addition, this unit generalizes the discussion of electric dipoles. This is accompanied by introducing the concept of multipole expansions. By using a multipole expansion, the electrostatic field and potential of an arbitrary charge distribution can be approximately calculated to any degree of accuracy. This reuires the introduction of the concepts of the monopole moment, dipole moment, uadrupole moment, etc., of a charge distribution. The moments of a charge distribution are very important in many fields when approximate calculations are being performed. 1. Read Ch. 2 of the text. 2. Procedures 2. Write down or underline the definitions, terms, and euations called for in Output Skills K1-K2. See the Supplementary Notes. 3. Write down the details of the derivation of the differential form of Gauss Law as given at the end of section 2-6, between es. 2-25 to 2-28. This proof can also run in the opposite direction by beginning with the differential form of Gauss Law and deriving the integral form. MISN-0-504 2 4. Write down the derivation of the approximate form of the electrostatic field (e. 2-36) of a simple electric dipole to first order in the dipole separation l beginning with the exact form of the electrostatic field (e. 2-32). Use the hints in section 2-8. The following formula is useful here, (1 ± x) n n(n + 1) = 1 nx + x 2... 2! for x < 1. So, if l 1, then ( 1 2( r r ) l r r 2 + ( 1 2( r r ) l r r 2 + to first order in l. Also, l 2 r r 2 ) 3/2 ( = 1 3 2 + 2( r r ) l r r 2 +..., l 2 r r 2 1 2( r r ) l r r 2 ) 3/2 ) 3/2 1 + 3( r r ) l r r 2 +... lim p = l. l 0 Of course the charge must increase as l decreases, in going to the limit, so that p remains finite. These results are used in the derivation. Write down the derivation of the approximate form of the electrostatic potential (e. 2-39) to first order in the dipole separation l beginning with the exact form of the electrostatic field. 5. Write down the expression of the approximate form of the electrostatic potential (e. 2-48) of an arbitrary charge distribution beginning with the exact form of the potential (e. 2-45). This expression reuires some comment. The charge is localized in the volume V with charge density ρ( r ) as shown in Fig. 2-12. Suppose the parameter d is a dimension characteristic of the spatial extent of the volume V. Then the observation point is taken to be r such that d/r 1 where r = r. Then, the expansion of the denominator r r 1 is made in terms of r /r. Terms involving cube and higher powers of r /r are dropped. This is the reasoning used 5 6

MISN-0-504 3 between e. 2-46 and 2-47 of the text. The final approximate result for the potential can be expressed as: V ( r) = 1 Q p r + 4πɛ 0 r r 3 + 1 x i x j 2 r 5 Q ij +... i=1 j=1 where Q = (monopole moment) = ρ( r )dv V p = (dipole moments) = rρ( r )dv V Q ij = (uadrupole moments) = (3x ix j δ ij r 2 )ρ( r )dv V This type of expansion is known as a multipole expansion. 1 The approximation gets better the more terms which are included. The next higher-order term beyond the uadrupole moment term is the octopole moment term. The octopole moment is important in nuclear physics but we shall not delve into it here. Note that the monopole moment is just the total charge. 6. Solve the following problems in the text: 2-23, 2-24, 2-25. Note: to solve 2-23 start with the expression: where F ext = E ext ( r) + E ext ( r + l) E ext ( r + l) E ext ( r) + l E ext ( r) +... Also, in 2-24 do not plot the euipotential surfaces. Keep up to the uadrupole term in the potential, however. 1 Q 11 = (3x V 1 x 1 δ 11r 2 )dv = ρ(3x 2 V 1 x 2 1 x 2 2 x 2 3 )dv Q 11 = ρ(2x 2 V 1 x 2 2 x 2 3 )dv, since δ 11 = 1 Q 12 = ρ(3x V 1 x 2 δ 12r 2 )dv = ρ3x V 1 x 2 dv MISN-0-504 4 x' z' O ' Figure 1.. 1 r1 ri i rn (i is an arbitrary charge in the assembly) n 3. Supplementary Notes Reference to an arbitrary origin In your past experiences with electrostatics, you have written down expressions for electrostatic forces, fields, and potentials where the point of interest was at the origin of the coordinate system. For example, consider the electrostatic force on a point charge due to an assembly of point charges 1, 2,..., n located at r 1, r 2, r 3,..., r n respectively. The point charge is located at the origin (see Fig. 1). where and Then the force F on is given by Coulomb s Law as, F = 4πɛ 0 n i=1 y' i ( r i) r i 3 r i = x i i + y i j + z i k r i = x 2 i + y i 2 + z i 2 The minus sign is present because the vector r i between i and is usually drawn from i to rather than from to i as we have it here. In the present text, the situation is generalized by allowing the charge to be located at r relative to some coordinate system (see Fig. 2). This arbitrary coordinate system is denoted by unprimed uantities. It should be pointed out that the vectors r i are considered as constant 7 8

MISN-0-504 5 MISN-0-504 6 z' Acknowledgments z x' O ' r y' ri r i' i The author would like to thank Illinois State University for support in the construction of this lesson. Preparation of this module was supported in part by the National Science Foundation, Division of Science Education Development and Research, through Grant #SED 74-20088 to Michigan State University. x O Figure 2.. y = r xì + yí + zî r = x Ì + y Í + z Î i i i i vectors (so the components are just constant scalars). This happens because the charge assembly is fixed. However, the charge is free to move so the vector i is considered as a variable vector. It is obvious that, and that, Combining (I-1) and (I-2) gives, r i = r + r i r i = r r i F = F ( r) = 4πɛ 0 n i=1 i ( r r i ) r r 3 This is the first term in e. (2-7) of the text. The other terms can be obtained in a similar manner. The notation in (I-4) is meant to dramatize that the force is now a function of the position vector r of the charge. So, F = F ( r) = (F x (x, y, z) i + F y (x, y, z) j + F z (x, y, z) k and F x (x, y, z) = 4πɛ 0 n i=1 i x x i [(x x i ) 2 + (y y i ) 2 + (z z i ) 2 ] 3/2 etc.. Keep in mind that (x, y, z) are variables above while all other symbols, including (x i, y i, z i ), are constants. 9 10

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