Closed book exam, no books, notebooks, notes, etc. allowed. However, calculators, rulers, and molecular model sets are permitted.

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Massachusetts Institute of Technology Organic Chemistry 5.13 Friday, September 26, 2003 Prof. Timothy F. Jamison Hour Exam #1 Name (please both print and sign your name) Official Recitation Instructor Directions: Closed book exam, no books, notebooks, notes, etc. allowed. However, calculators, rulers, and molecular model sets are permitted. Please read through the entire exam before beginning, in order to make sure that you have all the pages and in order to gauge the relative difficulty of each question. Budget your time accordingly. Show all of your work if you wish to receive partial credit. You should have 12 pages total: 6 exam pages including this page, 4 pages of reference information, and 2 blank pages for scratchwork. Question: 1. / 36 points 2. / 20 points 3. / 20 points 4. / 24 points Grader: Total: / 100 points 1

1. (36 points total) Use the information provided below and the IR and NMR spectra on the next page to answer the following questions. a. (10 points) Determine the molecular formula that satisfies the following data (circle your final answer): EA (found): C, 37.02; H, 2.22; N, 18.50; and M = 227 b. (6 points) Calculate the Index of Hydrogen Deficiency (IHD) for the molecule in a, above (circle your final answer). c. (5 points) An IR spectrum of the molecule in a appears on the following page. What functional group or groups correspond(s) to the 2 most intense peaks in the spectrum? Draw the structure of this/these group(s), showing all bonds (i.e. single, double, triple). d. (10 points) Using the information in a, b, and c, above, and the 1 H NMR and 13 C NMR spectra on the next page, determine a structure of this unknown molecule that is consistent with all data. Draw the structure of this molecule below (circle your final answer). e. (5 points) Provide an explanation for the fact that the singlet at 9.4 ppm in the 1 H NMR spectrum appears so far downfield. f. (EXTRA CREDIT, 5 points): What is this compound, and what is its most notorious physical property? 2

(IR, 1 H NMR and 13 C NMR spectra for the molecule in problem 1 on the previous page) IR 1544 1351 13 C NMR 160 140 120 100 80 60 40 20 0 PPM 1 H NMR 3H 2H 10 8 6 4 2 0 PPM 3

2. (20 points) Using only 1 H NMR spectroscopy, how would you conclusively distinguish between all 3 isomers (ortho, meta, and para) of bromophenol? Be as specific as necessary in order to differentiate ortho from meta, meta from para, and ortho from para. (Suggestion: Use chemical structures as part of your answer.) OH OH OH Br Br Br 4

3. (20 points) An unknown compound X (containing only carbon, hydrogen, and oxygen) has m/z = 172 (M ) and 115, and its 13 C NMR spectrum below. When treated with lithium aluminum hydride in ether, a single compound Y is produced, and its 1 H NMR spectrum is given below. In the space below the NMR spectra at the bottom of the page, draw the structures of X and Y. Circle your final answers and clearly indicate which is compound X (12 points) and which is compound Y (8 points). 13 C NMR of compound X 180 160 140 120 100 80 60 40 20 0 PPM 1 H NMR of compound Y 9H 2H 1H (broad) 4 3 2 1 0 PPM 5

4. (24 points) Mass spectrometry was performed on 5-phenyl-2-pentanone (below), and several signals corresponding to fragments (M f ) were observed in the spectrum. Write the m/z value observed for M in the box provided (3 points). In each question below the m/z value for M f is provided. Draw the structure of M f in the corresponding box (3 points each). Also, write the molecular weight of the neutral species (M neutral ) formed in each fragmentation in the boxes on the right (1 point each). Finally, draw the structure of each (Mneutral) in the boxes on the right (3 points each). BE SURE TO INDICATE WHETHER EACH M f and EACH M neutral is a radical (i.e. has an unpaired electron). H 3 C O M = (Write the structure of M f here.) ( Wr i te the structure of M neutral here. ) a. m/z for M f = 147 mass of M = neutral (Write the structure of M f here.) ( Wr i te the structure of M neutral here. ) b. m/z for M f = 91 mass of M = neutral (Write the structure of M f here.) ( Wr i te the structure of M neutral here. ) c. m/z for M f = 58 mass of M = neutral 6

Characteristic Functional Group Chemical Shifts in 13 C NMR (ppm) Alkanes Organohalogen Methyl (RCH 3 ) 0-30 C F 70-80 Methylene (RCH 2 R ) 15-55 C Cl 25-50 Methine (RCH(R )(R )) 25-55 C Br 10-40 Quaternary (RC(R )(R )(R )) 30-40 C I 20-10 Alkenes 100-150 Ketones, Aldehydes 185-220 Aromatic 120-160 Carboxyl Derivatives Alkynes 70-90 Acids 150-185 Nitriles 110-125 Esters 155-180 Alcohols, Ethers 50-90 Amides 150-180 Amines 40-60 Carbamates 150-160