EQUIVALENCE OF STURM-LIOUVILLE PROBLEM WITH FINITELY MANY ABDULLAH KABLAN, MEHMET AKİF ÇETİN

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International Journal of Analysis and Applications Volume 16 Number 1 (2018) 25-37 URL: https://doi.org/10.28924/2291-8639 DOI: 10.28924/2291-8639-16-2018-25 EQUIVALENCE OF STURM-LIOUVILLE PROBLEM WITH FINITELY MANY δ-interactions AND MATRIX EIGENVALUE PROBLEMS ABDULLAH KABLAN MEHMET AKİF ÇETİN Faculty of Arts and Sciences Department of Mathematics Gaziantep University Gaziantep 27310 Turkey Corresponding author: kablan@gantep.edu.tr Abstract. The purpuse of this article is to show the matrix representations of Sturm-Liouville operators with finitely many δ-interactions. We show that a Sturm-Liouville problem with finitely many δ-interactions can be represented as a finite dimensional matrix eigenvalue problem which has the same eigenvalue with the former Sturm-Liouville operator. Moreover an example is also presented. 1. Introduction Acording to classical spectral theory a Sturm Liouville problem (SLP) consisting of the equation (py ) + qy = λwy on J = (a b) and boundary conditions has infinite spectrum under some assumptions. Atkinson in his book [1] suggested that if the coefficients of SLP satisfy some conditions the problem may have finite eigenvalues. Then in [2] Kong Wu and Zettl obtained the following result: For every positive integer n we can construct a class of regular self-adjoint and nonself-adjoint SLP with exactly n eigenvalues by choosing p and w such that 1/p and w are alternatively zero on consecutive subintervals. Recently there has been much attention paid to the SLPs with finite spectrum. For a comprehensive treatment of the subject we refer the reader to the book by Zettl [3] and the papers by Kong Wu and Zettl [2] Ao Sun and Zhang [4] [5] and Ao Bo and Sun [6] [7]. In 2009 the equivalence of SLP with Received 7 th September 2017; accepted 20 th October 2017; published 3 rd January 2018. 2010 Mathematics Subject Classification. 34B24 47A10 15A18. Key words and phrases. one-dimensional Schrödinger operator; finite spectrum; point interactions. c 2018 Authors retain the copyrights of their papers and all open access articles are distributed under the terms of the Creative Commons Attribution License. 25

Int. J. Anal. Appl. 16 (1) (2018) 26 a matrix eigenvalue problem was first constructed by Volkmer and Zettl in [8]. By equivalance of matrix eigenvalue problems for the SLPs with finite spectrum we mean to construct a matrix eigenvalue problem with exactly the same eigenvalues as the corresponding SLP. Then the matrix representations of SLPs with finite spectrum are extended to various problems. For the SLPs see [8]- [11] and for fourth order boundary value problems see [12]- [16]. The goal of this paper is to find the matrix representation of the following Sturm-Liouville problem with finitely many δ-interactions: (py ) + α n δ(x x n )y + qy = λwy on J = (a b) (1.1) n=1 where J = (a x 1 ) (x 1 x 2 )... (x n b) x 1... x n (a b) with < a < b < α j s are real numbers δ(x) is the Dirac delta function and λ C is a spectral parameter. Sturm-Liouville equations with Dirac delta function potentials often appear in quantum mechanics. For example such an equations had been used for modelling of atomic and molecular systems including atomic lattices quantum heterostructures semiconductors organic fluorescent materials solar cells etc. (see [17] [18] [19] and citations of them). Recently we generalize the finite spectrum result to the problem (1.1) in [20]. The equation (1.1) is equivalent to the many-point boundary value problem (see [19]). So we can understand problem (1.1) as studying the equation (py ) + qy = λwy on J (1.2) and n transmission conditions C j Y (x j ) = Y (x j +) Y = y py j = 1 2... n (1.3) where x j s are inner discontinuity points and C j = 1 0 α j 1. Additionally let us consider the boundary conditions of the form AY (a) + BY (b) = 0 A B M 2 (C) (1.4) where A = (a ij ) 2 2 B = (b ij ) 2 2 are complex valued 2 2 matrices and M 2 (C) denotes the set of square matrices of order 2 over C. Here the coefficients fulfill the following minimal conditions: r = 1 q w L(J C) (1.5) p where L(J C) denotes the complex valued functions which are Lebesgue integrable on J.

Int. J. Anal. Appl. 16 (1) (2018) 27 The BC (1.3) is said to be self-adjoint if the following two conditions are satisfied: rank(a B) = 2 AEA = BEB with E = 0 1. (1.6) 1 0 It is well known that under the condition (1.5) the BCs (1.3) fall into two disjoint classes: seperated and coupled. The seperated boundary conditions have the canonical representation: cos αy(a) sin α(py )(a) = 0 0 α < π (1.7) cos βy(b) sin β(py )(b) = 0 0 < β π. The real coupled boundary conditions have the canonical representation: Y (b) = KY (a) with K = (k st ) 2 2 k st R det(k) = 1. (1.8) Let u = y and v = (py ). Then we have the system representation of equation (1.2) u = rv v = (q λw)u on J. (1.9) 2. Matrix representations of SLPs with Finitely Many δ-interactions Definition 2.1. A Sturm-Liouville equation with finitely many δ-interactions (1.1) or equivalently the equation (1.2) with transmission condition (1.3) is said to be of Atkinson type if for some integers m j 1 j = 0 1... n there exists a partition of the interval J a = x 00 < x 01 < x 02 <... < x 02m0+1 = x 1 (2.1) x 1 = x 10 < x 11 < x 12 <... < x 12m1+1 = x 2. x n 1 = x n 10 < x n 11 < x n 12 <... < x n 12mn 1+1 = x n x n = x n0 < x n1 < x n2 <... < x n2mn+1 = b such that for each j {0 1... n} r = 1 p = 0 on (x j2k; ] k = 0 1... m j 1 and [ x j2mj ; x j2mj+1) x j2k w 0 x j2k q 0 k = 0 1... m j (2.2) and q = w = 0 on [ ; x j2k+2 ] x j2k+2 r 0 k = 0 1... m j 1. (2.3)

Int. J. Anal. Appl. 16 (1) (2018) 28 Our main aim in this section is to constract matrix eigenvalue problems in such a way that its eigenvalues are exactly the same as those of the corresponding SLPs with finitely many δ-interactions of Atkinson type. Definition 2.2. A SLP with finitely many δ-interactions of Atkinson type is said to be equivalent to a matrix eigenvalue problem if the former has exactly the same eigenvalues as the latter. We begin by stating some additional notation. For each j {0 1... n} given (2.1)-(2.3) let q jk = p jk = x j2k x j2k 1 r x j2k q w jk = 1 k = 1 2... m j ; x j2k w k = 0 1... m j. (2.4) and let introduce the notation n m = m j. (2.5) j=0 We note from (2.2) and (2.3) that p jk w jk R {0} and no sign restrictions are imposed on them. From (2.2) and (2.3) we can make the following observation: For any solution u v of (1.9) u is constant on the intervals where r is identically zero and v is constant on the intervals where both q and w are both identically zero. Let u 0k = u(x) x [x 02k ; x 02k+1 ] k = 0 1... m 0 1 (2.6) u 0m0 = u(x) x [x 02m0 ; x 02m0+1) u j0 = u(x) x (x j0 ; x j1 ] j = 1 2... n u jk = u(x) x [x j2k ; ] k = 1 2... m j 1 j = 1 2... n 1 u jmj = u(x) x [x j2mj ; x j2mj+1) j = 0 1... n 1 u nk = u(x) x [x n2k ; x n2k+1 ] k = 1 2... m n v jk = v(x) x [x j2k 1 ; x j2k ) k = 1 2... m j j = 0 1... n and set v j0 = v(x j0 +) v jmj+1 = v(x j2mj+1 ) j = 0 1... n. (2.7) Lemma 2.1. Assume Eq. (1.2) is of Atkinson type. Then for each j = 0 1... n and for any solution u v of Eq. (1.9) we have p jk (u jk u jk 1 ) = v jk k = 1 2... m j (2.8) v jk+1 v jk = u jk (q jk λw jk ) k = 0 1... m j. (2.9)

Int. J. Anal. Appl. 16 (1) (2018) 29 Conversely for any solution u jk k = 0 1... m j and v jk k = 0 1... m j + 1 of system (2.8) (2.9) there is a unique solution u(x) and v(x) of Eq. (1.9) satisfying (2.6) and (2.7). Proof. Relying on the first equation of (1.9) for k = 1 2... m j we have u jk u jk 1 = u(x j2k ) u(x j2k 2 ) = = x j2k x j2k 1 rv = v jk x j2k x j2k x j2k 2 u = x j2k 1 r = v jk p jk. x j2k x j2k 2 rv This establishes (2.8). Similarly from second equation of (1.9) for k = 0 1... m j we have which gives (2.9). v jk+1 v jk = v( ) v(x j2k 1 ) = = x j2k (q λw)u = u jk x j2k 1 v = x j2k 1 (q λw)u x j2k (q λw) = u jk (q jk λw jk ) On the other hand if u jk v jk satisfy (2.8) and (2.9) then we define u(x) and v(x) according to (2.6) and (2.7) and then extend them continuously to the whole interval J as a solution of (1.9) by integrating the equations in (1.9) over subintervals. First we consider SLP with transmission condition(1.2)-(1.4) with seperated BC (1.7). Theorem 2.1. Assume α [0 π) β (0 π]. Define an (m + 1) (m + 1) tridiagonal block matrix and diagonal matrices M 0 N 1 M 1 N 2 M 2 P αβ =...... N n M n N n+1 M n+1 Q αβ = diag (q 00 sin α q 01... q 0m0 1 q 0m0 + q 10 q 11... q nmn 1 q nmn sin β) W αβ = diag (w 00 sin α w 01... w 0m0 1 w 0m0 + w 10 w 11... w nmn 1 w nmn sin β). Then SLP with transmission conditions (1.2) (1.3) (1.7) is equivalent to matrix eigenvalue problem (P αβ + Q αβ ) U = λw αβ U (2.10)

Int. J. Anal. Appl. 16 (1) (2018) 30 where m is as defined in (2.5) U = [u 00 u 01... u 0m0 u 11... u 1m1... u n1... u nmn ] T and the matrices M j s and N j s are defined as follows: [ M 0 = p 01 sin α + cos α p 01 sin α ] (2.11) for each j = 0 1... n the m j 2 matrices N j+1 = p j1 p j1 + p j2 0 p j2 0 0.. 0 0 (2.12) for each j = 0 1... n 1 the m j m j matrices p j2 p j2 + p j3 p j3 p j3 p j3 + p j4 p j4 M j+1 =......... p jmj 1 p jmj 1 + p jmj p jmj p jmj p jmj + p j+11 + α j+1 p j+11 (2.13) and the m n (m n 1) matrix p n2 p n2 + p n3 p n3 p n3 p n3 + p n4 p n4 M n+1 =......... p nmn 1 p nmn 1 + p nmn p nmn p nmn sin β p nmn sin β cos β. (2.14) Proof. For each j = 0 1... n and k = 1 2... m j 1 there is one-to-one correspondence between the solutions of system (2.8) (2.9) and the solutions of the following system: p j1 (u j1 u j0 ) v j0 = u j0 (q j0 λw j0 ) (2.15) p jk+1 (u jk+1 u jk ) p jk (u jk u jk 1 ) = u jk (q jk λw jk ) (2.16) v jmj+1 p jmj (u jmj u jmj 1 ) = u jmj (q jmj λw jmj ) (2.17)

Int. J. Anal. Appl. 16 (1) (2018) 31 Therefore by Lemma 2.1 any solution of equation (1.9) and hence of (1.2) is uniquely determined by a solution of system (2.15)-(2.17). Note that from boundary condition (1.7) we have u 00 cos α = v 00 sin α (2.18) u nmn cos β = v nmn+1 sin β and for each j = 0 1... n 1 from the transmission condition (1.3) we have u j+10 = u jmj (2.19) v j+10 = α j+1 u jmj + v jmj+1. Additionally for each j = 0 1... n 1 from the equations (2.15)-(2.19) we have ( ) ( ) ( ) p j+11 uj+11 u jmj pjmj ujmj u jmj 1 ujmj qjmj λw jmj (2.20) = α j+1 u jmj + u jmj (q j+10 λw j+10 ) p j+12 (u j+12 u j+11 ) p j+11 ( uj+11 u jmj ) = uj+11 (q j+11 λw j+11 ). (2.21) Then the equivalence follows from (2.15)-(2.18) and (2.20) (2.21). Corollary 2.1. Assume α β (0 π). Define the (m + 1) (m + 1) tridiagonal block matrix and diagonal matrices M 0 N 1 M 1 N 2 M 2 P αβ =...... N n M n N n+1 M n+1 Q αβ = diag (q 00 q 01... q 0m0 1 q 0m0 + q 10 q 11... q nmn 1 q nmn ) W αβ = diag (w 00 w 01... w 0m0 1 w 0m0 + w 10 w 11... w nmn 1 w nmn ). Then SLP with transmission conditions (1.2) (1.3) (1.7) is equivalent to matrix eigenvalue problem (P αβ + Q αβ ) U = λw αβ U (2.22) where U = [u 00 u 01... u 0m0 u 11... u 1m1... u n1... u nmn ] T

Int. J. Anal. Appl. 16 (1) (2018) 32 and the matrices M j s and N j s are defined as in Theorem 2.1 except M 0 and M n+1. In this case M 0 is 1 2 matrix [ M 0 = p 01 + cot α p 01 ] and M n+1 is m n (m n 1) matrix p n2 p n2 + p n3 p n3 p n3 p n3 + p n4 p n4 M n+1 =......... p nmn 1 p nmn 1 + p nmn p nmn p nmn cot β p nmn. Proof. If we divide the first and the last rows of system (2.10) by sin α and sin β respectively then we obtain (2.22). Theorem 2.1 and its Corollary show that the problem (1.2)-(1.4) (1.7) of Atkinson type have representations by tridiagonal matrix eigenvalue problems. Now we will show that the problem (1.2)-(1.4) (1.8) of Atkinson type also have representations. Theorem 2.2. Consider the boundary condition (1.8) with = 0. Define the m m matrix which is tridiagonal except for the (1 m) and (m 1) entries M 0 k 11 p nmn N 1 M 1 N 2 M 2 P 1 =...... N n M n k 11 p nmn N n+1 M n+1 and diagonal matrices Q 1 = diag ( q 00 + k 2 11q nmn q 01... q 0m0 1 q 0m0 + q 10 q 11... q nmn ) W 1 = diag ( w 00 + k11w 2 ) nmn w 01... w 0m0 1 w 0m0 + w 10 w 11... w nmn. Then SLP with transmission conditions (1.2) (1.3) (1.8) is equivalent to matrix eigenvalue problem (P 1 + Q 1 ) U = λw 1 U (2.23) where U = [ ] T u 00 u 01... u 0m0 u 11... u 1m1... u n1... u nmn 1

Int. J. Anal. Appl. 16 (1) (2018) 33 and the elements of the matrix P 1 are defined as follows: The 1 2 matrix [ M 0 = k 11 k 21 + p 01 + k 2 11p nmn p 01 ] for each j = 0 1... n 1 the m j 2 and for j = n the (m n 1) 2 matrices N j+1 = p j1 p j1 + p j2 0 p j2 0 0.. 0 0 for each j = 0 1... n 1 the m j m j matrices M j+1 = p j2 p j2 + p j3 p j3 p j3 p j3 + p j4 p j4......... p jmj 1 p jmj 1 + p jmj p jmj p jmj p jmj + p j+11 + α j+1 p j+11 and the (m n 1) (m n 2) matrix M n+1 = p n2 p n2 + p n3 p n3 p n3 p n3 + p n4 p n4......... p nmn 2 p nmn 2 + p nmn 1 p nmn 1 p nmn 1 p nmn 1 + p nmn. Proof. As mentioned before the transmission condition (1.3) is the same as (2.19). On the other hand since = 0 the boundary condition (1.8) is represented as follows: u nmn = k 11 u 00 (2.24) u nmn+1 = k 21 u 00 + k 22 v 00 where k 11 k 22 = 1. We find out that for each j = 0 1... n 1 and k = 0 1... m j 1 there is one-to-one correspondence between the solutions consisting of system (2.8) (2.9) (2.19) (2.24) and the solutions of the

Int. J. Anal. Appl. 16 (1) (2018) 34 following system: [ k11 k 21 + k11 2 ( pj+1mj+1 + q j+1m λw )] j+1 j+1m j+1 uj0 (2.25) = (λw j0 p j1 q j0 )u j0 + p j1 u j1 + k 11 p j+1mj+1 u j+1mj+1 1 p jk+1 (u jk+1 u jk ) p jk (u jk u jk 1 ) = u jk (q jk λw jk ) (2.26) p j+11 (u j+11 u j+10 ) v j+10 = u j+10 (q j+10 λw j+10 ) (2.27) p j+1mj+1 ( k11 u j0 u j+1mj+1 1) pj+1mj+1 1u j+1mj+1 1 (2.28) = p j+1mj+1 1u j+1mj+1 2 + u j+1mj+1 1(q j+1mj+1 1 λw j+1mj+1 1) Then by Lemma 2.1 any solution of system (1.9) hence of (1.2) is uniquely determined by a solution of system (2.25)-(2.28). Theorem 2.3. Consider the boundary condition (1.8) with 0. Define the (m + 1) (m + 1) matrix which is tridiagonal except for the (1 m + 1) and (m + 1 1) entries and diagonal matrices N 1 M 1 P 2 = M 0 1 N 2 M 2...... N n M n 1 N n+1 M n+1 Q 2 = diag (q 00 q 01... q 0m0 1 q 0m0 + q 10 q 11... q nmn 1 q nmn ) W 2 = diag (w 00 w 01... w 0m0 1 w 0m0 + w 10 w 11... w nmn 1 w nmn ) Then SLP with transmission conditions (1.2) (1.3) (1.8) is equivalent to matrix eigenvalue problem (P 2 + Q 2 ) U = λw 2 U (2.29) where U = [u 00 u 01... u 0m0 u 11... u 1m1... u n1... u nmn ] T and the elements of the matrix P 3 are defined as follows: For each j = 0 1... n the matrices N j+1 s and for each j = 0 1... n 1 the matrices M j+1 s are defined as in Theorem 2.2. On the other hand the 1 2 matrix [ M 0 = p 01 k11 p 01 ]

Int. J. Anal. Appl. 16 (1) (2018) 35 and the m n (m n 1) matrix p n2 p n2 + p n3 p n3 p n3 p n3 + p n4 p n4 M n+1 =......... p nmn 1 p nmn 1 + p nmn p nmn p nmn p nmn k22. Proof. The boundary condition (1.8) can be represented as follows: u nmn = k 11 u 00 + v 00 v nmn+1 = k 21 u 00 + k 22 v 00. Since k 11 k 22 k 21 = 1 we have from the this condition that v 00 = k 11 u 00 + 1 u nmn v nmn+1 = 1 u 00 + k 22 u nmn. On the other hand if we consider the transmission condition (2.19) the proof is similar with Theorem 2.2. 3. Example In this section we give an example to illustrate that a SLP with finitely many δ-interactions and it s equivalent matrix eigenvalue problem we will construct it have same eigenvalues. Consider the SLP with δ-interactions on J = ( 3 0) (0 6) (py ) + δ(x 0)y + qy = λwy. (3.1) This equation is equivalent to the following SLP (py ) + qy = λwy (3.2) with transmission condition y(0 ) y(0+) = 0 y(0 ) + py (0 ) py (0+) = 0. (3.3) By choosing α = 0 and β = π we consider the following boundary conditions y( 3) = 0 y(6) = 0. (3.4)

Int. J. Anal. Appl. 16 (1) (2018) 36 In this case the matrices in (1.3) and (1.4) become C 1 = 1 0 1 1 A = 1 0 0 0 B = 0 0 1 0 respectively. Now let s take a partition of the interval J as follows: a = 3 < 2 < 1 < 0 = x 1 (3.5) x 1 = 0 < 2 < 3 < 4 < 5 < 6 = x 2 = b. This yields that m 0 = 1 m 1 = 2 and define the piecewise constant functions p q w are as follows: ( 3 2) 0 ( 3 2) 1 ( 3 2) 1 ( 2 1) 0 ( 2 1) 0 ( 2 1) p(x) = ( 1 0) (0 2) 1 2 (2 3) q(x) = 1 ( 1 0) 2 (0 2) 0 (2 3) w(x) = 3 ( 1 0) 4 (0 2) 0 (2 3) (3.6) (3 4) 3 (3 4) 1 (3 4) 1 4 (4 5) (5 6) 0 (4 5) 4 (5 6) 0 (4 5) 2 (5 6) By using the similar method as given in [4] [5] or [20] we have the following two eigenvalues λ 1 = 0.67442 λ 2 = 3.75739. (3.7) On the other hand if we find the values p jk q jk w jk from (2.4) and use Theorem 2.1 we get the matrices P 0π = 1 0 0 0 1 5 2 1 2 0 0 1 2 3 4 1 4 0 0 0 1 Q 0π = 0 0 0 0 0 5 0 0 0 0 3 0 0 0 0 0 W 0π = 0 0 0 0 0 11 0 0 0 0 1 0 0 0 0 0 (3.8) and so the matrix eigenvalue problem (P 0π + Q 0π ) U = λw 0π U (3.9) which is equivalance of SLP with finitely many δ-interactions in (3.1). Indeed if we find the eigenvalues of the matrix eigenvalue problem (3.9) we obtain the eigenvalues in (3.7).

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