Formulae and examples of calculation

Similar documents
Front flange FLV. Max. [knm/stroke]

Vane Type Rotary Actuators Series Variations

AMORTIGUADORES DE IMPACTO

Check-Q-meter. Table of contents. Features. Functions. RE 27551/ /10 Replaces: Type FD

HRN/HRN-C Series Hydraulic Vane Rotary Actuators

is acting on a body of mass m = 3.0 kg and changes its velocity from an initial

Rotational Mechanics Part III Dynamics. Pre AP Physics

Wheel and Axle. Author: Joseph Harrison. Research Ans Aerospace Engineering 1 Expert, Monash University

Compendium Screw Jacks

Mechanics II. Which of the following relations among the forces W, k, N, and F must be true?

A 954 C HD. Technical Description Hydraulic Excavator. Machine for Industrial Applications

Linear guide drives. Synchronous shafts The use of synchronous shafts enables several linear axes to be operated with one drive.

Physics 23 Exam 3 April 2, 2009

DYNAMICS MOMENT OF INERTIA

Precision Ball Screw/Spline

Physics 53 Exam 3 November 3, 2010 Dr. Alward

Chapter 6. Hydraulic cylinders/rams (linear motors), and Lines/fittings. - Transforms the flow of a pressurized fluid into a push or pull of a rod.

Overview. Dry Friction Wedges Flatbelts Screws Bearings Rolling Resistance

APEX DYNAMICS, INC. Staianless

Selection Calculations For Linear & Rotary Actuators

Phys101 Second Major-173 Zero Version Coordinator: Dr. M. Al-Kuhaili Thursday, August 02, 2018 Page: 1. = 159 kw

Physics 201 Exam 3 (Monday, November 5) Fall 2012 (Saslow)

Selection table for guided systems (crank driven)

Chapter 8. Rotational Equilibrium and Rotational Dynamics. 1. Torque. 2. Torque and Equilibrium. 3. Center of Mass and Center of Gravity

Physics. TOPIC : Rotational motion. 1. A shell (at rest) explodes in to smalll fragment. The C.M. of mass of fragment will move with:

Ballistic pendulum Operating Instructions Fig. 1: Ballistic pendulum SAFETY PRECAUTIONS

Force and Motion 20 N. Force: Net Force on 2 kg mass = N. Net Force on 3 kg mass = = N. Motion: Mass Accel. of 2 kg mass = = kg m/s 2.

Webreview Torque and Rotation Practice Test

Physics I (Navitas) FINAL EXAM Fall 2015

PY205N Spring The vectors a, b, and c. are related by c = a b. The diagram below that best illustrates this relationship is (a) I

Quiz Number 4 PHYSICS April 17, 2009

Name Date Period PROBLEM SET: ROTATIONAL DYNAMICS

Use the following to answer question 1:

Engineering Reference

Final Examination Thursday May Please initial the statement below to show that you have read it

PHY218 SPRING 2016 Review for Final Exam: Week 14 Final Review: Chapters 1-11, 13-14

M/60210/M Miniature rotary actuators

A) 4.0 m/s B) 5.0 m/s C) 0 m/s D) 3.0 m/s E) 2.0 m/s. Ans: Q2.

1 MR SAMPLE EXAM 3 FALL 2013

Flywheels-Function need and Operation

NR ROTARY RING TABLE: FLEXIBLE IN EVERY RESPECT

Rotation. PHYS 101 Previous Exam Problems CHAPTER

Engineering Science OUTCOME 2 - TUTORIAL 3 FREE VIBRATIONS

CEE 271: Applied Mechanics II, Dynamics Lecture 25: Ch.17, Sec.4-5

Sensor Accessories. Rotary Motion Accessory Pack. Pendulum Rod with two masses, Angular Momentum disc set and Linear Rack with mini c-clamp

The basic dynamic load rating C is a statistical number and it is based on 90% of the bearings surviving 50 km of travel carrying the full load.

Identification system for short product names. Changes/amendments at a glance. 2 Bosch Rexroth AG OBB omega modules R ( )

TOPIC D: ROTATION EXAMPLES SPRING 2018

b) 2/3 MR 2 c) 3/4MR 2 d) 2/5MR 2

of the four-bar linkage shown in Figure 1 is T 12

On my honor, I have neither given nor received unauthorized aid on this examination.

LECTURE 11 FRICTION AND DRAG

CHAPTER 8: ROTATIONAL OF RIGID BODY PHYSICS. 1. Define Torque

Q1. Which of the following is the correct combination of dimensions for energy?

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Physics for Scientist and Engineers third edition Rotational Motion About a Fixed Axis Problems

r r Sample Final questions for PS 150

Solutions Midterm Exam 3 December 12, Match the above shown players of the best baseball team in the world with the following names:

PHYSICS 221 Fall 2016 EXAM 2: November 02, :15pm 10:15pm. Name (printed): Recitation Instructor: Section #:

Name: Date: Period: AP Physics C Rotational Motion HO19

Contents. Dynamics and control of mechanical systems. Focus on

Selection Calculations For Motorized Actuators

Ball Reverser. Ball Reverser Actuator. FLENNOR Power Transmission Products. Patented

SCHOOL OF COMPUTING, ENGINEERING AND MATHEMATICS SEMESTER 1 EXAMINATIONS 2012/2013 XE121. ENGINEERING CONCEPTS (Test)

Rotary modules.

AP Physics Free Response Practice Dynamics

Quantitative Skills in AP Physics 1

Fig. 6.1 Plate or disk cam.

ENGINEERING COUNCIL DYNAMICS OF MECHANICAL SYSTEMS D225 TUTORIAL 4 MOMENT OF INERTIA. On completion of this tutorial you should be able to

Rotation. I. Kinematics - Angular analogs

Physics Exam 2 October 11, 2007

5. Plane Kinetics of Rigid Bodies

Lightweight. Geislinger Gesilco

Unless otherwise specified, use g = 9.80 m/s2

DO NOT TURN PAGE TO START UNTIL TOLD TO DO SO.

Physics P201 D. Baxter/R. Heinz. EXAM #2 October 18, :00 9:00 PM INSTRUCTIONS

Q.1 a) any six of the following 6x2= 12. i) Define - ( Each term 01 mark)

Center of Gravity Pearson Education, Inc.

PHY131H1S - Class 20. Pre-class reading quiz on Chapter 12

Linear Shaft Motor Sizing Application Note

Sample Final Exam 02 Physics 106 (Answers on last page)

Rotational Motion Test

Pneumatic Universal. Actuator MOTORIZED VALVES USE TECHNICAL FEATURES OF THE ACTUATOR. Data sheet

PHYSICS 221 Fall 2007 EXAM 2: November 14, :00pm 10:00pm

Advanced Higher Physics. Rotational motion

UNIT 4 FLYWHEEL 4.1 INTRODUCTION 4.2 DYNAMICALLY EQUIVALENT SYSTEM. Structure. Objectives. 4.1 Introduction

On my honor, I have neither given nor received unauthorized aid on this examination.

PROBLEM 16.4 SOLUTION

Physics Lecture 13. P. Gutierrez. Department of Physics & Astronomy University of Oklahoma

End-of-Chapter Exercises

Dept of ECE, SCMS Cochin

SIR MICHELANGELO REFALO CENTRE FOR FURTHER STUDIES VICTORIA GOZO

Objectives. Power in Translational Systems 298 CHAPTER 6 POWER

Summer Physics 41 Pretest. Shorty Shorts (2 pts ea): Circle the best answer. Show work if a calculation is required.

C7047. PART A Answer all questions, each carries 5 marks.

Physics 2211 M Quiz #2 Solutions Summer 2017

Physics 6A Winter 2006 FINAL

NCK/SCK/FCK Related products Shock absorber NCK/ SCK/FCK

ROTARY MOTION CONTROL

Conveyor Equipment Manufacturers Association

Transcription:

Shock absorber Formulae and examples of calculation A shock absorber decelerates linearly. Roughly 90% of shock absorber applications can be modelled if the following 4 factors are known: 1. Mass to slow down m (kg) 2. Impact velocity v D (m/s) 3. Propelling force F (N) 4. Shocks per hour C (hr) Symbols used in the formulae: W 1 Kinetic enerngy (Nm) W 2 Propelling energy (Nm) W 3 Total energy per cycle (W1+W2) (Nm) W 4 Total erergy per hour (W3C) (Nm/hr) me Effective weight (kgme) m Mass to slow down (kg) *v Velocity or moving mass (m/s) *v D Impact velocity of shock absorber (m/s) w Angular velocity (rad/s) F Propelling force (N) C Number of shocks per hour (/hr) P Motor power (kw) ST Setting coefficient (normally 2.5) 1 à 2.5 1. Mass without propelling force 0 m 2. Mass with propelling force F. s 2.1 Mass moving upwards ( F - m. g ). s 2.2 Mass moving downwards ( F + m. g ). s 3. Mass pulled by a motor 1000. P. ST. s v M Propelling torque (Nm) I Moment of inertia (kgm 2 ) g Gravity = 9,81 (m/s 2 ) h Drop height exc. shock abs. stroke (m) s Shock absorber stroke (m) Q Reactive force (N) μ Friction coefficient t Braking time (sec) a Side load inclination (m/sec 2 ) a Radius of inclination ( ) β Angle of inclination ( ) Radius of mass (m) R Dist. pivot/installation pt. of damp. (m) r Dist. pivot/force application pt. (m) 4. Mass on motorised rollers m. μ. g. s 5. Swinging mass with propelling force M. s R vd = = w. R *v or v D is the impact velocity of the mass. In the case of an accelerated movement (for example when the mass is deplaced by a pneumatic cylinder), the impact velocity can be 1.5 to 2 times greater than the average velocity. 240 Volume 1 2016 www.hpceurope.com - Tel: +33(0)4 37 496 496

Shock absorber Formulae and examples of calculation 6. Free falling mass W1 = m. g. h m. g. s vd = 2. g. h 6.1 Mass rolling or sliding on an inclined plane W1 = m. g. h = m.. 0,5 m. g. sinβ. s v D = 2. g. h 6.1a Mass with upwards propelling force ( F - m. g. sinβ ). s 6.1b Mass with downwards propelling force W3 = ( F + m. g. sinβ ). s 6.2 Mass free falling abut a pivot point Formulae: Follow calculation for example 6.1. Verify the radial load. tan a = s R 7. Rotary index table with propelling torque W1 = m. v 2. 0,25 M. s R vd = = w. R NOTE: mass evenly spread 8. Rotating mass with propelling torque W1 = m. v 2. 0,18 M. s R NOTE: mass evenly spread vd = = w. R 2 v D 9. Rotating mass with propelling force NOTE: mass W1 = m.. 0,18 evenly spread F. r. s M. s = R R vd = = w.r 10. Mass in controlled descent without propelling force m. g. s These formulae will Reactive force Q(N) give you approximate 1, values to assist in Q = s the selection of a Braking time (s) shock absorber but a 2,6. s safety margin should t = v D always be applied. Deceleration (m/s 2 ) (Precise values can a = 0,6. vd only be calculated if 2 actual parameters are s known). Fax: +33(0)4 37 490 055 - cial2@hpceurope.com Volume 1 2016 241

Shock absorber HPC technical assistance Fax +33 (0)4 37 490 055 Request for technical assistance with your application If you would like assistance with an application, please enlarge this form by 200% (to A4 size), fill in as much information as possible and return it by fax to our technical team. Company... Contact... Address...... Telephone... Fax... For which machine, fitting or application do you need help selecting a shock absorber?... What material is there at the end of stroke? Rubber cushion r Shock-absorbing cylinder r Brake cylinder r No shock-absorber r Other r What problems do you have? Safety r Stopping too quickly r Stopping too slowly r Incorrect deceleration r Frequent breakages/faults r Continuous operation r Please see preceding pages to select your intended use. Otherwise use the space below for a sketch or any other description thereof. Fixtures R - Flange behind F - Flange in front S - Foot mounting C - Oscillating mounting Total weight of mass to be dampened m (kg)... External influences - Application Impact velocity on shock-absorber vd (m/s)... Ouside r Propelling force of cylinder or other F (N)... Extrusions into soft water r Electric motor power P (kw)... Extrusions into sea water r No of shocks per hour C (1/h)... Marine environment r N of shock-absorbers in parallel n ()... Acidic environment r (Desired) shock-absorber stroke length s (mm)... Electrical contact r Total height of fall h (m)... In foundry r Torque M (Nm)... In pneumatic cylinder r Friction coefficient μ... Temperature... Radius /R/r (m)... Other... Other info.... 242 Volume 1 2016 www.hpceurope.com - Tel: +33(0)4 37 496 496

Self-compensating shock-absorber MC Non adjustable - MC25 and MC75: integrated stroke end stop and noise reducing buffer - MC150: mechanical stop required about 1mm before the shockabsorber stroke-end. - Working temperature 0 to +65 C - Materials: Body: blackened steel Rod: stainless steel Buffer: steel with elastomer insert (MC25 and MC75 only).accessories. - See stroke end stop and universal universal flange.info.. - MC150: to avoid damaging the EPDM membrane do not turn the rod - For better heat dissipation, do not paint shock-absorbers M10 x 1 5 Ø5,1 4 MC25 M12 x 1 5 Ø8,4 5 MC75 5 3,2 Stroke S/P12 6,6 14,6 57,6 3 3,2 Course S/P14 10 18 70 4,8 Ø7,6 Ø7,6 M14 x 1,5 Stroke 12 12 S/P12 6 S/P17 12,5 61,9 17,5 86,6 MC150M Effective Max capacity (Nm) Return Rod Max. Weight Per Per spring reset side Price (kgme) cycle hour force time load each Part number Min Max W3 W4 (N) (S) angle Stock* 1 to 5 MC25-M 0,7 2,2 2,8 22600 3-6 0,3 2 81,85 F MC25-M 1,8 5,4 2,8 22600 3-6 0,3 2 69,00 F MC25-MH 4,6 13,6 2,8 22600 3-6 0,3 2 69,00 F MC75-M1 0,3 1,1 9,0 28200 4-9 0,3 2-110,65 F MC75-M2 0,9 4,8 9,0 28200 4-9 0,3 2 110,65 F MC75-M3 2,7 36,2 9,0 28200 4-9 0,3 2 110,65 F MC150-M 0,9 10,0 20,0 34000 3-8 0,4 4 146,57 F MC150-MH 8,6 86,0 20,0 34000 3-8 0,4 4-146,57 F MC150-MH2 70,0 200,0 20,0 34000 3-8 0,4 4-146,57 F Fax: +33(0)4 37 490 055 - cial2@hpceurope.com Volume 1 2016 243

Adjustable shock-absorber RMSA - Standard part with locknut and knob - Materials: Body: blackened steel Rod: stainless steel - Adjustment. The adjustment ring is calibrated from 0 to 9. The adjustment knob is secured by a set screw which must be slackened with a 1.5mm Allen key before carrying out adjustment (do not remove completely ). After installing the shock absorber, cycle the machine a few times and alter the adjustment so that optimum deceleration is achieved. For hard impact at start of stroke turn ring towards 9, for harder impact at the end of the stroke, turn towards 0. Retighten the set screw. - Max. impact velocity 3,6m/s - Working temperature -12 to +90 C - Stroke end stop and anti-noise buffer fully integrated - Max. angle of incidence: 2 (except RMSA-900 : 1 ).Uses. - Upon impact of the load the piston moves back A causing an immediate build up of internal pressure. Oil is then d2 allowed to pass through the metering orifices bringing the load smoothly to rest. Fast reset is assured by an anti-return valve and spring incorporated in the piston..accessories. - Universal flange STC... - Stroke end stop MF... Can be adjuster in-situ to suit application C 12 AF1 l1 B max.. Typical application d1 Part Stroke number (mm) A B C d1 d2 d3 l1 AF AF1 RMSA-500 19,00 M20 x 1,5 118 13,5 4,8 17,0 17,0 8 23 18 RMSA-600 25,40 M25 x 1,5 143 16,5 6,3 22,4 23,0 10 30 23 RMSA-900 40,00 M25 x 1,5 189 16,5 6,3 22,4 23,0 10 30 23 Max. energy capacity (Nm) Effective weight Return spring Rod per per (kgme) force time Price Part cycle hour Min Max Min. Max. reset Weight each number W3 W4 (kg) (kg) (N) (N) (S) (kg) Stock* 1 to 5 RMSA-500 25 45 000 2,30 226 5 10 0,10 0,13 156,87 F RMSA-600 68 68 000 9,00 1 360 10 30 0,20 0,31 216,36 F RMSA-900 100 90 000 14,00 2 040 10 35 0,40 0,40-300,94 F 244 Volume 1 2016 www.hpceurope.com - Tel: +33(0)4 37 496 496 AF Stroke 11 d3 4,6

Shock-absorber - universal flange Mounting accessory MF - Universal flange for shock-absorber b5 Ød4 Ød3 b2 Ød2 Ød4 MF10 to 14 b4 b1 b5 Typical application Ød3 For shock- Price each Part number Ød2 Ød3 Ød4 b1 b2 b4 b5 absorber Stock* 1 to 5 MF-10 M10x1 4,5 4,5 8 38 25 12 25 5 MC25 43,91 F MF-12 M12x1 4,5 4,5 8 38 25 12 25 5 MC75 4 43,91 F MF-14 M14x1,5 4,5 4,5 8 45 29 16 35 5 MC150-47,23 F MF-20 M20x1,5 5,5 5,5 10 47 35 16 35 10 RMSA500-58,71 F MF-25 M25x1,5 5,5 5,5 10 47 35 16 35 10 RMSA600-900 - 58,69 F Ød2 25,5 MF20 to 25 b4 b1 b2 Fax: +33(0)4 37 490 055 - cial2@hpceurope.com Volume 1 2016 245

Shock absorber - stop collar STC Mounting accessory - Stop collar for shock absorber - Warning: for certain shock absorbers, the use of this stop collar is essential Ød6 Ød5 Ød6 STC10 to 12 AF b5 b4 STC14 to 25 Typical application Part number For shockabsorber Stock* Price each Ød5 Ød6 b4 b5 AF 1 to 5 STC10 M10x1-14,3 20 - - - MC25 12,39 F STC12 M12x1-16,0 20 - - - MC75 12,39 F STC14 M14x1,5 14,5 18,0 19 12 06 13 MC150-13,47 F STC20 M20x1,5 20,5 25,0 25 12 08 22 RMSA500-20,05 F STC25 M25x1,5 25,5 32,0 45 16 10 27 RMSA600-900 28,47 F 246 Volume 1 2016 www.hpceurope.com - Tel: +33(0)4 37 496 496