Why the ABC conjecture

Similar documents
Introduction Diophantine Equations The ABC conjecture Consequences. The ABC conjecture. Brian Conrad. September 12, 2013

The 98th Mathematics Colloquium Prague November 8, Random number theory. Carl Pomerance, Dartmouth College

THE ABC CONJECTURE AND ITS APPLICATIONS JOSEPH SHEPPARD. B.A., Kansas State University, 2014 A REPORT

Chapter 6. Approximation of algebraic numbers by rationals. 6.1 Liouville s Theorem and Roth s Theorem

Chapter 6. Approximation of algebraic numbers by rationals. 6.1 Liouville s Theorem and Roth s Theorem

Notice how these numbers thin out pretty quickly. Yet we can find plenty of triples of numbers (a, b, c) such that a+b = c.

NOTES ON DIOPHANTINE APPROXIMATION

INTEGRAL POINTS ON VARIABLE SEPARATED CURVES

On a Problem Related to the ABC Conjecture

Two problems in combinatorial number theory

Perfect numbers among polynomial values

CHAPTER 10: POLYNOMIALS (DRAFT)

THE ABC CONJECTURE, ARITHMETIC PROGRESSIONS OF PRIMES AND SQUAREFREE VALUES OF POLYNOMIALS AT PRIME ARGUMENTS

Counting in number theory. Fibonacci integers. Carl Pomerance, Dartmouth College. Rademacher Lecture 3, University of Pennsylvania September, 2010

Elliptic Curves and the abc Conjecture

Abstract. On the abc Conjecture and some of its consequences by. Michel Waldschmidt

arxiv: v2 [math.nt] 10 Mar 2017

MATH 2400 LECTURE NOTES: POLYNOMIAL AND RATIONAL FUNCTIONS. Contents 1. Polynomial Functions 1 2. Rational Functions 6

The ABC Conjecture and its Consequences on Curves

Primality testing: variations on a theme of Lucas. Carl Pomerance, Dartmouth College Hanover, New Hampshire, USA

A MORE GENERAL ABC CONJECTURE. Paul Vojta. University of California, Berkeley. 2 December 1998

Order and chaos. Carl Pomerance, Dartmouth College Hanover, New Hampshire, USA

Polynomial Rings : Linear Algebra Notes

Basic Algorithms in Number Theory

Summary Slides for MATH 342 June 25, 2018

ABC Triples in Families

How many elliptic curves can have the same prime conductor? Alberta Number Theory Days, BIRS, 11 May Noam D. Elkies, Harvard University

Order and chaos. Carl Pomerance, Dartmouth College Hanover, New Hampshire, USA

Euclidean prime generators

FINITENESS RESULTS FOR F -DIOPHANTINE SETS

HOW OFTEN IS EULER S TOTIENT A PERFECT POWER? 1. Introduction

Rational Points on Conics, and Local-Global Relations in Number Theory

Beyond Fermat s Last Theorem

We only consider r finite. P. Erdős, On integers of the form 2 k +p and some related problems, Summa Brasil. Math. 2 (1950),

Euler s ϕ function. Carl Pomerance Dartmouth College

On the power-free parts of consecutive integers

Fibonacci numbers of the form p a ± p b

Definition For a set F, a polynomial over F with variable x is of the form

The Impossibility of Certain Types of Carmichael Numbers

g(x) = 1 1 x = 1 + x + x2 + x 3 + is not a polynomial, since it doesn t have finite degree. g(x) is an example of a power series.

Balanced subgroups of the multiplicative group

DEFINABILITY OF FROBENIUS ORBITS AND A RESULT ON RATIONAL DISTANCE SETS

The ranges of some familiar arithmetic functions

The ranges of some familiar functions

IT S AS EASY AS abc. Andrew Granville and Thomas J. Tucker

D-MATH Algebra I HS18 Prof. Rahul Pandharipande. Solution 6. Unique Factorization Domains

Lecture Notes Math 371: Algebra (Fall 2006) by Nathanael Leedom Ackerman

88 SEON-HONG KIM and deg A(x) = deg B(x) = deg C(x). Here Mason's ABC polynomial theorem (see [11]) gives a negative result. In 1981, Stothers [17] pr

On the number of special numbers

Polynomial Rings. i=0

THE SOLOVAY STRASSEN TEST

A Proposed Proof of The ABC Conjecture

Journal of Number Theory

arxiv: v1 [math.nt] 7 Sep 2015

Section III.6. Factorization in Polynomial Rings

The ranges of some familiar arithmetic functions

On integer solutions to x 2 dy 2 = 1, z 2 2dy 2 = 1

Dense product-free sets of integers

Diophantine equations and beyond

Further linear algebra. Chapter II. Polynomials.

PRIME FACTORS OF DYNAMICAL SEQUENCES. Xander Faber and Andrew Granville

A 1935 Erdős paper on prime numbers and Euler s function

The multiplicative order mod n, on average

Number Theory. Final Exam from Spring Solutions

Algebraic Number Theory and Representation Theory

ELLIPTIC CURVES BJORN POONEN

1. Factorization Divisibility in Z.

arxiv: v1 [math.nt] 4 Nov 2015

MODULAR FORMS AND EFFECTIVE DIOPHANTINE APPROXIMATION

The ABC's of Number Theory

Lecture 7. January 15, Since this is an Effective Number Theory school, we should list some effective results. x < π(x) holds for all x 67.

Errata List for Rational Points on Elliptic Curves by Joseph H. Silverman and John Tate Version 1.3a July 5, 1994; revised by JEC, 1998

LINEAR FORMS IN LOGARITHMS

that if a b (mod m) and c d (mod m), then ac bd (mod m) soyou aren't allowed to use this fact!) A5. (a) Show that a perfect square must leave a remain

8 Appendix: Polynomial Rings

D-MATH Algebra I HS 2013 Prof. Brent Doran. Exercise 11. Rings: definitions, units, zero divisors, polynomial rings

Variety Evasive Sets

MTH310 EXAM 2 REVIEW

Part II. Number Theory. Year

It s As Easy As abc. Andrew Granville and Thomas J. Tucker. Introduction

Ideals: Definitions & Examples

Fermat s Last Theorem for Regular Primes

1. Algebra 1.5. Polynomial Rings

Local properties of plane algebraic curves

Number Theory Seminar Spring, 2018: Modularity

Two Diophantine Approaches to the Irreducibility of Certain Trinomials

Math 203A - Solution Set 3

Polynomial Ideals. Euclidean algorithm Multiplicity of roots Ideals in F[x].

Carmichael numbers and the sieve

Test 2. Monday, November 12, 2018

On a Question of Wintner Concerning the Sequence of Integers Composed of Primes from a Given Set

Salem numbers of trace 2 and a conjecture of Estes and Guralnick

Runge s theorem on Diophantine equations Martin Klazar

The Number of Fields Generated by the Square Root of Values of a Given Polynomial

Amicable numbers. CRM Workshop on New approaches in probabilistic and multiplicative number theory December 8 12, 2014

Math 547, Exam 2 Information.

Sums and products. Carl Pomerance, Dartmouth College Hanover, New Hampshire, USA. Dartmouth Mathematics Society May 16, 2012

Lecture Notes Math 371: Algebra (Fall 2006) by Nathanael Leedom Ackerman

THE DENOMINATORS OF POWER SUMS OF ARITHMETIC PROGRESSIONS. Bernd C. Kellner Göppert Weg 5, Göttingen, Germany

IRREDUCIBILITY TESTS IN Q[T ]

Transcription:

Why the ABC conjecture Carl Pomerance, Dartmouth College Hanover, New Hampshire, USA Kummer classes and anabelian geometry U. Vermont, September 10 11, 2016

(The Farside, Gary Larson) 1

What is the ABC conjecture? Qualitatively it says that if a, b, c are positive integers with a + b = c, then the product of the primes in abc cannot be much smaller than c. To make this more precise, define rad(n) = p n p. So, rad(10) = 10, rad(72) = 6, and rad(2401) = 7, for example. The ABC conjecture is saying that when a + b = c, rad(abc) cannot be too small in comparison to c. But wait, there are counterexamples! 2

For example, 32 + 32 = 64, and rad(32 32 64) = 2. Even more with 2 k + 2 k = 2 k+1. There are more complicated counterexamples, such as 17 4 + 34 4 = 17 5. So, to bar these monsters, we insist that a, b, c be pairwise coprime. But wait, there are still counterexamples! 3

Take 1 + 8 = 9. We have rad(1 8 9) = 6. And 6 is considerably smaller than 9. Or take 2 + 3 10 109 = 23 5, where 2 3 109 23 = 15042 and 23 5 = 6436343. Well, it s in how you measure, and it s in how you treat counterexamples. Here s the official statement. The ABC conjecture: For each ɛ > 0, there are at most finitely many coprime triples a, b, c of positive integers with a + b = c and rad(abc) < c 1 ɛ. The conjecture is due to Masser and Oesterlé. 4

Where did the ABC conjecture come from? In efforts to prove Fermat s Last Theorem, people wondered if it could be proved in other contexts, such as for polynomials. This was done by Liouville (1851) over C, and then Mason (1983) found the following generalization. Mason s theorem: If f, g, h are coprime nonzero polynomials over a field of characteristic 0 with f + g = h and deg h > 0, then deg rad(fgh) max{deg f, deg g, deg h} + 1. (By rad(f ) we mean the product of the monic irreducible divisors of F.) 5

Proof: Assume f + g = h with deg h the maximum of the 3 degrees. Note that for a nonzero polynomial F we have F/(F, F ) squarefree, so it divides rad(f ). Hence deg F deg rad(f ) deg(f, F ). From f + g = h we get f + g = h, so with some high school algebra: fg f g = g h gh. But (f, f ), (g, g ), (h, h ) all divide the two sides of this equation, and they are coprime, so their product divides. Further, the two sides may be assumed nonzero, else g is a constant multiple of h, violating coprimeness. Hence deg f+ deg g+ deg h deg rad(fgh) deg(f, f )+ deg(g, g )+ deg(h, h ) deg(fg f g) deg f+ deg g 1 and we re done. 6

Why is the ABC conjecture true? Let s start with an easier question: Why is Fermat s last theorem true? Here is an argument due to Erdős and Ulam: Let k 4 be an integer and consider a random sequence of positive integers such that the mth term is m k. So, the chance a number n is in the sequence is about n 1+1/k. What is the chance that a random number n is the sum of two terms of the sequence? This should be at most about a+b=n a 1+1/k b 1+1/k. Assuming a b, we have b 1+1/k (n/2) 1+1/k, so the sum is c 0 n 1+1/k a n/2 a 1+1/k c 1 n 1+1/k n 1/k = c 1 n 1+2/k. 7

Good, and the event that n is a sum of two sequence terms should be independent from n being in the sequence. So, the probability that a + b = n has a solution in sequence terms is c 2 n 2+3/k. But, n=1 c 2 n 2+3/k < since k 4. Thus, we expect at most finitely many solutions, and if there are no small ones, then no solutions. Now apply this to the decidedly non-random sequence which is the union of all powers of integers higher than the 3rd power. 8

The heuristic suggests that a u + b v = c w, with u, v, w 4 has at most finitely many solutions. But recall: 2 k + 2 k = 2 k+1, and (2 k + 1) k + (2(2 k + 1)) k = (2 k + 1) k+1, etc. So, being a power has some correlations, like the product of two kth powers is again a kth power. Let s assume coprimeness, and maybe we re happy with the heuristic? One other caution: The heuristic actually suggests that there are infinitely many coprime solutions to x 3 + y 3 = z 3. 9

By the way, Darmon and Granville proved (using Faltings theorem) that for any triple u, v, w with reciprocal sum 1, there are at most finitely many coprime solutions to a u + b v = c w. OK, that was a warm-up. Why is the ABC conjecture true? 10

We begin with a lemma: For each fixed δ > 0 and x sufficiently large, the number of integers n x with rad(n) y is yx δ. Let i, j, k run over positive integers with i + j + k (1 ɛ) log x. For each i, j, k consider a, b x and 1 2 x < c x with rad(a) e i, rad(b) e j, rad(c) e k. Then rad(abc) e i+j+k x 1 ɛ < 2c 1 ɛ. By the lemma, the number of choices for a is e i x δ, and similarly for b and c. So, the number of triples a, b, c is e i+j+k x 3δ x 1 ɛ+3δ = x 1 1 2 ɛ, assuming that δ = 1 6 ɛ. So the total # of triples: x1 1 2 ɛ log 3 x. Given a, b, the chance that a random c ( 1 2x, x] happens to be a + b is proportional to 1/x, so letting a, b run, the chance we have an a, b, c triple is at most about x 1 2 ɛ log 3 x. Now let x run over powers of 2, and we get a convergent series. 11

Why is the ABC conjecture important? It has tons of interesting consequences. For example: 1. Fermat s last theorem has at most finitely many counterexamples. 2. Pillai s conjecture holds: the gaps between perfect powers tend to infinity. 3. There are at most finitely many coprime powers a u, b v, c w with 1/u + 1/v + 1/w 1 and a u + b v = c w. 12

4. (Silverman) There are infinitely many non-wieferich primes. 5. (Granville) For a squarefree polynomial f Z[x], and with B the gcd of the values f(n), then there is a positive density of n s with f(n)rad(b)/b squarefree. 6. Szpiro s conjecture on the conductors of elliptic curves. 7. The Erdős Woods conjecture: If x is large and rad(x) = rad(y), then rad(x + 1) rad(y + 1). 8. (Granville Stark) There are no Siegel zeros (following from a uniform ABC conjecture for number fields).

9. Erdős s conjecture that there are at most finitely many triples of consecutive squarefull numbers (n is squarefull if p 2 n whenever p n). 10. Dressler s conjecture that if m < n and rad(m) = rad(n), then there is a prime in [m, n]. 11. Lang s conjecture on the number of integral points on an elliptic curve. 12. Bounds for the order of the Tate Shafarevich group of an elliptic curve.

13. Vojta s conjecture for curves. 14. The Schinzel Tijdeman conjecture: If f(x) Z[x] has at least 3 simple roots, then f(n) is squarefull at most finitely many times. 15. (M. R. Murty) There are many quadratic number fields with class number divisible by a fixed integer. I like to joke that it has been shown that everything can be proved starting from a false statement, so perhaps the ABC conjecture is more and more resembling one!

What has been proved? One type of result produces triples a, b, c with a + b = c and rad(abc) is fairly small. For example, a = 1, b = 64 n 1, c = 64 n. Then rad(abc) 2 3 (64n 1) < 3 2 c. By this method, there are infinitely many coprime triples a + b = c with rad(abc) = O(c/ log c). van Frankenhuijsen has shown there are infinitely many coprime triples a + b = c with rad(abc) c/ exp ( 6.068(log c) 1/2 / log log c ). (Robert, Stewart, and Tenenbaum have a heuristic that this is close to best possible.) 13

Another type of result proves a weaker version of the ABC conjecture. For example, Stewart and Yu have proved that there is some κ > 0 such that for coprime a + b = c, rad(abc) κ(log c/ log log c) 3. Baker has a numerically explicit ABC conjecture: If a + b = c are coprime, then c 6 5 R)k R(log, where R = rad(abc) has k distinct prime divisors. k! 14

An ABCD conjecture? The same heuristics suggest that if a + b + c + d = 0 where a, b, c, d is a coprime 4-tuple of nonzero integers, then rad(abcd) > d 1 ɛ. But consider the polynomial identity (x 1) 5 + 10(x 2 + 1) 2 8 = (x + 1) 5, and let x run over numbers of the form 11 k 1. This gives (11 k 2) 5 + 10((11 k 1) 2 + 1) 2 8 = 11 5k, and rad(abcd) 22(11 k 2)((11 k 1) 2 + 1) = O( d 0.6 ). Granville has conjectured that infinite-family counterexamples must come from polynomial identities such as this, and that for fixed ɛ > 0, there are only finitely many polynomials. 15

Thank you! 16

Further resources: A. Granville and T. Tucker, It s as easy as abc, Notices AMS 49 (2002), 1223 1231; www.ams.org/notices/200210/fea-granville.pdf A. Nitaj, The abc home page, http://www.math.unicaen.fr/ nitaj/abc.html C. Pomerance, Computational number theory, Princeton Companion to Math., T. Gowers, ed., Princeton U. Press 2008, pp. 348 362. M. Waldschmidt, Lecture on the abc conjecture and some of its consequences, https://webusers.imjprg.fr/ michel.waldschmidt/articles/pdf/abclahore032013.pdf 17