Get the frictional force from the normal force. Use dynamics to get the normal force.

Similar documents
P6.5 (a) static friction. v r. = r ( 30.0 cm )( 980 cm s ) P6.15 Let the tension at the lowest point be T.

SECTION A Torque and Statics

(C) 7 s. (C) 13 s. (C) 10 m

PHYS 100: Lecture 4 PROJECTILE MOTION. y = (v 0 /v T ) x (g/2v T2 )x 2. Velocity of Train v T. Physics 100 Lecture 4, Slide y(m)

v( t) g 2 v 0 sin θ ( ) ( ) g t ( ) = 0

HW9.2: SHM-Springs and Pendulums

Problem Set: Fall #1 - Solutions

Lecture 08 Conservation of Energy

One-Dimensional Motion Review IMPORTANT QUANTITIES Name Symbol Units Basic Equation Name Symbol Units Basic Equation Time t Seconds Velocity v m/s

Exam 2A Solution. 1. A baseball is thrown vertically upward and feels no air resistance. As it is rising

jfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksm+nklth egkjkt

CJ57.P.003 REASONING AND SOLUTION According to the impulse-momentum theorem (see Equation 7.4), F t = mv

Get Solution of These Packages & Learn by Video Tutorials on PROJECTILE MOTION

Chapter 4 Two-Dimensional Kinematics. Copyright 2010 Pearson Education, Inc.

Chapter 9 Centre of Mass and Linear Momentum

AAPT UNITED STATES PHYSICS TEAM AIP 2009

PSI AP Physics C Kinematics 2D. Multiple Choice Questions

FOCUS ON CONCEPTS Section 7.1 The Impulse Momentum Theorem

(a) 1m s -2 (b) 2 m s -2 (c) zero (d) -1 m s -2

UNDERSTAND MOTION IN ONE AND TWO DIMENSIONS

KINEMATICS PREVIOUS EAMCET BITS ENGINEERING PAPER

University of Alabama Department of Physics and Astronomy. PH 125 / LeClair Fall Exam III Solution

Physics 111. Lecture 7 (Walker: 4.2-5) 2D Motion Examples Projectile Motion

before the collision and v 1 f and v 2 f after the collision. Since conservation of the linear momentum

Physics 231 Lecture 9

UNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics

Work and Energy Problems

Geodesics as gravity

Chapter 14 - Fluids. Pressure is defined as the perpendicular force on a surface per unit surface area.

Review. acceleration is the rate of change of velocity (how quickly the velocity is changing) For motion in a line. v t

Physics 11 Fall 2012 Practice Problems 2 - Solutions

Chapter (3) Motion. in One. Dimension

Conservation of Mechanical Energy 8.01

the equations for the motion of the particle are written as

Experiment 3 The Simple Pendulum

Linear Motion. Miroslav Mihaylov. February 13, 2014

Chapter 2. Kinematic Equations. Problem 1. Kinematic Equations, specific. Motion in One Dimension

Projectile Motion. Equipment: Ballistic Gun Apparatus Projectiles Table Clamps 2-meter Stick Carbon Paper, Scratch Paper, Masking Tape Plumb Bob

Chapter 11 Collision Theory

Chapter 2 One-Dimensional Kinematics. Copyright 2010 Pearson Education, Inc.

Ground Rules. PC1221 Fundamentals of Physics I. Position and Displacement. Average Velocity. Lectures 7 and 8 Motion in Two Dimensions

XI PHYSICS M. AFFAN KHAN LECTURER PHYSICS, AKHSS, K.

Physics 18 Spring 2011 Homework 2 - Solutions Wednesday January 26, 2011

Physics 40 Chapter 8 Homework Q: 12, 13 P: 3, 4, 7, 15, 19, 24, 32, 34, 39, 54, 55, 58, 59, 62, 64

MOTION IN A STRAIGHT LINE. time interval t and as t approaches zero, the ratio. has a finite limiting value.(where x is the distance

Module 27: Rigid Body Dynamics: Rotation and Translation about a Fixed Axis

PHYS1100 Practice problem set, Chapter 2: 6, 10, 13, 17, 22, 24, 25, 34, 42, 50, 55, 65, 71, 82

Physics 231 Lecture 12

Experiment 1: Simple Pendulum

UNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics

This Week. Next Week

when the particle is moving from D to A.

Motion in Two Dimensions Sections Covered in the Text: Chapters 6 & 7, except 7.5 & 7.6

Homework # 2. SOLUTION - We start writing Newton s second law for x and y components: F x = 0, (1) F y = mg (2) x (t) = 0 v x (t) = v 0x (3)

Prince Sultan University Physics Department First Semester 2012 /2013. PHY 105 First Major Exam Allowed Time: 60 min

PROJECTILES. Launched at an Angle

Displacement, Time, Velocity

PROJECTILE MOTION. ( ) g y 0. Equations ( ) General time of flight (TOF) General range. Angle for maximum range ("optimum angle")

f 1. (8.1.1) This means that SI unit for frequency is going to be s 1 also known as Hertz d1hz

(A) (B) (C) (D) None of these

Answers to Coursebook questions Chapter 2.10

1 CHAPTER 7 PROJECTILES. 7.1 No Air Resistance

PhysicsAndMathsTutor.com

Problem Set 2 Solutions

Firing an Ideal Projectile

Solutions to Physics: Principles with Applications, 5/E, Giancoli Chapter 6

Phys207: Lecture 04. Today s Agenda 3-D Kinematics Independence of x and y components Baseball projectile Shoot the monkey Uniform circular motion

GRADE 12 JUNE 2017 PHYSICAL SCIENCES P1

REVIEW: Going from ONE to TWO Dimensions with Kinematics. Review of one dimension, constant acceleration kinematics. v x (t) = v x0 + a x t

Transformations of Quadratic Functions

Your Thoughts. What is the difference between elastic collision and inelastic collision?

Pre-AP Physics Chapter 1 Notes Yockers JHS 2008

Motion in Two and Three Dimensions

Introductory Physics Questions

Lesson 6: Apparent weight, Radial acceleration (sections 4:9-5.2)


PHYS 1114, Lecture 9, February 6 Contents:

Circular_Gravitation_P1 [22 marks]

Tutorial 1 Calculating the Kinetic Energy of a Moving Object

Assignment 6. Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Conservation of Energy

SOLUTIONS TO PRACTICE PROBLEMS FOR MIDTERM I

Chapter 2. Motion along a straight line

1999 AAPT PHYSICS OLYMPIAD

Conservation of Linear Momentum, Collisions

g L Simple Pendulum, cont Simple Pendulum Period of Simple Pendulum Equations of Motion for SHM: 4/8/16 k m

Follows the revised HSC syllabus prescribed by the Maharashtra State Board of Secondary and Higher Secondary Education, Pune.

Page 1. t F t m v. N s kg s. J F t SPH4U. From Newton Two New Concepts Impulse & Momentum. Agenda

Mechanics Cycle 3 Chapter 12++ Chapter 12++ Revisit Circular Motion

CHAPTER 2 LINEAR MOTION

Motion in Two and Three Dimensions

Answers. Chapter 4 A33. + as. 4.1 Start Thinking

Midterm Feb. 17, 2009 Physics 110B Secret No.=

7.2 Maximization of the Range of a Rocket

Exam 2: Tonight 8:20-10:10pm

Physics 20 Lesson 16 Friction

Linear Momentum and Collisions Conservation of linear momentum

Newton's laws of motion

Physics Test VI Chapter 7 Impulse and Momentum

Dynamics ( 동역학 ) Ch.2 Motion of Translating Bodies (2.1 & 2.2)

Transcription:

. L F n µ k L =00 t µ k = 0.60 = 0 o = 050 lb F n +y +x x = sin y = cos = µf n Is the initial elocity o the car reater than 30 mph? Approach: Use conseration o enery. System: car Initial time: beore you apply brakes. Final time: ater you stop. Enery output rom car by rictional orce and component o raitational orce (weiht) alon direction o motion. Nelect the air resistance. Use dynamics to et rictional orce. Enery diaram L = 0 0 Initial State Enery Transer Final State E i = m E = 0 L L E output = dx dx sin L L 0 x + = + 0 Conseration o Enery: E - E i = E input - E output. 0 m = ( sin L + L ) and =m ( sin L L ) o = + Get the rictional orce rom the normal orce. Use dynamics to et the normal orce. Fy = ( Fn cos) = 0

Plan Find unknowns ( sin L L ) = + [] Find = µf n [] F n Find F n ( F n cos) = 0 [3] 3 unknown, 3 equations ( F n cos) = 0 F n = cos into [] = µ k cos into [] = = ( sin L + µ cosl) ( sin L + µ k cos L) ( sin + µ ) = L k cos check units k m m = [ m] = correct or elocity s s t + 0 s o o ( 00t )( sin 0 0.6 cos ) = 3 = 70 t/s t mi 60s 60 min 70 = 48mph s 580t min hr were speedin. This is reater than the 30 mph speed limit. You The elocity has the correct units o t/s. I were 90 o, the car would be allin straiht down. The answer becomes = L which does not depend on the coeicient o riction. This is reasonable i the car is in ree all. I the skid lenth increases, the initial elocity would be reater. This is reasonable since it would take a loner distance to stop the car i it were oin at a hiher speed.

3. m a x m h Find the distance the ruit hits the round as a unction o the initial speed and anle o the arrow, the heiht o the ruit on the tree, the mass o the ruit and the mass o the arrow. + y + x Approach: Use kinematics to calculate rom and h. Ater the arrow enters the ruit and it lies throuh the air with a constant ertical acceleration and constant horizontal elocity. Since the arrow sticks in the ruit, there is a lare internal enery chane in the arrow-ruit system. Use conseration o momentum to relate the arrow s elocity just beore it hits the ruit to the elocity o the ruit just ater the arrow enters it. Since the arrow hits the ruit at the hihest part o its path, its elocity is horizontal and equal to the horizontal component o the arrow s initial momentum. The horizontal component o the elocity o the arrow is constant. x = cos Conseration o momentum p x - p ix = p input x - p output x System: arrow + ruit Initial time: just beore arrow enters ruit pix = m a x = m a cos Final time: just ater arrow enters ruit p x = ( m a + m ) No momentum transer in x direction since no orces in x direction. ( m a + m ) ma cos = 0 Fliht o arrow and ruit ater leain the tree Constant horizontal elocity: aerae x component o elocity = instantaneous x component o elocity. x = a = = Constant ertical acceleration: aerae y component o acceleration = instantaneous y component o acceleration. x = a = and y = a y ( ) + y( ) + yo

Plan unknowns Find = [], Find [] Find ( m a + m ) ma cos = 0 [3] 3 unknowns, 3 equations ( m + m ) m cos 0 a a o = ma cos = into [] ( ma + m ) h t = into [] ma cos ( m + m ) a = h ma cos h = ( m a + m ) Ealuate: Check units: m [ k] s k [ ] [ m] m = [ s ] = [ m] m s s correct or a distance I the initial speed ( ) o the arrow is reater, the ruit oes a reater distance (). This is reasonable. I the anle the arrow is shot is 90 o, the distance the ruit oes is zero. That is reasonable because i the arrow is shot straiht up, the ruit must be directly oer the hero to hit it. The ruit will then all straiht down ater it is hit.

I the mass o the ruit is larer, then it does not o as ar rom the tree. That is reasonable. The hiher the ruit is o the round, the arther it alls rom the tree. That is reasonable since its horizontal component o elocity is the same but it has a loner time to trael. Conceptual Questions:. b. a 3. a 4. a 5. c 6. e 7. d 8. c 9. b 0. b