Order and chaos in wave propagation

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Order and chaos in wave propagation Nalini Anantharaman Université Paris 11, Orsay January 8, 2012

A physical phenomenon : harmonics (stationary vibration modes). A mathematical theorem : the spectral decomposition of the laplacian.

The wave equation : u(t, x, y)

The wave equation : u(t, x, y) 2 ( ) 2 t 2 u = c2 x 2 + 2 y 2 u 2 t 2 u = c2 u

An abstract language allowing unified treatment of all wave phenomena, regardless of their physical origin (sound, electromagnetic waves, seismic waves,...)

The wave equation has special stationary solutions, i.e. of the form u(t, x, y) = e iωt ψ(x, y), also called eigenmodes, characteristic modes. The function ψ must satisfy ψ = ω2 c 2 ψ.

Figure: Ernst Chladni (1756-1827)

Figure: Sophie Germain (1776-1831)

Doing research in math? Observing the world... answering questions... always leads to new questions!

Can we calculate explicitly the eigenfrequencies and eigenmodes? it depends on the shape of the membrane, but in general the answer is NO.

Nodal lines for a guitar table :

Nodal lines on a sphere : [Eric Heller Gallery]

(R. Courant s theorem) For the n-th eigenmode, the nodal lines cut the membrane into at most n pieces (= nodal domains). (Pleijel s theorem) In dimension 2. For n large enough, the nodal lines of the n-th eigenmode cut the membrane into at most αn pieces with α = 0, 54.

The nodal lines seem to invade the domain, to form a denser and denser family of curves, as the frequency increases. Mathematical proof?

(Donnelly-Fefferman 1988) The total length of nodal lines grows proportionnally to frequency : Z ψ = {x, ψ(x) = 0}. C 1 ω n length(z ψn ) C 2 ω n. (proven if the boundary is analytic. Conjectured by Yau to hold always).

(Egorov-Kondratiev 1996, Nazarov-Polterovich-Sodin 2005) The spacing between nodal lines decreases like the inverse of frequency. Let r ψn be the inner radius (radius of a ball included in a nodal domain). Then C 1 ω n r ψn C 2 ω n

Billard régulier n = 100 n = 1000 n = 1500 n = 2000 Billard chaotique

How to explain the following patterns? [Eric Heller Gallery]

[Pär Kurlberg]

The Weyl law : N(λ) := {n, ω n λ}

The Weyl law : N(λ) := {n, ω n λ} λ + 1 4π Area(Ω)λ2

The Weyl law : N(λ) := {n, ω n λ} λ + 1 4π Area(Ω)λ2 and more generally, for a C 0 (Ω), a(x, y) ψ n (x, y) 2 1 dx dy λ + 4π λ2 n,ω n λ Ω (Here (ψ n ) is an orthonormal basis of L 2 (Ω) such that ψ n = ω 2 nψ n ) Ω a(x, y)dx dy.

1 N(λ) n,ω n λ a(x, y) ψ n (x, y) 2 dx dy λ + 1 a(x, y)dx dy Area(Ω) Ω

1 N(λ) n,ω n λ a(x, y) ψ n (x, y) 2 dx dy λ + Individual behaviour of ψ n (x, y) 2 as n +? 1 a(x, y)dx dy Area(Ω) Ω

Do we have a(x, y) ψ n (x, y) 2 dx dy λ + 1 a(x, y)dx dy? Area(Ω) Ω If this is true, this means that the eigenfunctions are becoming uniformly spread out for high frequencies, and is interpreted as their having a disordered behaviour. The answer seems to depend on the geometry of the domain.

For negatively curved manifolds, it is believed that a(x, y) ψ n (x, y) 2 1 dx dy a(x, y)dx dy. λ + Area(Ω) Quantum Unique Ergodicity conjecture 1992, proven in some cases by E. Lindenstrauss (2002) Ω

For negatively curved manifolds, it is believed that a(x, y) ψ n (x, y) 2 1 dx dy a(x, y)dx dy. λ + Area(Ω) Quantum Unique Ergodicity conjecture 1992, proven in some cases by E. Lindenstrauss (2002) For the stadium billiard, Hassell has proved in 2008 that QUE is false : there are families of eigenfunctions that concentrate inside the rectangle. Ω

[Pär Kurlberg]

Can one hear the shape of a drum?

If one hears the harmonics produced by a drum, can one guess its shape? Is it possible for two membranes with different shapes to produce the same harmonics?

One can prove mathematically that : if two membranes have the same harmonics, they must have the same area ; this comes from the Weyl law : {n, ω n λ} λ + 1 4π Area(Ω)λ2. if two membranes have the same harmonics, they must have the same perimeter ; if a membrane has the same harmonics as a circular membrane, it must be circular ; if two rectangular membranes have the same harmonics, the rectangles must be the same.

BUT...