day June 20XX Morning/Afternoon MAXIMUM MARK 70 AS Level Chemistry A H032/01 Breadth in chemistry PRACTICE MARK SCHEME Duration: 1 hour 30 minutes

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day June 20XX Morning/Afternoon AS Level Chemistry A H032/01 Breadth in chemistry PRACTICE MARK SCHEME Duration: 1 hour 30 minutes MAXIMUM MARK 70 This document consists of 13 pages

MARKING INSTRUCTIONS PREPARATION F MARKING SCIS 1. Make sure that you have accessed and completed the relevant training packages for on-screen marking: scoris assessor Online Training; OCR Essential Guide to Marking. 2. Make sure that you have read and understood the mark scheme and the question paper for this unit. These are posted on the RM Cambridge Assessment Support Portal http://www.rm.com/support/ca 3. Log-in to scoris and mark the required number of practice responses ( scripts ) and the required number of standardisation responses. YOU MUST MARK 10 PRACTICE AND 10 STANDARDISATION RESPONSES BEFE YOU CAN BE APPROVED TO MARK LIVE SCRIPTS. MARKING 1. Mark strictly to the mark scheme. 2. Marks awarded must relate directly to the marking criteria. 3. The schedule of dates is very important. It is essential that you meet the scoris 50% and 100% (traditional 50% Batch 1 and 100% Batch 2) deadlines. If you experience problems, you must contact your Team Leader (Supervisor) without delay. 4. If you are in any doubt about applying the mark scheme, consult your Team Leader by telephone, email or via the scoris messaging system. 2

5. Work crossed out: a. where a candidate crosses out an answer and provides an alternative response, the crossed out response is not marked and gains no marks b. if a candidate crosses out an answer to a whole question and makes no second attempt, and if the inclusion of the answer does not cause a rubric infringement, the assessor should attempt to mark the crossed out answer and award marks appropriately. 6. Always check the pages (and additional objects if present) at the end of the response in case any answers have been continued there. If the candidate has continued an answer there then add a tick to confirm that the work has been seen. 7. There is a NR (No Response) option. Award NR (No Response) - if there is nothing written at all in the answer space - if there is a comment which does not in any way relate to the question (e.g. can t do, don t know ) - if there is a mark (e.g. a dash, a question mark) which isn t an attempt at the question. Note: Award 0 marks for an attempt that earns no credit (including copying out the question). 8. The scoris comments box is used by your Team Leader to explain the marking of the practice responses. Please refer to these comments when checking your practice responses. Do not use the comments box for any other reason. If you have any questions or comments for your Team Leader, use the phone, the scoris messaging system, or email. 9. Assistant Examiners will send a brief report on the performance of candidates to their Team Leader (Supervisor) via email by the end of the marking period. The report should contain notes on particular strengths displayed as well as common errors or weaknesses. Constructive criticism of the question paper/mark scheme is also appreciated. 3

10. Annotations Annotation DO NOT ALLOW IGNE ALLOW Meaning Answers which are not worthy of credit Statements which are irrelevant Answers that can be accepted ( ) Words which are not essential to gain credit ECF AW A Underlined words must be present in answer to score a mark Error carried forward Alternative wording Or reverse argument 4

11. Subject-specific Marking Instructions INTRODUCTION Your first task as an Examiner is to become thoroughly familiar with the material on which the examination depends. This material includes: the specification, especially the assessment objectives the question paper the mark scheme. You should ensure that you have copies of these materials. You should ensure also that you are familiar with the administrative procedures related to the marking process. These are set out in the OCR booklet Instructions for Examiners. If you are examining for the first time, please read carefully Appendix 5 Introduction to Script Marking: Notes for New Examiners. Please ask for help or guidance whenever you need it. Your first point of contact is your Team Leader. 5

SECTION A 1 D 1 2 A 1 3 B 1 4 B 1 5 C 1 6 B 1 7 C 1 8 A 1 9 A 1 10 B 1 11 D 1 12 D 1 13 C 1 14 A 1 15 C 1 16 B 1 17 A 1 18 D 1 19 D 1 20 D 1 Total 20 6

SECTION B 21 (a) (i) Structure of 2-chloropropene 1 ALLOW any unambiguous structure ALLOW CH 3 CCl=CH 2 (Double bond must be shown) (ii) HCl gas is passed through alkali/carbonate 1 (iii) Reduces the dependency on finite resources Biodegradable Photodegradable (b) (i) Ag + + Cl AgCl Ag + + Br AgBr Ag + + I AgI 1 ALLOW crude oil petroleum fossil fuels for finite resources 1 ALLOW rots naturally (ii) Bond enthalpy decreases C Cl > C Br > C I 1 ALLOW chlorine carbon bonds are strongest. (iii) Heat the test tubes in a water bath. 1 Total 6 7

22 (a) Aliphatic = E, H, I, J 3 Alicyclic = E, H, J Aromatic = F, G (b) C n H 2n+1 1 DO NOT ALLOW C n H 2n+ 1 (c) (i) Equation: C 6 H 12 O C 6 H 10 + H 2 O 4 IGNE state symbols ALLOW C 6 H 11 OH for C 6 H 12 O Calculation: FIRST CHECK THE ANSWER ON THE ANSWER LINE IF answer = 32.7 (%) award 3 marks theoretical yield = 7.65 / 100 = 0.0765 (mol) actual yield = 2.05 / 82 = 0.025 (mol) If there is an alternative answer, check to see if there is any ECF credit possible using working below % yield must be to 1 dp ALLOW theoretical and actual yield calculated in mass % yield = (0.025 / 0.0765) 100% = 32.7(%) theoretical yield = 0.0765 82 = 6.273 g % yield = (2.05 / 6.273) = 32.7(%) ALLOW ECF from calculated actual and theoretical yields (ii) bromine water is decolourised 2 ALLOW bromine water turns colourless IGNE goes clear ALLOW correct structural displayed skeletal formula mixture of the above 8

Total 10 9

23 (a) 63 p 90 n 60 e 1 (b) 2 2 18 (c) n(eu) = 0.0019 / 152.0 = 1.25 10 5 Atoms of Eu = 1.25 x 10 5 6.02 10 23 = 7.5 10 18 3 2 ALLOW 0.0000125 Must be standard form AND two significant figures ALLOW ECF from incorrect amount ALLOW 2 marks for correct answer without working (d) n(h 2 ) = 144 / 24000 = 6(.00) 10 3 (mol) 3 n(eu) = 0.608 / 152.0 = 4(.00) 10 3 (mol) AND ratio n(eu) : n(h 2 ) = 2 : 3 2Eu + 3H 2 SO 4 Eu 2 (SO 4 ) 3 + 3H 2 Look for evidence of 2 : 3 anywhere. Could be within an attempted equation. IGNE state symbols Total 9 10

24 (a) (i) [CH 3OH] 1 K c = 2 [CO][H ] 2 (ii) [CH 3 OH] = 14.6 (3.10 10 3 ) (2.40 10 3 ) 2 2 = 2.61 10 7 (mol dm 3 ) (b) (i) Yield decreases AND Equilibrium (position) has moved to the left 1 ALLOW moved towards reactants moved towards CO and H 2 (ii) Oxidised Nitrogen AND 3 AND +2 Reduced Oxygen AND 0 AND 2 2 Total 6 11

25 (a) (i) H 2 SO 4 + 2KOH K 2 SO 4 + 2H 2 O 1 ALLOW multiples (ii) Energy (into water) mark 70.0 4.18 16.5 = 4827.9 (J) or 4.8279 (kj) 3 ALLOW rounding to 4828 4830 amount of substance mark 35. 0 n(h 2 O) = 2.40 = 0.084(0) (mol) 1000 ALLOW amount of substance mark to be based upon KOH, or H 2 SO 4 with correct ratio neut H mark ( )4.8279 / 0.084(0) = ( )57.475 ( )57.48 ( )57.5 ALLOW ECF for Energy (into water) mark Amount of substance mark Correctly rounded to at least 3 significant figures (iii) 1 mole of water had been formed 1 (iv) 2 0.5 100 = 6% 16.5 (b) (i) Amount of each element mark H O N 0.025 0.300 0.175 1.0 16.0 14.0 1 2 = 0.025 0.01875 0.0125 Simplest whole number ratio empirical formula 0.025 = 2 0.01875 = 1.5 0.0125 = 1 0.0125 0.0125 0.0125 AND H 4 O 3 N 2 ALLOW 2 marks for correct answer without working (ii) acid: HNO 3 AND base: NH 3 1 ALLOW atoms within HNO 3 and NH 3 in any order Total 9 12

26 (a) Initiation Cl 2 2Cl 5 Propagation C 2 H 6 + Cl C 2 H 5 + HCl C 2 H 5 + Cl 2 C 2 H 5 Cl + Cl If the structure of the ethyl radical is drawn, the lone electron must be attached to a C atom (b) Termination Cl + Cl Cl 2 C 2 H 5 + Cl C 2 H 5 Cl C 2 H 5 + C 2 H 5 C 4 H 10 Initiation, propagation, termination used in correct context I = C 4 H 10 + II = C 3 H 7 + III = C 2 H 5 + C 3 H 7 + could be CH 3 CH 2 CH 2 + or CH 3 CHCH 3 + C 3 H 7 + could be from CH 3 CH 2 CH 2 CH 3 or CH 3 CH(CH 3 ) 2 CH 3 CH 2 + could only be from CH 3 CH 2 CH 2 CH 3 5 THROUGHOUT: IF any charge is missing, DO NOT ALLOW 1st formula but allow subsequent formulae by ECF ALLOW + charge anywhere Total 10 13