Formation of complexes: thermodynamics

Similar documents
Chapter 25 Transition Metals and Coordination Compounds Part 1

Coordination Number Six

Lecture 11 Reaction Types and Mechanisms for Inorganic Complexes

Electronic structure Crystal-field theory Ligand-field theory. Electronic-spectra electronic spectra of atoms

Complexes. Commonly, transition metals can have molecules or ions that bond to them. These give rise to complex ions or coordination compounds.

Coordination chemistry and organometallics

Chapter 21: Transition Metals and Coordination Chemistry

CHEMISTRY Topic #3: Colour in Chemistry Fall 2017 Dr. Susan Findlay See Exercises 12.1 to Fe 2 O 3 Cr 2 O 3 Co 2 O 3 TiO 2.

Inorganic Chemistry with Doc M. Fall Semester, 2012 Day 21. Transition Metals Complexes V: Reaction Mechanisms

15 THE TRANSITION METALS

13 Energetics II. Eg. Na (g) Na + (g) + e - ΔH = +550 kj mol -1

Aqueous Equilibria: Acids and Bases

Acid-Base Strength. Chapter 6. Monday, November 2, 2015

Orbitals and energetics

Predicting LA-LB reactions

Chapter 16. Solubility and Complex Ion Equilibria

RDCH 702 Lecture 4: Orbitals and energetics

Q.1 Predict what will happen when SiCl 4 is added to water.

Transition Metal Chemistry

Coordination Chemistry II: Bonding

Chapter 20 d-metal complexes: electronic structures and properties

CHEM N-3 November Transition metals are often found in coordination complexes such as [NiCl 4 ] 2. What is a complex?

Chemistry 324 Final Examination

Coordination Compounds

Coordination compounds

Electronic structure / bonding in d-block complexes

Transition Metals and Coordination Chemistry. 1. In the transition metals section chemical similarities are found within a and across a.

CHAPTER - 9 ORDINATION COMPOUNDS

What is the difference between a d-block element and a transition element? Clue: Sc and Zn are not transition elements.

CHEM J-14 June 2014

Downloaded from

Transition Metal Chemistry

Chapter 19 Chemical Thermodynamics

If you put an electron into the t 2g, like that for Ti 3+, then you stabilize the barycenter of the d orbitals by 0.4 D o.

Copper Chemistry. Cu : 1s 2 2s 2 2p 6 3s 2 3p 6 4s 1 3d 10

AP* Chapter 16. Solubility and Complex Ion Equilibria

Mechanisms of Inorganic Reactions HS -26

Chemistry 1B. Fall Lectures Coordination Chemistry

Properties of Acids and Bases

- an approach to bonding that is useful for making estimates of E of orbitals in coordination complexes

The d-block elements. Transition metal chemistry is d-orbitals/electrons

CBSE Class-12 Chemistry Quick Revision Notes Chapter-09: Co-ordination Compounds

Chemical Thermodynamics

Coordination Chemistry: Bonding Theories. Crystal Field Theory. Chapter 20

12A Entropy. Entropy change ( S) N Goalby chemrevise.org 1. System and Surroundings

Q.1 Predict what will happen when SiCl 4 is added to water.

Transition Metal Chemistry

Chemistry 3211 Coordination Chemistry Part 3 Ligand Field and Molecular Orbital Theory

Chemistry 1B. Fall Lectures Coordination Chemistry

BASICS OUTLINE 8/23/17. Start reading White (CH 1) QoD Schedule

IB Topics 5 & 15 Multiple Choice Practice

Jahn-Teller Distortions

Transition Metals. Tuesday 09/22/15. Tuesday, September 22, 15

Chem 1102 Semester 2, 2011!

CHEM 116-Dr. Babb s Sections Answer Key to Lecture Problem Sheet Questions for Chapters 20, 21, and 23.

489--Lectures 3 and 4. Fundamentals of Inorganic Chemistry

CHEM 10123/10125, Exam 3

Print version. Lecture #26 Coordination Chemistry: Hydrolysis. Benjamin; Chapter (Stumm & Morgan, Chapt.6: pg ) Updated: 22 March 2018

Chemistry 1B. Fall Topics Lectures Coordination Chemistry

Topics in the June 2006 Exam Paper for CHEM1901

Schedule. Lecture 7: M-M bonds δ-bonds and bonding in metal clusters

Chapter 5 - Homework solutions

Transition Metal Chemistry and Coordination Compounds

Chapter 21 Transition Metals and Coordination Chemistry

Chapter 21 Transition Metals and Coordination Chemistry

Topics Coordination Complexes Chemistry 1B-AL, Fall 2016

CHERRY HILL TUITION AQA CHEMISTRY A2 PAPER Section A. Answer all questions in the spaces provided.

Topic 5.5 REACTIONS OF INORGANIC COMPOUNDS IN SOLUTION. Lewis Acids and Bases Hydrated Metal Cations Reactions of Complex Ions

SOLUBILITY EQUILIBRIA (THE SOLUBILITY PRODUCT)

5.111 Principles of Chemical Science

Solubility Equilibria

Chapter 21 Coordination chemistry: reactions of complexes

1.8 Thermodynamics. N Goalby chemrevise.org. Definitions of enthalpy changes

CHEM- 457: Inorganic Chemistry

CBSE Class 12 th Chemistry Solved Guess Paper

Inorganic Pharmaceutical Chemistry. Coordination compounds

Applications of Aqueous Equilibria Chapter 15. Solubility Equilbriua Sections 6-8

Inorganic Chemistry with Doc M. Fall Semester, 2012 Day 16. Transition Metals Complexes: Structure and Isomers

CO-ORDINATION COMPOUNDS

Ligands: an ion or molecule capable of donating a pair of electrons to the central atom via a donor atom.


I. Multiple Choice Questions (Type-I) ] 2+, logk = [Cu(NH 3 ) 4 O) 4. ] 2+, logk = 8.9

NAME: SECOND EXAMINATION

Chapter 3 (part 3) The Structures of Simple Solids

Inorganic chemistry 3-stage Lec. 2. Dr- leaqaa

Crystal Field Theory

Week 13 Transition metals

Crystal Field Theory. 2. Show the interaction between the d-orbital and the negative point charge ligands

Chap 10 Part 4Ta.notebook December 08, 2017

The elements 18.1 Occurrence and recovery 18.2 Physical properties Trends in chemical properties 18.3 Oxidation states across a series 18.

Solubility and Complex-ion Equilibria

Transition Elements. pranjoto utomo

CH1810 Lecture #1 Solutions of Ionic Compounds

The Transition Elements and Coordination Compounds

Chemical Equilibrium. What is the standard state for solutes? a) 1.00 b) 1 M c) 100% What is the standard state for gases? a) 1 bar b) 1.

Thermodynamics: Free Energy and Entropy. Suggested Reading: Chapter 19

Section 6 Questions from Shriver and Atkins

Ch. 23: Transition metals and Coordination Chemistry

Transition Metals and Complex Ion Chemistry

1. KCl.MgCl 2 .6H 2. Oisa. a) Mixed salt. c) Basic salt d) Complex salt

Transcription:

LN08-1 Formation of complexes: thermodynamics Or, How to think about making and using transition metal complexes Its important to always consider, and distinguish between, stability and inertness of complexes. When discussing the stability of a metal complex, it s important to establish: stable (or unstable) with respect to what? e.g. relative to the reagents you used to make it? e.g. relative to possible further reaction products? Decomposition products Combustion products Constituent elements in their native form?

LN08-2 Formation of complexes: thermodynamics For example: making a new coordination complex often involves taking a simple metal halide salt (MX n (s)) from a bottle and dissolving it in water before adding ligand(s) One measure of the stability of your aqueous M n+ reagent is relative to the solid precursor: MX n (s) G (or H) M n+ (aq) + nx (aq) ( G lattice or H lattice ) Born Haber cycle M n+ (g) + nx (g) ( G hydration ) Free energy (or enthalpy) of dissolution = G lattice + G hydration

LN08-3 Orbital occupation effects Experimental lattice energies for MCl 2 (M = 3d metal); the point for d 0 corresponds to CaCl 2. Data not available for Sc, where the stable oxidation state is 3. Fig 20.35, p.708 Absolute enthalpies of hydration of the M 2 ions of the first row metals; the point for d 0 corresponds to Ca 2. Data are not available for Sc 2, Ti 2 and V 2 (+2 O.S. unstable to oxidation) Fig 20.36, p.708

LN08-4 Orbital occupation effects A ligand field stabilization energy (LFSE) is associated with any given Oh complex of d n configuration, based on its t 2g and e g orbital occupancies. By convention, negative LFSE is more stable. e.g. for Oh HS d 4 ion:

LN08-5 Orbital occupation effects LFSEs as a function of oct for high-spin Oh and Td systems. Compare these spectroscopic energies with experimental thermodynamic energies on previous slide. Fig 20.34, p.708 These spectroscopic and thermodynamic stabilization energies are not equivalent! But they are related and give similar trends.

LN08-6 Stability constants Review: H&S 7.12 Typically discuss the stability of coordination complexes with respect to their formation from aquated metal ions [M(H 2 O) 6 ] n+. e.g. Consider the equilibrium arising from addition of an excess ( 6 equivalents) of ligand L (where L is a neutral donor, like NH 3 ) to an aqueous solution of M n+ e.g. [Fe(H 2 O) 6 ] 3+ + 6NH 3 > [Fe(NH 3 ) 6 ] 3+ (aq) + 6H 2 O < The product-favouredness of this equilibrium is described by G = RTln K; The size of the equilibrium constant directly represents the thermodynamic stability of the product relative to the aqueous metal lion and free ligand in water. K = [[Fe(NH 3 ) 6 ] 3+ ] [H 2 O] 6 [[Fe(H 2 O) 6 ] 3+ ] [NH 3 ] 6

LN08-7 Review: H&S 7.12 Stepwise stability constants, K x, reported. These correspond to the individual steps in the replacement of coordinated H 2 O by L. e.g. for the first step in the formation of the above hexaammineiron(iii) complex: [Fe(H 2 O) 6 ] 3+ + NH 3 Stability constants > [Fe(H 2 O) 5 (NH 3 )] 3+ (aq) + H 2 O < Similarly, for the substitution of the second H 2 O by NH 3 : [Fe(H 2 O) 5 (NH 3 )] 3+ + NH 3 > [Fe(H 2 O) 4 (NH 3 ) 2 ] 3+ (aq) + H 2 O <

LN08-8 Stability constants We can arrive at an overall equilibrium constant ( 2 ) for the substitution of two water ligands by two ammine ligands: [Fe(H 2 O) 6 ] 3+ + 2NH 3 > [Fe(H 2 O) 4 (NH 3 ) 2 ] 3+ (aq) + 2H 2 O < 2 = K 1 x K 2 = [[Fe(H 2 O) 5 (NH 3 )] 3+ ] x [[Fe(H 2 O) 4 (NH 3 ) 2 ] 3+ ] [[Fe(H 2 O) 6 ] 3+ ] [NH 3 ] [[Fe(H 2 O) 5 (NH 3 )] 3+ ] [NH 3 ] Important to keep in mind the difference between K x and β x

LN08-9 Overall stability constants For the formation of a new complex from [M(H 2 O) 6 ] n+ and ligand L, the overall stability constant is: [[M(H 2 O) 6-x L x ] n+ ] x = = K 1 K 2 K 3 K x [[M(H 2 O) 6 ] n+ ] [L] x e.g. 6 for the substitution of all six H 2 O ligands in [Fe(H 2 O) 6 ] 2+ with CN ligands is: = [[Fe(CN) 6 ] 4 ] = 10 35 (or log = 35) [[Fe(H 2 O) 6 ] 2+ ] [CN ] 6 This is large! means collective equilibria heavily favour product. Stepwise (K) and overall (b) stability constants are often discussed as their log values. Larger log K n or log n for the formation of a complex indicates that the equilibrium concentration of the complex is larger. Log values are useful because: (i) x and K x can span many, many orders of magnitude; (ii) (ii) the relative stabilities of different complexes only become meaningful when their stability constants different by orders of magnitude.

LN08-10 Examples of stability constants M L log K 1 log K 2 log K 3 log K 4 log K 5 log K 6 log Ni 2+ NH 3 2.8 2.24 1.73 1.19.75.03 8.7 Cu 2+ NH 3 4.17 3.53 2.88 2.05.7-11.9 Too small to measure [M(H 2 O) 6 ] 2+ + xnh 3 > [M(H 2 O) 6-x (NH 3 ) x ] 2+ (aq) + x2h 2 O Normally see a steady decrease in log K n values as n increases. This is in part due to statistics: NH 3 is more likely to replace one of six water ligands in [Ni(H 2 O) 6 ] 2+ than one of five in [Ni(H 2 O) 5 (NH 3 )] 2+. This dependence is a function of the fact that the equilibria are all interrelated, and in the presence of a large excess of H 2 O.

LN08-11 Examples of stability constants M L log K 1 log K 2 log K 3 log K 4 log K 5 log K 6 log Ni 2+ NH 3 2.8 2.24 1.73 1.19.75.03 8.7 Cu 2+ NH 3 4.17 3.53 2.88 2.05.7-11.9 Why are log K n values for Ni 2+ and Cu 2+ for substitution of H 2 O by NH 3 different? Cu 2+ is d 9, which is prone to Jahn-Teller distortion ( Z-out ). regular octahedron: All Ni-O bonds 2.07 Å distorted octahedron: Red Ni-O bonds 1.95 Å Blue Ni-O bonds 2.38 Å

LN08-12 Examples of stability constants M L log K 1 log K 2 log K 3 log K 4 log K 5 log K 6 log Ag + NH 3 3.14 3.82 7.0 Hg 2+ CN 18.00 16.70 3.83 2.98 41.5 Hg 2+ I 12.87 10.95 3.67 2.37 29.9 Deviations from a steady trend in successive log K n can indicate: (i) abrupt change in coordination number and geometry along the series of complexes (ii) abrupt change in the electronic structure of the metal ion (iii) special steric effects that become important only at certain degrees of coordination E.g. big drop from log K 2 to log K 3 for all 3 examples above. HgX 2 is very stable with CN=2, linear. So is silver. In the case of silver, actually causes an unusual increase for K 2 relative to K 1 The strong preference for low coordination numbers here offsets the usual trend of gradually diminishing K n for octahedral substitution.

LN08-13 7.12-7.13 Factors affecting stability of metal complexes G = RTlnK = H T S Enthalpy effects are important in determining the size of stability constants. We instinctively think of this in the context of M-L bond strengths. What are the relative M-L bond strengths? i) Is L a strong sigma donor? ii) Are additional, bond strengthening π-interactions possible/probable? e.g. Hg(CN) 2 (aq) versus Hg(I) 2 (aq): log 2 = 34.70 vs 23.82

LN08-14 HSAB iii) Consider the match of M with L in terms of the Hard/Soft Acid/Base theory. In aqueous solution, hard Lewis acids (metal cations) form more stable complexes with hard Lewis bases (ligands), while soft acids (soft metal cations) preferentially bind soft Lewis bases (ligands) Table 7.9, p.235 Hard vs soft relates to polarizability Hard acids: small monocations with high charge density, or highly charged cations (again with high charge density) Hard bases: donor atoms that are not very polarizable, e.g. F Soft acids: large monocations of low charge density, low or zero-oxidation state metals Soft bases: contain donor atoms that are highly polarizable, eg. I (For bases, consider electronegativity of the donor atoms.)

LN08-15 Example: HSAB [M(H 2 O) 6 ] n+ + X- > [M(H 2 O) 5 X]( n-1)+ (aq) + x2h 2 O Log K 1 F- Cl- Br- I- Fe 3+ 6.0 1.4 0.5 - Hg 2+ 1.0 6.7 8.9 12.9

LN08-16 G = RTlnK = H T S Both H and S are at play in the formation of complexes between highly charged cations and anions. [M(H 2 O) 6 ] n+ + yx- > [M(H 2 O) 6-y (X) y ] (n-y)+ (aq) + y2h 2 O Enthalpy: cancellation of (isolated) charges gives a negative change (heat released reaction is favoured). Entropy: the water molecules on M are highly ordered around the charged M n+ and around the X- (via hydrogen-bonding).

LN08-17 The chelate effect Complexes of polydentate ligands are more stable than complexes with the corresponding number of comparable monodentate ligands (e.g. similar donor atoms, Lewis basicities). [M(H 2 O) 6 ] 2+ + xnh 3 > [M(H 2 O) 6-x (NH 3 ) x ] 2+ (aq) + x2h 2 O [M(H 2 O) 6 ] 2+ + x en > [M(H 2 O) 6-2x (en) x ] 2+ (aq) + 2x2H 2 O M L log K 1 log K 2 log K 3 log K 4 log K 5 log K 6 log Cu 2+ NH 3 4.17 3.53 2.88 2.05 12.6 Ni 2+ NH 3 2.8 2.24 1.73 1.19.75.03 8.7 Cu 2+ en 10.55 9.05 20.6 Ni 2+ en 7.45 6.23 4.34 18.0 Compare log K 1 for the addition of en to M 2+ (aq) to log 2 for addition of two NH 3 : for Cu 2+ : NH 3 log β 2 = (4.17 + 3.53) = 7.70 en log K 1 = 10.55 for Ni 2+ NH 3 log β 2 = (2.8 + 2.24) = 5.04 en log K 1 = 7.45

LN08-18 The chelate effect Consider the equilibrium [Co(NH 3 ) 6 ] 3+ + 3en < > [Co(en) 3 ] 3+ + 6NH 3 3 = 18.7 G = RTlnK = H T S The chelate effect is an entropically driven phenomenon

LN08-19 Chelate effect The chelate effect is amplified for ligands capable of forming multiple chelate rings Ethylenediamine tetraacetate (EDTA) M Log K 1 Ag + 7.3 Ca 2+ 10.8 Cu 2+ 18.7 Ni 2+ 18.6 Fe 2+ 14.3 Fe 3+ 25.1 Co 2+ 16.1 Co 3+ 36.0 V 2+ 12.7 V 3+ 25.9

LN08-20 The macrocyclic effect The there is a distinct difference between chelating ligands and macrocyclic ones macrocyclic effect L 4 ligand cyclam ligand Log K 1 Ni(L 4 ) 2+ 15.3 Ni(cyclam) 2+ 22.2 Consider the following reaction [Ni(L 4 )] 2+ + cyclam > [Ni(cyclam)] 2+ + L 4 <

LN08-21 The macrocyclic effect The free ligand L4 does not adopt the orientation shown. floppy ends. The binding of L4 involves a significant loss of entropy (conformational degrees of freedom) This effect counters the entropy increase incurred by the release of NH 3 molecules. The cyclam free macrocycle has fewer degrees of freedom: preorganization diminishes loss of entropy upon complex formation

LN08-22 The macrocyclic effect Enthaply can also be important in macrocyclic ligand binding. (and not always favouring the macrocycle- because the macrocycle is already somewhat restricted/constrained, it cannot as easily accommodate the steric/electronic requirements of the metal (and other ligands) G = RTlnK = H T S kj/mol Log K 1 ΔH TΔS 15.3-71 -17 22.2-130 -2.5