Math 03 - Departmental Eit Assessment Review (Student Version) Factor completel. (Factoring Review) ) 6-6 - 0 ) 3-343 3) 3 - + 8-40 4) - 36 ) + - 6 + 9 + 8 - + + Add or subtract as indicated. Simplif completel. (Section.) 3 + 8) - 4 - - + 6-4 - ) 343 3 + 00 6) - + 6 ) -0 3 + - 60 9) 0) m - 6 m + 4m + 48 + 4m - m + m - 8 4 + 0 + - 4 8) 9-48 + 64 9) 8 + ) 4 - Simplif. (Section.3) ) + 3-9 Simplif the rational epression. (Section.) + 3 ) + 9 + 6 ) - 8-3 ) 9 - + 3 Multipl or divide as indicated. Simplif completel. (Section.) 3) - 4 4) - + 8 + + + 4 ) z 4z 6) - 6 + - 6 9-9 + 8 + + - 6 3-3 Solve the equation. (Section.) 4 3) + - 9 - = - 4) ) 6) + + 6 + + 3 = -3 + 9 + 8 + 4-3 + - 4-4 + 4 = - 4-3 + 3 - = - (3 - )
Solve. (Section.6) ) A recent advertisement claimed that out of ever 3 doctors recommend a certain herbal supplement to increase energ levels. If a local hospital emplos 90 doctors, how man doctors would ou epect to recommend the supplement? (Round to the nearest whole number, if necessar.) 8) A painter can finish painting a house in 6 hours. Her assistant takes 8 hours to finish the same job. How long would it take for them to complete the job if the were working together? 9) One pump can drain a pool in 8 minutes. When a second pump is also used, the pool onl takes minutes to drain. How long would it take the second pump to drain the pool if it were the onl pump in use? Use radical notation to write the epression. Simplif if possible. (Section.) 30) 4/3 Write with positive eponents. Simplif if possible. (Section.) 3) 36-3/ 3) + 9 43-48 38) 3 4 + 8 Multipl, and then simplif if possible. Assume all variables represent positive real numbers. (Section.4) 39) (4-4) 40) ( + )( + 9) 4) ( - 3-4) Rationalize the denominator and simplif. Assume that all variables represent positive real numbers. (Section.) 4) 43) - 8 Solve. (Section.6) 44) 3 - = - Use the properties of eponents to simplif the epression. Write with positive eponents. (Section.) 3) 6/ /6 3/ Simplif the radical epression. Assume that all variables represent positive real numbers. (Section.3) 33) 3 34) 3 8 4) + 3 - + 3 = 4 46) 4 + = 3 + - Write in terms of i. (Section.) 4) -900 48) - Perform the indicated operation. Write the result in the form a + bi. (Section.) 49) (9 - i) 3) 48 0) + 9i + i Add or subtract. Assume all variables represent positive real numbers. (Section.4) 36) 63-343 Find the domain and the range of the relation. Then determine whether the relation is a function. (Section 8.) ) {(-3, -6), (0, 4), (4, ), (6, -)}
) {(4, -3), (, -), (, 0), (9, ), (, 4)} Determine whether the graph is that of a function. (Section 8.) 3) Find the indicated value. (Section 8.) 8) Use the graph to find f(-4). - - - - - - - 4) - Solve the problem. (Section 8.) 9) Find f(4) when f() = + +. Find an equation of the line through the pair of points. Write the equation in the form A + B = C. (Section 8.) 60) (-, 6) and (0, -9) - - - - Write an equation of the line with the given slope and containing the given point. Write the equation using function notation. (Section 8.) 6) Slope - 4 ; through (, ) Decide whether the relation defines a function. (Section 8.) ) = - 3 6) = - ) = Find an equation of the line passing through the given points. Use function notation to write the equation. (Section 8.) 6) (-, -), (, 0) Write an equation in standard form for the line graphed. (Section 8.) 63) - - - - 3
Solve. Assume the eercise describes a linear relationship. (Section 8.) 64) The average value of a certain tpe of automobile was $3,60 in 99 and depreciated to $6840 in 99. Let be the average value of the automobile in the ear, where = 0 represents 99. Write a linear equation that models the value of the automobile in terms of the ear. 6) When making a telephone call using a calling card, a call lasting minutes costs $.0. A call lasting 4 minutes costs $3.30. Let be the cost of making a call lasting minutes using a calling card. Write a linear equation that models the cost of making a call lasting minutes. Find an equation of the line. Write the equation using function notation. (Section 8.) 66) Through (, 9); parallel to f() = - 6 6) Through (-3, -); perpendicular to f() = 3 + ) 8 3t - 4 8) + 4 < and -4 < - 9) or 8 80) < 4 or < 8) 9-6 < 3 or - -6 Graph the inequalit. (Section 8.) 8) + > 3 83) 6-30 Solve the equation b factoring. (Review) 84) ( + )( + ) = 40 Use the square root propert to solve the equation. (Section.) 8) = 4 68) Through (, 3); parallel to + = - 69) Through (-6, ); perpendicular to + 8 = 83 Graph the function. (Section 8.3) 0) f() = + 4 86) ( + 8) = 40 8) ( - ) = Solve the equation b completing the square. (Section.) 88) + 8 + 6 = 0 Graph the linear equation b finding and plotting its intercepts. (Section 8.3) ) - + = 6 Graph the quadratic equation b finding and plotting ordered pair solutions. (Section 8.3) ) = 3 89) 49 + 84 + 3 = 0 Use the quadratic formula to solve the equation. (Section.) 90) + + 3 = 0 9) - 4-9 = 0 Solve the inequalit. (Section.9 &.) 3) 0 + 3 > (3 + 8) 9) + 8 = - 4) -6 + 6 -( - ) ) 8 ( - ) 6) - and - 4
Solve. (Section.3) 93) A ball is thrown upward with an initial velocit of meters per second from a cliff that is 0 meters high. The height of the ball is given b the quadratic equation h = -4.9t + t + 0 where h is in meters and t is the time in seconds since the ball was thrown. Find the time it takes the ball to hit the ground. Round our answer to the nearest tenth of a second. Solve the absolute value equation. (Section.) 94) + 8 = 4 9) 3 + + = 3 96) + 9 + 6 = 4 9) + 9 = - 3 Solve the inequalit. (Section.) 98) k + 6 99) - 9 > 0) + > 6
Answer Ke Testname: MATH03REVIEWSTUDENTFR ) (3 + )( - ) ) (8 - )(64 + 6 + 49) 3) (3 + 8)( - ) 4) ( + 6)( - 6) ) ( + )(49-0 + 0) 6) (3 - )(4-3) ) -( - 4)( - 3) 8) (3-8) 9) Prime ) ( + )( + )( - ) ) + ) - 3 3) 4) ) 6) 3 ( + ) + ) + 4 + 8) 9) 0) - 6 m + m - 4 (m + 8)(m + 6)(m - ) 3-3 ( + 4)( - 3) ) + 3-9 ) - 3 9 3) -4 4) ) 3 6) - 3, 6 ) 93 doctors 8) 3 3 hr 9) 3 3 min 30) 8 3) 6 3) 33/ 33) 4 34) 3 3 4 3) 6 36) -4 3) 6 3 38) 3 39) 9-3 40) 6 + 43 4) - 8-3 + 3 4) 43) - 44) 9 4) -4 46), 6 + 40 4 4) 30i 48) 4i 49) 3-6i 0) 6 3 + 49 3 i ) domain: {-3, 0, 4, 6} range: {-6, 4,, -} function ) domain: {4, 9,, } range: {-3, -, 0,, 4} not a function 3) function 4) not a function ) function 6) function ) function 8) 8 9) 9 60) - - = 8 6) f() = - 4 + 6) f() = 8-6 63) - 3 = 64) = -60 + 3,60 6) = 0. + 0. 66) f() = - 6) f() = - 3-3 68) f() = - + 8 6
Answer Ke Testname: MATH03REVIEWSTUDENTFR 69) f() = 8 + 3 0) 8) - - - - 83) - - ) - - - - - 84) -, 3 8) -, 86) -8 -, -8 + 8), 0 88) -9-4, -9 + 4 89) - 4, - 8-90) - -, - + ) 9) 9, - 9) -4-6, -4 + 6 - - 93) 6.0 sec 94) -, - 6 9) 96) -, - - 9) - 3, - 3) (, ) 4) [-4, ) ) [, ] 6) (-, -] ) [3, ] 8) 9) (-, ] [8, ) 80) (-, ) 8) (-, ) [3, ) - 98) - 8, 4 99) (-, -) (0, ) 0) (-, -) (, )