ERRATA. COMPUTER-AIDED ANALYSIS OF MECHANICAL SYSTEMS Parviz E. Nikravesh Prentice-Hall, (Corrections as of November 2014)

Similar documents
Robot Modeling and Kinematics Errata R. Manseur. List of errors and typos reported as of 4/1/2007:

ERRATA For the book A farewell to Entropy, Statistical Thermodynamics Based on Information

6.3.7 Example with Runga Kutta 4 th order method

Translational Equations of Motion for A Body Translational equations of motion (centroidal) for a body are m r = f.

Four Bar Linkages in Two Dimensions. A link has fixed length and is joined to other links and also possibly to a fixed point.

ENGN 40 Dynamics and Vibrations Homework # 7 Due: Friday, April 15

November 5, 2002 SE 180: Earthquake Engineering SE 180. Final Project

Week3, Chapter 4. Position and Displacement. Motion in Two Dimensions. Instantaneous Velocity. Average Velocity

Chapter 11 Angular Momentum

CHAPTER 10 ROTATIONAL MOTION

Georgia Tech PHYS 6124 Mathematical Methods of Physics I

Mathematical Preparations

Corrections to Weak Scale Supersymmetry

Rigid body simulation

Week 9 Chapter 10 Section 1-5

Physics 141. Lecture 14. Frank L. H. Wolfs Department of Physics and Astronomy, University of Rochester, Lecture 14, Page 1

Lesson 5: Kinematics and Dynamics of Particles

Classical Mechanics ( Particles and Biparticles )

Physics 181. Particle Systems

χ x B E (c) Figure 2.1.1: (a) a material particle in a body, (b) a place in space, (c) a configuration of the body

COMPOSITE BEAM WITH WEAK SHEAR CONNECTION SUBJECTED TO THERMAL LOAD

π e ax2 dx = x 2 e ax2 dx or x 3 e ax2 dx = 1 x 4 e ax2 dx = 3 π 8a 5/2 (a) We are considering the Maxwell velocity distribution function: 2πτ/m

Physics 5153 Classical Mechanics. Principle of Virtual Work-1

I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

10/23/2003 PHY Lecture 14R 1

Indeterminate pin-jointed frames (trusses)

Lecture 23: Newton-Euler Formulation. Vaibhav Srivastava

Physics 5153 Classical Mechanics. D Alembert s Principle and The Lagrangian-1

Causal Diamonds. M. Aghili, L. Bombelli, B. Pilgrim

Please review the following statement: I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

Iterative General Dynamic Model for Serial-Link Manipulators

Poisson brackets and canonical transformations

11. Dynamics in Rotating Frames of Reference

CHALMERS, GÖTEBORGS UNIVERSITET. SOLUTIONS to RE-EXAM for ARTIFICIAL NEURAL NETWORKS. COURSE CODES: FFR 135, FIM 720 GU, PhD

From Biot-Savart Law to Divergence of B (1)

12. The Hamilton-Jacobi Equation Michael Fowler

= 1.23 m/s 2 [W] Required: t. Solution:!t = = 17 m/s [W]! m/s [W] (two extra digits carried) = 2.1 m/s [W]

Please review the following statement: I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

Rotational Dynamics. Physics 1425 Lecture 19. Michael Fowler, UVa

Supplemental document

Workshop: Approximating energies and wave functions Quantum aspects of physical chemistry

The classical spin-rotation coupling

Spin-rotation coupling of the angularly accelerated rigid body

Lecture 2: Numerical Methods for Differentiations and Integrations

Kinematics of Fluids. Lecture 16. (Refer the text book CONTINUUM MECHANICS by GEORGE E. MASE, Schaum s Outlines) 17/02/2017

Angular Momentum and Fixed Axis Rotation. 8.01t Nov 10, 2004

COMPLEX NUMBERS AND QUADRATIC EQUATIONS

10/9/2003 PHY Lecture 11 1

Slide. King Saud University College of Science Physics & Astronomy Dept. PHYS 103 (GENERAL PHYSICS) CHAPTER 5: MOTION IN 1-D (PART 2) LECTURE NO.

ELASTIC WAVE PROPAGATION IN A CONTINUOUS MEDIUM

Chapter 11 Torque and Angular Momentum

Transfer Functions. Convenient representation of a linear, dynamic model. A transfer function (TF) relates one input and one output: ( ) system

This model contains two bonds per unit cell (one along the x-direction and the other along y). So we can rewrite the Hamiltonian as:

COMPARISON OF SOME RELIABILITY CHARACTERISTICS BETWEEN REDUNDANT SYSTEMS REQUIRING SUPPORTING UNITS FOR THEIR OPERATIONS

Quantum Mechanics I - Session 4

Modeling of Dynamic Systems

Inductance Calculation for Conductors of Arbitrary Shape

EXAM INFORMATION. Harmonic Oscillator. Anharmonic Oscillator 1 ~ 1. Rigid Rotor

Boise State University Department of Electrical and Computer Engineering ECE 212L Circuit Analysis and Design Lab

Physics 111: Mechanics Lecture 11

8.1 Arc Length. What is the length of a curve? How can we approximate it? We could do it following the pattern we ve used before

MTH 263 Practice Test #1 Spring 1999

AGC Introduction

ENGI 1313 Mechanics I

Spring 2002 Lecture #13

Please review the following statement: I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

ˆ (0.10 m) E ( N m /C ) 36 ˆj ( j C m)

Physics 3A: Linear Momentum. Physics 3A: Linear Momentum. Physics 3A: Linear Momentum. Physics 3A: Linear Momentum

14 The Postulates of Quantum mechanics

Chapter 8. Potential Energy and Conservation of Energy

Axial Turbine Analysis

Lecture Notes 7: The Unruh Effect

So far: simple (planar) geometries

Introduction. - The Second Lyapunov Method. - The First Lyapunov Method

Statistics MINITAB - Lab 2

Linear Momentum. Center of Mass.

Boise State University Department of Electrical and Computer Engineering ECE 212L Circuit Analysis and Design Lab

The decomposition of inequality and poverty

Physics 4B. Question and 3 tie (clockwise), then 2 and 5 tie (zero), then 4 and 6 tie (counterclockwise) B i. ( T / s) = 1.74 V.

RIGID BODY MOTION. Next, we rotate counterclockwise about ξ by angle. Next we rotate counterclockwise about γ by angle to get the final set (x,y z ).

PHYS 705: Classical Mechanics. Calculus of Variations II

EN40: Dynamics and Vibrations. Homework 7: Rigid Body Kinematics

Structure and Drive Paul A. Jensen Copyright July 20, 2003

Conservation of Angular Momentum = "Spin"

Quantum Mechanics for Scientists and Engineers. David Miller

9.2 Seismic Loads Using ASCE Standard 7-93

PHYS 705: Classical Mechanics. Canonical Transformation II

Introduction to the lattice Boltzmann method

( ) = ( ) + ( 0) ) ( )

Gravitational Acceleration: A case of constant acceleration (approx. 2 hr.) (6/7/11)

where v means the change in velocity, and t is the

SUPPLEMENTARY INFORMATION

Technical Report TR05

Moments of Inertia. and reminds us of the analogous equation for linear momentum p= mv, which is of the form. The kinetic energy of the body is.

HW #6, due Oct Toy Dirac Model, Wick s theorem, LSZ reduction formula. Consider the following quantum mechanics Lagrangian,

Please review the following statement: I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

Review: Fit a line to N data points

% & 5.3 PRACTICAL APPLICATIONS. Given system, (49) , determine the Boolean Function, , in such a way that we always have expression: " Y1 = Y2

ENGI9496 Lecture Notes Multiport Models in Mechanics

Elshaboury SM et al.; Sch. J. Phys. Math. Stat., 2015; Vol-2; Issue-2B (Mar-May); pp

Transcription:

ERRATA COMPUTER-AIDED ANALYSIS OF MECHANICAL SYSTEMS Parvz E. Nkravesh Prentce-Hall, 1988 (Correctons as of November 2014 Address to an error s gven n the frst column by the page number and n the second column by a lne number, or a fgure number, or an equaton number. For example: lne 2 means the second lne from the top of the page; lne 3 means the thrd lne from the bottom of the page; Eq. 2.30, +2 means the second lne followng Eq. 2.30; Eq. 6.48, lne 1 means the frst lne n Eq. 6.48. Page Lne, Fg., Error Correcton 10 Eq. 1.6 correct to: (r 2 + l 2 + s 2 d 2 2rlcosφ 2lscosθ 1 + 2rscos(φ +θ 1 Eq. 1.7 correct to: (r 2 + l 2 s 2 d 2 2rlcosφ + 2dscosθ 2 11, 12 Fgs. 1.12, 1.13, 1.14 The lnk lengths are: crank = r, coupler = d, follower = s, frame = l 12 Eq. 1.12, 4 th lne d 2 snφ 2 + d 2 snφ 2 23 Eq. 2.30, +3 a a 25 Eq. 2.33, +1 Eq. 2.42 correct to: where I s a 3 x 3 dentty matrx. The 0 0 28 Eq. 2.61 α a α a 29 lne 2 = c = c 2 30 Ex. 2.5, +4 6x 2 x 4 6x 2 x 4 32 Eq. 2.75, -2 n-vector 3-vector Eq. 2.75, +1 n x m matrx 3 x m matrx 34 Prob. 2.16 make the followng correctons: cosφ snφ 0 1.2 0.3 x 2 x 1 A = snφ cosφ 0 c 1 = 0.5 c 2 = 0.8 d = y 2 y 1 0 0 1 0 0 0 42 Eq. 3.4, +5 m = 4 x 3 = 12 m = 6 x 2 = 12 45 Fg. 3.9 l 3 = 3 m l 3.3 m Eq. a v v footnote, lne 1 [u t,v t ] [u T,v T ] 48 lne 3 φ 3 = 5.39 φ 3 = 5.39 49 Eq. 3.15, 1 st ( q ( q Eq. 3.15, 2 nd ( + ( q q + ( + ( q q + 60 last equaton 1 1 3.5 3.5 7 7 17 17 ERRATA (Computer-Aded Analyss of Mechancal Systems Page 1

67 Fg. 3.11 nfecton nflecton 69 Ex. 3.13, +2 Φ 2 φ 2 Ex. 3.13, +2 Φ 1 φ 1 Ex. 3.13, +7 [Φ 2,d] T [φ 2,d] T Ex. 3.13, +8 [Φ 1 ] [φ 1 ] Φ 1 Φ 1 Eq. 5 Φ 2 Φ 2 70 lne 11 move the thck lne from before the table to below the table 2 nd row n the table 326 320 103 lne 2 r.. r lne 3 r.. r lne 7, crcled 2 ξ P snφ + η P cosφ ξ P snφ η P cosφ 109 Eq. f, lne 3 Φ 3 Φ 1 Φ 3 φ 1 110 lne 5 (y 1 100snφ 1 (y 1 lne 22, crcled 30 (x 1 100cosφ 1 (x 1 replace the statement for crcled 30 wth: crcled 7, crcled 11, crcled 21, crcled 25, crcled 30 lne 25, crcled 33 (y 1 100snφ 1 (y 1 (x 1 100cosφ 1 (x 1 114 before last parag. redundant data (t could be removed 127 Sub. INPOIN, +6 centrod orgn 133 Sub. SMPL, +4 NG>0 and NS>0 NG>0 or NS>0 141 top lne Program Expanson Problems 143 top lne Program Expanson Problems 145 top lne Program Expanson Problems 147 top lne Program Expanson Problems 149 top lne Program Expanson Problems 151 top lne Program Expanson Problems 154 Fg. 6.2 z s mssng on the axs 155 lne 11 ( u (z u (z 158 Fg. 6.4 replace wth the followng fgure 160 Eq. 6.22 e T e T ERRATA (Computer-Aded Analyss of Mechancal Systems Page 2

165-7 0.922 0.922 u ζ = = 0.293 u ζ = = 0.029 0.387 0.387-5 A = 0.293 A = 0.029-4 p = [0.810, 0.029, 0.543, 0.191] T p = [0.810, 0.1103, 0.543, 0.191] T 168 Eq. 6.48, lne 1 e T e T e + e 0 I e + e 0 I 171 Eq. b p. p lne 4 + = a p + = a p 174 footnote, +2 (s' P ( s ' P 175 Eq. 6.109, +1 + 2G p + 2G p 176 last equaton S s 178 Eq. 6.118, lne 1 e 0 e 0 e e 181 PROBLEMS, -2 mssng Eq. # ω = ω + ω (6.128 201 Eq. 5, +1 Eqs. 6.73, 6.54, Eqs. 6.73, 6.55, 202 Ex. 7.3, last equaton G L G L (correct twce 203 TABLE 7.2 col. 3, row 5 s' s ' col. 5, row 3 B s' B s ' col. 6, row 3 s T (h B h B s T (h B h B col. 6, row 5 s (h B h B s (h B h B col. 6, row 7 2d T (h P h P 2d T (h P h P 206 top fgure mssng capton Fgure P.7.19 209 Eq. (a, -1 body partcle 210 Fg. 8.2 f p f p 213 lne 4 n O = n O = lne 6 n = s A f + s B ( f n = s A f + s B ( f 216 Eq. P r P r 219 Eq. 8.27, lne 3 subscrpt (v for the ntegral s mssng 223 parag. 2, +6 h = [ r T T,ω'] h = [ r T,ω' T T ] 229 lne 5 s P P = A s' s P P = A s' 250 Prob. 9.7 (c 0.05, determne 0.05 (other veloctes are zero, determne Prob. 9.7 add the followng: (e Fnd the acceleratons n ths confguraton. Prob. 9.8 (d add to the end: (let x 1 = y 1 = y 2 ERRATA (Computer-Aded Analyss of Mechancal Systems Page 3

256 lne 20 correct to: C..N must be greater than or equal to M 257 M10, Length N N + M T M Φ q M10, Descrpton Φ q Φ q 0 260 lne 9, ETA, P-J, ETA-P-J Sub. TRANSF, Sec. 5.1.1, Sec. 5.1.2 262 Followng Sub. TRIG, before Sub. MASS mssng statement for Sub. MASS (add the followng: Subroutne MASS. Ths subroutne generates the square matrx to the left of Eq. 10.5 contanng the mass and the moment of nerta for each body, the Jacoban matrx and ts transpose. Subroutne MASS s as follows: 263 Sub. FUNCT Sec. 5.2.3 Sec. 5.1.3 Sub. RVLT Sec. 5.2.3 Sec. 5.1.3 Sub. TRAN Sec. 5.2.3 Sec. 5.1.3 Sub. SMPL Sec. 5.2.3 Sec. 5.1.3 269 lne 6 data 1,2,0,-1,0 1,2,0,0,-1,0 275 lne 14 2,3,-.38 2,3,-.38,0,0 276 lne 3 3.669.2 3669.2 284 Prob. 10.24, lne 3, as can that, as that 286 last lne axal radal 289 lne 7 n lne 5 n n' n' 290 Eq. (b lne 1 δ(a s' (A s' δp p lne 5 p T p 1 p T p 1 296 Eq. 11.40 ω ' 1 J' 1 ω ' ω ' 1 J' 1 ω' 1 299 Eq. 3 + ( s T s ω ' + + ( s T s ω ' + followng Eq. 4 a thck lne s needed parag. followng Eq. 4 the paragraph should not be ndented TABLE 11.1 col. 6, row 6 2d T d + 2 d T d + followng Table 11.1 remove the thck lne Prob. 11.3 Eq. 11.6 Eq. 11.16 300 Fg. P.11.7 the vecor for n 2 should be a thck lne 302 Eq. 12.5 ε = y(t y ε = y(t y 311 Eq. 12.24 1 1 Δy +1 = I b 1 Δy +1 = I hb 1 314 lne before footnote tme t o to a fnal tme t 0 to a fnal 316 lne 7 Method 1. Method I. 333 parag. 3, +3 the for of the form of 334 lne (a.3 θ θ ERRATA (Computer-Aded Analyss of Mechancal Systems Page 4

352 Eq. A.7 cosφ 1 cosφ 3 cosφ 2 cosφ 3 357 Ref. 15 Wehave Wehage 368 Sparse matrx 100, 144 110, 144 ERRATA (Computer-Aded Analyss of Mechancal Systems Page 5