Well Stimulation and Sand Poduction Management (PGE 489 ) Sin Effect and Fomation Damage By D. Moammed A. Kami 02-02-2016
Sin Facto A fomation damage model i a dynamic elationip expeing te fluid tanpot capability of poou medium undegoing vaiou alteation pocee. Modeling fomation damage in petoleum eevoi a been of continuing inteet. Altoug many model ave been popoed, tee model do not ave te geneal applicability.
Hain Fomula p p eal p ideal
Hain Fomula eal f eal q p p p ln 2, ideal f ideal q p p p ln 2, q p 2 ideal eal p p p Steady-tate peue dop due to in i given by: q q q ln 2 ln 2 2 ln 1 ln 1 1 ln 1 Hain Fomula P p f
Hain Fomula p p eal ideal p q 2 d ( ) q ln 2 q 2 Steady-tate peue dop due to in i given by: p f P p p eal p ideal q q d q 2 2 ( ) 2 1 d ( ) 1 ln ln d ( ) ln Geneal Hain Fomula
Hain Fomula - Example
Hain Fomula - Example Example: aume tat a ell a a adiu equal to 0.25 ft, and te damage beyond te ell i 5 ft. Wat ould be te in effect if te pemeability impaiment eult in / equal to 6 and 12, epectively. Solution: 5.25 1 ln 0.25 6 1ln 15. 22 5.25 1 ln 0.25 12 1ln 33. 49
non-dacy Sin (S) Sin due to tubulence i additional peue dop caued by ig ga velocity nea te ellboe and applie only to ga ell. Dq D 610 5 0.1 2 pef Wee, i te ga gavity, i te nea-ellboe pemeability in md, and pef ae te net and pefoated ticnee in ft and i te ga vicoity in cp. Ti o te appaent in fom ell teting. Dq
non-dacy Sin (S) Example: Calculate te non-dacy coefficient fo ell it ellboe adiu of 0.25 ft. Aume tat i te ame a te eevoi pemeability (0.1 md) and pef i alf of te eevoi ticne. Ue a vicoity of 0.01 cp, ga gavity of 0.6, and eevoi ticne of 80 ft. Wat ill appen if te neaellboe pemeability educed by damage to one-fift? Solution: D 610 5 0.1 2 pef 610 5 (0.6)(0.1) 0.1 (0.01)(0.25)(40) (80) 2 9.0610 9 MSCF / d 1 D 610 5 0.1 2 pef 610 5 (0.6)(0.02) 0.1 (0.01)(0.25)(40) 2 (80) 1.0610 8 MSCF / d 1
Slanted/Patial Penetation
Patial Completion Sin Sin due to patial penetation i alay geate tan 0 and typically ange fom 0 to 30. Patial penetation it vetical pemeability ( v ) equal to zeo i te limiting cae. Sin facto can be etimated uing Hain fomula.
Patial Completion Sin Muat Model pp e 1 ln 1 0.5 1 7 co 2 z Completion Ratio = Reevoi eigt = Pefoation eigt z = Te elevation of te pefoation midpoint fom te bae of te eevoi Ti model did not conide te pemeability aniotopy
Ode Model pp Patial Completion Sin 0.825 H H 1.35 1 ln 0.49 0.1ln ln c 1. 95 V V Wee, c exp0.2126 z m 2.753 fo fo y 0 y 0 z m y 2 = Reevoi eigt = Pefoation eigt z = Te elevation of te pefoation midpoint fom te bae of te eevoi y = Te ditance fom top of eevoi to top of pefoation y z
Patial Completion Sin Papatzaco Model pp Wee, D 1D 1 pd A B 1D 1D pd y 1 ln 2D V H 1 1 3 pd 0.5 pd 4 4 1 pd 1 pd pd A1 B 1 0.5 All model aumed x = y y z = Reevoi eigt = Pefoation eigt z = Te elevation of te pefoation midpoint fom te bae of te eevoi y = Te ditance fom top of eevoi to top of pefoation
Patial Completion Sin Ref. Yildiz (2006), SPE-82249
Patial Completion Sin Example: A ell it a adiu = 0.328 ft i completed in a 33-ft eevoi. In ode to avoid evee ate coning poblem, only 8 ft ae completed and te midpoint of te pefoation i 29 ft above te bae of te eevoi. 1. Calculate te in effect due to patial completion fo a vetical ell. Wat ould be te compoite in effect if Ɵ = 45? 2. Repeat ti poblem fo = 330 ft, = 80 ft and z = 290 ft.
Patial Completion Sin - Example Solution: Te dimenionle eevoi ticne D i / = 33/0.328 = 100. Te elevation atio i z / = 29/33 = 0.875 Te completion atio i / = 8/33 = 0.25. Fom Table 5-1 fo a vetical ell, Ɵ = 0 and S c + Ɵ = 8.6, S c = 8.6 and S Ɵ = 0. If Ɵ = 45, ten S c = 8.6 but S Ɵ = -2.7 eulting in S c + Ɵ = 6. If D = 330/0.328 = 1000 and te ote atio ae te ame. Fom Table 5-2 S c + Ɵ = 15.7 fo te vetical ell and = 10.4 fo te 45 lant ell. S c + Ɵ
Patial Completion Sin - Example Solution: Ɵ D z / / S Ɵ + c S c S Ɵ
Sin due to Inclination Wen te angle of inclination toug te fomation i ignificant (> 10 ), a eduction in peue dop can occu due to te angle of inclination. Ti peue dop i defined a in due to inclination Te in i negative and te lage te angle of lant, te lage te negative contibution to te total in effect. ' 41 2.06 ' 56 1.865 log 100 D Doe negative all te time? H ' tan 1 tan V D H V
Pefoation Sin