CHEM3.4 Demonstrate understanding of thermochemical principles and the properties of particles and substances

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CHEM3.4 Demonstrate understanding of thermochemical principles and the properties of particles and substances We have covered the underlined part so far. This is: Electron configurations with s, p, d orbitals Periodic trends (atomic, ionic radii, electronegativity, ionisation energy) Lewis diagrams and shapes Polarity Intermolecular forces and physical properties

Thermochemical principals Enthalpy Exothermic Endothermic ΔH = H products - H reactants ΔH is ve ΔH is +ve Units: kj.mol -1

Heats of reaction When chemicals react together there is a transfer of energy. For example: Chemical energy is converted to heat energy when we burn fuels Chemical energy is converted to heat energy when we digest food The change in heat content during a reaction is called the change in enthalpy (ΔH) and is measured in kj.mol -1. Δ r H = H products H reactants Exothermic reactions have a ve ΔH Endothermic reactions have a +ve ΔH

Exo and endo thermic reactions E a Ea ΔH ΔH

Level 2 2013 Exam Q3 (a)

Level 2 2013 Q3 (b)

Do now: What are the products from the combustion reactions of the following compounds? C + O 2 CO 2 CH 3 OH + 3/2 O 2 CO 2 + 2 H 2 O C 5 H 12 + 8 O 2 5 CO 2 + 6 H 2 O S + O 2 SO 2

Standard heats of reaction The amount of heat given out is dependent on the amount of reactants involved in the reaction. 2 Ca (s) + O 2(g) 2 CaO (s) ΔH = -317.5 kj When 2 moles of Ca react with 1 mole of O 2 317.5 kj of energy is released. When 1 mole of Ca reacts with ½ a mole of O 2 half as much energy is released (158.75 kj). Standard heat of reaction Δ r H this bit means standard conditions 2 H 2(g) + O 2(g) 2 H 2 O (l) Δ r H (H 2 O (l) ) = -570 kj.mol -1 this bit means per mole of reaction (determined by the chemical equation)

Standard heats of reaction Standard heat of combustion Δ c H enthalpy change when 1 mole of a substance is burnt completely with all products and reactants in their standard states Always exothermic H 2(g) + ½ O 2(g) H 2 O (l) Δ c H (H 2(g) ) = -285 kj.mol -1 only 1 mole of the compound being combusted Standard heat of formation Δ f H enthalpy change when 1 mole of a substance is formed from its elements with all products and reactants in their standard states For all elements the standard heat of formation is zero H 2(g) + ½ O 2(g) H 2 O (l) Δ f H (H 2 O (g) ) = -285 kj.mol -1 elements in their standard states

Standard heats of reaction Write the equations for: The enthalpy of formation, Δ f H, for zinc oxide Zn (s) + ½O 2(g) ZnO (s) Δ f H (NH 3 ) ½N 2(g) + 1 ½H 2(g) NH 3(g) The enthalpy of combustion, Δ c H, for methanol, CH 3 OH CH 3 OH (l) + 1 ½O 2(g) CO 2(g) + 2 H 2 O (g) Δ c H (C 2 H 6 ) C 2 H 6(g) + 3 ½O 2(g) 2 CO 2(g) + 3 H 2 O (g) Workbook pg 51

Measuring enthalpy changes We can t measure the change in enthalpy directly, so we measure the increase or decrease in temperature of another substance, usually water, to work out how much energy has been lost or gained in the reaction. In the school lab, we measure the temperature change of a reaction with a thermometer and perform calculations. In industry insulated devices called calorimeters are used to measure the heat transferred to water. Tomorrow we will be measuring the enthalpy change of a neutralisation reaction.

Calculating standard enthalpy change of a reaction We need to know the mass, the change in temperature and the specific heat capacity of the solution. This allows us to work out ΔH. 1 st step q = m. Δt. s you will always be given this value J g C J. C -1 g -1 2 nd step Did temp increase or decrease? Increase ve value, decrease +ve value. This value is ΔH (you may convert to kj). 3 rd step Work out number of moles in reaction. Divide ΔH by number of moles to get a value for ΔH r in kj.mol -1

2013 Exam Q2 (b)

2013 Exam Q2 (b)

2013 Exam Q2 (b)

Do now: What is meant by the term Δ c H (CH 3 COOH)? The enthalpy change when 1 mole of ethanoic acid is burnt completely with all products and reactants in their standard states What is meant by the term Δ f H (CH 3 COOH)? The enthalpy change when 1 mole of ethanoic acid is formed from its elements with all products and reactants in their standard states Write equations for each Δ c H (CH 3 COOH) is CH 3 COOH + 2 O 2 2 CO 2 + 2 H 2 O Δ f H (CH 3 COOH) is 2 C + O 2 + 2 H 2 CH 3 COOH

Today Measuring the temperature change in a neutralisation reaction so that we can calculate the enthalpy change of the reaction and then the standard enthalpy change of the reaction (ΔH r ).

Do now: Write balanced equations for the following: Δ f H (CaO) Ca + ½ O 2 CaO Δ c H (C 4 H 10 ) Δ f H (C 6 H 12 O 6 ) C 4 H 10 + 13/2 O 2 4 CO 2 + 5 H 2 O 6 ½ 6 C + 3 O 2 + 6 H 2 C 6 H 12 O 6

Phase changes What occurs during a phase change? Breaking intermolecular bonds Δ vap H = energy needed to change one mole of substance from liquid to gas H 2 O (l) H 2 O (g) Δ vap H (H 2 O) = 41.1 kj.mol -1 Δ fus H = energy needed to change one mole of substance from solid to liquid H 2 O (s) H 2 O (l) Δ fus H (H 2 O) = 6 kj.mol -1 Why does the temperature not increase? Heat energy is being used to break intermolecular bonds rather than increase temp

Phase changes Workbook pg 55 and 56 Write equations for: Δ fus H (NaCl) NaCl (s) NaCl (l) Δ vap H (C 2 H 6 ) Δ f H (CH 3 CH 2 OH) C 2 H 6(l) C 2 H 6(g) 2 C + 3 H 2 + ½ O 2 CH 3 CH 2 OH (s) (g) (g) (l) Δ fus H (NH 3 ) NH 3(s) NH 3(l) What determines the size of Δ fus H and Δ vap H? The strength of the intermolecular forces. Strong intermolecular forces are harder to break so Δ fus H and Δ vap H will be higher.

Do now: Write balanced equations for the following (don t forget your states! (s), (l), (g) : Δ f H (CH 3 Br) Δ fus H (CH 3 OH) Δ vap H (CH 3 OH) C (s) + 1 ½ H 2(g) + ½ Br 2(l) CH 3 Br (g) CH 3 OH (s) CH 3 OH (l) CH 3 OH (l) CH 3 COH (g) What is the energy being used for in Δ vap H (CH 3 OH)? To break the intermolecular forces (hydrogen bonding) between the molecules What will have greatest value Δ fus H (CH 3 OH) or Δ vap H (CH 3 OH)? Δ vap H (CH 3 OH)

2014 Exam Q2 d Key words in the question? Key words in your answer?

2014 Exam Q2 d